Re: [R] Sparse KMeans/KDE/Nearest Neighbors?

2010-02-25 Thread Tal Galili
Hello Manyu,
I am guessing you refer to the netflix dataset.

Try looking at ways to represent large data sets, that is, the list from
here:
http://cran.r-project.org/web/views/HighPerformanceComputing.html


Here it is:

*Large memory and out-of-memory data*

   - The biglm http://cran.r-project.org/web/packages/biglm/index.html
package
   by Lumley uses incremental computations to offers lm() and glm()
functionality
   to data sets stored outside of R's main memory.
   - The ff http://cran.r-project.org/web/packages/ff/index.html package
   by Adler et al. offers file-based access to data sets that are too large to
   be loaded into memory, along with a number of higher-level functions.
   - The bigmemoryhttp://cran.r-project.org/web/packages/bigmemory/index.html
package
   by Kane and Emerson permits storing large objects such as matrices in memory
   and uses external pointer objects to refer to them. This permits transparent
   access from R without bumping against R's internal memory limits. Several R
   processes on the same computer can also shared big memory objects.
   - A large number of database packages, and database-alike packages (such
   as sqldf http://cran.r-project.org/web/packages/sqldf/index.html by
   Grothendieck and
data.tablehttp://cran.r-project.org/web/packages/data.table/index.html
by
   Dowle) are also of potential interest but not reviewed here.
   - The 
HadoopStreaminghttp://cran.r-project.org/web/packages/HadoopStreaming/index.html
package
   provides a framework for writing map/reduce scripts for use in Hadoop
   Streaming; it also facilitates operating on data in a streaming fashion
   which does not require Hadoop.
   - The speedglmhttp://cran.r-project.org/web/packages/speedglm/index.html
package
   permits to fit (generalised) linear models to large data. For in-memory data
   sets, speedlm() or speedglm() can be used along with update.speedlm() which
   can update fitted models with new data. For out-of-memory data sets, shglm()
   is available; it works in the presence of factors and can check for singular
   matrices.
   - The biglars
http://cran.r-project.org/web/packages/biglars/index.html package
   by Seligman et al can use the
ffhttp://cran.r-project.org/web/packages/ff/index.html to
   support large-than-memory datasets for least-angle regression, lasso and
   stepwise regression.






Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
--




On Thu, Feb 25, 2010 at 12:00 AM, manyu_aditya
abhimanyu.adi...@gmail.comwrote:


 hi,

 I have a dataset (the netflix dataset) which is basically ~18k columns and
 well variable number of rows but let's assume 25 thousand for now. The
 dataset is very sparse. I was wondering how to do kmeans/nearest neighbors
 or kernel density estimation on it.

 I tired using the spMatrix function in Matrix package. I think I'm able
 to
 create the matrix but as soon as I pass it to kmeans functions in package
 stats it says cannot allocate 3.3Gb. Which is basically 18k * 25K * 8.

 There is a sparse kmeans solver by tibshirani but that epxects a regular
 dense format matrix so again the issue is the same.

 A simple no this is not possible answer shall suffice as long as you are
 right!!!

 tHanks much.
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[R] different types graphs

2010-02-25 Thread chinna

library(RODBC)
ch- odbcConnect(durga)
 sqlQuery(ch, paste(SELECT * from emp))
sqlQuery(ch, (SELECT * from xyz))

store  revenue   year_y
1  bigbazar  7878752008
2  more   87876 2008

 plot(revenue ~ year_y, data=xyz, pch=16)


can i get any diffrent types of graphs like pie charts, bar plots.using plot
commands?

please give me suggestions.
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[R] What is assign attribute?

2010-02-25 Thread rkevinburton

I am just curious. Every once and a while I see an attribute attached to an 
object called assign. What meaning does this have? For example:

dist ~ speed, data=cars

forms a matrix like:

 num [1:50, 1:2] 1 1 1 1 1 1 1 1 1 1 ...
 - attr(*, dimnames)=List of 2
  ..$ : chr [1:50] 1 2 3 4 ...
  ..$ : chr [1:2] (Intercept) speed
 - attr(*, assign)= int [1:2] 0 1

The dimnames attribute is fairly self-explanatory. I just am not sure what 
the assign attribute means.

Thank you.

Kevin

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[R] What is assign attribute?

2010-02-25 Thread rkevinburton

I am just curious. Every once and a while I see an attribute attached to an 
object called assign. What meaning does this have? For example:

dist ~ speed, data=cars

forms a matrix like:

 num [1:50, 1:2] 1 1 1 1 1 1 1 1 1 1 ...
 - attr(*, dimnames)=List of 2
  ..$ : chr [1:50] 1 2 3 4 ...
  ..$ : chr [1:2] (Intercept) speed
 - attr(*, assign)= int [1:2] 0 1

The dimnames attribute is fairly self-explanatory. I just am not sure what 
the assign attribute means.

Thank you.

Kevin

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Re: [R] different types graphs

2010-02-25 Thread Ivan Calandra

Hi!

Here are a few tips to start finding what you need (in R):
apropos(pie)
RSiteSearch(pie)

Try also:
?pie
?barplot

I guess there are hundreds of commands to do every type of graphics, but 
you can start there.
The manual Using R for Data Analysis and Graphics from JH Maindonald 
is also quite good, among many others!


HTH
Ivan

Le 2/25/2010 09:48, chinna a écrit :
   

library(RODBC)
ch- odbcConnect(durga)
sqlQuery(ch, paste(SELECT * from emp))
sqlQuery(ch, (SELECT * from xyz))
 

 store  revenue   year_y
1  bigbazar  7878752008
2  more   87876 2008

  plot(revenue ~ year_y, data=xyz, pch=16)


can i get any diffrent types of graphs like pie charts, bar plots.using plot
commands?

please give me suggestions.



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Re: [R] different types graphs

2010-02-25 Thread Detlef Steuer
On Thu, 25 Feb 2010 00:48:04 -0800 (PST)
chinna durgache...@gmail.com wrote:

 
 library(RODBC)
 ch- odbcConnect(durga)
  sqlQuery(ch, paste(SELECT * from emp))
 sqlQuery(ch, (SELECT * from xyz))
 
 store  revenue   year_y
 1  bigbazar  7878752008
 2  more   87876 2008
 
  plot(revenue ~ year_y, data=xyz, pch=16)
 
 
 can i get any diffrent types of graphs like pie charts, bar plots.using plot
 commands?
 
 please give me suggestions.

try

demo(graphics) for a start

detlef

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[R] how to fast extract values from different list elements

2010-02-25 Thread Heym, Peter-Paul
hi,

I have a list L having more than 14000 Elements, each of these contains an
array of about length 1200.

 L[[1]][26:30] # e.g. print 5 entries of first element of L
[1]   0.000   6.7982652 114.4737184  89.7328239   3.2001664

Furthermore I get two arrays A and B of same length as input.

A-c(4,7,9,34,463,788)
B-c(50,67,87,361,45,89)

I would like to extract (or print or save) certain values of L which I do in
the following (inefficient) way at the moment:

for (i in 1:length(A) {
print( L[[A[i]]][B[i]] ) }

this works fine but it is very slow (since A and B can be very large and I
have to repeat this about 5000 times). I would like to make this faster using
e.g. apply or lapply but I didn't get it work using these methods. Does
anybody know an EFFICIENT or FAST way extract the values from L using the
values from A and B?

thanks for your answers.
Peter

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[R] locfit: max number of predictors?

2010-02-25 Thread Keith Jewell
Hi All,

In another thread Andy Liaw, who CRAN lists as locfit maintainer; said:
quote
From: Liaw, Andy andy_l...@merck.com
To: Guy Green guygr...@netvigator.com; r-help@r-project.org
Subject: Re: Alternatives to linear regression with multiple variables
Date: 22 February 2010 17:50

You can try the locfit package, which I believe can handle up to 5
variables.  E.g.,
/quote

Looking in the locfit documentation (e.g. 
http://www.stats.bris.ac.uk/R/web/packages/locfit/locfit.pdf) I can't see an 
upper limit on the number of predictors; if it is 5 I'm getting close in one 
of my applications.

Can anyone confirm or deny the existence of a 'crisp' upper limit on the 
number of predictors in locfit?

If it is 5, or thereabouts, can anyone suggest an alternative which can 
handle a few more? (I'm using it for multidimensional interpolation).

Best regards,

Keith Jewell

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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Ivan Calandra

Hi!

I've tried it, but the problem is that each element has a different 
size, with makes rbind() useless.
Is there then a function/package that allows appending data in an Excel 
sheet?
I've searched already for a few packages, but none (except, in theory, 
RODBC) can append.


Any suggestion?
Regards,
Ivan

Le 2/24/2010 19:38, Dieter Menne a écrit :


Ivan Calandra wrote:
   

...
for (i in 1:4){
sqlSave(xlsFile, as.data.frame(test[[i]]), tablename=test, rownames=F,
addPK=T, append=T)
}
Error in odbcUpdate(channel, query, mydata, coldata[m, ], test = test,
:  missing columns in 'data'
odbcCloseAll()


 

I have never managed to write to Excel with ODBC with append=TRUE. If you
do not want to Access instead where this works, best is to collect (rbind)
the data in an R data frame, and write everything in one chunk.

Dieter



   


--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Institut und Museum
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calan...@uni-hamburg.de

**
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http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php

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[R] Help with split.

2010-02-25 Thread rkevinburton
I read in the documentation for split:

‘split’ divides the data in the vector ‘x’ into the groups defined by ‘f’. 

But I am still unclear as to its function. Take for example:

x - 1:4
split(x, c(0,1))
$`0`
[1] 1 3

$`1`
[1] 2 4

I am not clear on how this result is reached.

Thank you.

Kevin

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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Dieter Menne


Ivan Calandra wrote:
 
 
 I've tried it, but the problem is that each element has a different 
 size, with makes rbind() useless.
 

Assuming that size means different number of columns, then appending is
not valid, because it would change the structure of the table, and with ODBC
we are in the relational database world. In that case, you should assemble
your data frame with all possible columns and leave the fields empty.

If size means different number of rows, where append DOES make sense, 
rbind is useful.

Dieter


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[R] Updating a hexbinplot

2010-02-25 Thread Marcin Kozak
Dear all,

Considering this simple example of hexbinplot:
mixdata -
 data.frame(x = c(rnorm(5000), rnorm(5000,4,1.5)),
y = c(rnorm(5000), rnorm(5000,2,3)),
a = gl(2, 5000))
fig - hexbinplot(y ~ x | a, mixdata)
print(fig)
update(fig, colramp = BTC)

produces a bad (non-updated) legend. Compare it with:

hexbinplot(y ~ x | a, mixdata, colramp = BTC)

What should I do to update the plot with the correct legend?

(I'm using R 2.10.1 under Windows XP).

Thanks in advance,
Marcin

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Re: [R] different types graphs

2010-02-25 Thread Jim Lemon

On 02/25/2010 07:48 PM, chinna wrote:



library(RODBC)
ch- odbcConnect(durga)
sqlQuery(ch, paste(SELECT * from emp))
sqlQuery(ch, (SELECT * from xyz))


 store  revenue   year_y
1  bigbazar  7878752008
2  more   87876 2008

  plot(revenue ~ year_y, data=xyz, pch=16)


can i get any diffrent types of graphs like pie charts, bar plots.using plot
commands?


Hi chinna,
You can get all of these and more. What type of plot you want depends 
upon what you want to illustrate:


# scatterplot - sprays all the values out with a
# different color for each store
plot(xyz$year_y,xyz$revenue,type=p,
 col=as.numeric(xyz$store))
# barplot - shows you the relative positions of
# the stores in different years
# this example was done with the toy data I posted last time
barplot(as.matrix(
 reshape(xyz,idvar=Store,timevar=Year,dir=wide)[,2:4])
 ,beside=TRUE)
legend(8,60,levels(xyz$Store),fill=c(gray80,gray50,gray20))
# pie chart - shows the mean revenue for each store
# over all the years sampled - again the previous toy data
pie(by(xyz$Revenue,xyz$Store,mean))

You have to decide on what you want to illustrate unless you are just 
producing PlotArt, a new genre in which the artist produces random plots 
of financial data to emphasize the meaninglessness of the materialistic 
culture in which we pretend that we are happy, but


No, I can't keep a straight face anymore.

Jim

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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Ivan Calandra

What if size means both columns and rows?

Here is one of such lists:
test - structure(list(m = structure(c(0.090909090909091, 
0.181818181818182,

0.272727272727273, 0.363636363636364, 0.454545454545455, 0.545454545454545,
0.636363636363636, 0.727272727272727, 0.818181818181818, 0.909090909090909,
1, NA, NA, NA, NA, NA, NA, -14.571209, -13.829402, -22.1283685,
-22.717841, -34.8053215, 12.988246, 10.2528335, 9.47791, 24.585605,
NA, NA, NA, NA, NA, NA, NA), .Dim = c(11L, 3L), .Dimnames = list(
NULL, c(qhat, lower, upper))), crit = 0.611274541966673,
numsig = 0L, pc = NA), .Names = c(m, crit, numsig,
pc))

I've managed to do what I want using write.csv() like:
for (i in 1:4){
 write.csv(test[[i]], file=test.csv, append=T, quote=F, row.names=F)
}

I would like to export directly into xls for 2 reasons:
- I won't have to save each file again in xls
- I can take advantage of the use of several sheets, which would reduce 
the number of files.


As I said in my earlier emails, what I want to export are test outputs 
from functions, so I cannot change it; I just have to deal with it.


Thanks again
Ivan


Le 2/25/2010 10:24, Dieter Menne a écrit :


Ivan Calandra wrote:
   


I've tried it, but the problem is that each element has a different
size, with makes rbind() useless.

 

Assuming that size means different number of columns, then appending is
not valid, because it would change the structure of the table, and with ODBC
we are in the relational database world. In that case, you should assemble
your data frame with all possible columns and leave the fields empty.

If size means different number of rows, where append DOES make sense,
rbind is useful.

Dieter





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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Dieter Menne


Ivan Calandra wrote:
 
 What if size means both columns and rows?
 
 
Then you are not longer in the database world, and should use one of the
half dozen other methods to write to Excel, either native, via Perl
(portable) or RCOM. Search R-search for write Excel.

Dieter


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Re: [R] Odp: Subset Question

2010-02-25 Thread Petr PIKAL
Hi

r-help-boun...@r-project.org napsal dne 25.02.2010 08:22:48:

 
 This shall work. What really are values of region? What does 
 str(eu08$region) tell you about it? If it is really factor, what are 
 really its levels? What does level(eu08$region) show?
 
