[R] Proc Mixed variance of random effects in R
Hi, I'm trying to convert the following SAS code in R to get the same result that I get from SAS. Here is the SAS code: DATA plants; INPUT sample $ treatmt $ y ; cards; 1 trt16.426264755 1 trt16.95419631 1 trt16.64385619 1 trt27.348728154 1 trt26.247927513 1 trt26.491853096 2 trt12.807354922 2 trt12.584962501 2 trt13.584962501 2 trt23.906890596 2 trt23 2 trt23.459431619 3 trt12 3 trt14.321928095 3 trt13.459431619 3 trt23.807354922 3 trt23 3 trt22.807354922 4 trt10 4 trt10 4 trt10 4 trt20 4 trt20 4 trt20 ; RUN; PROC MIXED ASYCOV NOBOUND DATA=plants ALPHA=0.05 method=ML; CLASS sample treatmt; MODEL y = treatmt ; RANDOM int treatmt/ subject=sample ; RUN; I get the following covariance estimates from SAS:Intercept sample == 5.5795treatmt sample == -0.08455Residual == 0.3181I tried the following in R, but I get different results. options(contrasts = c(factor = contr.SAS, ordered = contr.poly)) df$sample=as.factor(df$sample) lmer(y~ 1+treatmt+(1+treatmt|sample),REML=FALSE, data = df) Since the results from R are standard deviations, I have to square all results to get the variances.sample== 2.357412^2 = 5.557391 sample*treatmt==0.004977^2 = 2.477053e-05 residual==0.517094^2 = 0.2673862As shown above, the results from SAS and R are different. Do you know how to get the exact values in R?I appreciate any help.Thanks,Gram [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] help
Hello, � I am a R-beginner and I need some help.�The question is very simple: I need to do a pearson correlations (r,p-value and FDR with BH) from an Expression array (with several thousand genes for lets say 20 cell lines)�with some features of those cell lines. My problem I have is the organization of the excel sheets and how to introduce the data into R and run the script. I though the easiest and more organized for me would be two expcel sheets: 1- Only Expression data (in rows the�genes and in colums cell lines) 2- Only the features (In row the features (e.g. a) growth rate, b) sensitivity to some drugs) and in columns the cell lines). --That would creat both sheets with 20 colums. Now I would like to get a correlation of the gene 1: the expression of all lines with the growth rate. the same for gene2... and soforth. I sould obtain as many r,p and BH(FDR) as genes there are. the same I would need to do for the sensitivity... and so on. Do you think this is doable? I am not at all a bioinformatic expert, so all help is very welcome. Thank you very much! Kind regards, Sarah -- Sarah Bazzocco, PhD student Group of Molecular Oncology, CIBBIM-Nanomedicine, Vall d'Hebron Hospital Research Institute, Passeig Vall d'Hebron 119-129, Barcelona 08035, Spain. Tel: +34-93-489-4056 Fax: +34-93-489-3893 Email: sarah.bazzo...@vhir.org [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Replace values in a dataframe
Try this: dat=structure(list(Color = c(5, 4,5, 5, 5), Unit = c(Hazen,Hazen,Hazen, Hazen, Hazen)), .Names = c(Color, Unit), row.names =c(1:2,1:3, 1:4, 1:5,1:6), class = data.frame) dat=as.data.frame(dat)dat$col2 - rep( , nrow(dat))dat[dat$Color == 4, ][, col2] - 2dat[dat$Color == 5, ][, col2] - 2.5 On Wednesday, June 17, 2015 1:33 PM, Shane Carey careys...@gmail.com wrote: Hey all, I have a dataframe that consists of: structure(list(Color = c(5, 4,5, 5, 5), Unit = c(Hazen, Hazen, Hazen, Hazen, Hazen)), .Names = c(Color, Unit), row.names = c(1:2, 1:3, 1:4, 1:5,1:6), class = data.frame) I need to find the 4 and have a new column with the result of 4 ÷ 2 = 2 Similarly I need to find the 5 and have the new column with the result of 5 ÷ 2 = 2.5 All other numeric values would be added to the new column also to end up with: Color New value Unit 1:2 5 5 Hazen 1:3 4 2 Hazen 1:4 5 5 Hazen 1:5 5 2.5 Hazen 1:6 5 5 Hazen Thanks for your help!! -- Shane [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] mlogit.effects()
