[R] Multi-Level classification
Hi, Thanks in advance. I am using R-3.0.1 on Windows XP. May I request you to assist me for the following please. I have a data set where each instance has two or more levels. As for example, level 1 (binary): 0, 1; level 2 (binary): 0, 1 and so on. These levels are target variables. The predictor variables may be numeric / factor /... / mixed. I am looking for models to analyse the data. Is there any R-package(s) / R-code(s) / any others to solve Multi-Level classification problems? I am looking for some literature also. Once again, thank you very much for the time you have given. Regards, Deb [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Reading shape files in R
Hi everyone, I am new with spatial data analysis in R and I'm not able to read a shape because of this error message but the shapefile is in my work directory. Here are my commands; ogrListLayers(border.shp), border=readOGR(border.shp,border). What does it mean?. Any help? Error in file(paste(dsn, .Platform$file.sep, layer, .dbf, sep = ), : cannot open the connection In addition: Warning message: In file(paste(dsn, .Platform$file.sep, layer, .dbf, sep = ), : cannot open file 'border.shp/border.dbf': No such file or directory Alexand Msc.agriScs [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] passing of arguments to R CMD BATCH in bash script that is submitted to torque (Linux platform)
Dear all I want to call R repeatedly in batch mode from a bash script that is then submitted to torque. My calls to R depend on optional arguments. When I introduce these arguments as literals, the calls work fine, for instance: R CMD BATCH --no-save --args PERIOD='08' YEAR='2008' SC='BAU' preparecostvectors.R However, the arguments PERIOD, YEAR and SC are really variables over which I 'loop'. When these variables are defined in the same script as the call to R CMD BATCH, this still works, for instance: year=2008 sc=BAU R CMD BATCH --no-save --args PERIOD='08' YEAR=\$year\ SC=\$sc\ preparecostvectors.R Things go wrong when the script is called from another script, for instanced with: qsub -v year=2008,sc=BAU ATLAS_assign.sh echo $sc and echo $year in ATLAS_assign.sh yield BAU and 2008 respectively. Thus, as far as I can see, nothing goes wrong in the passing of the optional arguments in qsub. However, R CMD BATCH --no-save --args PERIOD='08' YEAR=\$year\ SC=\$sc\ preparecostvectors.R is not executed. I do not get even an Rout file, so I suppose the R script is not even called. I suppose there is something wrong in the format in which I submit year and sc, but I do not see what. Laurent Franckx, PhD VITO NV Boeretang 200, 2400 MOL, Belgium Tel. + 32 14 33 58 22 Skype: laurent.franckx laurent.fran...@vito.be Visit our website: www.vito.be/english and http://www.vito.be/transport [http://www.vito.be/e-maildisclaimer/vito.png] Ontdek hoe VITO de transitie naar een duurzame maatschappij op gang trekt: www.vito.be/duurzaamheidsverslag2012http://www.vito.be/duurzaamheidsverslag2012 Discover how VITO initiates the transition towards a sustainable society: www.vito.be/sustainabilityreport2012http://www.vito.be/sustainabilityreport2012 VITO Disclaimer: http://www.vito.be/e-maildisclaimer __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Trouble sorting the matrix
I would like to sort matrix3, so that every column in output matrix is
sorted. Also I have to unsort it later on.
matrix1-matrix(rnorm(100,354,78),ncol=10)
matrix2-matrix(rnorm(100,225,102),ncol=10)
matrix3-cbind(matrix1,matrix2)
nrCol-length(matrix3[1,])
class1-1:10
for(i in 1:nrCol)
{
sorted.matrix-matrix3[order(matrix3[class1,i]),]
}
for(i in 1:liczbaKolumn)
{
output-sorted.matrix[order(matrix3[class1,i]),]
}
--
Aleksandra Cabaj
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trouble sorting the matrix
Hi. Here is an example of sorting matrix columns:
mat - matrix(10:1, ncol=2, byrow=TRUE)
mat
[,1] [,2]
[1,] 109
[2,]87
[3,]65
[4,]43
[5,]21
apply(mat, 2, function(x) x[order(x)])
[,1] [,2]
[1,]21
[2,]43
[3,]65
[4,]87
[5,] 109
You should read help page [, apply and order (?[, ?apply, ?order)
Hope this helps
Andrija
On Sat, Jun 15, 2013 at 12:36 PM, Ola Cabaj olaca...@gmail.com wrote:
I would like to sort matrix3, so that every column in output matrix is
sorted. Also I have to unsort it later on.
matrix1-matrix(rnorm(100,354,78),ncol=10)
matrix2-matrix(rnorm(100,225,102),ncol=10)
matrix3-cbind(matrix1,matrix2)
nrCol-length(matrix3[1,])
class1-1:10
for(i in 1:nrCol)
{
sorted.matrix-matrix3[order(matrix3[class1,i]),]
}
for(i in 1:liczbaKolumn)
{
output-sorted.matrix[order(matrix3[class1,i]),]
}
--
Aleksandra Cabaj
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Error: cannot allocate vector of size 1.9 Gb when loading xtable help
On 13-06-14 7:02 PM, Dan Keshet wrote: I am using xtable version 1.7-1 built for R 3.0.1 on: R version 3.0.1 (2013-05-16) Platform: i686-pc-linux-gnu (32-bit) Sometimes, not every time, when I load xtable or attempt to load the help, I get an error such as this Error: cannot allocate vector of size 1.9 Gb (Stacktrace from recover() below). Other times, when loading packages that depend on xtable, I get an error such as this: Loading required namespace: xtable Error in assign(identifier, list(name, description, identifier, help, : lazy-load database 'P' is corrupt I have attempted to reinstall the package using install.packages(xtable, type=source), but the error persists (and the xtable.rdb file is identical). I have also tried this on macs and gotten the same error. Thank you for any help. - ?xtable Error: cannot allocate vector of size 1.9 Gb I would guess this is not related to the xtable help page, but is a sign of something being corrupted (e.g. an out of range write in memory), and this is just a symptom of the corruption. If we could make this reliably reproducible, we could track it down, but without that, it is nearly impossible. Could try starting an empty R session (nothing reloaded from .Rdata), run until you trigger the error, then save the session history? See if replaying that history triggers the error again in the same place. If so, see if you can shrink it to a minimal script that others can try, and post that. Duncan Murdoch Enter a frame number, or 0 to exit 1: print(/usr/local/analytics/rlibs/xtable/help/xtable) 2: print.help_files_with_topic(/usr/local/analytics/rlibs/xtable/help/xtable 3: tools::Rd2txt(.getHelpFile(file), out = tempfile(Rtxt), package = pkgname 4: prepare_Rd(Rd, defines = defines, stages = stages, fragment = fragment, ... 5: .getHelpFile(file) 6: tools:::fetchRdDB(RdDB, basename(file)) 7: lazyLoadDBexec(filebase, fun) 8: fun(environment()) 9: fetch(key) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R session freezes when I try to save a new script
On 13-06-14 10:52 AM, anferg...@aol.com wrote: All: Recently my R session freezes when I try to open a file or save a new script after I have run existing scripts. The session freezes so that I can no longer click on any windows within the R session -- including other scripts that are open or the R console. (I hear the ding sound when I try to click on anything.) I have looked at the Task Manager on the computer and R is still running (and is still responsive according to the Task Manager), but I cannot do anything within R. I have tried pressing Esc and that does not help. Any suggestions would be greatly appreciated! I am using a 32 bit Windows 7 computer with 4gb ram and 250gb hard drive. Thanks in advance for any suggestions! I have sometimes seen symptoms like that when an open file dialog gets hidden behind another window. R is waiting for the dialog to complete, but since it is hidden, it never does. Generally it pops up eventually; I'm not sure why it is allowed to be hidden at all. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trouble sorting the matrix
Hello,
If I understand it correctly, the following should sort all columns of
matrix3 and then unsort the sorted matrix.