 My thoughts were also that it would work, but it results in 130 column
 headings stripped of all rows.
 To answer your questions:
 str(eu08$region) yielded:
 $ region  : Factor w/ 10 levels 1.Byrard,..: 3 3 3 3 10 10 10 4 4 4 
...
 
 level(eu08$region) yielded nothing, but levels(eu08$region) yielded:
 [1] 1.Byrard2.Alsat   3.Bigur 
  [4] 4.Itziar5.Ingur   6.Git 
  [7] 7.Git Balance   8.Triage 9.Snolunt
 [10] 10.Bigntu

Here is your problem. Factor is integer numeric vector with label for each 
separate level of factor.  If you want question your factor you need to 
use proper label.

see
subset(eu08, region==1.Byrard)

Regards
Petr


 
 Thanks for your attention, Petr!
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[R] Odp: different types graphs

2010-02-25 Thread Petr PIKAL
Hi

r-help-boun...@r-project.org napsal dne 25.02.2010 09:48:04:

 
 library(RODBC)
 ch- odbcConnect(durga)
  sqlQuery(ch, paste(SELECT * from emp))
 sqlQuery(ch, (SELECT * from xyz))
 
 store  revenue   year_y
 1  bigbazar  7878752008
 2  more   87876 2008
 
  plot(revenue ~ year_y, data=xyz, pch=16)
 
 
 can i get any diffrent types of graphs like pie charts, bar plots.using 
plot
 commands?
 
 please give me suggestions.

Your installation of R must be broken. I can easily get help pages for

?plot
?pie
?barplot

Regards
Petr


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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Ivan Calandra
As I said earlier, none of the packages I have found (dataframes2xls, 
WriteXLS, xlsReadWrite, xlsx) to export to xls allow appending on the 
same sheet.

So at the end, write.csv() is more flexible for my use.

Do you know if the RExcel add-on would be useful in my case? I took a 
look at the manual, but it doesn't really describe well the possibilites.


Thank you anyway
Ivan

Le 2/25/2010 10:53, Dieter Menne a écrit :


Ivan Calandra wrote:
   

What if size means both columns and rows?


 

Then you are not longer in the database world, and should use one of the
half dozen other methods to write to Excel, either native, via Perl
(portable) or RCOM. Search R-search for write Excel.

Dieter





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Re: [R] multicore in R

2010-02-25 Thread Mario Valle

Why don't use the mclapply() function?
It takes care of everything.
mario

On 25-Feb-10 8:56, dikshie wrote:

Hi,
i have a function:
zz- (constrOptim(c(.5,0), fr, grr, ui=rbind(c(-1,0),c(1,-1)), ci=c(-0.9,0.1)))
i can get the result by using command (for example):  zz$par

now if i can use multicore:
zz-parallel(constrOptim(c(.5,0), fr, grr, ui=rbind(c(-1,0),c(1,-1)),
ci=c(-0.9,0.1)))
result  collect(zz)

i cant get my the result: result$par because multicore add process id.
for example:
$`2493`$par
[1] 0.8891335 0.7891335

i try to get the result by:  result$`processID(zz)`$par
but it return NULL.

so any idea how to get the result?

with best regards,


--
Ing. Mario Valle
Data Analysis and Visualization Group| 
http://www.cscs.ch/~mvalle

Swiss National Supercomputing Centre (CSCS)  | Tel:  +41 (91) 610.82.60
v. Cantonale Galleria 2, 6928 Manno, Switzerland | Fax:  +41 (91) 610.82.82

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Re: [R] angle phase mapping

2010-02-25 Thread Magali teurlai
Hi all,

sorry,
here is the pdf and I re post my question :

could anyone give me a clue for the name of a function that would
allow me to create the same kind of plot as the attached image in R?

I know how to create a map (shapefile polygons), I just want to add
the phase information as triangles , pointing in the direction
according to the phase, and the colors of the triangle describing as
well the phase
I will have a vector of phases : one scalr (the phase) per polygon
plotted on the map

Thanks very much for any help

Magali

2010/2/25 Magali teurlai teurlaima...@gmail.com

 Hi all,

 could anyone give me a clue for the name of a function that would allow me 
 create the same kind of plot as the attached image in R?

 I know how to create a map (shapfile polygons), I just want to add the phase 
 information

 Thanks very much for any help

 Magali


phase angle map.pdf
Description: Adobe PDF document
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[R] Help with Beta Distribution and Transformation method

2010-02-25 Thread tbmcea

The following are problems for my Data Analysis course.  The professor has
allowed us to use internet help sites such as these to solve the problems
since he didn't teach us how to use R in class.

1.  I have learned how many random numbers must be simulated for the Beta
distribution
using Acceptance-Rejection method. I need to write an R code/function to
check how many random numbers
must be simulated to generate 1000 samples from the Beta( a= 2; B = 2)
distribution.

Also, I need to do a simulation study for the following problems
[Transformation Methods]:
2  . If Z ~N(0; 1), then V = Z^2=x^  2(1). Draw a random sample of size
100 from V and compare
this with theoretical samples. Summarize the result.
3.  If U ~x^2(m) and V  ~x^2(n) are independent, then F = (U/m)/
(V/n) has the F distribution with
(m, n) degrees of freedom. Choose the values m = 2 and n = 3. Draw a random
sample of size 100
from F and compare this with theoretical sample. Summarize the result.
4. I f U,V ~Unif(0; 1) are independent , then
Z1 =
(sqrt(-2 log U)) cos(2piV ); Z2 =(sqrt(-2 log V)) sin(2piU)
are independent standard normal [N(0; 1)] variables. Draw a random sample of
size 100 from Z1
and Z2 and compare this with theoretical samples. Summarize the result.

Any help would be greatly appreciated as to how to solve these using R code. 
I am a beginner at R and don't know it nearly well enough to solve these.

Thanks,

Tyler
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Re: [R] Bimodal distribution

2010-02-25 Thread Samor Gandhi
Hi Ingmar,

Thank you for your reply! How to fit a mixture distribution to the data, do you 
mean by using mixed model? 

Regards,
Samor

--- On Wed, 24/2/10, Ingmar Visser i.vis...@uva.nl wrote:

From: Ingmar Visser i.vis...@uva.nl
Subject: Re: [R] Bimodal distribution
To: Samor Gandhi samorgan...@yahoo.com
Cc: r-help@r-project.org
Date: Wednesday, 24 February, 2010, 19:14

Samor,

A somewhat indirect answer: you could fit a mixture distribution to your data 
and test
how many components are needed to best describe your data. 

hth, Ingmar


On Wed, Feb 24, 2010 at 1:22 PM, Samor Gandhi samorgan...@yahoo.com wrote:

Hello,



Is there any test  for bimodality in R that



x - c(rnorm(1000,0,1),rnorm(1000,3,1))

hist(x,nclass=100)



Thank you in advance for any help.



Regards,

Samor







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[R] Barplot colours

2010-02-25 Thread koj

Hi all,

my plotbase (height) is a 2x2 matrix and I want to draw a plot with
different colours. I used beside = FALSE and so the elements (1,1) and (2,1)
are in one bar and the elements (1,2) and (2,2) are in the other bar
(stacked). This is no problem, if the first row has one colour and the
second line has one colour. But now I want to draw the frist bar in one
colour an the second bar in two different colours. Is there apossibility to
do this? I tried to do this in providing a 2x2 matrix with different colours
in the parameter col but without sucess. 

Thank you very much in advance,

Jens. 
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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Dieter Menne


Ivan Calandra wrote:
 
 As I said earlier, none of the packages I have found (dataframes2xls, 
 WriteXLS, xlsReadWrite, xlsx) to export to xls allow appending on the 
 same sheet.
 

Please check again. WriteXLS has a parameter where to start writing.

D

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[R] how to install rattle for data mining

2010-02-25 Thread chinna

 library(rattle)
Loading required package: pmml
Loading required package: XML
Error: package 'XML' could not be loaded
In addition: Warning message:
In library(pkg, character.only = TRUE, logical.return = TRUE, lib.loc =
lib.loc) :
  there is no package called 'XML'



i have installed glade package 

install.packages(RGtk2)
 install.packages(rattle)
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Re: [R] export tables to Excel files

2010-02-25 Thread Erich Neuwirth
OK, I think dirung the disuccion we mixed up the directions of transfer.
The example I sent was Excel - R
For R - Excel you need something like


RInterface.GetDataframe dfname, Worksheets(wsname).Range(A1)

dfname, wsname and the cell refence (A1)
have to be given for each dataframe you want to transfer.


You need to install RExcel to do this.

CRAN has a package RExcelInstaller
which does everything for you.



On 2/24/2010 4:35 PM, Tal Galili wrote:
 Hi Erich.
 I admit I haven't gotten all that is necessary to implement it.
 But thanks anyway :)
 
 Tal
 
 
 Contact
 Details:---
 Contact me: tal.gal...@gmail.com mailto:tal.gal...@gmail.com |
  972-52-7275845
 Read me: www.talgalili.com http://www.talgalili.com (Hebrew) |
 www.biostatistics.co.il http://www.biostatistics.co.il (Hebrew) |
 www.r-statistics.com http://www.r-statistics.com (English)
 --
 
 
 
 
 On Wed, Feb 24, 2010 at 12:55 PM, Erich Neuwirth
 erich.neuwi...@univie.ac.at mailto:erich.neuwi...@univie.ac.at wrote:
 
 This was a VBA program which from R put the dataframes into R.
 Then in R you can do whatever you want.
 
 
 On 2/24/2010 7:52 AM, Tal Galili wrote:
  (off mailing list)
  Thanks Erich for the example, only please note that I asked about the
  other way around (reading the excel into R)
 
  Either way - Thanks!
  Tal
 
 
 
  Contact
  Details:---
  Contact me: tal.gal...@gmail.com mailto:tal.gal...@gmail.com
 mailto:tal.gal...@gmail.com mailto:tal.gal...@gmail.com |
   972-52-7275845
  Read me: www.talgalili.com http://www.talgalili.com
 http://www.talgalili.com (Hebrew) |
  www.biostatistics.co.il http://www.biostatistics.co.il
 http://www.biostatistics.co.il (Hebrew) |
  www.r-statistics.com http://www.r-statistics.com
 http://www.r-statistics.com (English)
 
 
 --
 
 
 
 
  On Wed, Feb 24, 2010 at 1:01 AM, Erich Neuwirth
  erich.neuwi...@univie.ac.at mailto:erich.neuwi...@univie.ac.at
 mailto:erich.neuwi...@univie.ac.at
 mailto:erich.neuwi...@univie.ac.at wrote:
 
  In RExcel, you can write VBA macros to perform R-related function.
  A cooked up example (not checked)
 
  Sub TransferFrames()
   MySheetNames = Array(Sheet1, Sheet2, Sheet3)
   MyDFNames = Array(mydf1, mydf2, mydf3)
   RInterface.StartRServer
   For i = Lbound(MySheetNames) to UBound(MySheetNames)
   RInterface.PutDataframe MyDFNames(i), _
   
  Worksheets(MySheetNames(i)).Range(A1).CurrentRegion
   Next i
  End Sub
 
 
  This will take the data in the rectangular nonempty range
  anchored at cell A1 for the 3 names sheets and transfer them
  to R as dataframes with the names given in MyDFNames
 
 
  On 2/23/2010 10:46 PM, Tal Galili wrote:
   Hi Richard,
   Thanks for pointing this out.
  
   BTW - How would you use Rexcel to write several data frames into
  several
   sheets in excel ?
  
   Thanks!
  
   Tal
  
  
  
   Contact
   Details:---
   Contact me: tal.gal...@gmail.com
 mailto:tal.gal...@gmail.com mailto:tal.gal...@gmail.com
 mailto:tal.gal...@gmail.com |
   972-52-7275845
   Read me: www.talgalili.com http://www.talgalili.com
 http://www.talgalili.com (Hebrew) |
  www.biostatistics.co.il http://www.biostatistics.co.il
 http://www.biostatistics.co.il (Hebrew) |
   www.r-statistics.com http://www.r-statistics.com
 http://www.r-statistics.com (English)
  
 
 
 --
  
  
  
  
   On Tue, Feb 23, 2010 at 5:04 PM, RICHARD M. HEIBERGER
  r...@temple.edu mailto:r...@temple.edu mailto:r...@temple.edu
 mailto:r...@temple.eduwrote:
  
   Please consider RExcel, which allows complete integration of R
  and Excel.
   See http://rcom.univie.ac.at
   for details and examples including a video.
   RExcel works in both directions (R to Excel, Excel to R) with
   Excel 2010, 2007, 2003, and 2002.
  
   Rich
  
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   __
   R-help@r-project.org 

Re: [R] Barplot colours

2010-02-25 Thread Jim Lemon

On 02/25/2010 08:59 PM, koj wrote:


Hi all,

my plotbase (height) is a 2x2 matrix and I want to draw a plot with
different colours. I used beside = FALSE and so the elements (1,1) and (2,1)
are in one bar and the elements (1,2) and (2,2) are in the other bar
(stacked). This is no problem, if the first row has one colour and the
second line has one colour. But now I want to draw the frist bar in one
colour an the second bar in two different colours. Is there apossibility to
do this? I tried to do this in providing a 2x2 matrix with different colours
in the parameter col but without sucess.


Hi Jens,
You can pass a matrix of colors to the barp function in the plotrix package.

Jim

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[R] data mining

2010-02-25 Thread chinna

how can we achieve data mining using R Project.
how to install Rattle gui for R project.


can anyone please help me.

i want to forecast the results .

Thanks in advance. 
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Re: [R] how to install rattle for data mining

2010-02-25 Thread Cedrick W. Johnson

   A little googling goes a LONG way:
   [1]http://datamining.togaware.com/survivor/Install_MS_Windows.html
   Explicity states how to install the 'XML' package required by R.

References

   1. http://datamining.togaware.com/survivor/Install_MS_Windows.html
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Re: [R] Help with split.

2010-02-25 Thread Peter Dalgaard

rkevinbur...@charter.net wrote:

I read in the documentation for split:

‘split’ divides the data in the vector ‘x’ into the groups defined by ‘f’. 


But I am still unclear as to its function. Take for example:

x - 1:4
split(x, c(0,1))
$`0`
[1] 1 3

$`1`
[1] 2 4

I am not clear on how this result is reached.


Usual recycling rule: Same result as split(x, c(0,1,0,1)).



--
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907

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Re: [R] What is assign attribute?

2010-02-25 Thread Peter Dalgaard

rkevinbur...@charter.net wrote:

I am just curious. Every once and a while I see an attribute attached to an object called 
assign. What meaning does this have? For example:

dist ~ speed, data=cars

forms a matrix like:

 num [1:50, 1:2] 1 1 1 1 1 1 1 1 1 1 ...
 - attr(*, dimnames)=List of 2
  ..$ : chr [1:50] 1 2 3 4 ...
  ..$ : chr [1:2] (Intercept) speed
 - attr(*, assign)= int [1:2] 0 1

The dimnames attribute is fairly self-explanatory. I just am not sure what the 
assign attribute means.