Dear colleagues, I am struggling mightily with the mlogit package. First, the reason that I am using mlogit as opposed to multinom() in nnet is because my data is ranked, not just ordinal. So, I’m really trying to fit an exploded logit or rank-ordered model. All of the covariates of interest are individual-specific, none are alternative specific. The code below produces a model with my covariates of interest, so that is good. But, I cannot get predict.mlogit or effects.mlogit to work *at all*. The help package is quite unclear as to how to format the sample data that is fed to either of those two functions. Can any one help in that regard? Failing that, can anyone provide a suggestion for an alternative way of modelling ranked categorical data? I’m aware of the pmr and Rankcluster packages. The former however is also poorly documented and the latter is computationally intense to select clusters. I’m trying to do this as simply as possible while remaining loyal to the ranked structure of the data. Thanks, Simon Kiss #Loadpackages library(RCurl) library(mlogit) library(tidyr) library(dplyr) #URL where data is stored dat.url- 'https://raw.githubusercontent.com/sjkiss/Survey/master/mlogit.out.csv' #Get data dat-read.csv(dat.url) #Complete cases only as it seems mlogit cannot handle missing values or tied data which in this case you might get because of median imputation dat-dat[complete.cases(dat),] #Tidy data to get it into long format dat.out-dat %% gather(Open, Rank, -c(1,9:12)) %% arrange(X, Open, Rank) #Create mlogit object mlogit.out-mlogit.data(dat.out, shape='long',alt.var='Open',choice='Rank', ranked=TRUE,chid.var='X') #Fit Model mod1-mlogit(Rank~1|gender+age+economic+Job,data=mlogit.out) __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Replace values in a dataframe
Hi Shane, On Wed, Jun 17, 2015 at 1:31 PM, Shane Carey careys...@gmail.com wrote: Hey all, I have a dataframe that consists of: structure(list(Color = c(5, 4,5, 5, 5), Unit = c(Hazen, Hazen, Hazen, Hazen, Hazen)), .Names = c(Color, Unit), row.names = c(1:2, 1:3, 1:4, 1:5,1:6), class = data.frame) Thanks for providing data. I need to find the 4 and have a new column with the result of 4 ÷ 2 = 2 Similarly I need to find the 5 and have the new column with the result of 5 ÷ 2 = 2.5 Are 4 and 5 the only possible non-numeric values? If so, this is an easy way to do it: mydata - structure(list(Color = c(5, 4,5, 5, 5), Unit = c(Hazen, + Hazen, + Hazen, Hazen, Hazen)), .Names = c(Color, Unit), row.names = + c(1:2, + 1:3, 1:4, 1:5,1:6), class = data.frame) mydata Color Unit 1:2 5 Hazen 1:34 Hazen 1:4 5 Hazen 1:55 Hazen 1:6 5 Hazen mydata$NewColor - ifelse(mydata$Color == 4, 4/2, ifelse(mydata$Color == 5, 5/2, as.numeric(mydata$Color))) mydata Color Unit NewColor 1:2 5 Hazen 5.0 1:34 Hazen 2.0 1:4 5 Hazen 5.0 1:55 Hazen 2.5 1:6 5 Hazen 5.0 This will throw a warning message that you can safely ignore. All other numeric values would be added to the new column also to end up with: Color New value Unit 1:2 5 5 Hazen 1:3 4 2 Hazen 1:4 5 5 Hazen 1:5 5 2.5 Hazen 1:6 5 5 Hazen Bonus points for providing data, demerits for posting in HTML so your email got mangled. Sarah -- Sarah Goslee http://www.functionaldiversity.org __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Problems using nlmrt package
Hello to everybody, I want to implement a non-linear least square curve fitting and I am using the package nlmrt, concretely the function nlxb. I have a dataset with three variables and 176 values, one response variables (R) and two predicting variables (T and H). When I fit a model of the form R ~ a*b^((T-10)/10) to my data using the function nlxb seems to be all ok with a complet output; the same happens when I fit a model R ~ a + b*H - c*H^2. But due to my research interest, when I try to fit a model result of the product of the above models (R ~ (b1*b2^((T-10)/10))*(b3 + b4*H - b5*H^2) I do obtain NA values in the SE, tstat and pval fields from the nlxb output, as showed below: nlmrt class object: x residual sumsquares = 25348 on 176 observations after 4Jacobian and 5 function evaluations namecoeff SE tstat pval gradientJSingval R100.0619936NA NA NA 7.494e-068822 Q10 2.27113NA NA NA 5.422e-08 217.5 a 133.85NA NA NA -2.288e-09 75.96 b56.8145NA NA NA 8.058e-09 0.658 c1.11775NA NA NA 2.8e-07 1.928e-15 I would like to know which error do you think I am making. Attached is the document which contain the data. Thank you very much in advance, Carlos. -- Carlos Ortiz Oñate PhD student Department of Agricultural Production Technical University of Madrid e-mail: ortiz.onate.car...