Re: best way to remove leading zeros from a tuple like string

[Dan Stromberg]

On Sun, May 20, 2018 at 12:54 PM,   wrote:
> Lets say I have the following tuple like string.
>   (128, 020, 008, 255)
>
> What is the best way to to remove leading zeroes and end up with the 
> following.
>   (128, 20, 8, 255)-- I do not care about spaces
>
> This is the solution I came up with
> s = "(128, 020, 008, 255)"
> v = s.replace ("(", "")
> v = v.replace (")", "")
> vv = ",".join([str(int(i)) for i in v.split(",")])
> final = "(" + vv + ")"

I actually like your solution pretty well - especially the splitting
on "," and applying int() to the pieces. If you want a simple regex
solution though, the following should work on Python 1.5 through
3.7b3:

$ pythons --command 'import re; print("(" + re.sub("(\(| )0*", "",
"(128, 020, 008, 255)"))'
below cmd output started 2018 Wed May 23 01:23:00 PM PDT
/usr/local/cpython-1.0/bin/python (1.0.1) bad
Traceback (innermost last):
  File "", line 1
ImportError: No module named re
/usr/local/cpython-1.1/bin/python (1.1) bad
Traceback (innermost last):
  File "", line 1, in ?
ImportError: No module named re
/usr/local/cpython-1.2/bin/python (1.2) bad
Traceback (innermost last):
  File "", line 1, in ?
ImportError: No module named re
/usr/local/cpython-1.3/bin/python (1.3) bad
Traceback (innermost last):
  File "", line 1, in ?
ImportError: No module named re
/usr/local/cpython-1.4/bin/python (1.4) bad
Traceback (innermost last):
  File "", line 1, in ?
ImportError: No module named re
/usr/local/cpython-1.5/bin/python (1.5.2) good (128,20,8,255)
/usr/local/cpython-1.6/bin/python (1.6.1) good (128,20,8,255)
/usr/local/cpython-2.0/bin/python (2.0.1) good (128,20,8,255)
/usr/local/cpython-2.1/bin/python (2.1.0) good (128,20,8,255)
/usr/local/cpython-2.2/bin/python (2.2.0) good (128,20,8,255)
/usr/local/cpython-2.3/bin/python (2.3.0) good (128,20,8,255)
/usr/local/cpython-2.4/bin/python (2.4.0) good (128,20,8,255)
/usr/local/cpython-2.5/bin/python (2.5.6) good (128,20,8,255)
/usr/local/cpython-2.6/bin/python (2.6.9) good (128,20,8,255)
/usr/local/cpython-2.7/bin/python (2.7.13) good (128,20,8,255)
/usr/local/cpython-3.0/bin/python (3.0.1) good (128,20,8,255)
/usr/local/cpython-3.1/bin/python (3.1.5) good (128,20,8,255)
/usr/local/cpython-3.2/bin/python (3.2.5) good (128,20,8,255)
/usr/local/cpython-3.3/bin/python (3.3.3) good (128,20,8,255)
/usr/local/cpython-3.4/bin/python (3.4.2) good (128,20,8,255)
/usr/local/cpython-3.5/bin/python (3.5.0) good (128,20,8,255)
/usr/local/cpython-3.6/bin/python (3.6.0) good (128,20,8,255)
/usr/local/cpython-3.7/bin/python (3.7.0b3) good (128,20,8,255)
/usr/local/jython-2.7/bin/jython (2.7.0) good (128,20,8,255)
/usr/local/pypy-5.10.0/bin/pypy (2.7.13) good (128,20,8,255)
/usr/local/pypy-5.3.1/bin/pypy (2.7.10) good (128,20,8,255)
/usr/local/pypy-5.9.0/bin/pypy (2.7.13) good (128,20,8,255)
/usr/local/pypy-6.0.0/bin/pypy (2.7.13) good (128,20,8,255)
/usr/local/pypy3-5.10.0/bin/pypy3 (3.5.3) good (128,20,8,255)
/usr/local/pypy3-5.5.0/bin/pypy3 (3.3.5) good (128,20,8,255)
/usr/local/pypy3-5.8.0-with-lzma-fixes/bin/pypy3 (3.5.3) good (128,20,8,255)
/usr/local/pypy3-5.8.0/bin/pypy3 (3.5.3) good (128,20,8,255)
/usr/local/pypy3-5.9.0/bin/pypy3 (3.5.3) good (128,20,8,255)
/usr/local/pypy3-6.0.0/bin/pypy3 (3.5.3) good (128,20,8,255)
/usr/local/micropython-git-2017-06-16/bin/micropython (3.4.0) good
(128,20,8,255)