It has to do with the mapping between terms of the formula and columns 
of the design matrix:


 str(model.matrix(Ozone~factor(Month)+Wind,data=airquality))
 num [1:116, 1:6] 1 1 1 1 1 1 1 1 1 1 ...
 - attr(*, dimnames)=List of 2
  ..$ : chr [1:116] 1 2 3 4 ...
  ..$ : chr [1:6] (Intercept) factor(Month)6 factor(Month)7 
factor(Month)8 ...

 - attr(*, assign)= int [1:6] 0 1 1 1 1 2
 - attr(*, contrasts)=List of 1
  ..$ factor(Month): chr contr.treatment

I.e. columns 2:5 belong to the first non-intercept term, factor(Month). 
(Notice that it is implicitly assumed that you have the corresponding 
terms() output to hand, likewise for the contrasts attribute.)

--
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907

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[R] Rearranging entries in a matrix

2010-02-25 Thread Juliet Ndukum
I have a matrix, called data. I used the code below to rearrange the data such 
that the first column remains the same, but the y value falls under either 
columns 2, 3 or 4, depending on the value of z. If z=1 for example, then the 
value of y will fall under column 2, if z=2, the value of y falls under column 
3, and so on. 

data
  x  y z
[1,] 50 13 1
[2,] 14  8 2
[3,]  3  7 3
[4,]  4 16 1
[5,]  6  8 2
[6,] 10  2 3
[7,] 15 11 1
[8,] 14  9 3
 data1 - data.frame(matrix(0, length(x), ncol(data)+1))
 colnames(data1) - c(x,y1,y2,y3)
 data1$x - data[,1]
 data1$y1 - apply(data, 1, function(x) (ifelse(x[3]==1,x[2],NA)))
 data1$y2 - apply(data, 1, function(x) (ifelse(x[3]==2,x[2],NA)))
 data1$y3 - apply(data, 1, function(x) (ifelse(x[3]==3,x[2],NA)))
 data1
   x y1 y2 y3
1 50 13 NA NA
2 14 NA  8 NA
3  3 NA NA  7
4  4 16 NA NA
5  6 NA  8 NA
6 10 NA NA  2
7 15 11 NA NA
8 14 NA NA  9

I used the apply function (three times) to generate the output below, which is 
as I wish to have it. 
Can any one write for me a for loop that would produce the same results.

Thanks in advance.
JN


  
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[R] adonis(), design

2010-02-25 Thread Kay Cichini

hello list,

i'd appreciate help regarding formula expression in adonis(), package vegan.

i'm interested in the effect of an impact on species composition and if this
effect is the same for different sites.
i have an impact survey with plot pairs, one plot with impact the other with
similar ecolgical conditions but without impact, which is the control 
(factor1: impact). 
two different sites were sampled, at each 6 plot pairs (factor2: community)
with a final N of 24. 
so this would be a 2-factorial crossed design, right? thus, i called: 

adonis(speciesdata~Community*Impact)

but do i have to a account for the identity of pairs by blocking them -
if so, how to achieve this in adonis?
i'm not sure about the reasons why a blocking would be needed and if the
rather small size of my data would allow a blocking, without loosing all
statistical power.

greetings,
kay
 
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Re: [R] R and Wordpress

2010-02-25 Thread Steve Lianoglou
Hi,

On Wed, Feb 24, 2010 at 11:40 PM, C.H. chainsawti...@gmail.com wrote:
 Dear R helpers,

 I have a question regarding wordpress and R. I have asked this
 question in Wordpress support (
 http://wordpress.org/support/topic/368312 ) but there is no answer so
 far, maybe the R community can have a better answer.

 I followed the excellent tutorial on r-statistics-blog (
 http://www.r-statistics.com/2010/02/r-syntax-highlight-on-your-blog-a-wordpress-plugin/
 ) to enable syntax hightlighting but Wordpress keeps breaking -
 into  - and I have to use = instead. (I think = is confusing.)
 And I think it is not related to the theme as well.

 Is there any clue to solve this? I am using Wordpress 2.9.2.

I'm guessing that your best bet is to ask the author of the blog that
you linked to in your post ... just post a comment on that post there.

-steve
-- 
Steve Lianoglou
Graduate Student: Computational Systems Biology
 | Memorial Sloan-Kettering Cancer Center
 | Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact

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Re: [R] how to fast extract values from different list elements

2010-02-25 Thread Tom Short
On Thu, Feb 25, 2010 at 4:10 AM, Heym, Peter-Paul ph...@ipb-halle.de wrote:

 this works fine but it is very slow (since A and B can be very large and I
 have to repeat this about 5000 times). I would like to make this faster using
 e.g. apply or lapply but I didn't get it work using these methods. Does
 anybody know an EFFICIENT or FAST way extract the values from L using the
 values from A and B?

Instead of L[[A[i]]][B[i]], try L[A][B]

- Tom

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Re: [R] Rearranging entries in a matrix

2010-02-25 Thread Dennis Murphy
Hi:

Loop? We don't need no steeenking loop!! Here's a way to create a matrix
with matrix indexing that you can attach with x to create a new data frame.
Calling your original data frame df,

 m - matrix(NA, nrow = nrow(df), ncol = 3)
# Create the indices of the initialized matrix to modify
 idx - cbind(1:nrow(m), df$z)
# Map the modifications to the matrix
 m[idx] - df$y
 m
 [,1] [,2] [,3]
[1,]   13   NA   NA
[2,]   NA8   NA
[3,]   NA   NA7
[4,]   16   NA   NA
[5,]   NA8   NA
[6,]   NA   NA2
[7,]   11   NA   NA
[8,]   NA   NA9
data1 - as.data.frame(cbind(df$x, m))
names(data1) - c(x, y1, y2, y3)
 data1
   x y1 y2 y3
1 50 13 NA NA
2 14 NA  8 NA
3  3 NA NA  7
4  4 16 NA NA
5  6 NA  8 NA
6 10 NA NA  2
7 15 11 NA NA
8 14 NA NA  9

HTH,
Dennis

On Thu, Feb 25, 2010 at 5:17 AM, Juliet Ndukum jpnts...@yahoo.com wrote:

 I have a matrix, called data. I used the code below to rearrange the data
 such that the first column remains the same, but the y value falls under
 either columns 2, 3 or 4, depending on the value of z. If z=1 for example,
 then the value of y will fall under column 2, if z=2, the value of y falls
 under column 3, and so on.

 data
  x  y z
 [1,] 50 13 1
 [2,] 14  8 2
 [3,]  3  7 3
 [4,]  4 16 1
 [5,]  6  8 2
 [6,] 10  2 3
 [7,] 15 11 1
 [8,] 14  9 3
  data1 - data.frame(matrix(0, length(x), ncol(data)+1))
  colnames(data1) - c(x,y1,y2,y3)
  data1$x - data[,1]
  data1$y1 - apply(data, 1, function(x) (ifelse(x[3]==1,x[2],NA)))
  data1$y2 - apply(data, 1, function(x) (ifelse(x[3]==2,x[2],NA)))
  data1$y3 - apply(data, 1, function(x) (ifelse(x[3]==3,x[2],NA)))
  data1
   x y1 y2 y3
 1 50 13 NA NA
 2 14 NA  8 NA
 3  3 NA NA  7
 4  4 16 NA NA
 5  6 NA  8 NA
 6 10 NA NA  2
 7 15 11 NA NA
 8 14 NA NA  9

 I used the apply function (three times) to generate the output below, which
 is as I wish to have it.
 Can any one write for me a for loop that would produce the same results.

 Thanks in advance.
 JN



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Re: [R] Rearranging entries in a matrix

2010-02-25 Thread Henrique Dallazuanna
Try this also:

reshape(cbind(Id = 1:8, DF), v.names = 'y', timevar = 'z', direction =
'wide', idvar = 'Id')[-1]

On Thu, Feb 25, 2010 at 10:17 AM, Juliet Ndukum jpnts...@yahoo.com wrote:
 I have a matrix, called data. I used the code below to rearrange the data 
 such that the first column remains the same, but the y value falls under 
 either columns 2, 3 or 4, depending on the value of z. If z=1 for example, 
 then the value of y will fall under column 2, if z=2, the value of y falls 
 under column 3, and so on.

 data
  x  y z
 [1,] 50 13 1
 [2,] 14  8 2
 [3,]  3  7 3
 [4,]  4 16 1
 [5,]  6  8 2
 [6,] 10  2 3
 [7,] 15 11 1
 [8,] 14  9 3
 data1 - data.frame(matrix(0, length(x), ncol(data)+1))
 colnames(data1) - c(x,y1,y2,y3)
 data1$x - data[,1]
 data1$y1 - apply(data, 1, function(x) (ifelse(x[3]==1,x[2],NA)))
 data1$y2 - apply(data, 1, function(x) (ifelse(x[3]==2,x[2],NA)))
 data1$y3 - apply(data, 1, function(x) (ifelse(x[3]==3,x[2],NA)))
 data1
   x y1 y2 y3
 1 50 13 NA NA
 2 14 NA  8 NA
 3  3 NA NA  7
 4  4 16 NA NA
 5  6 NA  8 NA
 6 10 NA NA  2
 7 15 11 NA NA
 8 14 NA NA  9

 I used the apply function (three times) to generate the output below, which 
 is as I wish to have it.
 Can any one write for me a for loop that would produce the same results.

 Thanks in advance.
 JN



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25° 25' 40 S 49° 16' 22 O

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Re: [R] Zero inflation model - pscl package

2010-02-25 Thread Achim Zeileis

On Wed, 24 Feb 2010, Nicholas M. Caruso wrote:


I have some questions regarding Zero Inflation Poisson models.

I am using count data to analyze abundance trends of salamanders.  However,
I have surveys which differ in the amount of effort (i.e. the number of
people searching and amount of time - I am using a museum database so not
all surveys were conducted by me).  Therefore I need to account for the
effort.  If change the count (response variable) then it will have decimals
and not be usable in this model.  So I decided to put this term into the
independent variable.


The usual approach would be the following: If you think that some link 
function of y/n (response per effort) is linear in a set of covariates x 
with coefficients b, you would typically write


  log(y/n) = x'b

which can be transformed to

  log(y) - log(n) = x'b
  log(y)  = x'b + log(n)

i.e., the log-effort would be an additional regressor with coefficient 
fixed to 1. This is called an offset so the R formula would be


  y ~ x + offset(log(n))

Alternatively, instead of relying on the fact the coefficient is exactly 
1, you can estimate and test it, i.e.


  y ~ x + log(n)


I am analyzing Historic vs. Current surveys.

Here is an example of my code:
require(pscl)
model - zeroinfl(Sallys~Survey:Person.Hours, dist=poisson, EM=TRUE)
summary(model)


I think I would allow different intercepts as well, i.e.,

  zeroinfl(Sallys ~ Survey * log(Person.Hours))


I have received some very significant results on most of them and on some
that I thought wouldn't be significant turned out to be.  So I am concerned
with the model being appropriate.  I created a simulated database and ran a
simple glm to see if y/b ~ x is the same as y~x:b and it is not (not
surprisingly).  Does anyone have suggestions for how to adjust my model to
allow for these comparisons?  I cannot use a glm with Poisson error because
of overdispersion and a lot of zeroes.  I thought about either rounding up
my ratios or multiplying everything by 100 to eliminate the decimals but to
keep the variation (I am not pleased with either of those options)

On another note, I am having a little trouble interpreting the results (I
think).  Which this may not matter if I cannot use the ZIP model.  Is the
Count model coefficients (poisson with log link) the measure of if the sites
differ and if so what do the estimates for both surveys indicate?  Is that
the mean for both surveys and it is testing them against zero?  If so I want
to test them against each other and I don't know exactly how to do that.
Here is the output:
   Estimate Std. Error z value
Pr(|z|)
(Intercept) 1.974180.06570  30.048   2e-16
***
SurveyCurrent:Person.Hours   0.041920.07597   0.5520.581
SurveyHistoric:Person.Hours  0.402210.01540  26.110   2e-16 ***


It forces the intercept to be the same, both for the current and the 
historic sites which is not so intuitive. The two slopes mean, that for 
the historic sites, the counts increased clearly with effort, but for the 
current sites it increased only slightly (not significantly).



As for the Zero-inflation model coefficients( binomial with logit link).  I
read that this is a measure of 1) suitability or 2) if the predictor of
excess zeros was significant.  Which one of these (or is it something else)
is correct and how do I interpret this?

Here is a sample of a read out:

Zero-inflation model coefficients (binomial with logit link):
   Estimate Std. Error z value
Pr(|z|)
(Intercept)   -1.1625 0.9833  -1.182
0.237
SurveyCurrent:Person.Hours   -1.1787 1.1304  -1.0430.297
SurveyHistoric:Person.Hours  -0.5050 0.3440  -1.4680.142


This reflects the probability of additional zeros which does not seem to 
depend on either site or effort.


For an introduction to the zero-inflation model and its implementation in 
R see

  vignette(countreg, package = pscl)

Also, I would recommend to consider hurdle() models as well. They often 
give similar fits and are slightly easier to interpret (IMO).


hth,
Z


http://search.twitter.com/search?q=%0D%0Ahttp://www.google.com/search?q=%0D%0Ahttp://smarterfox.com/wikisearch/search?q=%0D%0Alocale=en-UShttp://www.oneriot.com/search?p=smarterfoxssrc=smarterfox_popup_bubblespid=8493c8f1-0b5b-4116-99fd-f0bcb0a3b602q=%0D%0A

Thanks for any suggestions/help!!

--
Nicholas M Caruso
Graduate Student
CLFS-Biology
4219 Biology-Psychology Building
University of Maryland, College Park, MD 20742-5815
phone: 301-405-6884



--
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and walked out pleased for having made the acquaintance.

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Re: [R] Reading a password-protected Excel workbook

2010-02-25 Thread Dieter Menne


Dimitri Shvorob wrote:
 
 I try reading a password-protected spreadsheet with RODBC, passing a file
 or an ODBC source to odbcConnect, e.g.
 
 con = odbcConnect(dsn = mywkbk, uid = , pwd = mypwd)
 
 but get Could not decrypt file pop-up error message.
 
 

Not really:

http://support.microsoft.com/default.aspx/kb/211378/EN-US/

Dieter

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Re: [R] latent class factor analysis (LCFA) in R?

2010-02-25 Thread Friedrich Leisch
 On Tue, 23 Feb 2010 13:43:44 +0100,
 Ingmar Visser (IV) wrote:

   Dear Mark,
   I don't know whether it has ... But there are some packages that provide
   functionality for
   specifying mixtures of user-defined distributions, in your case a factor
   model. package
   flexmix has an example of how to fit mixtures of user-defined models and so
   does
   my own package depmixS4 (which may be overkill here as it is meant for
   markov mixtures
   of general distributions). Hence, you could use one of these in combination
   with your
   favorite factor modeling package to specify the model you want.

   hth, Ingmar

   On Tue, Feb 23, 2010 at 12:46 PM, Mark Heckmann mark.heckm...@gmx.dewrote:

   I am looking for a package that can perform latent class factor
   analysis (LCFA) like in LatentGold.
   Does someone know wether or not it has been implemented in some package?
   I just can't find it.
   