@gmail.com t...@life.ku.dk R T H 36.47 14.10 5.95 34.28 14.25 5.65 35.86 14.90 7.78 38.18 18.10 4.53 33.52 14.40 6.15 29.44 14.60 4.55 34.79 14.80 6.78 20.38 16.70 3.58 26.70 14.90 3.00 33.30 14.90 3.65 20.28 15.00 3.58 51.18 16.90 2.78 29.76 14.90 2.48 14.90 15.10 2.40 21.05 15.30 3.10 16.18 17.10 2.85 26.50 11.40 10.85 37.69 11.90 7.08 37.37 11.90 7.30 27.02 12.00 5.83 42.16 7.2026.03 47.75 7.7020.15 53.05 7.9017.78 26.48 8.0013.53 47.50 7.2011.45 28.47 7.4020.85 45.62 7.4015.23 42.31 7.9016.45 18.10 4.1027.35 27.71 5.5017.58 34.27 5.6028.33 27.75 5.7021.03 33.09 4.2037.28 19.05 4.2041.63 14.08 4.8036.48 23.15 5.3028.93 24.64 4.3031.48 35.80 4.4033.50 23.41 4.4032.63 29.63 4.6025.25 78.01 10.00 25.45 60.40 10.20 28.28 61.32 10.20 32.35 48.25 10.30 28.45 54.62 11.00 18.63 55.19 11.10 21.18 69.03 11.80 22.03 64.01 14.40 15.78 41.20 12.70 16.43 39.20 12.80 12.63 35.20 12.90 12.88 79.98 15.30 11.03 69.60 13.80 27.65 64.32 14.00 18.20 93.22 14.30 24.58 91.86 15.80 22.23 50.28 14.40 4.73 37.03 14.50 5.03 47.23 14.90 5.33 47.65 16.80 3.93 48.68 14.90 8.38 73.43 14.90 10.00 47.31 15.10 7.38 75.10 15.90 11.93 45.40 12.60 10.13 47.86 12.90 9.28 49.39 13.10 12.05 37.27 13.70 5.53 41.63 8.4011.43 53.83 9.1011.48 36.66 9.208.85 44.03 9.6011.23 45.94 5.9029.70 60.64 6.6014.98 48.91 6.6023.83 47.02 6.6025.13 13.62 1.3014.98 24.86 1.6013.75 27.28 1.8017.08 28.16 2.2014.13 23.29 2.6039.65 23.23 2.6036.35 25.10 2.7036.05 25.68 3.4032.85 54.88 9.9026.80 39.19 10.50 25.23 59.74 10.90 25.03 42.39 12.50 26.23 49.24 6.8030.65 52.70 7.0030.00 49.18 7.5029.43 69.69 7.6029.30 56.05 9.8028.78 45.72 9.9026.53 56.07 10.30 28.70 48.40 11.80 29.25 39.10 14.60 11.15 58.45 14.90 9.58 78.41 15.50 6.50 65.89 15.70 12.05 45.25 13.40 5.40 45.87 14.00 5.00 32.47 14.40 7.05 46.08 16.70 1.65 43.08 16.70 4.18 50.24 17.10 6.43 39.22 17.60 4.83 26.41 17.70 5.30 37.58 12.30 5.78 20.67 12.90 3.15 25.80 12.90 2.63 27.71 13.20 3.80 22.74 13.20 4.50 17.18 13.40 4.50 17.95 13.70 5.75 15.77 14.30 4.75 80.91 6.6024.25 37.71 6.8017.00 60.88 7.3017.50 47.62 7.3015.00 45.92 4.4027.50 19.28 5.7019.50 32.94 6.1022.25 52.46 6.4019.50 20.03 1.2025.88 26.29 1.9023.75 25.09 2.4021.00 35.26 2.8023.10 11.00 1.3027.60 23.49 1.6022.70 48.21 2.4021.38 17.76 3.1024.95 10.95 1.7027.60 20.90 1.8024.95 28.61 1.9022.70 47.77 2.0021.38 24.96 3.1019.55 20.90 6.1019.75 24.63 6.2017.45 27.10 6.2022.30 28.96 10.00 18.70 32.04 10.00 15.80 44.78 10.20 19.60 50.55 10.80 21.40 33.81 11.70 9.80 42.71 12.00 12.60 42.32 12.10 11.90 56.49 16.80 11.20 53.77 12.50 12.10 81.96 12.80 12.00 67.85 13.40 9.00 38.25 13.60 9.90 58.57 16.00 3.40 44.80 16.00 3.40 27.37 16.30
[R-es] funciones en estructura data.table
-Mensaje original- De: Patricio Fuenmayor Viteri patricio.fuenma...@outlook.com Enviado: 17 de junio de 2015 6:37 PM Para: r-help...@r-ptoject.org, patricio.fuenma...@outlook.com Asunto: funciones en estructura data.table hola... luego de haber migrado la mayoria de mis procesos a data.table. aun me kedan ciertos detalles por afinar.. eate es un ejemplo de eso.. tengo una tabla de emails y necesito hacer un analisis de dominios... para separar el nombre de usuario el dominio uso la funcion str_split del paquete stringr... pero el resultado me queda en una sola columna y separada por una coma... mi pregunta es ... como puedo hacer ke los multiples resultados de una funcion ... se guarden en diferentes columnas de mi data.table email01[,.(str_split(email))] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R] Replace values in a dataframe
Is the following what you want:
(z is your data frame)
change -c(2,2.5)
names(change) - c(4,5)
(note: this can be automated using regular expressions and will work for
lots more values to change. Sarah's ifelse() solution is fine for the
example, but becomes too cumbersome (as she intimated) for more values.)