ord - apply(matrix3, 2, order)
# sort matrix3
mat4 - sapply(seq_len(ncol(ord)), function(i) matrix3[ord[,i], i])
mat4
# unsort mat4
mat5 - sapply(seq_len(ncol(ord)), function(i) mat4[order(ord[,i]), i])
identical(matrix3, mat5) # TRUE
Hope this helps,
Rui Barradas
Em 15-06-2013 11:36, Ola Cabaj escreveu:
I would like to sort matrix3, so that every column in output matrix is
sorted. Also I have to unsort it later on.
matrix1-matrix(rnorm(100,354,78),ncol=10)
matrix2-matrix(rnorm(100,225,102),ncol=10)
matrix3-cbind(matrix1,matrix2)
nrCol-length(matrix3[1,])
class1-1:10
for(i in 1:nrCol)
{
sorted.matrix-matrix3[order(matrix3[class1,i]),]
}
for(i in 1:liczbaKolumn)
{
output-sorted.matrix[order(matrix3[class1,i]),]
}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trouble sorting the matrix
Hello,
Yes, you can do it like you say. Or you can unsort first and multiply later.
mat5.1 - sapply(seq_len(ncol(ord)), function(i) mat4[order(ord[,i]), i])
multip-mat4*2
mat5.2 - sapply(seq_len(ncol(ord)), function(i) multip[order(ord[,i]), i])
identical(mat5.1*2, mat5.2) #TRUE
Also, it's better if you Cc the list, for others to read and eventually
find it of some use.
Rui Barradas
Em 15-06-2013 12:48, Ola Cabaj escreveu:
Thanks, that helps a lot! I got another question, if you don't mind.
If I would like to multiply mat4 by a number/vector
multip-mat4*2
so to unsort this multiplied matrix I have to change mat4 to multip?
mat5 - sapply(seq_len(ncol(ord)), function(i) multip[order(ord[,i]), i])
2013/6/15 Rui Barradas ruipbarra...@sapo.pt mailto:ruipbarra...@sapo.pt
Hello,
If I understand it correctly, the following should sort all columns
of matrix3 and then unsort the sorted matrix.
ord - apply(matrix3, 2, order)
# sort matrix3
mat4 - sapply(seq_len(ncol(ord)), function(i) matrix3[ord[,i], i])
mat4
# unsort mat4
mat5 - sapply(seq_len(ncol(ord)), function(i) mat4[order(ord[,i]), i])
identical(matrix3, mat5) # TRUE
Hope this helps,
Rui Barradas
Em 15-06-2013 11:36, Ola Cabaj escreveu:
I would like to sort matrix3, so that every column in output
matrix is
sorted. Also I have to unsort it later on.
matrix1-matrix(rnorm(100,354,__78),ncol=10)
matrix2-matrix(rnorm(100,225,__102),ncol=10)
matrix3-cbind(matrix1,__matrix2)
nrCol-length(matrix3[1,])
class1-1:10
for(i in 1:nrCol)
{
sorted.matrix-matrix3[order(__matrix3[class1,i]),]
}
for(i in 1:liczbaKolumn)
{
output-sorted.matrix[order(__matrix3[class1,i]),]
}
--
Aleksandra Cabaj
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Plotting two y-axis vs non-numeric x-axis
Hi dear all, the following code is correct. but I want to use non-numeric x-axis, for example if I replace time - seq(0,72,6) by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) Ofcourse I use factor(month) instead of time; but I didn't get similar plot as the example shown. any help is greatful ;) month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(factor(month), music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(factor(month), actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(month),10)) mtext(Month,side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] GGally installation problems
On 12.06.2013 15:08, Tim Smith wrote: Hi, I was trying to install the GGally package, but was getting errors. Here is what I get: install.packages(GGally) Installing package(s) into ‘/Users/ts2w/Library/R/2.15/library’ (as ‘lib’ is unspecified) Warning in install.packages :  package ‘GGally’ is not available (for R version 2.15.2) install.packages(GGally,repos=http://cran-r.project.org;) Wrong repository: http://cran-r.project.org; - http://cran.r-project.org; ? uwe ligges Installing package(s) into ‘/Users/ts2w/Library/R/2.15/library’ (as ‘lib’ is unspecified) Warning in install.packages :  cannot open: HTTP status was '404 Not Found' Warning in install.packages :  cannot open: HTTP status was '404 Not Found' Warning in install.packages :  unable to access index for repository http://cran-r.project.org/src/contrib Warning in install.packages :  package ‘GGally’ is not available (for R version 2.15.2) Warning in install.packages :  cannot open: HTTP status was '404 Not Found' Warning in install.packages :  cannot open: HTTP status was '404 Not Found' Warning in install.packages :  unable to access index for repository http://cran-r.project.org/bin/macosx/leopard/contrib/2.15 thanks. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Widows 8
Can anyone confirm that R runs on Widows 8? Thanks, Chet Seligman [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Widows 8
Seems unlikely but it runs on Windows 8 John Kane Kingston ON Canada -Original Message- From: chet.selig...@gmail.com Sent: Sat, 15 Jun 2013 07:50:45 -0700 To: r-help@r-project.org Subject: [R] Widows 8 Can anyone confirm that R runs on Widows 8? Thanks, Chet Seligman [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks orcas on your desktop! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Widows 8
On Sat, 15 Jun 2013, Chet Seligman wrote: Can anyone confirm that R runs on Widows 8? You can : http://lmgtfy.com/?q=site%3Astat.ethz.ch+%22windows+8%22 Thanks, Chet Seligman [[alternative HTML version deleted]] Please read the Posting Guide, and asi it requests post in plain text. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Widows 8
confirmed. On Sat, Jun 15, 2013 at 10:50 AM, Chet Seligman chet.selig...@gmail.comwrote: Can anyone confirm that R runs on Widows 8? Thanks, Chet Seligman [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- == WenSui Liu Credit Risk Manager, 53 Bancorp wensui@53.com 513-295-4370 == [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] A strange issue with GSub