   Bests,
   Mark
   ���
   Mark Heckmann
   Dipl. Wirt.-Ing. cand. Psych.
   Vorstra�e 93 B01
   28359 Bremen
   Blog: www.markheckmann.de
   R-Blog: http://ryouready.wordpress.com
   
   
   
   
   
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[R] behavior of seq_along

2010-02-25 Thread Dale Steele
I'm trying to understand the behavior of seq_along in the following example:

x - 1:5; sum(x)
y - 6:10; sum(y)

data - c(x,y)
S - sum( data[seq_along(x)] )
S
T - sum( data[seq_along(y)] )
T

Why is T != sum(y) ?

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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Ivan Calandra
I've checked in the package WriteXLS and couldn't find such parameter (I 
hope I didn't overlook anything!).

However write.xls() in xlsReadWrite package has such parameter.
I've tried it and the problem is that, even though I can make the 
writing start at the last line, it will overwrite the whole file. Even 
if I try to append on a new sheet, the xls file is overwritten.

One by one, I'm crossing off the possibilities...
Thanks!
Ivan

Le 2/25/2010 11:58, Dieter Menne a écrit :


Ivan Calandra wrote:
   

As I said earlier, none of the packages I have found (dataframes2xls,
WriteXLS, xlsReadWrite, xlsx) to export to xls allow appending on the
same sheet.

 

Please check again. WriteXLS has a parameter where to start writing.

D




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Re: [R] Subset Question

2010-02-25 Thread Erik Iverson

Chertudi wrote:

Hello helpful R folks,

   First off, please forgive my English.  Second, I'm new with R, I've
searched the archives about subsets, and I haven't found quite the help I
need.

I'm currently analysing a population survey whose data set has about 15000
households (the rows/observations) and 130 variables (the columns).  I've
managed to import the set into R as a data.frame called eu08.  Now, I'm
trying to look at all of the variables, but limited to one province in the
region variable.  I think the provinces are factors, and the province of
interest is labeled '3'.
I've tried the following:

region3=subset(eu08, region==3)
--this simply strips all of the rows from the columns, and I know that about
4000 of the observations are specific to region 3.  So does putting the 3 as
'3' and 3.

 Any help would be greatly appreciate.

  
Well, we don't know if it really is a factor.  You can determine that by 
doing...


class(eu08$region)

If it is a factor, then

levels(eu08$region)

should let you know what you can subset with. 


str(eu08) might also be good to look at...

Erik

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Re: [R] latent class factor analysis (LCFA) in R?

2010-02-25 Thread Friedrich Leisch

Hi,

We (i.e. Bettina Grün) have some experimental code for mixtures of
factor analyzers in flexmix, because we needed it for one paper. We
have not released it yet because the code is not very well tested (and
we do have concerns about identification of such models, but that's a
different issue). As there seems to be interest in it we will release
a new version of flexmix in the next days which includes mixtures of
factor analyzers. Look for help(FLXMCfactanal) in flexmix version
2.2-5 (next Monday or so).

Best,
Fritz



 On Tue, 23 Feb 2010 13:43:44 +0100,
 Ingmar Visser (IV) wrote:

   Dear Mark,
   I don't know whether it has ... But there are some packages that provide
   functionality for
   specifying mixtures of user-defined distributions, in your case a factor
   model. package
   flexmix has an example of how to fit mixtures of user-defined models and so
   does
   my own package depmixS4 (which may be overkill here as it is meant for
   markov mixtures
   of general distributions). Hence, you could use one of these in combination
   with your
   favorite factor modeling package to specify the model you want.

   hth, Ingmar

   On Tue, Feb 23, 2010 at 12:46 PM, Mark Heckmann mark.heckm...@gmx.dewrote:

   I am looking for a package that can perform latent class factor
   analysis (LCFA) like in LatentGold.
   Does someone know wether or not it has been implemented in some package?
   I just can't find it.
   
   Bests,
   Mark
   ���
   Mark Heckmann
   Dipl. Wirt.-Ing. cand. Psych.
   Vorstra�e 93 B01
   28359 Bremen
   Blog: www.markheckmann.de
   R-Blog: http://ryouready.wordpress.com
   
   
   
   
   
   [[alternative HTML version deleted]]
   
   
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[R] Building R packages in Windows 7

2010-02-25 Thread Eric Ferreira
Dear useRs,

I'm having trouble building R packages in Windows 7 regarding HTML help
Workshop.
Pointing PATH to c:\Program Files\HTML help Workshop does work in Windows
(e.g. Vista) and does not in Windows 7.

Some tips??

Kind regards,

-- 
Dr Eric B Ferreira
Exact Sciences Department
Federal University of Alfenas
Brazil

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Re: [R] behavior of seq_along

2010-02-25 Thread Dieter Menne


Dale Steele wrote:
 
 
 x - 1:5; sum(x)
 y - 6:10; sum(y)
 
 data - c(x,y)
 S - sum( data[seq_along(x)] )
 S
 T - sum( data[seq_along(y)] )
 T
 
 

If in doubt, divide and conquer:

seq_along(x)
[1] 1 2 3 4 5
 seq_along(y)
[1] 1 2 3 4 5

You expected  that the second vector is 6,7...
Dieter

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Re: [R] behavior of seq_along

2010-02-25 Thread Henrique Dallazuanna
Because,

data[seq_along(x)]  == data[seq_along(y)],

You need this:

sum(data[length(x) + seq_along(y)])

On Thu, Feb 25, 2010 at 11:02 AM, Dale Steele dale.w.ste...@gmail.com wrote:
 I'm trying to understand the behavior of seq_along in the following example:

 x - 1:5; sum(x)
 y - 6:10; sum(y)

 data - c(x,y)
 S - sum( data[seq_along(x)] )
 S
 T - sum( data[seq_along(y)] )
 T

 Why is T != sum(y) ?

 __
 R-help@r-project.org mailing list
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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Re: [R] angle phase mapping

2010-02-25 Thread David Winsemius


On Feb 25, 2010, at 5:51 AM, Magali teurlai wrote:


Hi all,

sorry,
here is the pdf and I re post my question :

could anyone give me a clue for the name of a function that would
allow me to create the same kind of plot as the attached image in R?

I know how to create a map (shapefile polygons), I just want to add
the phase information as triangles , pointing in the direction
according to the phase, and the colors of the triangle describing as
well the phase
I will have a vector of phases : one scalr (the phase) per polygon
plotted on the map


You have a plot with shapes indicating directions and magnitudes  
overlayed on latitude and longitude on a map. Look for vectorFields in  
package plotrix. There is also a dataset in ggplot that is described  
as being a vector field but I don't see a plotting method mentioned in  
that dataset page.






Thanks very much for any help

Magali

2010/2/25 Magali teurlai teurlaima...@gmail.com


Hi all,

could anyone give me a clue for the name of a function that would  
allow me create the same kind of plot as the attached image in R?


I know how to create a map (shapfile polygons), I just want to add  
the phase information


Thanks very much for any help

Magali

phase angle map.pdf__
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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] problem with looping on sqlSave()

2010-02-25 Thread Marc Schwartz
Just to confirm, WriteXLS() does not have such a parameter, but write.xls() in 
the xlsReadWRite package does. As you have noted however, none of these 
approaches are really designed to enable flexible appending to an existing 
Excel file.

As I believe Dieter noted in an earlier post, your best option may be to look 
at the RCOM/RExcel based solution, which gives you more flexibility in writing 
to Excel files. More info at http://rcom.univie.ac.at/.

HTH,

Marc Schwartz

On Feb 25, 2010, at 8:02 AM, Ivan Calandra wrote:

 I've checked in the package WriteXLS and couldn't find such parameter (I hope 
 I didn't overlook anything!).
 However write.xls() in xlsReadWrite package has such parameter.
 I've tried it and the problem is that, even though I can make the writing 
 start at the last line, it will overwrite the whole file. Even if I try to 
 append on a new sheet, the xls file is overwritten.
 One by one, I'm crossing off the possibilities...
 Thanks!
 Ivan
 
 Le 2/25/2010 11:58, Dieter Menne a écrit :
 
 Ivan Calandra wrote:
   
 As I said earlier, none of the packages I have found (dataframes2xls,
 WriteXLS, xlsReadWrite, xlsx) to export to xls allow appending on the
 same sheet.
 
 
 Please check again. WriteXLS has a parameter where to start writing.
 
 D

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Re: [R] reducing data.frame

2010-02-25 Thread John Kane
Perhaps the reshape package?

It's just about impossible to read your data layout.  Could you resubmit the 
example using dput()?

Thanks

--- On Thu, 2/25/10, AC Del Re de...@wisc.edu wrote:

 From: AC Del Re de...@wisc.edu
 Subject: [R] reducing data.frame
 To: r-help@r-project.org
 Received: Thursday, February 25, 2010, 12:44 AM
 Hi All,
 
 Is there an easy way to reduce a data.frame to 1 'id' per
 row while keeping
 information from the other rows of that same variable, if
 applicable? e.g.:
 
 # data
 
  multi[1:15,]
      id     
    r  n wi   wi.tau 
        z   k
 alliance a.rater   eml
 treatment outcome  o.rater german
 1   100 0.280 44 41 21.72514 0.2876821
 210     NA   
 NA  NA
  NA   
 NA   Client   NA
 2   100 0.280 44 41 21.80953 0.2876821
 182     NA   
 NA Early
  NA    NA 
    NA   NA
 3   100 0.280 44 41 22.36641 0.2876821
 206     NA  Client 
 NA
  NA    NA 
    NA   NA
 4   100 0.280 44 41 23.59224 0.2876821
 188     NA   
 NA  NA
  NA    NA 
    NA  Other
 5   100 0.280 44 41 23.83157 0.2876821
 147      WAI    NA 
 NA
  NA    NA 
    NA   NA
 6   101 0.000 37 34 19.65678 0.000
 182     NA   
 NA Early
  NA    NA 
    NA   NA
 7   101 0.5423790 37 34 17.65078
 0.6075200  98     NA 
   NA  NA
 Psychodymic    NA 
    NA   NA
 8   101 0.5423790 37 34 19.58820 0.6075200
 210     NA   
 NA  NA
  NA    NA
 Observer   NA
 9   101 0.5423790 37 34 21.09334 0.6075200
 188     NA   
 NA  NA
  NA    NA 
    NA  Other
 10  101 0.9075737 37 34 19.65678 1.5135878 182 
    NA    NA 
 Late
  NA    NA 
    NA   NA
 11 103a 0.495 18 15 10.36364 0.5426615  90 
    NA    NA 
 NA
  NA     SCL 
    NA   NA
 12 103a 0.6171548 18 15 11.32425 0.7203964 210 
    NA    NA 
 NA
  NA    NA
 Observer   NA
 13 103a 0.6171548 18 15 11.34714 0.7203964 182 
    NA    NA Early
  NA    NA 
    NA   NA
 14 103a 0.6171548 18 15 11.49606 0.7203964 206 
    NA  Client  NA
  NA    NA 
    NA   NA
 15 103a 0.6171548 18 15 11.81150 0.7203964 188 
    NA    NA 
 NA
  NA    NA 
    NA  Other
 
 # with the goal of having a reduced df (1 id per row) like
 this:
 
    id     
    r  n wi   wi.tau 
        z   k
 alliance a.rater   eml
 treatment outcome  o.rater german
 1   100 0.280 44 41 21.72514 0.2876821
 210     wai    client 
 early
    NA   
 NA   Client   other
      101 etc...
 
 Ideally, I would like to reduce by id and r, if the values
 are the same and
 keep any discrepant values as a separate row (if possible),
 e.g.:
 
 6   101 0.000 37 34 19.65678 0.000
 182     NA   
 NA Early
  NA    NA 
    NA   NA
 7   101 0.5423790 37 34 17.65078
 0.6075200  98     NA 
   NA  Late
 Psychodymic   
 NA   Observer  Other
 
 I appreciate any assistance,
 
 AC
 
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Re: [R] Building R packages in Windows 7

2010-02-25 Thread Duncan Murdoch

On 25/02/2010 9:06 AM, Eric Ferreira wrote:

Dear useRs,

I'm having trouble building R packages in Windows 7 regarding HTML help
Workshop.
Pointing PATH to c:\Program Files\HTML help Workshop does work in Windows
(e.g. Vista) and does not in Windows 7.

Some tips??
  


We don't use the HTML Help Workshop any more since R 2.10.0, so you 
could upgrade to the current R, and the problem will go away.  
Otherwise, I think you'll have to ask Microsoft for help.  But they 
aren't likely to be helpful:  Win XP is the most recent OS listed as 
supported.


Duncan Murdoch

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Re: [R] behavior of seq_along

2010-02-25 Thread David Winsemius


On Feb 25, 2010, at 9:02 AM, Dale Steele wrote:

I'm trying to understand the behavior of seq_along in the following  
example:


x - 1:5; sum(x)
y - 6:10; sum(y)

data - c(x,y)
S - sum( data[seq_along(x)] )
S
T - sum( data[seq_along(y)] )
T

Why is T != sum(y) ?


Look at

seq_along(y)

seq_along returns indices for the purpose of accession of elements, so  
it starts with 1 and ends with the length of the object.


Had you asked for sum(data[y[seq_along(y)]]) you might have achieved  
your expectation.




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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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[R] error using pvcm() on unbalanced panel data

2010-02-25 Thread Liviu Andronic
Dear all
I am trying to fit Variable Coefficients Models on Unbalanced Panel
Data. I managed to fit such models on balanced panel data (the example
from the plm vignette), but I failed to do so on my real, unbalanced
panel data.

I can reproduce the error on a modified example from the vignette:
 require(plm)
 data(Hedonic)
 Hed - pvcm(mv ~ crim + zn + indus + chas + nox + rm + age + dis +rad + tax + 
 ptratio + blacks + lstat, Hedonic, model = within,index = townid)
Error in FUN(X[[1L]], ...) : insufficient number of observations
 ##it fails for both FE and RE cases
 Hed - pvcm(mv ~ crim + zn + indus + chas + nox + rm + age + dis +rad + tax + 
 ptratio + blacks + lstat, Hedonic, model = random,index = townid)
Error in FUN(X[[1L]], ...) : insufficient number of observations

Would this be expected behaviour for unbalanced data? The vignette
warns of several limitations regarding such data, but doesn't mention
this specific case as a limitation. I would like to subsequently
perform  a test of poolability on my real data.