z$newcol - with(z,{
+ for(nm in names(change))Color[Color == nm]-change[nm]
+ as.numeric(Color)
+ })
z
Color Unit newcol
1:2 5 Hazen5.0
1:34 Hazen2.0
1:4 5 Hazen5.0
1:55 Hazen2.5
1:6 5 Hazen5.0
Incidentally, if this is how you are attempting to deal with censored data,
it may be a very bad idea. For why, consult a local statistician or post on
a statistics list like stats.stackexchange.com
Cheers,
Bert
Bert Gunter
Data is not information. Information is not knowledge. And knowledge is
certainly not wisdom.
-- Clifford Stoll
On Wed, Jun 17, 2015 at 10:31 AM, Shane Carey careys...@gmail.com wrote:
Hey all,
I have a dataframe that consists of:
structure(list(Color = c(5, 4,5, 5, 5), Unit = c(Hazen,
Hazen,
Hazen, Hazen, Hazen)), .Names = c(Color, Unit), row.names =
c(1:2,
1:3, 1:4, 1:5,1:6), class = data.frame)
I need to find the 4 and have a new column with the result of 4 ÷ 2 = 2
Similarly
I need to find the 5 and have the new column with the result of 5 ÷ 2 =
2.5
All other numeric values would be added to the new column also to end up
with:
Color New value Unit 1:2 5 5 Hazen 1:3 4 2 Hazen 1:4 5 5 Hazen 1:5 5
2.5 Hazen 1:6 5 5 Hazen
Thanks for your help!!
--
Shane
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] generating a data frame for plm regression
Hi everybody, I am working with the plm package. I am struggling with the generation of the data frame in the plm() function. An example of my data are found in the attachment and I want to run a pooled regression on those. Hence, I need to generate a data frame using pdata.frame() function and this is what I get: pdata.frame(plm.CoVaR,index=c(Sector,Date))-data head(data,100) Sector Date DeltaCoVaR 1-01/02/2000 1 01/02/2000 -2.331174662 1-01/02/2001 1 01/02/2001 -2.091099896 1-01/02/2002 1 01/02/2002 -2.126445804 1-01/02/2005 1 01/02/2005 -1.580493046 1-01/02/2006 1 01/02/2006 -1.648100073 1-01/02/2007 1 01/02/2007 -1.494696604 The problem is that I do not understand the first column. Furthermore, I have daily data but the variables are not sorted by their date. The ordering looks confusing and some years are omitted in the R output. What is wrong here? Can anybody help me? Thanks in advance. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R-es] funciones en estructura data.table
Estimado Patricio Fuenmayor Viteri De cran.r-project.org/web/packages/stringr/stringr.pdf página 17, interpreto que van la cadena y la separación (el tercer parámetro no iría en su caso). Tendría que probarlo pero estoy casi seguro que es eso. Javier Rubén Marcuzzi Técnico en Industrias Lácteas Veterinario De: Patricio Fuenmayor Viteri Enviado el: miércoles, 17 de junio de 2015 09:26 p.m. Para: R-help-es@r-project.org -Mensaje original- De: Patricio Fuenmayor Viteri patricio.fuenma...@outlook.com Enviado: 17 de junio de 2015 6:37 PM Para: r-help...@r-ptoject.org, patricio.fuenma...@outlook.com Asunto: funciones en estructura data.table hola... luego de haber migrado la mayoria de mis procesos a data.table. aun me kedan ciertos detalles por afinar.. eate es un ejemplo de eso.. tengo una tabla de emails y necesito hacer un analisis de dominios... para separar el nombre de usuario el dominio uso la funcion str_split del paquete stringr... pero el resultado me queda en una sola columna y separada por una coma... mi pregunta es ... como puedo hacer ke los multiples resultados de una funcion ... se guarden en diferentes columnas de mi data.table email01[,.(str_split(email))] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R] Read text file
I am not sure what you mean by a block, but you can probably use scan() instead of read.table(): txt - 1 21 41 61 81 d - data.frame(Numbers=scan(text=txt, what=numeric, quiet=TRUE)) d Numbers 1 1 2 21 3 41 4 61 5 81 Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, Jun 17, 2015 at 10:10 PM, Steven Yen sye...@gmail.com wrote: How do I read a block of space-delimited numbers into a column vector using the read.table command? Thank you. -- Steven Yen __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Read text file