Greetings, Apologies if this turns out to be a very silly question, but because I am the only person learning/using R at my workplace, I have no choice but to ask folks here. I have been using Gsub to change some expressions in my Corpus object. After applying the gsub function, say newCorpus- gsub(game,war,newCorpus, fixed=TRUE) an object of class character is returned by the gsub function, as is understandable, like so: [1] this is the text of the 1st document[1000] this is the text of the 1000th document. However, all such text is enclosed as such: [1] c(\this is the text of the 1st document.\, \\\a\) ...[1000] c(\this is the text of the 1000th document.\, \\\a\) The worst part is that I tried recreating the problem with another example to post here, but I face no such problem with the example. So, after banging my head against the computer for two days now, I still remain clueless as to why this is happening. I was wondering if somebody had an explanation to why this happens? That will be very helpful. The only thing I can think of is that I had initially converted MS word documents into txt files, and then imported them using R's plain text reader. Could this be the issue? Thanks. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Plotting two y-axis vs non-numeric x-axis
On Jun 15, 2013, at 5:18 AM, Birdada Simret wrote: Hi dear all, the following code is correct. but I want to use non-numeric x-axis, for example if I replace time - seq(0,72,6) by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) Ofcourse I use factor(month) instead of time; but I didn't get similar plot as the example shown. any help is greatful ;) We are not seeing any example. Please read the documentation for the Rhelp mailing list more carefully. The information about attachments may not be in the PostingGuide but instead in the listinfo page. (I for one do not understand what you are requesting.) month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(factor(month), music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(factor(month), actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(month),10)) mtext(Month,side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) [[alternative HTML version deleted]] -- David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] A strange issue with GSub
On Jun 15, 2013, at 7:46 AM, Ali Arslan Kazmi wrote: Greetings, Apologies if this turns out to be a very silly question, but because I am the only person learning/using R at my workplace, I have no choice but to ask folks here. I have been using Gsub to change some expressions in my Corpus object. After applying the gsub function, say newCorpus- gsub(game,war,newCorpus, fixed=TRUE) an object of class character is returned by the gsub function, as is understandable, like so: [1] this is the text of the 1st document[1000] this is the text of the 1000th document. However, all such text is enclosed as such: [1] c(\this is the text of the 1st document.\, \\\a\) ...[1000] c(\this is the text of the 1000th document.\, \\\a\) The worst part is that I tried recreating the problem with another example to post here, but I face no such problem with the example. So, after banging my head against the computer for two days now, I still remain clueless as to why this is happening. I was wondering if somebody had an explanation to why this happens? That will be very helpful. The only thing I can think of is that I had initially converted MS word documents into txt files, and then imported them using R's plain text reader. Could this be the issue? Thanks. [[alternative HTML version deleted]] You are misspelling the gsub function name. You are not describing your process with enough detail to replicate it. You are using packages that you are not naming. I suspect you are using gsub with an item of a class for which it was never intended. Consider this: mydf - data.frame(a=c(this is a test, another test), b=c(athird, a fourth)) gsub(test,tester, mydf) [1] c(2, 1) c(2, 1) Please read the Posting Guide. Please make your example reproducible. -- David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Plotting two y-axis vs non-numeric x-axis
Hi, You could use ?twoord.plot() from library(plotrix): library(plotrix) dat2- data.frame(month,music,actor) dat2$month- factor(month,labels=c(month.abb,Pag)) dat2New-dat2[order(dat2$month),] with(dat2New,twoord.plot(month,music,actor, lylim=c(0,1),rylim=c(0,13000), ylab=Music, rylab=Actor,main=Enjoy, type=c(p,b),lcol=1,rcol=red,xtickpos=month,xticklab=month)) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),col=c(black,red)) #I tried to change the plotting symbol using pch inside the twoord.plot(), but it seems to be not working. with(dat2New,twoord.plot(month,music,actor, lylim=c(0,1),rylim=c(0,13000), ylab=Music, rylab=Actor,main=Enjoy, type=c(p,b),pch=c(1,4),lcol=1,rcol=red,xtickpos=month,xticklab=month)) #Error in localWindow(xlim, ylim, log, asp, ...) : # formal argument pch matched by multiple actual arguments A.K. - Original Message - From: Birdada Simret birdad...@gmail.com To: r-help@r-project.org Cc: Sent: Saturday, June 15, 2013 8:18 AM Subject: [R] Plotting two y-axis vs non-numeric x-axis Hi dear all, the following code is correct. but I want to use non-numeric x-axis, for example if I replace time - seq(0,72,6) by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) Ofcourse I use factor(month) instead of time; but I didn't get similar plot as the example shown. any help is greatful ;) month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(factor(month), music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(factor(month), actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(month),10)) mtext(Month,side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] transform summary table list to summary table (for .csv output)
Hi,
You could try this:
#In one of the list element
SampleSummary$ConcLow
# Min. 1st Qu. Median Mean 3rd Qu. Max. NA's
# 0.4200 0.6100 0.7300 0.7373 0.8150 1.6600 1
#additional entry for NA. You may need to check the data and remove the
missing value. Here, I removed that entry.