Thank you
Liviu


 sessionInfo()
R version 2.10.1 (2009-12-14)
x86_64-pc-linux-gnu

locale:
 [1] LC_CTYPE=en_GB.UTF-8   LC_NUMERIC=C
 [3] LC_TIME=en_GB.UTF-8LC_COLLATE=en_GB.UTF-8
 [5] LC_MONETARY=C  LC_MESSAGES=en_GB.UTF-8
 [7] LC_PAPER=en_GB.UTF-8   LC_NAME=C
 [9] LC_ADDRESS=C   LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_GB.UTF-8 LC_IDENTIFICATION=C

attached base packages:
[1] splines   stats graphics  grDevices utils datasets  methods
[8] base

other attached packages:
 [1] plm_1.2-3sandwich_2.2-5   zoo_1.6-2MASS_7.3-5
 [5] Formula_0.2-0kinship_1.1.0-23 lattice_0.18-3   nlme_3.1-96
 [9] survival_2.35-8  fortunes_1.3-7   RGtk2_2.12.18cairoDevice_2.10
[13] sos_1.2-5brew_1.0-3   hints_1.0.1-1

loaded via a namespace (and not attached):
[1] grid_2.10.1  tools_2.10.1

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[R] Reading a password-protected Excel workbook

2010-02-25 Thread Dimitri Shvorob

I try reading a password-protected spreadsheet with RODBC, passing a file or
an ODBC source to odbcConnect, e.g.

con = odbcConnect(dsn = mywkbk, uid = , pwd = mypwd)

but get Could not decrypt file pop-up error message.

Can anyone help?

Thank you.

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[R] mtext with at=NULL

2010-02-25 Thread Ulrike Feldmann
Hello,

in the help of mtext I found

at: If ‘length(at)==0’ (the default), the location will be determined
by ‘adj’

But if I use mtext( hello world, at=NULL) there comes the following
error message:

Fehler in mtext(hallo Welt, side = 3, adj = NA, at = NULL) :
  'at' mit Länge 0 angegeben

So the help says it is ok to use at with length(at) == 0 but if I use an
at with length(at) == 0 I get an error message.

This is a bug, isn't it?

Kind regards,

Ulrike Feldmann

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[R] export results

2010-02-25 Thread Wendy

Hi all,
 
I am looping through a function for 100 time in the middle of my code, and I
want to output the results from this function. Is there a way to write the
results into a txt or csv fil? For example, I write the results from the
first loop to the first column of a spreadsheet and the results from the
second loop to the second coclumn of a spreadsheet etc.
 
Thank you very much, 
Wendy 
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Re: [R] error using pvcm() on unbalanced panel data

2010-02-25 Thread Liviu Andronic
On 2/25/10, Liviu Andronic landronim...@gmail.com wrote:
  I can reproduce the error on a modified example from the vignette:
   require(plm)
   data(Hedonic)
   Hed - pvcm(mv ~ crim + zn + indus + chas + nox + rm + age + dis +rad + 
 tax + ptratio + blacks + lstat, Hedonic, model = within,index = townid)
  Error in FUN(X[[1L]], ...) : insufficient number of observations
   ##it fails for both FE and RE cases
   Hed - pvcm(mv ~ crim + zn + indus + chas + nox + rm + age + dis +rad + 
 tax + ptratio + blacks + lstat, Hedonic, model = random,index = townid)
  Error in FUN(X[[1L]], ...) : insufficient number of observations


A quick update, the function pooltest() used via its formula interface
fails in a similar way:
 pooltest(mv ~ crim + zn + indus + chas + nox + rm + age + dis +rad + tax + 
 ptratio + blacks + lstat, Hedonic, model = within,index = townid)
Error in FUN(X[[1L]], ...) : insufficient number of observations
 pooltest(mv ~ crim + zn + indus + chas + nox + rm + age + dis +rad + tax + 
 ptratio + blacks + lstat, Hedonic, model = pooling,index = townid)
Error in FUN(X[[1L]], ...) : insufficient number of observations

Liviu

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Re: [R] mtext with at=NULL

2010-02-25 Thread Duncan Murdoch

On 25/02/2010 8:58 AM, Ulrike Feldmann wrote:

Hello,

in the help of mtext I found

at: If ‘length(at)==0’ (the default), the location will be determined
by ‘adj’

But if I use mtext( hello world, at=NULL) there comes the following
error message:

Fehler in mtext(hallo Welt, side = 3, adj = NA, at = NULL) :
  'at' mit Länge 0 angegeben

So the help says it is ok to use at with length(at) == 0 but if I use an
at with length(at) == 0 I get an error message.

This is a bug, isn't it?


I'd say it's a documentation error:  it claims that the default is 
length 0, but the default is NA, which is length 1.  The actual test in 
the code uses adj when a C equivalent of is.finite(at) is TRUE, so I'll 
change the docs to match the behaviour, rather than changing the 
behaviour to match the docs.


Duncan Murdoch

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[R] Odp: export results

2010-02-25 Thread Petr PIKAL
Hi

r-help-boun...@r-project.org napsal dne 25.02.2010 12:42:46:

 
 Hi all,
 
 I am looping through a function for 100 time in the middle of my code, 
and I
 want to output the results from this function. Is there a way to write 
the
 results into a txt or csv fil? For example, I write the results from the
 first loop to the first column of a spreadsheet and the results from the
 second loop to the second coclumn of a spreadsheet etc.

make a data frame, let say res

res=as.data.frame(matrix(NA, n, 100)) #predefine data frame
 
for (i in ...) {

some stuff
res[,i] - some function result
}

write.table(res,)

Regards
Petr




 
 Thank you very much, 
 Wendy 
 -- 
 View this message in context: 
http://n4.nabble.com/export-results-tp1568880p1568880.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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http://www.R-project.org/posting-guide.html
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[R] How to extract one of four plots in a linear regression model

2010-02-25 Thread FMH
Dear All,

A linear regression model could be fitted by using lm function and the plot 
function can be used to check the assumption of the model. 

The help menu shows few instances on suitable coding for fitting such a linear 
model. In addition, four different plots could be extracted simultaneously with 
only a single plot function as followed:



require(graphics)
## Annette Dobson (1990) An Introduction to Generalized Linear Models.
## Page 9: Plant Weight Data.
ctl - c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)
trt - c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
group - gl(2,10,20, labels=c(Ctl,Trt))
weight - c(ctl, trt)
anova(lm.D9 - lm(weight ~ group))
opar - par(mfrow = c(2,2), oma = c(0, 0, 1.1, 0))
plot(lm.D9, las = 1) 




The plot function gives four different plots simulaneously but i just need only 
part of them, for instance the normality plot. Could someone  give some ideas 
the way to extract this single plot as i need to copy only this plot and paste 
it into Word document.

Thanks
Fir





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Re: [R] Building R packages in Windows 7

2010-02-25 Thread Duncan Murdoch

On 25/02/2010 10:40 AM, Eric Ferreira wrote:

Dear Duncan

Thank so much for your reply.
Actually, I'm using the latest version of R and the problem persists. What
do you use instead of HTML Help Workshop for newer R versions?
  


We just produce text and HTML help pages on demand, and LaTeX ones for 
the pdf manuals.  How are you asking for CHMs to be produced?


Duncan Murdoch

Best regards

Eric.

On 25 February 2010 11:43, Duncan Murdoch murd...@stats.uwo.ca wrote:

 On 25/02/2010 9:06 AM, Eric Ferreira wrote:

 Dear useRs,

 I'm having trouble building R packages in Windows 7 regarding HTML help
 Workshop.
 Pointing PATH to c:\Program Files\HTML help Workshop does work in Windows
 (e.g. Vista) and does not in Windows 7.

 Some tips??



 We don't use the HTML Help Workshop any more since R 2.10.0, so you could
 upgrade to the current R, and the problem will go away.  Otherwise, I think
 you'll have to ask Microsoft for help.  But they aren't likely to be
 helpful:  Win XP is the most recent OS listed as supported.

 Duncan Murdoch







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[R] How to do: Correlation with blocks (or - repeated measures ?!) ?

2010-02-25 Thread Tal Galili
Hello dear R help group,

I have the following setup to analyse:
We have about 150 subjects, and for each subject we performed a pair of
tests (under different conditions) 18 times.
The 18 different conditions of the test are complementary, in such a way so
that if we where to average over the tests (for each subject), we would get
no correlation between the tests (between subjects).
What we wish to know is the correlation (and P value) between the tests, in
within subjects, but over all the subjects.

The way I did this by now was to perform the correlation for each subject,
and then look at the distribution of the correlations received so to see if
it's mean is different then 0.
But I suspect there might be a better way for answering the same question
(someone said to me something about geographical correlation, but a
shallow search didn't help).

p.s: I understand there might be a place here to do some sort of mixed
model, but I would prefer to present a correlation, and am not sure how to
extract such an output from a mixed model.

Also, here is a short dummy code to give an idea of what I am talking about:

attach(longley)
N - length(Unemployed)
block - c(
rep( a, N),
rep( b, N),
 rep( c, N)
)
 Unemployed.3 - c(Unemployed + rnorm(1),
Unemployed + rnorm(1),
Unemployed + rnorm(1))

GNP.deflator.3 - c(GNP.deflator + rnorm(1),
GNP.deflator + rnorm(1),
GNP.deflator + rnorm(1))

cor(Unemployed, GNP.deflator)
cor(Unemployed.3, GNP.deflator.3)
cor(Unemployed.3[block == a], GNP.deflator.3[block == a])
cor(Unemployed.3[block == b], GNP.deflator.3[block == b])
cor(Unemployed.3[block == c], GNP.deflator.3[block == c])

(I would like to somehow combine the last three correlations...)



Any ideas will be welcomed.

Best,
Tal






Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
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[R] How to add a title to represent four different plot in lm function

2010-02-25 Thread FMH
Dear All,

A linear regression model could be fitted by using lm function and the plot 
function can be used to check the assumptions of the model. The example is as 
followed.

require(graphics)
## Annette Dobson (1990) An Introduction to Generalized Linear Models.
## Page 9: Plant Weight Data.
ctl - c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)
trt - c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
group - gl(2,10,20, labels=c(Ctl,Trt))
weight - c(ctl, trt)
anova(lm.D9 - lm(weight ~ group))
opar - par(mfrow = c(2,2), oma = c(0, 0, 1.1, 0))
plot(lm.D9, las = 1) 

Could someone advice me the way to add a single title either at the above or 
bottom of these 4 plots, entitled The verification of model assumtion via four 
different plots ?

Thanks
Fir




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Re: [R] Building R packages in Windows 7

2010-02-25 Thread Duncan Murdoch

On 25/02/2010 10:56 AM, Eric Ferreira wrote:

This is my first package. I'm just getting started doing that, following the
steps described on you website... I really don't know how I asking for CHMs
to be produced, sorry.
  


All I can suggest is that you need to be less stingy with information.  
Tell us what you did.  Tell us what symptoms you saw.  Do both of those 
by cut and paste from your console, don't paraphrase, or refer to vague 
instructions like your website.


Duncan Murdoch


On 25 February 2010 12:52, Duncan Murdoch murd...@stats.uwo.ca wrote:

 On 25/02/2010 10:40 AM, Eric Ferreira wrote:

 Dear Duncan

 Thank so much for your reply.
 Actually, I'm using the latest version of R and the problem persists. What
 do you use instead of HTML Help Workshop for newer R versions?



 We just produce text and HTML help pages on demand, and LaTeX ones for the
 pdf manuals.  How are you asking for CHMs to be produced?

 Duncan Murdoch

  Best regards

 Eric.

 On 25 February 2010 11:43, Duncan Murdoch murd...@stats.uwo.ca wrote:

  On 25/02/2010 9:06 AM, Eric Ferreira wrote:
 
  Dear useRs,
 
  I'm having trouble building R packages in Windows 7 regarding HTML help
  Workshop.
  Pointing PATH to c:\Program Files\HTML help Workshop does work in
 Windows
  (e.g. Vista) and does not in Windows 7.
 
  Some tips??
 
 
 
  We don't use the HTML Help Workshop any more since R 2.10.0, so you
 could
  upgrade to the current R, and the problem will go away.  Otherwise, I
 think
  you'll have to ask Microsoft for help.  But they aren't likely to be
  helpful:  Win XP is the most recent OS listed as supported.
 
  Duncan Murdoch
 












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Re: [R] How to extract one of four plots in a linear regression model

2010-02-25 Thread Alain Guillet

Hi,

You can extract a plot in using the option which in specifying the 
number of the plot (from 1 to 6). For example:


 plot(lm.D9, which=1)

Regards,
Alain Guillet


On 25-Feb-10 16:50, FMH wrote:

Dear All,

A linear regression model could be fitted by using lm function and the plot 
function can be used to check the assumption of the model.

The help menu shows few instances on suitable coding for fitting such a linear 
model. In addition, four different plots could be extracted simultaneously with 
only a single plot function as followed:



require(graphics)
## Annette Dobson (1990) An Introduction to Generalized Linear Models.
## Page 9: Plant Weight Data.
ctl- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)
trt- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
group- gl(2,10,20, labels=c(Ctl,Trt))
weight- c(ctl, trt)
anova(lm.D9- lm(weight ~ group))
opar- par(mfrow = c(2,2), oma = c(0, 0, 1.1, 0))
plot(lm.D9, las = 1) 





The plot function gives four different plots simulaneously but i just need only 
part of them, for instance the normality plot. Could someone  give some ideas 
the way to extract this single plot as i need to copy only this plot and paste 
it into Word document.

Thanks
Fir





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--
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Statistician and Computer Scientist

SMCS - Institut de statistique - Université catholique de Louvain
Bureau c.316
Voie du Roman Pays, 20
B-1348 Louvain-la-Neuve
Belgium

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Re: [R] data mining

2010-02-25 Thread Tal Galili
It depends on what you want to do.
Start by looking at:
http://cran.r-project.org/web/views/

http://cran.r-project.org/web/views/There are also some nice startup
tutorials on google, start from that...

Tal

Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
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On Thu, Feb 25, 2010 at 1:32 PM, chinna durgache...@gmail.com wrote:


 how can we achieve data mining using R Project.
 how to install Rattle gui for R project.


 can anyone please help me.

 i want to forecast the results .

 Thanks in advance.
 --
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 http://n4.nabble.com/data-mining-tp1568872p1568872.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] Odp: export results

2010-02-25 Thread jim holtman
If your data can fit in memory, consider creating a list of the
intermediate values and then 'cbind'ing the result into a matrix that
you want to write out.

result - lapply(1:100, function(x)  your function )
# if everything is the same size
result - do.call(cbind, result)

On Thu, Feb 25, 2010 at 10:44 AM, Petr PIKAL petr.pi...@precheza.cz wrote:
 Hi

 r-help-boun...@r-project.org napsal dne 25.02.2010 12:42:46:


 Hi all,

 I am looping through a function for 100 time in the middle of my code,
 and I
 want to output the results from this function. Is there a way to write
 the
 results into a txt or csv fil? For example, I write the results from the
 first loop to the first column of a spreadsheet and the results from the
 second loop to the second coclumn of a spreadsheet etc.

 make a data frame, let say res

 res=as.data.frame(matrix(NA, n, 100)) #predefine data frame

 for (i in ...) {

 some stuff
 res[,i] - some function result
 }

 write.table(res,)

 Regards
 Petr





 Thank you very much,
 Wendy
 --
 View this message in context:
 http://n4.nabble.com/export-results-tp1568880p1568880.html
 Sent from the R help mailing list archive at Nabble.com.