HTH
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Re: best way to remove leading zeros from a tuple like string

[Chris Angelico]

On Wed, May 23, 2018 at 12:50 AM, Grant Edwards
 wrote:
> On 2018-05-22, Thomas Jollans  wrote:
>> On 2018-05-20 23:54, Paul wrote:
>>> you will find several useful sites where you can test regexes.  Regex
>>> errors are very common, even after you have experience with them.
>>
>> What's the benefit of those compared to simply trying out the regex in a
>> Python console?
>
> Doesn't everybody have an executable file in their home directory
> named "testit.py" which is continually morphed to test different
> Python features?
>

Certainly not! Mine is ~/tmp/runme.py in case I need other files with it.

:)

ChrisA
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Re: best way to remove leading zeros from a tuple like string

[Grant Edwards]

On 2018-05-22, Thomas Jollans  wrote:
> On 2018-05-20 23:54, Paul wrote:
>> you will find several useful sites where you can test regexes.  Regex
>> errors are very common, even after you have experience with them.
>
> What's the benefit of those compared to simply trying out the regex in a
> Python console?

Doesn't everybody have an executable file in their home directory
named "testit.py" which is continually morphed to test different
Python features?

-- 
Grant Edwards   grant.b.edwardsYow! What's the MATTER
  at   Sid? ... Is your BEVERAGE
  gmail.comunsatisfactory?

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Re: best way to remove leading zeros from a tuple like string

[Paul]

Thomas Jollans wrote:

> On 2018-05-20 23:54, Paul wrote:
> > you will find several useful sites where you can test regexes.
>
> What's the benefit of those compared to simply trying out the regex in a
> Python console?
>

Possibly nothing.  But there are obvious benefits compared to trying to
write and test such an expression in one's head, which was the situation
which led me to suggest it.  :)

>
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Re: best way to remove leading zeros from a tuple like string

[Thomas Jollans]

On 2018-05-20 23:54, Paul wrote:
> you will find several useful sites where you can test regexes.  Regex
> errors are very common, even after you have experience with them.

What's the benefit of those compared to simply trying out the regex in a
Python console?
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Re: best way to remove leading zeros from a tuple like string

[Wolfram Hinderer via Python-list]

Am 21.05.2018 um 01:16 schrieb bruceg113...@gmail.com:

If I decide I need the parentheses, this works.


"(" + ",".join([str(int(i)) for i in s[1:-1].split(",")]) + ")"

'(128,20,8,255,-1203,1,0,-123)'

Thanks,
Bruce


Creating the tuple seems to be even simpler.

>>> str(tuple(map(int, s[1:-1].split(","
'(128, 20, 8, 255, -1203, 1, 0, -123)'

Wolfram
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Re: best way to remove leading zeros from a tuple like string

[brucegoodstein]

On Monday, May 21, 2018 at 1:05:52 PM UTC-4, Rodrigo Bistolfi wrote:
> >>> repr(tuple(int(i) for i in s[1:-1].split(',')))
> '(128, 20, 8, 255, -1203, 1, 0, -123)'
> 
> 2018-05-21 4:26 GMT-03:00 Peter Otten <__pete...@web.de>:
> 
> > bruceg113...@gmail.com wrote:
> >
> > > Looking over the responses, I modified my original code as follows:
> > >
> >  s = "(128, 020, 008, 255, -1203,01,-000, -0123)"
> >  ",".join([str(int(i)) for i in s[1:-1].split(",")])
> > > '128,20,8,255,-1203,1,0,-123'
> >
> > I think this looks better with a generator instead of the listcomp:
> >
> > >>> ",".join(str(int(i)) for i in s[1:-1].split(","))
> > '128,20,8,255,-1203,1,0,-123'
> >
> >
> > --
> > https://mail.python.org/mailman/listinfo/python-list
> >


I am not familiar with the repr statement.
Looking into your response, I like it.
There is no need to add-in the parentheses.