Hi, I think that you need scan() but you should at least give us an example of your text data. Olivier. -- Olivier Crouzet LLING - Laboratoire de Linguistique de Nantes - EA3827 Université de Nantes -Original Message- From: Steven Yen sye...@gmail.com Sender: R-help r-help-boun...@r-project.orgDate: Thu, 18 Jun 2015 01:10:39 To: r-helpr-help@r-project.org Reply-To: sye...@gmail.com Subject: [R] Read text file How do I read a block of space-delimited numbers into a column vector using the read.table command? Thank you. -- Steven Yen __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R-es] funciones en estructura data.table
No limpió, no fijó y no dio esplendor nunca... 2015-06-17 21:26 GMT-03:00 Patricio Fuenmayor Viteri patricio.fuenma...@outlook.com: -Mensaje original- De: Patricio Fuenmayor Viteri patricio.fuenma...@outlook.com Enviado: 17 de junio de 2015 6:37 PM Para: r-help...@r-ptoject.org, patricio.fuenma...@outlook.com Asunto: funciones en estructura data.table hola... luego de haber migrado la mayoria de mis procesos a data.table. aun me kedan ciertos detalles por afinar.. eate es un ejemplo de eso.. tengo una tabla de emails y necesito hacer un analisis de dominios... para separar el nombre de usuario el dominio uso la funcion str_split del paquete stringr... pero el resultado me queda en una sola columna y separada por una coma... mi pregunta es ... como puedo hacer ke los multiples resultados de una funcion ... se guarden en diferentes columnas de mi data.table email01[,.(str_split(email))] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es -- «No soy aquellas sombras tutelares que honré con versos que no olvida el tiempo.» JL Borges [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
[R] Replace values in a dataframe
Hey all, I have a dataframe that consists of: structure(list(Color = c(5, 4,5, 5, 5), Unit = c(Hazen, Hazen, Hazen, Hazen, Hazen)), .Names = c(Color, Unit), row.names = c(1:2, 1:3, 1:4, 1:5,1:6), class = data.frame) I need to find the 4 and have a new column with the result of 4 ÷ 2 = 2 Similarly I need to find the 5 and have the new column with the result of 5 ÷ 2 = 2.5 All other numeric values would be added to the new column also to end up with: Color New value Unit 1:2 5 5 Hazen 1:3 4 2 Hazen 1:4 5 5 Hazen 1:5 5 2.5 Hazen 1:6 5 5 Hazen Thanks for your help!! -- Shane [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to call rbind using arguments from a list
I *think* you want: ZC - do.call(rbind,lapply(a,get)) But why do you make a a *list* of names rather than a vector of names? Generally one uses lists to hold complicated structures. A sequence of character scalars is best stored in an atomic vector. cheers, Rolf Turner P. S. Thank you for providing a reproducible example! :-) R. T. On 17/06/15 21:58, Matteo wrote: Hello R users, I am trying to run the command rbind gathering the name of tables to bind from a list argument. Unfortunately I am not able to obtain it. I would appreciate any suggestions. Below is a reproducible example with the problem. Thanks Matteo ## ZA-data.frame(x = 1:2, y = 1:10,z=letters[1:5]) ZB-data.frame(x = 1, y = 5:24,z=letters[2]) a-as.list(ls(pattern= ^Z?));a # I_would_like_ZC-rbind(ZA,ZB) # this is what I would like to have # b-(paste(a, collapse = ',')) call(rbind,(b)) # I am not able to remove b-noquote(paste(a, collapse = ',')) call(rbind,(b)) # I am not able to remove -- Technical Editor ANZJS Department of Statistics University of Auckland Phone: +64-9-373-7599 ext. 88276 __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Read text file
How do I read a block of space-delimited numbers into a column vector using the read.table command? Thank you. -- Steven Yen __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R-es] Problemas al cargar Rcomander en consola de Rstudio