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 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

 __
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-- 
Jim Holtman
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+1 513 646 9390

What is the problem that you are trying to solve?

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Re: [R] Use 2 ifelse to sort data

2010-02-25 Thread Greg Snow
There is the %% operator in the TeachingDemos package that allows comparisons 
like:

5 %% a %% 10

But in this case it is not needed (and in this case it takes more key strokes 
than 5  a  a  5, so may not be worth it).

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of bill.venab...@csiro.au
 Sent: Monday, February 22, 2010 8:55 PM
 To: tu_chun...@yahoo.com; r-help@r-project.org
 Subject: Re: [R] Use 2 ifelse to sort data
 
 a - 1:20
 tt - ifelse(a  10, A, ifelse(a  5, B, C))
 
 The problem you have is with '5  a = 10'.  Such double sided
 inequalities are used in mathematics but not in R.  Here you only need
 the first part, but if you did need both you would need to write
 
 5  a  a = 10
 
 Look carefully and spot the difference.
 
 Bill Venables
 CSIRO/CMIS Cleveland Laboratories
 
 
 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Chunhao
 Sent: Tuesday, 23 February 2010 12:13 PM
 To: r-help@r-project.org
 Subject: [R] Use 2 ifelse to sort data
 
 
 Dear R users,
 I have a question how to use 2 ifelse to sort my data. Such as
 from 11 to 20 assign to A; 6 to 10 assign to B, and the rest of them
 assign
 to C
 
 a-1:20
 
 tt-ifelse(a10, A,no=ifelse( 5 a =10, B, C))
 
 
 Many Thanks
 Chunhao
 
 --
 View this message in context: http://n4.nabble.com/Use-2-ifelse-to-
 sort-data-tp1565422p1565422.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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Re: [R] Normal distribution (Lillie.test())

2010-02-25 Thread Greg Snow
You should probably read fortune(117) and fortune(234) (and possibly some of 
the original discussions that lead to the fortunes).  Reading the help page for 
the SnowsPenultimateNormalityTest function (TeachingDemos package) may also 
help.  If you are happy with the plots, but still feel the need for a test of 
some sort, then you should investigate using the vis.test function in the 
TeachingDemos package.

Hope this helps,

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Bosken
 Sent: Tuesday, February 23, 2010 4:13 AM
 To: r-help@r-project.org
 Subject: Re: [R] Normal distribution (Lillie.test())
 
 
 Hi,
 
 Thanks for your reaction;
 
 How do you come to the decision that my data not is normal distributed?
 
 With the 69-95-99.7 test and Q-Q plot seems it ok! But these test are
 not
 exact, they only give you an image.
 
 Gr. Bosken
 --
 View this message in context: http://n4.nabble.com/Normal-distribution-
 Lillie-test-tp1565083p1565762.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.

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[R] error in lmLists in lme4 package (bug?)

2010-02-25 Thread Elizabeth Purdom

Hello,
I am trying to use lmLists in the lme4 package and copying over very 
standard code from the nlme package given in 'Mixed-Effects Models in S 
and S-Plus'. It appears to not accept an 'I(age-11)' in the formula, 
though it will accept the formula with out the subtraction of 11 from 
age. This seems like it would be a bug, since this is standard formula 
syntax, unless I'm missing something about lmList in lme4. Please see my 
session info and output below.

Thanks for your help,
Elizabeth

 library(lme4)
 data(Orthodont)
 sessionInfo()
R version 2.10.0 (2009-10-26)
x86_64-apple-darwin9.8.0

locale:
[1] en_US.UTF-8/en_US.UTF-8/C/C/en_US.UTF-8/en_US.UTF-8

attached base packages:
[1] stats graphics  grDevices utils datasets  methods   base


other attached packages:
[1] MEMSS_0.3-6lme4_0.999375-32   Matrix_0.999375-31 
lattice_0.17-26  


loaded via a namespace (and not attached):
[1] grid_2.10.0  tools_2.10.0
 fm1Orth.lis-lmList(distance~age|Subject, data=Orthodont)
 fm2Orth.lis-lmList(distance~I(age-11)|Subject, data=Orthodont)
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found
Error in unique(c(AsIs, oldClass(x))) : object 'age' not found

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Re: [R] Reading a password-protected Excel workbook

2010-02-25 Thread Gabor Grothendieck
Use RDCOMClient or rcom to open it and then use RODBC to read it.

On Thu, Feb 25, 2010 at 7:26 AM, Dimitri Shvorob
dimitri.shvo...@gmail.com wrote:

 I try reading a password-protected spreadsheet with RODBC, passing a file or
 an ODBC source to odbcConnect, e.g.

 con = odbcConnect(dsn = mywkbk, uid = , pwd = mypwd)

 but get Could not decrypt file pop-up error message.

 Can anyone help?

 Thank you.

 --
 View this message in context: 
 http://n4.nabble.com/Reading-a-password-protected-Excel-workbook-tp1568925p1568925.html
 Sent from the R help mailing list archive at Nabble.com.

 __
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


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Re: [R] Single character input without Enter

2010-02-25 Thread Greg Snow
The getGraphicsEvent function only works on windows (at least last time I 
checked), so if you are working only on windows, you can use that.  If you want 
something that works cross platform, then the tcltk solution is a possibility.

Your original question did not indicate if you would be willing to have this 
working through a graph or not, so I was not sure if this was a good solution 
or not.

I would have told you this on Monday, but I was out of town the first part of 
the week and not reading r-help.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Dieter Menne
 Sent: Thursday, February 25, 2010 11:29 AM
 To: r-help@r-project.org
 Subject: Re: [R] Single character input without Enter
 
 
 
 Greg Snow-2 wrote:
 
  The playSudoku function in the sudoku package has 2 examples/methods
 of
  responding to single key strokes, whether those methods will work for
 your
  application or not depends on what you are trying to do.
 
 
 
 Thanks, Greg, it boils down to the rather basic
 
 getGraphicsEvent(prompt = Waiting for input,
  onMouseDown = NULL, onMouseMove = NULL,
  onMouseUp = NULL, onKeybd = NULL)
 
 in grDevices; so no tclk needed.  Strange that nobody told me
 
 Dieter
 
 
 
 
 --
 View this message in context: http://n4.nabble.com/Single-character-
 input-without-Enter-tp1564153p1569460.html
 Sent from the R help mailing list archive at Nabble.com.
 
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 PLEASE do read the posting guide http://www.R-project.org/posting-
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Re: [R] Normal distribution (Lillie.test())

2010-02-25 Thread Greg Snow
Install and load the fortunes package first, then run fortune(117), etc.  Then 
run fortune() quite a few times for possible enlightenment (or at least mild 
entertainment).

Do your NoiseGenerotors need to generate exactly normal data (they don't, see 
SnowsPenultimateNormalityTest), or is there a level of close enough?  If I 
remember correctly, you were testing 2000 values, with that sample size most 
normality tests will find very small differences to be significantly different, 
even if those small differences are practically meaningless.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Bosken
 Sent: Thursday, February 25, 2010 10:21 AM
 To: r-help@r-project.org
 Subject: Re: [R] Normal distribution (Lillie.test())
 
 
 Hi,
 
 Thanks for your reaction.
 
 The purpose of my test is to check if my NoiseGenerators really are
 Normal
 Distributed en witch circuit is the best!
 
 So I need some good test to do this.
 
 But what with: Fortune(117) and fortune(234), can't find anything about
 it..
 
 Thanks for the help!
 
 Bosken
 --
 View this message in context: http://n4.nabble.com/Normal-distribution-
 Lillie-test-tp1565083p1569361.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] Normal distribution (Lillie.test())

2010-02-25 Thread Ravi Varadhan
May be you should have said:

Normality tests are standard farce in a host of statistical texts.

Ravi.


---

Ravi Varadhan, Ph.D.

Assistant Professor, The Center on Aging and Health

Division of Geriatric Medicine and Gerontology 

Johns Hopkins University

Ph: (410) 502-2619

Fax: (410) 614-9625

Email: rvarad...@jhmi.edu

Webpage:
http://www.jhsph.edu/agingandhealth/People/Faculty_personal_pages/Varadhan.h
tml

 





-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Bert Gunter
Sent: Thursday, February 25, 2010 12:24 PM
To: 'Greg Snow'; 'Bosken'; r-help@r-project.org
Subject: Re: [R] Normal distribution (Lillie.test())

...

But,quoting Pogo, We have met the enemy, and he is us.

Normality tests are standard fare in a host of statistical texts.

Bert Gunter
Genentech Nonclinical Biostatistics
 
 

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Greg Snow
Sent: Thursday, February 25, 2010 9:00 AM
To: Bosken; r-help@r-project.org
Subject: Re: [R] Normal distribution (Lillie.test())

You should probably read fortune(117) and fortune(234) (and possibly some of
the original discussions that lead to the fortunes).  Reading the help page
for the SnowsPenultimateNormalityTest function (TeachingDemos package) may
also help.  If you are happy with the plots, but still feel the need for a
test of some sort, then you should investigate using the vis.test function
in the TeachingDemos package.

Hope this helps,

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Bosken
 Sent: Tuesday, February 23, 2010 4:13 AM
 To: r-help@r-project.org
 Subject: Re: [R] Normal distribution (Lillie.test())
 
 
 Hi,
 
 Thanks for your reaction;
 
 How do you come to the decision that my data not is normal distributed?
 
 With the 69-95-99.7 test and Q-Q plot seems it ok! But these test are
 not
 exact, they only give you an image.
 
 Gr. Bosken
 --
 View this message in context: http://n4.nabble.com/Normal-distribution-
 Lillie-test-tp1565083p1565762.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.

__
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Re: [R] two questions for R beginners

2010-02-25 Thread Clint Bowman
I started using statistical software with the commercial product S+ 
when I obtained a new HP735 workstation.  We kept the S+ license 
going for a number of years until I heard about R.  It was an easy 
transition and because I have been proficient in fortran and perl, 
the scripting came naturally--except for some syntax 
similarities/differences between perl and R interacting with a 
natural tendency towards dyslexia.


I especially like that I can slice and dice the data to ferret out 
relationships e.g., concentration by hour of day, by month, by wind 
speed, by wind direction--love those boxplots.


I also find that even the default settings produce some pretty 
attractive plots that are useable in many settings--I've also 
produced some pretty awful ones.


And the price always reminds me that I need to find every way 
possible to contribute to the overall good--I've forgotten too much 
of my fortran and C programming skills to contribute directly to 
the R Project.


Clint

--
Clint BowmanINTERNET:   cl...@ecy.wa.gov
Air Quality Modeler INTERNET:   cl...@math.utah.edu
Department of Ecology   VOICE:  (360) 407-6815
PO Box 47600FAX:(360) 407-7534
Olympia, WA 98504-7600

On Thu, 25 Feb 2010, Ralf B wrote:


My biggest blocker was my misconception that R is extremely difficult
to start with. It is powerful and one can do very complicated things (
that consequently turn things  complicated) but it comes with very
nice defaults and one can produce great results with standard tasks in
very little time - especially if one has done programming and/or
scripting before.

I pushed it away for too long that way. I wish I would have used it
years ago and avoided SPSS altogether - must have wasted 100s of hours
doing repetitive tasks by click and partial scripts in SPSS. Not to
mention a horrible license policy and a visualization unit that is
simply embarrassing for a product that is in its 18th or 19th version.

Ralf

On Thu, Feb 25, 2010 at 1:11 PM, Tal Galili tal.gal...@gmail.com wrote:

My biggest stumbling blocks to getting up and running with R was whenever I
was lazy and impatient.

The more you love R, the more it loves you back.

Tal




Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
--




On Thu, Feb 25, 2010 at 7:31 PM, Patrick Burns pbu...@pburns.seanet.comwrote:


* What were your biggest misconceptions or
stumbling blocks to getting up and running
with R?

* What documents helped you the most in this
initial phase?

I especially want to hear from people who are
lazy and impatient.

Feel free to write to me off-list.  Definitely
write off-list if you are just confirming what
has been said on-list.

--
Patrick Burns
pbu...@pburns.seanet.com
http://www.burns-stat.com
(home of 'The R Inferno' and 'A Guide for the Unwilling S User')

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       [[alternative HTML version deleted]]

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Re: [R] Bimodal distribution

2010-02-25 Thread Greg Snow
You could use:

library(TeachingDemos)

x - c(rnorm(1000,0,1),rnorm(1000,3,1))
TeachingDemos:::vis.test( x, TeachingDemos:::vt.normhist )

Then click on the plot that looks most different.

Sorry about needing TeachingDemos::: for now, the functions were accidentally 
left out of the NAMESPACE file, this has been fixed and will not be needed for 
version 2.6 on.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Samor Gandhi
 Sent: Wednesday, February 24, 2010 5:23 AM
 To: r-help@r-project.org
 Subject: [R] Bimodal distribution
 
 Hello,
 
 Is there any test  for bimodality in R that
 
 x - c(rnorm(1000,0,1),rnorm(1000,3,1))
 hist(x,nclass=100)
 
 Thank you in advance for any help.
 
 Regards,
 Samor
 
 
 
   [[alternative HTML version deleted]]

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Re: [R] Building R packages in Windows 7

2010-02-25 Thread Duncan Murdoch

On 25/02/2010 11:49 AM, Eric Ferreira wrote:

Ok,

I'm working under:
Windows 7 Professional 32bits, 4 GB RAM, 320 GB HD, Intel Core 2 Duo
processor
R 2.10.1

I've installed:
Rtools211
MikteX 2.8
HTML Help Workshop

Setting my PATH to:
c:\Rtools\bin;c:\Rtools\perl\bin;c:\Rtools\MinGW\bin;c:\Arquivos de
Programas\R\R-2.10.1pat\bin;c:\Arquivos de Programas\MikTeX
2.8\miktex\bin;c:\Program Files\HTML Help Workshop

...creating the package called ExpDes and asking (at the prompt) :

Rcmd build --binary ExpDes

Among others, a warning message is printed: WARNING: some HTML links may
not be found, and no html files are produced.
  


Right, HTML help files are produced on demand, they aren`t stored in the 
binary package zip file.  HTML Help Workshop is not being used at all.


Duncan Murdoch

Thank you again.






On 25 February 2010 13:02, Duncan Murdoch murd...@stats.uwo.ca wrote:

 On 25/02/2010 10:56 AM, Eric Ferreira wrote:

 This is my first package. I'm just getting started doing that, following
 the
 steps described on you website... I really don't know how I asking for
 CHMs
 to be produced, sorry.



 All I can suggest is that you need to be less stingy with information.
  Tell us what you did.  Tell us what symptoms you saw.  Do both of those by
 cut and paste from your console, don't paraphrase, or refer to vague
 instructions like your website.

