Re: Please help for Python programming
Thanks for your help! I am already fix it!! Many thanks! -- http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
[EMAIL PROTECTED] wrote:
I am sorry that i forgot to see the working example. Base on your
example, i can show the value without missing but got the other
problem. I would like to culmulate the value by users.
This is (almost) exactly the same.
I was rewrite
your example but cannot not work.
##
import sys
import pprint
try:
f = open('data.txt', 'r')
except IOError, e:
print sys.stderr, Cannot open file data.txt for reading : %s
%e
sys.exit(1)
users = {}
cumdata2 = 0
cumdata3 = 0
for line in f:
try:
user, data1, data2 = line.strip().split('\t')
except ValueError:
print sys.stderr, wrong file format
f.close()
sys.exit(1)
try:
users[user].append(%s : %s % (data1, data2))
cumdata2 = int(data2) + cumdata2
Q1 : What do you think this will do ?
except KeyError:
users[user] = [%s : %s % (data1, data2)]
cumdata3 = int(data2) + cumdata3
Q2 : What do you think this will do ?
f.close()
print collected data:;
pprint.pprint(users)
print cumdata2
print cumdata3
##
The above example can run but the total num are wrong.
First, please post your test data set, the expected result and the
actual result. Saying 'the total num is wrong' doesn't give a clue.
Would you mind
to figure out where is my problem?
I may be wrong (pun intended), but I think you don't really understand
what this code is doing, specially this part :
try:
users[user].append(something)
except KeyError:
users[user] = [something]
In fact I think your problem is that you still have not read the fine
manual, specially the part about dicts.
Read the manual, understand the above snippet - which is a pretty common
idiom in Python -, try to answer Q1 and Q2, and you should be able to
work it out by yourself.
--
bruno desthuilliers
python -c print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])
--
http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
Thanks for your advice.^^
I find out something special (because i don't know). I would like to
retrieve data from source file into array. The data will be omited if
the value is duplicated. For example, there is 3 values - 1,2,1. It
will only display 1,2 after i ran the script.
value = (1,2,1)
while 1:
users = {}
byteDict = {}
byteDict = users[value]
users[value] = byteDict
print users
I think the above code cannot run properly. Any ppl knows why the value
omited when it was duplicated.
Many of thanks for all!!!
--
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Re: Please help for Python programming
[EMAIL PROTECTED] wrote:
Thanks for your advice.^^
It would be more useful to follow them than to thank me.
I find out something special (because i don't know). I would like to
retrieve data from source file into array. The data will be omited if
the value is duplicated. For example, there is 3 values - 1,2,1. It
will only display 1,2 after i ran the script.
value = (1,2,1)
while 1:
users = {}
byteDict = {}
byteDict = users[value]
users[value] = byteDict
print users
I think the above code cannot run properly.
Don't think. Be sure. Verify. Try to find out why it cannot run at
all[1]. Fix this problem first. *Then* we'll happily read your next
posts and try to help you fix the other problems if there are...
[1] It's pretty obvious for anyone having read any python beginner
tutorial, I already explained you why, and gave you a working example.
If you don't read answers, don't post questions :-/
--
bruno desthuilliers
python -c print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])
--
http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
I am sorry that i forgot to see the working example. Base on your
example, i can show the value without missing but got the other
problem. I would like to culmulate the value by users. I was rewrite
your example but cannot not work.
##
import sys
import pprint
try:
f = open('data.txt', 'r')
except IOError, e:
print sys.stderr, Cannot open file data.txt for reading : %s
%e
sys.exit(1)
users = {}
cumdata2 = 0
cumdata3 = 0
for line in f:
try:
user, data1, data2 = line.strip().split('\t')
except ValueError:
print sys.stderr, wrong file format
f.close()
sys.exit(1)
try:
users[user].append(%s : %s % (data1, data2))
cumdata2 = int(data2) + cumdata2
except KeyError:
users[user] = [%s : %s % (data1, data2)]
cumdata3 = int(data2) + cumdata3
f.close()
print collected data:;
pprint.pprint(users)
print cumdata2
print cumdata3
##
The above example can run but the total num are wrong. Would you mind
to figure out where is my problem?