El 16/06/15 a las 21:33, eric escribió: MaLuz, hasta donde entiendo RStudio y R-commander son entornos de trabajo graficos para R, R-commander no es una libreria (http://www.rcommander.com/), de modo que me parece raro invocarlo desde dentro de R. Segun yo deberias llamar a R-commander tal como llamas a RStudio, como un programa desde la consola linux o con un shorcut o desde un menu o algo asi. TclTk si es un conjunto de librerias graficas, por eso las puedes cargar sin problemas desde dentro de R. Saludos, eric. Pues no amigo Eric. RCommander, a diferencia de RStudio, es una libreria o paquete de R , que abre su propia ventana gráfica cuando se le invoca. El paquete en concreto es Rcmdr. La primera invocación de RCommander es simplemente: library(Rcmdr) Y si por alguna razón se cierra la ventana gráfica de RCommander, se vuelve a poner en marcha mediante el comando: Commander() RCommander es perfectamente compatible con RStudio, aportándole menús para procedimientos estadísticos de nivel básico y general de los que carece RStudio. Este está más centrado en el control de los datos y objetos del entorno que en proporcionar menús para procedimientos estadísticos. Basta con marcar el paquete Rcmdr en la solapa Packages de RStudio para incorporar RCommander a RStudio, aunque en estas condiciones puede hacer falta retocar la configuración de RCommander para que la convivencia sea perfecta (en concreto puede que redirija la salida a RStudio en lugar de hacerlo hacia su propio editor de resultados). Un saludo. On 16/06/15 05:14, MªLuz Morales wrote: Hola, tengo instalado R y Rstudio sobre linux en máquina virtual. en la consola de Rstudio he instalado el interfaz Rcommander con la instrucción: install.packages(Rcmdr,dependences=TRUE), pero al cargar el paquete library(Rcmdr) obtengo el siguiente error: Loading required package: splinesLoading required package: RcmdrMiscLoading required package: carLoading required package: sandwichError : .onLoad failed in loadNamespace() for 'Rcmdr', details: call: structure(.External(.C_dotTclObjv, objv), class = tclObj) error: [tcl] invalid command name tk_messageBox. In addition: Warning message:In fun(libname, pkgname) : couldn't connect to display :0Error: package or namespace load failed for ‘Rcmdr’ Esto lo carga sin problemas library(tcltk) Gracias Un saludo MªLuz [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R] cluster analysis
Hi -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Venky Sent: Wednesday, June 17, 2015 8:43 AM To: R Help R Subject: [R] cluster analysis Hi friends, I have data like this In R or elsewhere? Group Employee size WOE Employee size2 Weight of Evidence 1081680995 0 0.12875537 0.128755 -0.30761 1007079896 1 0.48380133 -0.46544 -0.70464 1000507407 2 0.26029825 -0.46544 0.070221 1006400720 3 0.12875537 0.128755 0.151385 1006916029 4 0.12875537 -0.05955 0.320269 1006717587 5 0.12875537 1002032301 6 0.12875537 1007021594 7 0.26029825 1007118066 8 0.26029825 In this data first variable (Employee size) has 10 rows and variable 2 (employee size2) has only 5 rows Extremely messy due to HTML posting. Use plain text post as recommended by Posting Guide. Question 1:there are different number of rows so that, we can able to do K-means cluster or not? I am not an expert but why not to try it? Question 2:If we run k-means clustering in R answer not coming because of NA exists I have used dataset-na.omit(dataset) But that time also i cannot able to run clustering Perhaps not enough data remained after NA removing. To get better answer you shall provide reproducible example or at least some usable data. Cheers Petr Please help me to find this answer [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému. Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat. Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu. V případě, že je tento e-mail součástí obchodního jednání: - vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu. - a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou. - trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech. - odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system. If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner. The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email. In case that this e-mail forms part of business dealings: - the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning. - if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation. - the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects. - the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the recipient, or the existence of such authorization is known to the recipient of the person represented by the recipient. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Polysomnographic data analysis with R?