 Duncan Murdoch


 On 25 February 2010 12:52, Duncan Murdoch murd...@stats.uwo.ca wrote:

  On 25/02/2010 10:40 AM, Eric Ferreira wrote:
 
  Dear Duncan
 
  Thank so much for your reply.
  Actually, I'm using the latest version of R and the problem persists.
 What
  do you use instead of HTML Help Workshop for newer R versions?
 
 
 
  We just produce text and HTML help pages on demand, and LaTeX ones for
 the
  pdf manuals.  How are you asking for CHMs to be produced?
 
  Duncan Murdoch
 
   Best regards
 
  Eric.
 
  On 25 February 2010 11:43, Duncan Murdoch murd...@stats.uwo.ca
 wrote:
 
   On 25/02/2010 9:06 AM, Eric Ferreira wrote:
  
   Dear useRs,
  
   I'm having trouble building R packages in Windows 7 regarding HTML
 help
   Workshop.
   Pointing PATH to c:\Program Files\HTML help Workshop does work in
  Windows
   (e.g. Vista) and does not in Windows 7.
  
   Some tips??
  
  
  
   We don't use the HTML Help Workshop any more since R 2.10.0, so you
  could
   upgrade to the current R, and the problem will go away.  Otherwise, I
  think
   you'll have to ask Microsoft for help.  But they aren't likely to be
   helpful:  Win XP is the most recent OS listed as supported.
  
   Duncan Murdoch
  
 
 
 
 
 
 
 











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Re: [R] angle phase mapping

2010-02-25 Thread Greg Snow
Look at the my.symbols function in the TeachingDemos package.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Magali teurlai
 Sent: Thursday, February 25, 2010 3:51 AM
 To: r-help@r-project.org
 Subject: Re: [R] angle phase mapping
 
 Hi all,
 
 sorry,
 here is the pdf and I re post my question :
 
 could anyone give me a clue for the name of a function that would
 allow me to create the same kind of plot as the attached image in R?
 
 I know how to create a map (shapefile polygons), I just want to add
 the phase information as triangles , pointing in the direction
 according to the phase, and the colors of the triangle describing as
 well the phase
 I will have a vector of phases : one scalr (the phase) per polygon
 plotted on the map
 
 Thanks very much for any help
 
 Magali
 
 2010/2/25 Magali teurlai teurlaima...@gmail.com
 
  Hi all,
 
  could anyone give me a clue for the name of a function that would
 allow me create the same kind of plot as the attached image in R?
 
  I know how to create a map (shapfile polygons), I just want to add
 the phase information
 
  Thanks very much for any help
 
  Magali

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Re: [R] Minimum Spanning Trees

2010-02-25 Thread Steve Lianoglou
Hi,

On Thu, Feb 25, 2010 at 12:16 PM, harunpirim harunpi...@gmail.com wrote:

 Hi,

 I need to find all minimum spanning trees of an unweighted graph.
 Is there a way in R to do that?

If you're working with graphs in R, you'll probably want to see what
the igraph library has to offer. For instance, it has a
minimum.spanning.tree function ...

-steve

-- 
Steve Lianoglou
Graduate Student: Computational Systems Biology
 | Memorial Sloan-Kettering Cancer Center
 | Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact

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[R] read.table (trying one more time)

2010-02-25 Thread Mestat

Hey listers,
I've posted this doubt other day... But I am still having a hard time...
I have a MAC and I am not getting how to use the read.table command...
At the bottom of the FINDER application I have the following path:

Macintosh HDUsuáriosUserMarcioUdeMTravail DirigéDataMU284
Population.txt

I didn't find out how I could copy and paste this path as it is possible to
do with the Windows. But, it's ok, cause I am trying the following command
with all possible choices, as below:

file-read.table(/User/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)
file-read.table(/Users/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)
file-read.table(/Usuários/User/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)
file-read.table(/Usuários/Users/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)

I've checked already the forum and I found a similar post that says to use
the command with the following path: /Users/Marcio/UdeM/Travail
Dirigé/Data/MU284 Population.txt
But at the bottom of the FINDER application is just USER.
Anyway I tried those options and other... But didn't work...
If anybody could give me a clue... THANKS A LOT!!!
Marcio


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Re: [R] Help with simple bootstrap test

2010-02-25 Thread Robert A LaBudde
The boot() function in the 'boot' package expects to find a function 
for the statistic with two arguments: The data object plus a row index object.


You don't indicate enough to see how you will be resampling. It you 
sum all elements in your table, resampling would have to be one of:


1. A sample with replacement of rows, or
2. A sample with replacement of columns, or
3. A sample with replacement of elements in the whole table.

Assuming you want sampling with replacement of rows:

sumf- function (x, i) { sum(x[i,]) }
result- boot(mytable, sumf, 1000)
boot.ci(result, type='bca')

A simulation:

 mytable- matrix(rnorm(2000), ncol=20)
 sum(mytable)
[1] -14.92842
 sumf- function(x,i) sum(x[i,])
 require('boot')
Loading required package: boot
 b1- boot(mytable, sumf, 1000)
 boot.ci(b1, type='bca')
BOOTSTRAP CONFIDENCE INTERVAL CALCULATIONS
Based on 1000 bootstrap replicates

CALL :
boot.ci(boot.out = b1, type = bca)

Intervals :
Level   BCa
95%   (-101.49,   85.20 )
Calculations and Intervals on Original Scale

At 01:28 PM 2/25/2010, xonix wrote:

Hi all
Forgive me, I'm a total R newbie, and this seems to be a straightforward
simple bootstrap problem, but after a whole day of trying to figure out how
to do it I'm ready to give up. Part of the problem is that every example and
every help page seems to be about doing something more far more complex.


I'm got a table with 40 columns and 750 rows. I sum all the values across
the whole table (and subsets of the columns). I want to bootstrap to get the
95% confidence intervals for that sum value.

result - boot(table, function, 1000)
boot.ci (result, bca)

It seems to me that the 'function' is something to sum all the columns and
rows of the table (or a subset should I desire). I've tried writing 'sum'
for the function, but this gives me a huge figure which can't possibly be
right.



Robert A. LaBudde, PhD, PAS, Dpl. ACAFS  e-mail: r...@lcfltd.com
Least Cost Formulations, Ltd.URL: http://lcfltd.com/
824 Timberlake Drive Tel: 757-467-0954
Virginia Beach, VA 23464-3239Fax: 757-467-2947

Vere scire est per causas scire

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Re: [R] two questions for R beginners

2010-02-25 Thread Patrick Burns

Apparently I need to explain the lazy and
impatient comment.  No offence was intended
(quite the contrary).  The meaning of it is
that the higher your level of frustration,
the more valuable your comments are likely to
be to me.

On 25/02/2010 17:31, Patrick Burns wrote:

* What were your biggest misconceptions or
stumbling blocks to getting up and running
with R?

* What documents helped you the most in this
initial phase?

I especially want to hear from people who are
lazy and impatient.

Feel free to write to me off-list. Definitely
write off-list if you are just confirming what
has been said on-list.



--
Patrick Burns
pbu...@pburns.seanet.com
http://www.burns-stat.com
(home of 'The R Inferno' and 'A Guide for the Unwilling S User')

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Re: [R] two questions for R beginners

2010-02-25 Thread Liviu Andronic
On 2/25/10, Patrick Burns pbu...@pburns.seanet.com wrote:
 * What were your biggest misconceptions or
  stumbling blocks to getting up and running
  with R?

  * What documents helped you the most in this
  initial phase?

  I especially want to hear from people who are
  lazy and impatient.

I'm quite resilient so I don't think I got to the point of
frustration, but getting up to speed was a lengthy process. The
biggest stumbler was getting onto the console, and not knowing what to
do next. (My first encounter with stats was SPSS, so it was similar to
getting onto a UNIX virtual console after a life-long experience with
point-and-click windows: it's not very reassuring to know that there
are man pages.) I stayed in the what-do-I-do-next state of mind for
about 6-12 months (I learned R myself, and my professors were quite
reticent when I first introduced them to R).

Of particular help to making progress were JGR (arguments suggestions,
editor with syntax highlighting, object browser, etc.), Rcmdr (quick
access to examples for performing specific tasks, etc.) and Sweave +
LyX (for easy results transfer and report creation, without the burden
of learning LaTeX). For graphics, playwith latticist and rggobi come
in very handy. From the documentation, right now I can recall Quick-R
and R for SAS and SPSS users. And of course, RSiteSearch (also via
the sos package), Rseek and the vignettes are a must.

Regards
Liviu

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[R] nested design

2010-02-25 Thread ixi10

This is a nested design where team is nested in group. Method is fixed, while
team and group are random. Is this the correct R code for this?

gunload.aov - aov(rounds ~ method+group + Error((team %in%
group)/method),data=gunload, qr=T)
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[R] Minimum Spanning Trees

2010-02-25 Thread harunpirim

Hi,

I need to find all minimum spanning trees of an unweighted graph. 
Is there a way in R to do that?

Thanks
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Re: [R] two questions for R beginners

2010-02-25 Thread Greg Snow
Patrick,

I would add one more question:

* where did you look for help expecting answers, but did not find them?

If you add hubris to laziness and impatience, you have Larry Wall's 3 virtues 
of a programmer.

To new users of R who may not understand why Patrick is asking:

Patrick Burns is the author of some great tutorials/references on S/R and is 
probably looking for questions to answer in his next contribution.

Lately there have been a large number of questions on some fairly basic issues 
(and some rather complex issues that people expected to be simple/basic).  My 
initial response (and probably others as well) to some of these requests was to 
quickly think that the answer is obvious and that the obvious place to look is 
..., but then I realize that I am a high school dropout who has been using S/R 
for over 20 years, majored in statistics but reads Shakespeare for fun, and 
have been known to saw people in half for the entertainment of others; so I am 
probably not representative of most beginners.  Fortune(89) probably applies 
here.  If R beginners will share their frustrations, where they looked but did 
not find answers (and why they looked there), what would have helped them, etc. 
 Then we (well probably Patrick mostly) can do more to help the next set of 
beginners.

It does not matter how good our answers are if they answer the wrong questions 
or are in places that the questioner never sees them.

The best way to spread information is to tell someone that it is a secret, the 
best way to keep it secret is to put it in a manual.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Patrick Burns
 Sent: Thursday, February 25, 2010 10:31 AM
 To: r-help@r-project.org
 Subject: [R] two questions for R beginners
 
 * What were your biggest misconceptions or
 stumbling blocks to getting up and running
 with R?
 
 * What documents helped you the most in this
 initial phase?
 
 I especially want to hear from people who are
 lazy and impatient.
 
 Feel free to write to me off-list.  Definitely
 write off-list if you are just confirming what
 has been said on-list.
 
 --
 Patrick Burns
 pbu...@pburns.seanet.com
 http://www.burns-stat.com
 (home of 'The R Inferno' and 'A Guide for the Unwilling S User')
 
 __
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 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
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Re: [R] How to add a title to represent four different plot in lm function

2010-02-25 Thread Greg Snow
Try something like:

 par(oma=c(0,0,3,0))
your plotting commands here
 mtext(your text here, outer=TRUE

Hope this helps,

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of FMH
 Sent: Thursday, February 25, 2010 9:01 AM
 To: r-help@r-project.org
 Cc: r-sig...@stat.math.ethz.ch
 Subject: [R] How to add a title to represent four different plot in lm
 function
 
 Dear All,
 
 A linear regression model could be fitted by using lm function and the
 plot function can be used to check the assumptions of the model. The
 example is as followed.
 
 require(graphics)
 ## Annette Dobson (1990) An Introduction to Generalized Linear
 Models.
 ## Page 9: Plant Weight Data.
 ctl - c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)
 trt - c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
 group - gl(2,10,20, labels=c(Ctl,Trt))
 weight - c(ctl, trt)
 anova(lm.D9 - lm(weight ~ group))
 opar - par(mfrow = c(2,2), oma = c(0, 0, 1.1, 0))
 plot(lm.D9, las = 1)
 
 Could someone advice me the way to add a single title either at the
 above or bottom of these 4 plots, entitled The verification of model
 assumtion via four different plots ?
 
 Thanks
 Fir
 
 
 
 
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Re: [R] How to fill in a region with different patterns?

2010-02-25 Thread Greg Snow
The rect function will draw a rectangle and can fill it with diagonal lines at 
specified angle and density.  But before you do that, really consider if and 
why you want to.  Using the diagonal lines became popular when the only way to 
get quality graphics was with a pen plotter (mechanical arm actually drawing 
the plot with a pen), filling an area was not reasonable (you could use a 
really high density of lines, but that usually made you unpopular with everyone 
else waiting for their turns, and often just wore a hole in your paper).

Research has shown (see Tufte's book) that patterns of lines are not the best 
approach, they can produce what is called the Moire effect which gives an 
illusion of color and movement.  These pattern fills are better at producing 
headaches and nausea and less effective at conveying information and producing 
useful plots.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of St.Jeff Shang
 Sent: Wednesday, February 24, 2010 8:34 PM
 To: r-help@r-project.org
 Subject: [R] How to fill in a region with different patterns?
 
 Hi to all,
 
 
 
 Here is a question which I cannot solve. Appreciate so much for any
 suggestions!
 
 
 
 I have a squared region which is irregularly divided into many
 rectangular patches.
 
 Each patch is associated with a value, and two patches possibly share a
 common value.
 
 I hope to fill in each patch a pattern according to its value. For
 instance, if a patch has value 1, then I fill in that patch with
 pattern A; if it has value 2, then fill in it with pattern B,...
 
 
 
 The pattern is something like a rectangular region with certain colored
 lines in it. For instance, pattern A may be a white rectangular region
 filled in by two thick black lines;
 
 pattern B may be a white rectagular region filled in by 10 thick black
 lines,...
 
 
 
 Is this available in matlab? I have serached polygnon in matlab user
 guide and found a
 
 fill function may work, however, there is still a long way to finally
 complete it.
 
 
 
 Many thanks again!
 
 Jeff
 
 
 
   [[alternative HTML version deleted]]
 
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Re: [R] Single character input without Enter

2010-02-25 Thread Dieter Menne


Greg Snow-2 wrote:
 
 The playSudoku function in the sudoku package has 2 examples/methods of
 responding to single key strokes, whether those methods will work for your
 application or not depends on what you are trying to do.
 
 

Thanks, Greg, it boils down to the rather basic

getGraphicsEvent(prompt = Waiting for input, 
 onMouseDown = NULL, onMouseMove = NULL,
 onMouseUp = NULL, onKeybd = NULL)

in grDevices; so no tclk needed.  Strange that nobody told me

Dieter




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Re: [R] Inverse function

2010-02-25 Thread Greg Snow
?uniroot

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of li li
 Sent: Wednesday, February 24, 2010 2:31 PM
 To: Bert Gunter
 Cc: r-help
 Subject: Re: [R] Inverse function
 
 This is not a homework problem.
 
 How to solve numerically for y from f(y,r) - a=g(y)=0? I am not too
 sure.
 