With the repr statment:
>>> bb = repr (tuple (int (i) for i in s [1: -1] .split (',')))
>>> bb
'(128, 20, 8, 255, -1203, 1, 0, -123)'
>>> type(bb)

>>>

Without the repr statement:
>>> aa = (tuple (int (i) for i in s [1: -1] .split (',')))
>>> aa
(128, 20, 8, 255, -1203, 1, 0, -123)
>>> type(aa)

>>>

Thanks,
Bruce



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Re: best way to remove leading zeros from a tuple like string

[Rodrigo Bistolfi]

>>> repr(tuple(int(i) for i in s[1:-1].split(',')))
'(128, 20, 8, 255, -1203, 1, 0, -123)'

2018-05-21 4:26 GMT-03:00 Peter Otten <__pete...@web.de>:

> bruceg113...@gmail.com wrote:
>
> > Looking over the responses, I modified my original code as follows:
> >
>  s = "(128, 020, 008, 255, -1203,01,-000, -0123)"
>  ",".join([str(int(i)) for i in s[1:-1].split(",")])
> > '128,20,8,255,-1203,1,0,-123'
>
> I think this looks better with a generator instead of the listcomp:
>
> >>> ",".join(str(int(i)) for i in s[1:-1].split(","))
> '128,20,8,255,-1203,1,0,-123'
>
>
> --
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>
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Re: best way to remove leading zeros from a tuple like string

[Peter Otten]

bruceg113...@gmail.com wrote:

> Looking over the responses, I modified my original code as follows:
> 
 s = "(128, 020, 008, 255, -1203,01,-000, -0123)"
 ",".join([str(int(i)) for i in s[1:-1].split(",")])
> '128,20,8,255,-1203,1,0,-123'

I think this looks better with a generator instead of the listcomp:

>>> ",".join(str(int(i)) for i in s[1:-1].split(","))
'128,20,8,255,-1203,1,0,-123'


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Re: best way to remove leading zeros from a tuple like string

[bruceg113355]

On Sunday, May 20, 2018 at 6:56:05 PM UTC-4, Ben Bacarisse wrote:
> "Michael F. Stemper"  writes:
> 
> > On 2018-05-20 16:19, Ben Bacarisse wrote:
> >> bruceg113...@gmail.com writes:
> >>
> >>> Lets say I have the following tuple like string.
> >>>(128, 020, 008, 255)
> >>>
> >>> What is the best way to to remove leading zeroes and end up with the 
> >>> following.
> >>>(128, 20, 8, 255)-- I do not care about spaces
> >>
> >> You could use a regexp:
> >>
> >>import re
> >>...
> >>re.sub(r"(? >>
> >> I post this because I think it works (interesting corner cases are 10005
> >> and 000), 
> >
> > Seeing this makes me realize that mine will eliminate any numbers that
> > are all leading zero, including '0'. Also, forms like '-0042' will be
> > left unchanged.
> 
> I realised after posting the negatives won't work.  Not, I suspect, an
> issue for the OP but -0042 can certainly be said to have "leading
> zeros".
> 
> > Maybe splitting it into integer forms and sending each through
> > str( int( ) ) would be the safest.
> 
> Yup.  I gave a version of that method too which handles negative numbers
> by accident (by leaving the - in place!).  A better version would be
> 
>   re.sub(r"-?[0-9]+", lambda m: str(int(m.group(0))), s)
> 
> 
> -- 
> Ben.



Looking over the responses, I modified my original code as follows:

>>> s = "(128, 020, 008, 255, -1203,01,-000, -0123)" 
>>> ",".join([str(int(i)) for i in s[1:-1].split(",")])
'128,20,8,255,-1203,1,0,-123'


If I decide I need the parentheses, this works.