library(stringr)
res-data.frame(lapply(SampleSummary,function(x)
{x1-x[names(x)!=NA's];Nch1-max(nchar(names(x1)));x2-str_pad(names(x1),Nch1,side=right,pad=
);paste(x2,x1,sep=:) }),stringsAsFactors=FALSE)
res1-as.table(as.matrix(res))
dimnames(res1)[[1]]-rep(,nrow(res1))
str(res1)
# 'table' chr [1:6, 1:17] Min. :1995-10-10 1st Qu.:1996-06-16 ...
# - attr(*, dimnames)=List of 2
# ..$ : chr [1:6] ...
# ..$ : chr [1:17] Date ConcLow ConcHigh Uncen ...
str(summarySample)
# 'table' chr [1:6, 1:17] Min. :2002-05-23 1st Qu.:2002-09-02 ...
# - attr(*, dimnames)=List of 2
# ..$ : chr [1:6] ...
# ..$ : chr [1:17] Date ConcLow ConcHigh Uncen ...
summarySample[,1:3]
# Date ConcLow ConcHigh
# Min. :2002-05-23 Min. :0.5800 Min. :0.5800
# 1st Qu.:2002-09-02 1st Qu.:0.7525 1st Qu.:0.7525
# Median :2003-01-07 Median :0.7800 Median :0.7800
# Mean :2003-01-16 Mean :0.8100 Mean :0.8100
# 3rd Qu.:2003-05-29 3rd Qu.:0.9025 3rd Qu.:0.9025
# Max. :2003-09-04 Max. :1.0900 Max. :1.0900
res1[,1:3]
# Date ConcLow ConcHigh
# Min. :1995-10-10 Min. :0.42 Min. :0.27
# 1st Qu.:1996-06-16 1st Qu.:0.61 1st Qu.:0.605
# Median :1996-12-10 Median :0.73 Median :0.7275
# Mean :1998-01-08 Mean :0.7373 Mean :0.7322
# 3rd Qu.:1998-03-12 3rd Qu.:0.815 3rd Qu.:0.8125
# Max. :2003-09-04 Max. :1.66 Max. :1.66
#There is some space on the right for each column of summarySample. Not sure
if you wanted that in res1.
A.K.
Hi, I have a R object called Sample which I am obtaining the summary
table for through 2 methods: summarySample - summary(Sample)
SampleSummary - lapply(Sample, summary). I would like to transform
the results of lapply(Sample, summary) into the same format as
summary(Sample). I have included dput for both summary results. After I
obtain the summary results I am exporting the table to a .csv and I
would like both .csv files to be similarly formatted; however, I am not
able to do that now. I have searched online for assistance, but I have
not been successful yet.
Thank you.
Irucka Embry
summarySample
dput(summarySample)
structure(c(Min. :2002-05-23 , 1st Qu.:2002-09-02 , Median :2003-01-07
,
Mean :2003-01-16 , 3rd Qu.:2003-05-29 , Max. :2003-09-04 ,
Min. :0.5800 , 1st Qu.:0.7525 , Median :0.7800 , Mean :0.8100 ,
3rd Qu.:0.9025 , Max. :1.0900 , Min. :0.5800 , 1st Qu.:0.7525 ,
Median :0.7800 , Mean :0.8100 , 3rd Qu.:0.9025 , Max. :1.0900 ,
Min. :1 , 1st Qu.:1 , Median :1 , Mean :1 , 3rd Qu.:1 ,
Max. :1 , Min. :0.5800 , 1st Qu.:0.7525 , Median :0.7800 ,
Mean :0.8100 , 3rd Qu.:0.9025 , Max. :1.0900 , Min. :55659 ,
1st Qu.:55762 , Median :55888 , Mean :55898 , 3rd Qu.:56031 ,
Max. :56128 , Min. : 2 , 1st Qu.: 5 , Median : 7 ,
Mean : 7 , 3rd Qu.: 9 , Max. :12 , Min. : 35.0 ,
1st Qu.:142.5 , Median :201.5 , Mean :199.3 , 3rd Qu.:247.2 ,
Max. :345.0 , Min. :2002 , 1st Qu.:2003 , Median :2003 ,
Mean :2003 , 3rd Qu.:2003 , Max. :2004 , Min. :1829 ,
1st Qu.:1833 , Median :1837 , Mean :1837 , 3rd Qu.:1841 ,
Max. :1845 , Min. :-0.9670 , 1st Qu.:-0.8075 , Median :-0.2531
,
Mean :-0.1224 , 3rd Qu.: 0.5788 , Max. : 0.9906 ,
Min. :-0.9917 , 1st Qu.:-0.7986 , Median :-0.5209 ,
Mean :-0.3123 , 3rd Qu.: 0.1663 , Max. : 0.9327 ,
Min. :0.1189 , 1st Qu.:0.5154 , Median :1.3734 , Mean :1.6672 ,
3rd Qu.:2.6618 , Max. :5.7483 , Min. :-2.12921 ,
1st Qu.:-0.71031 , Median : 0.30516 , Mean : 0.02173 ,
3rd Qu.: 0.97834 , Max. : 1.74891 , Min. :-0.4057 ,
1st Qu.:-0.2986 , Median :-0.2131 , Mean :-0.2022 ,
3rd Qu.:-0.1459 , Max. : 0.0798 , Min. :0.02030 ,
1st Qu.:0.03857 , Median :0.06197 , Mean :0.06628 ,
3rd Qu.:0.08225 , Max. :0.17336 , Min. :0.6766 ,
1st Qu.:0.7432 , Median :0.8117 , Mean :0.8259 , 3rd Qu.:0.8646 ,
Max. :1.0838 ), .Dim = c(6L, 17L), .Dimnames = list(c(,
, , , , ), c( Date, ConcLow, ConcHigh,
Uncen, ConcAve, Julian, Month, Day,
DecYear, MonthSeq, SinDY, CosDY, Q,
LogQ, yHat, SE, ConcHat)), class = table)
SampleSummary
dput(SampleSummary)
structure(list(Date = structure(c(9413, 9663, 9840, 10234.0652174,
10297.75, 12299), .Names = c(Min., 1st Qu., Median, Mean,
3rd Qu., Max.), class = c(summaryDefault, table, Date
)), ConcLow = structure(c(0.42, 0.61, 0.73, 0.7373, 0.815, 1.66,
1), .Names = c(Min., 1st Qu.,
Re: [R] Windows R_LIBS_USER confusion under R-3.0.1
On 12.06.2013 16:35, Paul Johnson wrote: I would appreciate ideas about MS Windows install issues. I'm at our stats summer camp and have been looking at a lot of Windows R installs and there are some wrinkles about R_LIBS_USER. On a clean Win7 or Win8 system, with R-3.0.1, we see the user library for packages defaulting to $HOME/R/win-library. I think that's awesome, the way it should be. Yea! But it does not appear that way on all systems, and I think it is because of lingering after-effects of previous R installs. In previous versions of R, R_LIBS_USER defaulted to $HOME/AppData/Roaming/... That was not so great because it was (default) hidden to the students and they were disoriented about how something that does not exist (or show) could hold packages. Aside from teaching them how to configure the file manager, we could navigate that. The problem is that with R-3.0.1, sometimes we are seeing the user package installs going into $HOME/AppData/Roaming/ In the user account, there is no $HOME/.Rprofile or $HOME/.Renviron. I hate to tell non-expert users that they ought to go fishing in the Windows registry, but I'm starting to suspect that is what they ought to do. What do you think? There is nothing in the registry, but maybe some startup file in the current working directory? Some declaration of environment variables somewhere else? Best, Uwe Ligges PJ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Calculate days with R
Hi, May be this helps: dat1- read.table(text= pbnr dat dep dys sop ago mis age female 1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 ,sep=,header=TRUE,stringsAsFactors=FALSE) dat1$dat- as.Date(dat1$dat) with(dat1,tapply(dat,list(pbnr),FUN=diff)) #10023 10028 10053 # 93 1809 191 library(plyr) ddply(dat1,.(pbnr),mutate,Datediff=diff(dat)) # pbnr dat dep dys sop ago mis age female Datediff #1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 93 #2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 93 #3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 1809 #4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 1809 #5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 191 #6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 191 #or dat2-aggregate(dat~pbnr,data=dat1,diff) colnames(dat2)[2]- Datediff join(dat1,dat2,by=pbnr) # pbnr dat dep dys sop ago mis age female Datediff #1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 93 #2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 93 #3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 1809 #4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 1809 #5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 191 #6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 191 A.K. Hi, I am new to this forum, and have a problem. I have data that looks like this: pbnr dat dep dys sop ago mis age female 1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 . And I want to know how many days each person (pbnr) has been in therapy. row 1 is first a date for person 10023 and row 2 the second but what do I do now Thanks for you help!! Sophie __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] [igraph] Counting edges for each vertex