Thanks for your prompt help!!!
--
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Re: Please help for Python programming
[EMAIL PROTECTED] wrote:
(snip)
The PRINT code is for my testing. My problem is bytemsg will be omitted
some records. For example, my text file have 53 records about username.
After byteDict = users1[user1],
Which, from your previous snippet, should raise a KeyError... If it
does, then first understand why and fix it. If it does not, then the
code you posted is absolutely useless for us to help you.
it remains 50 records in the output
file.
There is nothing about reading and parsing file in the code you posted.
I'm afraid you did not follow Diez's advice, nor mine. Please re-read my
previous post, take appropriate action, and re-post with the minimum
*working* snippet that exhibit your problem.
I would like to know how to culmulate some data by users.
data.txt
user1;aaa;000
user2;aab;001
user3;aac;002
user1;aad;004
user3;aae;005
user1;aaf;006
user2;aag;007
user2;aah;008
user2;aak;009
user1;zzz;999
accu.py
import sys
import pprint
try:
f = open('data.txt', 'r')
except IOError, e:
print sys.stderr, Cannot open file data.txt for reading : %s % e
sys.exit(1)
users = {}
for line in f:
try:
user, data1, data2 = line.strip().split(';')
except ValueError:
print sys.stderr, wrong file format
f.close()
sys.exit(1)
try:
users[user].append(%s : %s % (data1, data2))
except KeyError:
users[user] = [%s : %s % (data1, data2)]
f.close()
print collected data:;
pprint.pprint(users)
--
bruno desthuilliers
python -c print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])
--
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Re: Please help for Python programming
Terry, This was posted from google groups, can you see the indents? # code snippet convertpage = 0 form = None for o, a in opts: if o in [-h, --help]: Usage() sys.exit() if o in [-o, --output, --out]: output = a if o in [-i, --input, --in]: input = a if input in [., cwd]: input = os.getcwd() Notice the 'fixed font / proportional font' link in the top right corner. I think they have fixed the problem. M.E.Farmer Terry Reedy wrote: This is what I see (minus the ' '): while 1: user, serviceType, msgType, inOut, date, time, numBytes = aLog.GetNextMessage() [etc] Advice: use spaces, not tabs, to indent posted code (some readers discard tabs). Don't use google groups to post code (it deletes initial spaces and won't, apparently, fix this bug). Use news.gmane.org group gmane.comp.python.genral instead (I believe they also have web interface in addition to newsreader interface). If you really, really must post thru google, prefix lines with char such as '|', even tho this kill cut and pastability. Terry J. Reedy -- http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
M.E.Farmer [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Terry, This was posted from google groups, can you see the indents? Yes, looks good # code snippet convertpage = 0 form = None for o, a in opts: if o in [-h, --help]: Usage() sys.exit() if o in [-o, --output, --out]: output = a if o in [-i, --input, --in]: input = a if input in [., cwd]: input = os.getcwd() Notice the 'fixed font / proportional font' link in the top right corner. I presume this is on the Google page. I think they have fixed the problem. Great. Now people have to learn to use the fixed font choice. TJR -- http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
Hello again, For some strange reason Google isn't showing this so I got this from gmane sorry if I missed something. The fixed/proportional link is located on the google groups c.l.py pages. I wasn't clear at all sorry for the ambiguity. Google groups for c.l.py seems to be fixed by default, so no need to click it. Proportional still retains spaces but is less tidy. M.E.Farmer Terry, This was posted from google groups, can you see the indents? Yes, looks good # code snippet convertpage = 0 form = None for o, a in opts: if o in [-h, --help]: Usage() sys.exit() if o in [-o, --output, --out]: output = a if o in [-i, --input, --in]: input = a if input in [., cwd]: input = os.getcwd() Notice the 'fixed font / proportional font' link in the top right corner. I presume this is on the Google page. I think they have fixed the problem. Great. Now people have to learn to use the fixed font choice. TJR -- http://mail.python.org/mailman/listinfo/python-list
Please help for Python programming
I don't know why i entered the below code and it will miss some
records.