>>> "(" + ",".join([str(int(i)) for i in s[1:-1].split(",")]) + ")"
'(128,20,8,255,-1203,1,0,-123)'

Thanks,
Bruce

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Re: best way to remove leading zeros from a tuple like string

[Ben Bacarisse]

"Michael F. Stemper"  writes:

> On 2018-05-20 16:19, Ben Bacarisse wrote:
>> bruceg113...@gmail.com writes:
>>
>>> Lets say I have the following tuple like string.
>>>(128, 020, 008, 255)
>>>
>>> What is the best way to to remove leading zeroes and end up with the 
>>> following.
>>>(128, 20, 8, 255)-- I do not care about spaces
>>
>> You could use a regexp:
>>
>>import re
>>...
>>re.sub(r"(?>
>> I post this because I think it works (interesting corner cases are 10005
>> and 000), 
>
> Seeing this makes me realize that mine will eliminate any numbers that
> are all leading zero, including '0'. Also, forms like '-0042' will be
> left unchanged.

I realised after posting the negatives won't work.  Not, I suspect, an
issue for the OP but -0042 can certainly be said to have "leading
zeros".

> Maybe splitting it into integer forms and sending each through
> str( int( ) ) would be the safest.

Yup.  I gave a version of that method too which handles negative numbers
by accident (by leaving the - in place!).  A better version would be

  re.sub(r"-?[0-9]+", lambda m: str(int(m.group(0))), s)


-- 
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Re: best way to remove leading zeros from a tuple like string

[Michael F. Stemper]

On 2018-05-20 16:19, Ben Bacarisse wrote:
bruceg113...@gmail.com writes:

Lets say I have the following tuple like string.
   (128, 020, 008, 255)

What is the best way to to remove leading zeroes and end up with the following.
   (128, 20, 8, 255)-- I do not care about spaces

You could use a regexp:

   import re
   ...
   re.sub(r"(?and 000), 

Seeing this makes me realize that mine will eliminate any numbers that
are all leading zero, including '0'. Also, forms like '-0042' will be
left unchanged.

Maybe splitting it into integer forms and sending each through
str( int( ) ) would be the safest. This partly does the trick, but
packing the results back into a string that resembles a tuple has
been left as a short exercise for the student:

>>> tuple = '(0128, 020, 000, 008, -0042,255)'
>>> fields = tuple[1:len(tuple)-1].split(",")
>>> for field in fields:
...   print( str(int(field)) )
...
128
20
0
8
-42
255
>>>


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Why doesn't anybody care about apathy?
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Re: best way to remove leading zeros from a tuple like string

[Peter Otten]

bruceg113...@gmail.com wrote:

> Lets say I have the following tuple like string.
>   (128, 020, 008, 255)
> 
> What is the best way to to remove leading zeroes and end up with the
> following.
>   (128, 20, 8, 255)-- I do not care about spaces
> 
> This is the solution I came up with
> s = "(128, 020, 008, 255)"
> v = s.replace ("(", "")
> v = v.replace (")", "")
> vv = ",".join([str(int(i)) for i in v.split(",")])
> final = "(" + vv + ")"

Two more:

>>> s = "(128, 020, 008, 255, -1203,01,-000, -0123)"

>>> str(tuple(map(int, s[1:-1].split(","
'(128, 20, 8, 255, -1203, 1, 0, -123)'

>>> re.sub(r"\b0+\B", "", s)
'(128, 20, 8, 255, -1203,1,-0, -123)'


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Re: best way to remove leading zeros from a tuple like string

[bruceg113355]

On Sunday, May 20, 2018 at 5:32:32 PM UTC-4, Paul wrote:
> >
> >
> > This works for me: mytuplestring.replace("0","")
> >
> > Your regex will also eliminate  non-leading zeros.


Your right, what was I thinking?
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Re: best way to remove leading zeros from a tuple like string

[Paul]

On Sun, May 20, 2018, 5:53 PM Paul  wrote:

> This works for me: mytuplestring.replace("0","")
>
>>
>>> Your regex will also eliminate  non-leading zeros.
>>
>>
> If you Google
>
> regex tester
>
> you will find several useful sites where you can test regexes.  Regex
> errors are very common, even after you have experience with them.
>
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Re: best way to remove leading zeros from a tuple like string

[Paul]

>
>
> This works for me: mytuplestring.replace("0","")
>
> Your regex will also eliminate  non-leading zeros.
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Re: best way to remove leading zeros from a tuple like string

[bruceg113355]