Hi all,
I'm analysing an e-mail network. I loaded the following information in a
directed igraph:
*Vertex* types: person, e-mail
V(g)[ type == person ]
V(g)[ type == email ]
*Edge* types: sends, receives
E(g)[ type == send ]
E(g)[ type == receive ]
So for example:
John --send-- email1 --receive-- Mary
John --send-- email2 --receive-- Mary
Mary --send-- email3 --receive-- John
I would like to generate a summary of the e-mail activity, with edges with
an attribute representing the number of emails:
John --2-- Mary
Mary --1-- John
I tried to do this, but I haven't figured it out yet.
I managed to get in/out edges for each letter, but then I don't know what to
do to hold a count.
lapply(V(g)[type==email],
function(e){
outedges = V(g) [ from(e) ]
print(outedges)
inedges = V(g) [ to(e) ]
print(inedges)
})
I just started using igraph, and I find even basic operations quite
difficult to carry out. :-/
How would I go about to do that?
Thanks,
Mulone
--
View this message in context:
http://r.789695.n4.nabble.com/igraph-Counting-edges-for-each-vertex-tp4669613.html
Sent from the R help mailing list archive at Nabble.com.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Plotting two y-axis vs non-numeric x-axis
Thank you. @David: The example is exactly this: time - seq(0,72,6) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(time, music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(time, actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(time),10)) mtext(Time (Hours),side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) Now, what if time is replaced by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) when I tried I got error like In pretty.default(range(month), 10) : NAs introduced by coercion I am newbie to R ;) many thanks @Arun, It is really helpful, thank you. though only the red marked plot is perfectly shown. On Sat, Jun 15, 2013 at 6:20 PM, arun smartpink...@yahoo.com wrote: Hi, You could use ?twoord.plot() from library(plotrix): library(plotrix) dat2- data.frame(month,music,actor) dat2$month- factor(month,labels=c(month.abb,Pag)) dat2New-dat2[order(dat2$month),] with(dat2New,twoord.plot(month,music,actor, lylim=c(0,1),rylim=c(0,13000), ylab=Music, rylab=Actor,main=Enjoy, type=c(p,b),lcol=1,rcol=red,xtickpos=month,xticklab=month)) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),col=c(black,red)) #I tried to change the plotting symbol using pch inside the twoord.plot(), but it seems to be not working. with(dat2New,twoord.plot(month,music,actor, lylim=c(0,1),rylim=c(0,13000), ylab=Music, rylab=Actor,main=Enjoy, type=c(p,b),pch=c(1,4),lcol=1,rcol=red,xtickpos=month,xticklab=month)) #Error in localWindow(xlim, ylim, log, asp, ...) : # formal argument pch matched by multiple actual arguments A.K. - Original Message - From: Birdada Simret birdad...@gmail.com To: r-help@r-project.org Cc: Sent: Saturday, June 15, 2013 8:18 AM Subject: [R] Plotting two y-axis vs non-numeric x-axis Hi dear all, the following code is correct. but I want to use non-numeric x-axis, for example if I replace time - seq(0,72,6) by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) Ofcourse I use factor(month) instead of time; but I didn't get similar plot as the example shown. any help is greatful ;) month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(factor(month), music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(factor(month), actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(month),10)) mtext(Month,side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Plotting two y-axis vs non-numeric x-axis
On Jun 15, 2013, at 11:14 AM, Birdada Simret wrote: Thank you. @David: The example is exactly this: time - seq(0,72,6) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(time, music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(time, actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(time),10)) mtext(Time (Hours),side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) Now, what if time is replaced by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) when I tried I got error like In pretty.default(range(month), 10) : NAs introduced by coercion I am newbie to R ;) many thanks Er, Not really. The error was the line above that warning: Error in plot.window(...) : need finite 'xlim' values In addition: Warning messages: 1: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 2: In min(x) : no non-missing arguments to min; returning Inf 3: In max(x) : no non-missing arguments to max; returning -Inf You are sending a character vector to plot() as the first argument, and plotting dispatch system cannot find a 'plot.character' method so it sends it to 'plot.default' which is expecting a numeric vector for x and things all fall apart from there. You could use: seq_along(month) # instead of month (And obviously the xlab would need to be changed, since you are no longer working with Hours.) And. Please learn to post in plain text. -- David @Arun, It is really helpful, thank you. though only the red marked plot is perfectly shown. On Sat, Jun 15, 2013 at 6:20 PM, arun smartpink...@yahoo.com wrote: Hi, You could use ?twoord.plot() from library(plotrix): library(plotrix) dat2- data.frame(month,music,actor) dat2$month- factor(month,labels=c(month.abb,Pag)) dat2New-dat2[order(dat2$month),] with(dat2New,twoord.plot(month,music,actor, lylim=c(0,1),rylim=c(0,13000), ylab=Music, rylab=Actor,main=Enjoy, type=c(p,b),lcol=1,rcol=red,xtickpos=month,xticklab=month)) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),col=c(black,red)) #I tried to change the plotting symbol using pch inside the twoord.plot(), but it seems to be not working. with(dat2New,twoord.plot(month,music,actor, lylim=c(0,1),rylim=c(0,13000), ylab=Music, rylab=Actor,main=Enjoy, type=c(p,b),pch=c(1,4),lcol=1,rcol=red,xtickpos=month,xticklab=month)) #Error in localWindow(xlim, ylim, log, asp, ...) : # formal argument pch matched by multiple actual arguments A.K. - Original Message - From: Birdada Simret birdad...@gmail.com To: r-help@r-project.org Cc: Sent: Saturday, June 15, 2013 8:18 AM Subject: [R] Plotting two y-axis vs non-numeric x-axis Hi dear all, the following code is correct. but I want to use non-numeric x-axis, for example if I replace time - seq(0,72,6) by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) Ofcourse I use factor(month) instead of time; but I didn't get similar plot as the example shown. any help is greatful ;) month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(factor(month), music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(factor(month), actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(month),10)) mtext(Month,side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) [[alternative HTML version deleted]] David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Downloading CSV file - RCurl help