 Thanks!
Hannah
 
 
 2010/2/24 Bert Gunter gunter.ber...@gene.com
 
  1. Is this a homework problem?
 
  2. Etiquette on this list is to sign with your full real name.
 Adhering to
  the list etiquette may enhance your chance of a useful response,
 especially
  in view of (1), as we (or at least some of us) do not wish to do
 students'
  homework for them.
 
  3. Hint: f(y,r) = a  ==  g(y) = 0 where g(y) == f(y,r) - a
  (for numerical solutions).
 
 
  Bert Gunter
  Genentech Nonclinical Biostatistics
 
   -Original Message-
  From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org]
  On
  Behalf Of li li
  Sent: Wednesday, February 24, 2010 12:46 PM
  To: r-help
  Subject: [R] Inverse function
 
  Hi all,
I have a function like the following:
 
   f - function(r,
  y){r/(2*pi)*exp(1)^(-y)*(1+r*(y/2)+r^(2)*(y-1)^(2)/6)}
 
  For fixed r, I want to find the inverse funtion in terms y.
  In other words, for fixed r, if the value of the function is given, I
 want
  to
  find the corrsponding y value that will achieve the specific function
  value.
 
  Can anyone help me?
 Hannah
 
 [[alternative HTML version deleted]]
 
  __
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  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
  http://www.R-project.org/posting-guide.htmlhttp://www.r-
 project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 
 
 
   [[alternative HTML version deleted]]
 
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Re: [R] Normal distribution (Lillie.test())

2010-02-25 Thread Bosken

Hi,

Thanks for your reaction.

The purpose of my test is to check if my NoiseGenerators really are Normal
Distributed en witch circuit is the best!

So I need some good test to do this.

But what with: Fortune(117) and fortune(234), can't find anything about it..

Thanks for the help!

Bosken
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Re: [R] Restructure some data

2010-02-25 Thread William Dunlap
 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of Doran, Harold
 Sent: Thursday, February 25, 2010 10:35 AM
 To: r-help@r-project.org
 Subject: [R] Restructure some data
 
 Suppose I have a data frame like dat below. For some 
 context, this is the format that represents student's taking 
 a computer adaptive test. first.item is the first item that 
 student was administered and then score.1 is the student's 
 response to that item and so forth.
 
 item.pool - paste(item, 1:10, sep = )
 set.seed(54321)
 dat - data.frame(id = c(1,2,3,4,5), first.item = 
 sample(item.pool, 5, replace=TRUE),
 second.item = sample(item.pool, 
 5,replace=TRUE), third.item = sample(item.pool, 5,replace=TRUE),
 score1 = sample(c(0,1), 5,replace=TRUE), 
 score2 = sample(c(0,1), 5,replace=TRUE), score3 = 
 sample(c(0,1), 5,replace=TRUE))
 
 I need to restructure this into a new format. The new matrix 
 df (after the loop) is exactly what I want in the end. But, 
 I'm annoyed at myself for not thinking of a more efficient 
 way to restructure this without using a loop.
 
 df - matrix(NA, ncol = length(item.pool), nrow = nrow(dat))
 colnames(df) - unique(item.pool)
 
 for(i in 1:5){
 for(j in 2:4){
 rr - which(dat[i,j] == colnames(df))
 df[i,rr] - dat[i, (j+3)]
 }
 }
 
 Any thoughts?

You can try subscripting by a 2-column matrix, the first
giving the row index and the second the column index.  E.g.,

   f - function(dat) {
  allItems - paste(item, 1:10, sep = )
  items - as.matrix(dat[2:4])
  scores - as.matrix(dat[, 5:7])
  retval - matrix(NA_real_, nrow = nrow(dat), ncol = 10,
  dimnames = list(character(), allItems))
  retval[cbind(dat$id, match(items, allItems))] - scores
  retval
  }
   identical(f(dat), df)
  [1] TRUE

That was a very nice problem description, letting me
reproduce the example data and desired output with
just copy and paste.

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com 

 
 Harold
 
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[R] Help with simple bootstrap test

2010-02-25 Thread xonix

Hi all
Forgive me, I'm a total R newbie, and this seems to be a straightforward
simple bootstrap problem, but after a whole day of trying to figure out how
to do it I'm ready to give up. Part of the problem is that every example and
every help page seems to be about doing something more far more complex.


I'm got a table with 40 columns and 750 rows. I sum all the values across
the whole table (and subsets of the columns). I want to bootstrap to get the
95% confidence intervals for that sum value. 

result - boot(table, function, 1000)
boot.ci (result, bca)

It seems to me that the 'function' is something to sum all the columns and
rows of the table (or a subset should I desire). I've tried writing 'sum'
for the function, but this gives me a huge figure which can't possibly be
right.

Thanks,
-- 
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Re: [R] Odp: How to read percentage and currency data?

2010-02-25 Thread Greg Snow
 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Hrishi Mittal
 Sent: Wednesday, February 24, 2010 8:56 AM
 To: r-help@r-project.org
 Subject: Re: [R] Odp: How to read percentage and currency data?

[snip]

 It's a shame that something which Excel deals with trivially is such a
 hack
 in R. 

I believe that this is a consequence of a fundamental difference in the 
philosophies of the authors of R and the authors of MS Excel.

The authors of R assume that their users are intelligent and have a greater 
understanding of their own data than the authors do.



-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111

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Re: [R] Alternatives to linear regression with multiple variables

2010-02-25 Thread Greg Snow
Well, the help page for the loess function says that the formula can include up 
to 4 predictor variables.  There are also additive models (mgcv or gam (or 
other) package).

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Guy Green
 Sent: Monday, February 22, 2010 5:47 AM
 To: r-help@r-project.org
 Subject: [R] Alternatives to linear regression with multiple variables
 
 
 I wonder if someone can give some pointers on alternatives to linear
 regression (e.g. Loess) when dealing with multiple variables.
 
 Taking any simple table with three variables, you can very easily get
 the
 intercept and coefficients with:
   summary(lm(read_table))
 
 For obvious reasons, the coefficients in a multiple regression are
 quite
 different from what you get if you calculate regressions for the single
 variables separately.  Alternative approaches such as Loess seem
 straightforward when you have only one variable, and have the advantage
 that
 they can cope even if the relationship is not linear.
 
 My question is: how can you extend a flexible approach like Loess to a
 multi-variable scenario?  I assume that any non-parametric calculation
 becomes very resource-intensive very quickly.  Can anyone suggest
 alternatives (preferably R-based) that cope with multiple variables,
 even
 when the relationship (linear, etc) is not known in advance?
 
 Thanks,
 
 Guy
 --
 View this message in context: http://n4.nabble.com/Alternatives-to-
 linear-regression-with-multiple-variables-tp1564370p1564370.html
 Sent from the R help mailing list archive at Nabble.com.
 
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 guide.html
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[R] Linear models interaction

2010-02-25 Thread gauravbhatti

My data looks like following:
cera3[i, ] batch lcl29 pdt
Untreated 3.185867 1 0   0
Untreated.4   3.185867 0 0   0
LCL29  4.357552 1 1   0
LCL29.6   3.446256 0 1   0
PDT   2.765535 1 0   1
PDT.5 3.584963 0 0   1
PDT+LCL29.1   2.867896 1 1   1
PDT+LCL29.3   2.827819 0 1   1

As you can see there are three factorls batch , lcl29 and pdt. I am trying
to fit the model: 
Y = batch +pdt*lcl29. I get the following coefficients:
Estimate Std. Errort value Pr(|t|)
(Intercept)  3.1524122  0.2487796 12.6715049 1.242191e-12
batch1  -0.2267947  0.2291590 -0.9896827 3.314508e-01
lcl291   0.6350186  0.3122910  2.0334194 5.233525e-02
pdt1 0.1046388  0.3122910  0.3350684 7.402619e-01
lcl291:pdt1 -0.6633316  0.4521381 -1.4670995 1.543419e-01

I know that the coef. of lcl291 i.e 0.635 is difference in means between
rows with lcl29 present alone and untreated ones. Same is true for the coef
of PDT1. However I am not sure about the coefficient of  lcl291:pdt1. 
where does this value come from? How is it calculated?
what does it tell? Is it Interaction versus all the rest because it is
certailnly not interaction versus untreated? 

Thank You

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Re: [R] How to fill in a region with different patterns?

2010-02-25 Thread baptiste auguie
Hi,

If you are curious you might like to try a highly experimental Grid
function I wrote some time ago,

library(grid)
source(http://gridextra.googlecode.com/svn/trunk/R/patternGrob.r;)

grid.newpage()
grid.pattern(x=seq(1/6, 5/6, length=6), width=unit(1/8,npc),
height=unit(0.5,npc),
 motif.width=unit(10, mm),  pattern=c(1:6),
orientation=45, motif.alpha=0.5,
 motif.cex=c(1, 0.5), motif.col=1:2, motif.fill=NA,
 gp=gpar(fill=blue, lwd=2, alpha=0.5),  clip=T)

If you really insist on using shading patterns despite Greg's sound
advice, it might give you some inspiration.

HTH,

baptiste


On 25 February 2010 04:34, St.Jeff Shang mathsh...@yahoo.com wrote:
 Hi to all,



 Here is a question which I cannot solve. Appreciate so much for any 
 suggestions!



 I have a squared region which is irregularly divided into many rectangular 
 patches.

 Each patch is associated with a value, and two patches possibly share a 
 common value.

 I hope to fill in each patch a pattern according to its value. For
 instance, if a patch has value 1, then I fill in that patch with
 pattern A; if it has value 2, then fill in it with pattern B,...



 The pattern is something like a rectangular region with certain colored
 lines in it. For instance, pattern A may be a white rectangular region
 filled in by two thick black lines;

 pattern B may be a white rectagular region filled in by 10 thick black 
 lines,...



 Is this available in matlab? I have serached polygnon in matlab user guide 
 and found a

 fill function may work, however, there is still a long way to finally 
 complete it.



 Many thanks again!

 Jeff



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-- 


Baptiste Auguié

Departamento de Química Física,
Universidade de Vigo,
Campus Universitario, 36310, Vigo, Spain

tel: +34 9868 18617
http://webs.uvigo.es/coloides

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Re: [R] read.table (trying one more time)

2010-02-25 Thread David Winsemius


On Feb 25, 2010, at 3:10 PM, Mestat wrote:



Hey listers,
I've posted this doubt other day... But I am still having a hard  
time...

I have a MAC and I am not getting how to use the read.table command...
At the bottom of the FINDER application I have the following path:

Macintosh HDUsuáriosUserMarcioUdeMTravail DirigéDataMU284
Population.txt

I didn't find out how I could copy and paste this path as it is  
possible to
do with the Windows. But, it's ok, cause I am trying the following  
command

with all possible choices, as below:

file-read.table(/User/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)
file-read.table(/Users/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)
file-read.table(/Usuários/User/Marcio/UdeM/Travail Dirigé/Data/MU284
Population.txt,header=T,skip=24)
file-read.table(/Usuários/Users/Marcio/UdeM/Travail Dirigé/Data/ 
MU284

Population.txt,header=T,skip=24)




I've checked already the forum and I found a similar post that says  
to use

the command with the following path: /Users/Marcio/UdeM/Travail
Dirigé/Data/MU284 Population.txt
But at the bottom of the FINDER application is just USER.
Anyway I tried those options and other... But didn't work...
If anybody could give me a clue... THANKS A LOT!!!


Two choices (and in any case, don't call your input dataframe just  
file, although that is probably not why you are having problems):


option 1) Type in:

file_inp -read.table(,header=T,skip=24)
### then click-hold-drag the file from a Finder window to the R  
console until the cursor bar is between the two quotes, then release- 
click.


optiuon 2)

file_inp-read.table(file=file.choose(),header=T,skip=24)

## and then navigate to the location of your file using the Mac File  
Chooser window.


And in the future, such questions should go to the Mac-SIG list.

--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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[R] Restructure some data

2010-02-25 Thread Doran, Harold
Suppose I have a data frame like dat below. For some context, this is the 
format that represents student's taking a computer adaptive test. first.item is 
the first item that student was administered and then score.1 is the student's 
response to that item and so forth.

item.pool - paste(item, 1:10, sep = )
set.seed(54321)
dat - data.frame(id = c(1,2,3,4,5), first.item = sample(item.pool, 5, 
replace=TRUE),
second.item = sample(item.pool, 5,replace=TRUE), third.item = 
sample(item.pool, 5,replace=TRUE),
score1 = sample(c(0,1), 5,replace=TRUE), score2 = 
sample(c(0,1), 5,replace=TRUE), score3 = sample(c(0,1), 5,replace=TRUE))

I need to restructure this into a new format. The new matrix df (after the 
loop) is exactly what I want in the end. But, I'm annoyed at myself for not 
thinking of a more efficient way to restructure this without using a loop.

df - matrix(NA, ncol = length(item.pool), nrow = nrow(dat))
colnames(df) - unique(item.pool)

for(i in 1:5){
for(j in 2:4){
rr - which(dat[i,j] == colnames(df))
df[i,rr] - dat[i, (j+3)]
}
}

Any thoughts?

Harold

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Re: [R] How to add a title to represent four different plot in lm function

2010-02-25 Thread Tal Galili
Hi there,

Try this:

par(mfrow=c(2,2))
for( i in 1:4 ) plot(1:10)
mtext(Title,side=3,outer=TRUE,padj=3)






Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
--




On Thu, Feb 25, 2010 at 10:43 PM, Greg Snow greg.s...@imail.org wrote:

 Try something like:

  par(oma=c(0,0,3,0))
 your plotting commands here
  mtext(your text here, outer=TRUE

 Hope this helps,

 --
 Gregory (Greg) L. Snow Ph.D.
 Statistical Data Center
 Intermountain Healthcare
 greg.s...@imail.org
 801.408.8111


  -Original Message-
  From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
  project.org] On Behalf Of FMH
  Sent: Thursday, February 25, 2010 9:01 AM
  To: r-help@r-project.org
  Cc: r-sig...@stat.math.ethz.ch
  Subject: [R] How to add a title to represent four different plot in lm
  function
 
  Dear All,
 
  A linear regression model could be fitted by using lm function and the
  plot function can be used to check the assumptions of the model. The
  example is as followed.
 
  require(graphics)
  ## Annette Dobson (1990) An Introduction to Generalized Linear
  Models.
  ## Page 9: Plant Weight Data.
  ctl - c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)
  trt - c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
  group - gl(2,10,20, labels=c(Ctl,Trt))
  weight - c(ctl, trt)
  anova(lm.D9 - lm(weight ~ group))
  opar - par(mfrow = c(2,2), oma = c(0, 0, 1.1, 0))
  plot(lm.D9, las = 1)
 
  Could someone advice me the way to add a single title either at the
  above or bottom of these 4 plots, entitled The verification of model
  assumtion via four different plots ?
 
  Thanks
  Fir
 
 
 
 
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