On Sunday, May 20, 2018 at 5:01:08 PM UTC-4, Michael F. Stemper wrote:
> On 2018-05-20 14:54, bruceg113...@gmail.com wrote:
> > Lets say I have the following tuple like string.
> >(128, 020, 008, 255)
> > 
> > What is the best way to to remove leading zeroes and end up with the 
> > following.
> >(128, 20, 8, 255)-- I do not care about spaces
> 
> 
> I'd use a few regular expressions:
> 
>  >>> from re import sub
>  >>> tuple = '(0128, 020, 008,012, 255)'
>  >>> sub( " 0*", " ", tuple ) # leading zeroes following space(s)
> '(0128, 20, 8,012, 255)'
>  >>> sub( ",0*", ",", tuple ) # leading zeroes following comma
> '(0128, 020, 008,12, 255)'
>  >>> sub( "\(0*", "(", tuple ) # leading zeroes after opening parend
> '(128, 020, 008,012, 255)'
> 
> Each step could be written as "tuple = sub( ..."
> 
>  >>> tuple = sub( " 0*", " ", tuple ) # following space(s)
>  >>> tuple = sub( ",0*", ",", tuple ) # following comma
>  >>> tuple = sub( "\(0*", "(", tuple ) # after opening parend
>  >>> tuple
> '(128, 20, 8,12, 255)'
>  >>>
> 
> 
> Or, if you like to make your code hard to read and maintain, you could
> combine them all into a single expression:
> 
>  >>> sub( " 0*", " ", sub( ",0*", ",", sub( "\(0*", "(", tuple ) ) )
> '(128, 20, 8,12, 255)'
>  >>>
> 
> -- 
> Michael F. Stemper
> What happens if you play John Cage's "4'33" at a slower tempo?



I did not think about using regular expressions.
After your response, I looked into regular expressions and also found  
Regex.Replace
After thinking about my question, I said why not use a replace statement.
This works for me: mytuplestring.replace("0","")

Thanks for a good starting point:)
Bruce
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Re: best way to remove leading zeros from a tuple like string

[Ben Bacarisse]

bruceg113...@gmail.com writes:

> Lets say I have the following tuple like string.
>   (128, 020, 008, 255)
>
> What is the best way to to remove leading zeroes and end up with the 
> following.
>   (128, 20, 8, 255)-- I do not care about spaces

You could use a regexp:

  import re
  ...
  re.sub(r"(?https://mail.python.org/mailman/listinfo/python-list

Re: best way to remove leading zeros from a tuple like string

[Michael F. Stemper]

On 2018-05-20 14:54, bruceg113...@gmail.com wrote:

Lets say I have the following tuple like string.
   (128, 020, 008, 255)

What is the best way to to remove leading zeroes and end up with the following.
   (128, 20, 8, 255)-- I do not care about spaces



I'd use a few regular expressions:

>>> from re import sub
>>> tuple = '(0128, 020, 008,012, 255)'
>>> sub( " 0*", " ", tuple ) # leading zeroes following space(s)
'(0128, 20, 8,012, 255)'
>>> sub( ",0*", ",", tuple ) # leading zeroes following comma
'(0128, 020, 008,12, 255)'
>>> sub( "\(0*", "(", tuple ) # leading zeroes after opening parend
'(128, 020, 008,012, 255)'

Each step could be written as "tuple = sub( ..."

>>> tuple = sub( " 0*", " ", tuple ) # following space(s)
>>> tuple = sub( ",0*", ",", tuple ) # following comma
>>> tuple = sub( "\(0*", "(", tuple ) # after opening parend
>>> tuple
'(128, 20, 8,12, 255)'
>>>


Or, if you like to make your code hard to read and maintain, you could
combine them all into a single expression:

>>> sub( " 0*", " ", sub( ",0*", ",", sub( "\(0*", "(", tuple ) ) )
'(128, 20, 8,12, 255)'
>>>

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What happens if you play John Cage's "4'33" at a slower tempo?
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best way to remove leading zeros from a tuple like string

[bruceg113355]

Lets say I have the following tuple like string.
  (128, 020, 008, 255)

What is the best way to to remove leading zeroes and end up with the following.
  (128, 20, 8, 255)-- I do not care about spaces

This is the solution I came up with
s = "(128, 020, 008, 255)"
v = s.replace ("(", "")
v = v.replace (")", "")
vv = ",".join([str(int(i)) for i in v.split(",")])
final = "(" + vv + ")"


Thanks,
Bruce
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