There are some CSV file from the link below. I'm having trouble installing the package. Is this the package I have to use or is there another one I need to use? If so how do I get this one loaded. https://www.enmax.com/Power/Energy+Retailers/Settlement+Reports/Profile+settlement+report.htm install.packages(RCurl, repos = http://cran.r-project.org/bin/windows/contrib/r-release/RCurl_1.95-4.1.zip;, type=source) Installing package into ‘C:/Users/James/Documents/R/win-library/3.0’ (as ‘lib’ is unspecified) Warning: unable to access index for repository http://cran.r-project.org/bin/windows/contrib/r-release/RCurl_1.95-4.1.zip/src/contrib Warning message: package ‘RCurl’ is not available (for R version 3.0.1) -- View this message in context: http://r.789695.n4.nabble.com/Downloading-CSV-file-RCurl-help-tp4669616.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Downloading CSV file - RCurl help
On Jun 15, 2013, at 11:41 AM, jcrosbie wrote: There are some CSV file from the link below. I'm having trouble installing the package. Is this the package I have to use or is there another one I need to use? If so how do I get this one loaded. https://www.enmax.com/Power/Energy+Retailers/Settlement+Reports/Profile+settlement+report.htm install.packages(RCurl, repos = http://cran.r-project.org/bin/windows/contrib/r-release/RCurl_1.95-4.1.zip;, type=source) Packages of type=source are not generally distributed as zip files. So R is unable to find it in the CRAN source directory. If you do want source you will also need RTools. But why not install as a binary file? Installing package into ‘C:/Users/James/Documents/R/win-library/3.0’ (as ‘lib’ is unspecified) Warning: unable to access index for repository http://cran.r-project.org/bin/windows/contrib/r-release/RCurl_1.95-4.1.zip/src/contrib Warning message: package ‘RCurl’ is not available (for R version 3.0.1) -- David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] quick Help needed
Hi, i am new to this forum and not sure how it works, I am trying to do deskriptive descripe my data in terms of gender: head(scltotal) pbnrdat dep dys sop ago mis age female messpunkt2 messpunkt1 tage eintrittsjahr 1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 8817 88170 1994 2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 8910 8817 93 1994 3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 8797 87970 1994 4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 10606 8797 1809 1999 5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 8840 88400 1994 6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 9031 8840 191 1994 so female is either 0 or 1 I assume 0 is male and 1 is female. And I want to look at dep, dys, sop, ago and mis how they are in terms of gender (female or male) I have no clue what to do :-( thanks for your help sophie [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How can make loop more faster?
Dear expert,
How can I make follow codematrix function more faster?
top20.dat - top20.dat[,7:length(top20.dat[1,])]
top40.dat -
read.table(top40snps.ped,header=F,sep=\t,stringsAsFactors=F)
row.names(top40.dat) - top40.dat[,1]
top40.dat - top40.dat[,7:length(top40.dat[1,])]
codematrix - function(dat)
{
new.dat - dat
for(col in 1:length(dat[1,]))
{
tbl - table(dat[,col])
max.allel - names(which(tbl==max(table(dat[,col]
for(row in 1:length(dat[,1]))
{
if(dat[row,col]==0 0)
{
new.dat[row,col]=NA
}else{
if(dat[row,col]==max.allel) {
new.dat[row,col]=0
}else{
allele - unlist(strsplit(
as.character(dat[row,col]), ))
if(allele[1]==allele[2]){
new.dat[row,col]=2
}else{
new.dat[row,col]=1
}
}
}
}
#})
cat(paste(col, ,sep=))
}
return(new.dat)
}
code.top20 - codematrix(top20.dat)
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Re: [R] quick Help needed
table(scltotal$female,scltotal$dys) Best Regards, Bhupendrasinh Thakre Sent from my iPad On Jun 15, 2013, at 3:58 PM, Sophie Homeyer sophie.home...@googlemail.com wrote: Hi, i am new to this forum and not sure how it works, I am trying to do deskriptive descripe my data in terms of gender: head(scltotal) pbnrdat dep dys sop ago mis age female messpunkt2 messpunkt1 tage eintrittsjahr 1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 8817 88170 1994 2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 8910 8817 93 1994 3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 8797 87970 1994 4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 10606 8797 1809 1999 5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 8840 88400 1994 6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 9031 8840 191 1994 so female is either 0 or 1 I assume 0 is male and 1 is female. And I want to look at dep, dys, sop, ago and mis how they are in terms of gender (female or male) I have no clue what to do :-( thanks for your help sophie [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How can make loop more faster?
On Jun 15, 2013, at 2:38 PM, Fabrice Tourre wrote:
Dear expert,
How can I make follow codematrix function more faster?
top20.dat - top20.dat[,7:length(top20.dat[1,])]
top40.dat -
read.table(top40snps.ped,header=F,sep=\t,stringsAsFactors=F)
Did you attach a file with a non-'.txt' extension?
row.names(top40.dat) - top40.dat[,1]
top40.dat - top40.dat[,7:length(top40.dat[1,])]
codematrix - function(dat)
{
new.dat - dat
for(col in 1:length(dat[1,]))
{
I'm guessing that using `ifelse` would be much faster than going column by
column and and then row by painful row through this testing with nested
`if(cond){conseq}else{alter}` . You should gain efficiency by setting up the
results of the `strsplit` operation on a full column at a time. Build a
function that would work one column at a time and then lapply it to the
dataframe.
tbl - table(dat[,col])
max.allel - names(which(tbl==max(table(dat[,col]
for(row in 1:length(dat[,1]))
{
if(dat[row,col]==0 0)
{
new.dat[row,col]=NA
}else{
if(dat[row,col]==max.allel) {
new.dat[row,col]=0
}else{
allele - unlist(strsplit(
as.character(dat[row,col]), ))
if(allele[1]==allele[2]){
new.dat[row,col]=2
}else{
new.dat[row,col]=1
You could leave the ==max.allelle test on the outer of nested ifelse
operations to overwrite the resutls of the testing of the two split-bits. But
I would make it a %in%-test so that it won't fail when mor than one maximum
occur.