Hi Charles, This looks like the European Data Format (EDF and EDF+), which has a complete file specification. If there is no existing R package, it might be possible to write an import function from the specification, something like the functions in the foreign package. Jim On Wed, Jun 17, 2015 at 4:55 AM, Charles Novaes de Santana charles.sant...@gmail.com wrote: Dear all, Do you know if there is any R package or function we can use to analyze polysomnographic data? For example, something that can import an EDF file (or in a different format) and can give some properties of the polysomnographic records like periods of different sleep phases, etc. I looked for it in the web and I didn't find. But maybe I used the wrong key-words. Any help will be much appreciated! Best, Charles -- Um axé! :) -- Charles Novaes de Santana, PhD http://www.imedea.uib-csic.es/~charles [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Aggregating on date at Monthly Level
Hi -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Shivi82 Sent: Wednesday, June 17, 2015 9:19 AM To: r-help@r-project.org Subject: [R] Aggregating on date at Monthly Level HI All, I have situation where i am aggregating weight on monthly and quarterly level. I need to summarize weight on variable ship date i.e. shipping date . As this date is in a character format so used the conversion as: Shipdate-as.Date(retail$ship.date, format=%m-%d-%Y). But when i see the output of Shipdate the result is NA. Are you sure that format is in aggreement with ship.date? typeof(Shipdate) gives me double. I am not sure what this is var type whereas class (Shipdate) is Date so i am a bit puzzled. Then i have created a new var which sums weight and gives me the desired result- aggr-aggregate(retail$weight,list(retail$ship.date),mean) Now if i want to group the result on a Month level i used the below syntax and gives me error: cut.Date(aggr,breaks = Month,labels = TRUE). x must be numeric- in the above syntax i have created it as a list. AFAIK aggr is data frame with Group.1 column the ship.date and x column the mean weight for each ship.date. If you want to further aggregate on month you can use the same approach with second parameter in aggregate an indication of months. If you want something else you shall be more specific about your data and intended result. Is there an easier way to achieve what i am looking for. Kindly suggest. Probably easiest way would be if you familiarise yourself with data types and operations e.g. by reading R-intro. Cheers Petr Thanks, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Aggregating-on-date-at-Monthly-Level- tp4708741.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému. Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat. Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu. V případě, že je tento e-mail součástí obchodního jednání: - vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu. - a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou. - trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech. - odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system. If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner. The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email. In case that this e-mail forms part of business dealings: - the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning. - if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation. - the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects. - the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the
Re: [R] Polysomnographic data analysis with R?
Dear Jim, Thank you for your response. Yes, it is the European Data Format you mention. Actually we can read the data correctly, but I was wondering if there is any package that can identify different sleep phases automatically based on the data. I supposed such a package does not exist, it is really difficult to automatize the identification of sleep phases based only on data, but I asked here just in case. Thanks for your attention! Best, Charles On 17 June 2015 at 13:46, Jim Lemon drjimle...@gmail.com wrote: Hi Charles, This looks like the European Data Format (EDF and EDF+), which has a complete file specification. If there is no existing R package, it might be possible to write an import function from the specification, something like the functions in the foreign package. Jim On Wed, Jun 17, 2015 at 4:55 AM, Charles Novaes de Santana charles.sant...@gmail.com wrote: Dear all, Do you know if there is any R package or function we can use to analyze polysomnographic data? For example, something that can import an EDF file (or in a different format) and can give some properties of the polysomnographic records like periods of different sleep phases, etc. I looked for it in the web and I didn't find. But maybe I used the wrong key-words. Any help will be much appreciated! Best, Charles -- Um axé! :) -- Charles Novaes de Santana, PhD http://www.imedea.uib-csic.es/~charles [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Um axé! :) -- Charles Novaes de Santana, PhD http://www.imedea.uib-csic.es/~charles [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] cluster analysis
Hi friends, I have data like this Group Employee size WOE Employee size2 Weight of Evidence 1081680995 0 0.12875537 0.128755 -0.30761 1007079896 1 0.48380133 -0.46544 -0.70464 1000507407 2 0.26029825 -0.46544 0.070221 1006400720 3 0.12875537 0.128755 0.151385 1006916029 4 0.12875537 -0.05955 0.320269 1006717587 5 0.12875537 1002032301 6 0.12875537 1007021594 7 0.26029825 1007118066 8 0.26029825 In this data first variable (Employee size) has 10 rows and variable 2 (employee size2) has only 5 rows Question 1:there are different number of rows so that, we can able to do K-means cluster or not? Question 2:If we run k-means clustering in R answer not coming because of NA exists I have used dataset-na.omit(dataset) But that time also i cannot able to run clustering Please help me to find this answer [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Aggregating on date at Monthly Level
HI All, I have situation where i am aggregating weight on monthly and quarterly level. I need to summarize weight on variable ship date i.e. shipping date . As this date is in a character format so used the conversion as: Shipdate-as.Date(retail$ship.date, format=%m-%d-%Y). But when i see the output of Shipdate the result is NA. typeof(Shipdate) gives me double. I am not sure what this is var type whereas class (Shipdate) is Date so i am a bit puzzled. Then i have created a new var which sums weight and gives me the desired result- aggr-aggregate(retail$weight,list(retail$ship.date),mean) Now if i want to group the result on a Month level i used the below syntax and gives me error: cut.Date(aggr,breaks = Month,labels = TRUE). x must be numeric- in the above syntax i have created it as a list. Is there an easier way to achieve what i am looking for. Kindly suggest. Thanks, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Aggregating-on-date-at-Monthly-Level-tp4708741.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Restricting Decimal Places in the Output