Anyone can help me???
users = {}
users1 = {}
while 1:
user, serviceType, msgType, inOut, date, time, numBytes =
aLog.GetNextMessage()
fullmsg = serviceType + | + msgType + | + inOut
bytemsg = user + + serviceType + + msgType + + inOut +
+ numBytes
user1 = user
msgDict = {}
byteDict = {}
print bytemsg # 53 records in source file
msgDict = users[user] # get the cum statistics for this user
byteDict = users1[user1]
print bytemsg # 50 records in source file
--
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Re: Please help for Python programming
[EMAIL PROTECTED] wrote: I don't know why i entered the below code and it will miss some records. Anyone can help me??? Sorry, my mindreading brain extension is at the service right now, so I can't guess what that piece of syntactically incorrect code is supposed to do and what error message it produces. Until you come up with a more detailed error description, I'll have a good read at http://www.catb.org/~esr/faqs/smart-questions.html Which I suggest you read too. -- Regards, Diez B. Roggisch -- http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
[EMAIL PROTECTED] wrote:
I don't know why i entered the below code
And we don't know either !-)
and it will miss some
records.
Anyone can help me???
If you hope to get some useful help, it would be a good idea to follow
Diez's advice (see other post in this thread)
users = {}
users1 = {}
while 1:
Unless there is a break somewhere in the following code (I can't find
one...), this is an endless loop. But you know this, don't you ?
user, serviceType, msgType, inOut, date, time, numBytes =
aLog.GetNextMessage()
fullmsg = serviceType + | + msgType + | + inOut
tip : use string formating instead (string concatenations are to be
avoided in Python), ie:
fullmsg = %s | %s | %s % (serviceType, msgType, inOut)
bytemsg = user + + serviceType + + msgType + + inOut +
+ numBytes
idem
user1 = user
msgDict = {}
byteDict = {}
This re-initialises both dicts on each iteration. Is this really what
you want ?
print bytemsg # 53 records in source file
Here you have an obvious indentation problem. This code *cannot* run.
Take care of not mixing tabs and spaces (tip: configure you editor to
only use spaces)
msgDict = users[user] # get the cum statistics for this user
Given the above binding of 'users' as an empty dict, this should raise a
KeyError. It's also overwriting the previous binding of msgDict.
byteDict = users1[user1]
idem. Also, you don't need to bind 2 different names to the same value
to use this value as key in 2 different dicts. Here you could as well
use user for both dicts, since user and user1 are bound to the same value.
print bytemsg # 50 records in source file
In addition to Diez's reading advice, here are some that are more
specific to code-related questions:
1/ paste code, dont re-type it
... this avoid stupid typos
2/ post running code
... if the code is so obviously broked that it cannot even compile|run,
readers will have to fix it first - which they'll probably won't do.
Even if they do, they may not fix it the right way. Everyone's losing
its time...
3/ post the smallest possible bit of code that exhibit your problem
... no one's going to [read 3000 lines of code | install 30 gigabytes of
third part libs | etc...] just to help you. Moreover, quite often, one
finds the bug while reducing the problematic code to it's smallest possible.
And one last: don't forget to put your bullet-proof jacket on before
reading the answers !-) (well, c.l.py is probably one of the friendliest
groups on usenet, but still, this is usenet).
--
bruno desthuilliers
python -c print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])
--
http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
This is what I see (minus the ' '): while 1: user, serviceType, msgType, inOut, date, time, numBytes = aLog.GetNextMessage() [etc] Advice: use spaces, not tabs, to indent posted code (some readers discard tabs). Don't use google groups to post code (it deletes initial spaces and won't, apparently, fix this bug). Use news.gmane.org group gmane.comp.python.genral instead (I believe they also have web interface in addition to newsreader interface). If you really, really must post thru google, prefix lines with char such as '|', even tho this kill cut and pastability. Terry J. Reedy -- http://mail.python.org/mailman/listinfo/python-list
Re: Please help for Python programming
Actually, this script will open a text file which is seperated by tabs. The PRINT code is for my testing. My problem is bytemsg will be omitted some records. For example, my text file have 53 records about username. After byteDict = users1[user1], it remains 50 records in the output file. I would like to know how to culmulate some data by users. Thanks! -- http://mail.python.org/mailman/listinfo/python-list