Perhaps (untested and a lot of guesswork):
testsplitfunc - function(col){
temptbl - table(col)
tempspl - strsplit(as.character(col) , split= )
allele -cbind( sapply(temp, [, 1),
sapply(temp, [, 2) )
res - ifelse ( col %in% names(temptbl)[ which(tbl==max(temptbl))] ,
0,
ifelse( allele[,1]==allele[,2], 2, 1) )
is.na(res) - col==0 0
}
code.top20 - do.call(cbind, lapply(top20.dat, testsplitfunc) )
}
}
}
}
#})
cat(paste(col, ,sep=))
}
return(new.dat)
}
code.top20 - codematrix(top20.dat)
In the absence of a problem description I will leave the details unaddressed.
[[alternative HTML version deleted]]
David Winsemius
Alameda, CA, USA
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[R] Optimization of a function using optim
I am attempting to optimize a function I have developed using optim. I am getting the below error message: Error in n 1: 'n' is missing Could some one provide some additional clarity regarding this message and what it entails, as well as, how to rectify this issue. Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Optimization of a function using optim
Not unless you read the Posting Guide, stop posting in HTML mail format, and provide a reproducible example. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. Graham McDannel graham.mcdan...@gmail.com wrote: I am attempting to optimize a function I have developed using optim. I am getting the below error message: Error in n 1: 'n' is missing Could some one provide some additional clarity regarding this message and what it entails, as well as, how to rectify this issue. Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Plotting two y-axis vs non-numeric x-axis
On 06/16/2013 04:14 AM, Birdada Simret wrote: Thank you. @David: The example is exactly this: time - seq(0,72,6) music - c(0.05,0.18,0.25,0.31,0.32,0.34,0.35, 0.36,0.37,0.38,0.39,0.40,0.41) actor - c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000) par(mar=c(5, 4, 4, 4) + 0.1) plot(time, music, pch=16, axes=F, ylim=c(0,1), xlab=, ylab=, type=b,col=black, main=Enjoy) axis(2, ylim=c(0,1),col=black) mtext(Music,side=2,line=2.5) box() par(new=T) plot(time, actor, pch=15, xlab=, ylab=, ylim=c(0,13000), axes=F, type=b, col=red) mtext(Actor,side=4,col=red,line=2.5) axis(4, ylim=c(0,13000), col=red,col.axis=red) axis(1,pretty(range(time),10)) mtext(Time (Hours),side=1,col=black,line=2.5) legend(5,13000,legend=c(Music,Actor),text.col=c(black,red),pch=c(16,15),col=c(black,red)) Now, what if time is replaced by month - c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec,Pag) Hi Birdada, You can get the month labels using something like this: twoord.plot(time,music,time,actor,lylim=c(0,1),type=c(l,b), xtickpos=seq(0,70,by=10),xticklab=month.abb[1:8]) Hi arun, This question may already have been answered, but to change the symbols, you have to use lpch= and rpch=. I get the appropriate types of plot when using the above, and I tried several combinations of point, line, both that all worked okay. If I figure out what happened in your example I'll email the answer. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Optimization of a function using optim
The r-help list should institute a prize for Most Obtuse Question of the Month. This one should be a shoe-in for the June 2013 prize. cheers, Rolf Turner On 16/06/13 12:08, Graham McDannel wrote: I am attempting to optimize a function I have developed using optim. I am getting the below error message: Error in n 1: 'n' is missing Could some one provide some additional clarity regarding this message and what it entails, as well as, how to rectify this issue. Thanks __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] quick Help needed
Hi, It is better to ?dput() the dummy dataset. I made up some data for female==0 dat1- read.table(text= pbnr dat dep dys sop ago mis age female messpunkt2 messpunkt1 tage eintrittsjahr 1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 8817 8817 0 1994 2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 8910 8817 93 1994 3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 8797 8797 0 1994 4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 10606 8797 1809 1999 5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 8840 8840 0 1994 6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 9031 8840 191 1994 7 10043 1994-02-21 0.85 1.20 0.51 0.55 0.95 45 0 8917 8817 0 1994 8 10043 1994-05-25 0.95 1.10 0.55 0.55 0.85 35 0 8950 8717 93 1994 9 10038 1994-02-01 2.50 1.85 3.20 0.70 1.70 45 0 9797 8897 0 1994 10 10038 1999-01-15 1.55 0.85 2.35 0.70 0.55 47 0 11606 9797 1809 1999 11 10063 1994-03-16 2.20 0.65 1.55 0.85 1.25 28 0 8940 8850 0 1994 12 10063 1994-09-23 3.55 1.35 1.55 0.95 2.35 32 0 9531 8340 191 1994 ,sep=,header=TRUE,stringsAsFactors=FALSE) by(dat1[, c(3:8)], dat1[,female], summary) #or library(psych) describeBy(dat1[,3:8],dat1$female) #or describeBy(dat1[,3:8],dat1$female,mat=TRUE) A.K. - Original Message - From: Sophie Homeyer sophie.home...@googlemail.com To: r-help@r-project.org Cc: Sent: Saturday, June 15, 2013 4:58 PM Subject: [R] quick Help needed Hi, i am new to this forum and not sure how it works, I am trying to do deskriptive descripe my data in terms of gender: head(scltotal) pbnr dat dep dys sop ago mis age female messpunkt2 messpunkt1 tage eintrittsjahr 1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 8817 8817 0 1994 2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1 8910 8817 93 1994 3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1 8797 8797 0 1994 4 10028 1999-01-15 1.25 0.75 2.25 0.50 0.25 42 1 10606 8797 1809 1999 5 10053 1994-03-16 2.50 0.75 1.25 0.50 1.25 22 1 8840 8840 0 1994 6 10053 1994-09-23 3.25 1.25 1.25 0.75 2.25 22 1 9031 8840 191 1994 so female is either 0 or 1 I assume 0 is male and 1 is female. And I want to look at dep, dys, sop, ago and mis how they are in terms of gender (female or male) I have no clue what to do :-( thanks for your help sophie [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] extract all numbers from a string
Hi all, I have been beating my head against this problem for a bit, but I can't figure it out. I have a series of strings of variable length, and each will have one or more numbers, of varying format. E.g., I might have: tmpstr = The first number is: 32. Another one is: 32.1. Here's a number in scientific format, 0.3523e10, and another, 0.3523e-10, and a negative, -313.1 How could I get R to just give me a list of numerics containing the numbers therein? Thanks very much to the regexp wizards! Cheers, Nick -- Nicholas J. Matzke Ph.D. Candidate, Graduate Student Researcher Huelsenbeck Lab Center for Theoretical Evolutionary Genomics 4151 VLSB (Valley Life Sciences Building) Department of Integrative Biology University of California, Berkeley Graduate Student Instructor, IB200B Principles of Phylogenetics: Ecology and Evolution http://ib.berkeley.edu/courses/ib200b/ http://phylo.wikidot.com/ Lab websites: http://ib.berkeley.edu/people/lab_detail.php?lab=54 http://fisher.berkeley.edu/cteg/hlab.html Dept. personal page: http://ib.berkeley.edu/people/students/person_detail.php?person=370 Lab personal page: http://fisher.berkeley.edu/cteg/members/matzke.html Lab phone: 510-643-6299 Dept. fax: 510-643-6264 Cell phone: 510-301-0179 Email: mat...@berkeley.edu Mailing address: Department of Integrative Biology 1005 Valley Life Sciences Building #3140 Berkeley, CA 94720-3140 - [W]hen people thought the earth was flat, they were wrong. When people thought the earth was spherical, they were wrong. But if you think that thinking the earth is spherical is just as wrong as thinking the earth is flat, then your view is wronger than both of them put together. Isaac Asimov (1989). The Relativity of Wrong. The Skeptical Inquirer, 14(1), 35-44. Fall 1989. http://chem.tufts.edu/AnswersInScience/RelativityofWrong.htm __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] extract all numbers from a string
HI, One way would be: library(stringr) tmpstr = The first number is: 32. Another one is: 32.1. Here's a number in scientific format, 0.3523e10, and another, 0.3523e-10, and a negative, -313.1 pattern- (\\d)+|(\\d+\\.\\d+)|(-\\d+\\.\\d+)|(\\d+.\\d+e\\d+)|(\\d+\\.\\d+e-\\d+) str_extract_all(tmpstr,pattern)[[1]] #[1] 32 32.1 0.3523e10 0.3523e-10 -313.1 as.numeric(str_extract_all(tmpstr,pattern)[[1]]) A.K. - Original Message - From: Nick Matzke mat...@berkeley.edu To: R-help@r-project.org Cc: Sent: Sunday, June 16, 2013 1:06 AM Subject: [R] extract all numbers from a string Hi all, I have been beating my head against this problem for a bit, but I can't figure it out. I have a series of strings of variable length, and each will have one or more numbers, of varying format. E.g., I might have: tmpstr = The first number is: 32. Another one is: 32.1. Here's a number in scientific format, 0.3523e10, and another, 0.3523e-10, and a negative, -313.1 How could I get R to just give me a list of numerics containing the numbers therein? Thanks very much to the regexp wizards! Cheers, Nick -- Nicholas J. Matzke Ph.D. Candidate, Graduate Student Researcher Huelsenbeck Lab Center for Theoretical Evolutionary Genomics 4151 VLSB (Valley Life Sciences Building) Department of Integrative Biology University of California, Berkeley Graduate Student Instructor, IB200B Principles of Phylogenetics: Ecology and Evolution http://ib.berkeley.edu/courses/ib200b/ http://phylo.wikidot.com/ Lab websites: http://ib.berkeley.edu/people/lab_detail.php?lab=54 http://fisher.berkeley.edu/cteg/hlab.html Dept. personal page: http://ib.berkeley.edu/people/students/person_detail.php?person=370 Lab personal page: http://fisher.berkeley.edu/cteg/members/matzke.html Lab phone: 510-643-6299 Dept. fax: 510-643-6264 Cell phone: 510-301-0179 Email: mat...@berkeley.edu Mailing address: Department of Integrative Biology 1005 Valley Life Sciences Building #3140 Berkeley, CA 94720-3140 - [W]hen people thought the earth was flat, they were wrong. When people thought the earth was spherical, they were wrong. But if you think that thinking the earth is spherical is just as wrong as thinking the earth is flat, then your view is wronger than both of them put together. Isaac Asimov (1989). The Relativity of Wrong. The Skeptical Inquirer, 14(1), 35-44. Fall 1989. http://chem.tufts.edu/AnswersInScience/RelativityofWrong.htm __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] extract all numbers from a string
Nick
try
as.numeric(
strsplit(gsub([[:alpha:][:punct:][:space:]]{2,},,,tmpstr),,)[[1]][-1]
)
see ?regexpr for information
HTH
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mac...@northnet.com.au
At 15:06 16/06/2013, you wrote:
Hi all,
I have been beating my head against this problem for a bit, but I
can't figure it out.
I have a series of strings of variable length, and each will have
one or more numbers, of varying format. E.g., I might have:
tmpstr = The first number is: 32. Another one is: 32.1. Here's a
number in scientific format, 0.3523e10, and another, 0.3523e-10, and
a negative, -313.1
How could I get R to just give me a list of numerics containing the
numbers therein?
Thanks very much to the regexp wizards!
Cheers,
Nick
--
Nicholas J. Matzke
Ph.D. Candidate, Graduate Student Researcher
Huelsenbeck Lab
Center for Theoretical Evolutionary Genomics
4151 VLSB (Valley Life Sciences Building)
Department of Integrative Biology
University of California, Berkeley
Graduate Student Instructor, IB200B
Principles of Phylogenetics: Ecology and Evolution
http://ib.berkeley.edu/courses/ib200b/
http://phylo.wikidot.com/
Lab websites:
http://ib.berkeley.edu/people/lab_detail.php?lab=54
http://fisher.berkeley.edu/cteg/hlab.html
Dept. personal page:
http://ib.berkeley.edu/people/students/person_detail.php?person=370
Lab personal page: http://fisher.berkeley.edu/cteg/members/matzke.html
Lab phone: 510-643-6299
Dept. fax: 510-643-6264
Cell phone: 510-301-0179
Email: mat...@berkeley.edu
Mailing address:
Department of Integrative Biology
1005 Valley Life Sciences Building #3140
Berkeley, CA 94720-3140
-
[W]hen people thought the earth was flat, they were wrong. When
people thought the earth was spherical, they were wrong. But if you
think that thinking the earth is spherical is just as wrong as
thinking the earth is flat, then your view is wronger than both of
them put together.
Isaac Asimov (1989). The Relativity of Wrong. The Skeptical
Inquirer, 14(1), 35-44. Fall 1989.
http://chem.tufts.edu/AnswersInScience/RelativityofWrong.htm
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