Good Morning All, I have working on a data set where I am finding mean and median for weight variable on a daily basis. The code: aggr-aggregate(retail$weight,list(retail$ship.date),mean) This is giving me an accurate result however with 4 decimal places for the mean weight. In order to restrict it i used the following syntax: format(aggr,digits=2,justify = c(right)) After the execution of this code i have mean weight but now there are no decimal places. Could you please advice what is incorrect in the syntax. Thank you, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Restricting-Decimal-Places-in-the-Output-tp4708739.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Restricting Decimal Places in the Output
Hi -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Shivi82 Sent: Wednesday, June 17, 2015 7:50 AM To: r-help@r-project.org Subject: [R] Restricting Decimal Places in the Output Good Morning All, I have working on a data set where I am finding mean and median for weight variable on a daily basis. The code: How about aggr-aggregate(retail$weight,list(retail$ship.date),function(x) round(mean(x,2))) Cheers Petr This is giving me an accurate result however with 4 decimal places for the mean weight. In order to restrict it i used the following syntax: format(aggr,digits=2,justify = c(right)) After the execution of this code i have mean weight but now there are no decimal places. Could you please advice what is incorrect in the syntax. Thank you, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Restricting-Decimal-Places-in-the-Output- tp4708739.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému. Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat. Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu. V případě, že je tento e-mail součástí obchodního jednání: - vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu. - a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou. - trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech. - odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system. If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner. The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email. In case that this e-mail forms part of business dealings: - the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning. - if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation. - the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects. - the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the recipient, or the existence of such authorization is known to the recipient of the person represented by the recipient. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Restricting Decimal Places in the Output
Hi It does not make sense. How you can get same result counting mean and sum? The only way I can imagine is that you have only one value per date. So aggregate does virtually nothing. round gives you n decimal places based on its second parameter. set.seed(111) x-rnorm(1) x-x*1000 round(x,1) [1] 235.2 round(x,2) [1] 235.22 round(x,3) [1] 235.221 round(x,4) [1] 235.2207 round(x,10) [1] 235.2207116 The last item has less than 10 decimal places due to my options(digits) setting. options(digits=20) round(x,10) [1] 235.2207116136 There are other ways to manipulate with printed digits. You can start with ?options Cheers Petr -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Shivi82 Sent: Wednesday, June 17, 2015 2:15 PM To: r-help@r-project.org Subject: Re: [R] Restricting Decimal Places in the Output Hi Petr, The solution you shared worked though it does not show any decimal values. The output is Group.1 x 11/1/2015309450 2 1/10/2015 332780 Instead of mean i used sum i think that should be fine. aggr-aggregate(retail$weight,list(retail$ship.date),function(x) round(sum(x,0))) So if i change above code to x,1 it changes values to Group.1 x 11/1/2015309451 2 1/10/2015 332781 Thanks, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Restricting-Decimal-Places-in-the-Output- tp4708739p4708755.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému. Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat. Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu. V případě, že je tento e-mail součástí obchodního jednání: - vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu. - a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou. - trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech. - odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system. If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner. The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email. In case that this e-mail forms part of business dealings: - the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning. - if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation. - the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects. - the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the recipient, or the existence of such authorization is known to the recipient of the person represented by the recipient. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
Re: [R] Error bars and CI
Your sample code is working. But I am missing the logic when my dataset is
involved.
My full dataset is this. It is the V1 column I am interested in. I am not
'grouping' here.
V1 IDX
1 0.796 1
2 0.542 2
3 0.510 3
4 0.617 4
5 0.482 5
6 0.387 6
7 0.272 7
8 0.536 8
9 0.498 9
10 0.402 10
11 0.328 11
12 0.542 12
13 0.299 13
14 0.647 14
15 0.291 15
16 0.815 16
17 0.680 17
18 0.363 18
19 0.560 19
20 0.334 20
Thanks,
Mohan
-Original Message-
From: Dennis Murphy [mailto:djmu...@gmail.com]
Sent: Tuesday, June 16, 2015 1:18 AM
To: Radhakrishnan, Mohan (Cognizant)
Subject: Re: [R] Error bars and CI
Hi:
Firstly, your dplyr code to generate the summary data frame is unnecessary and
distracting, particularly since you didn't provide the input data set; you are
asked to provide a *minimal* reproducible example, which you could easily have
done with a built-in data set.
That said, to get what I perceive you want, I used the InsectSprays data from
the autoloaded datasets package.
# Function to compute standard error of a mean sem - function(x)
sqrt(var(x)/length(x))
## Use insectSprays data for illustration ## Compute mean and SE of count for
each level of spray
library(dplyr)
library(ggplot2)
insectSumm - InsectSprays %%
group_by(spray) %%
summarise(mean = mean(count), se = sem(count))
# Since the x-variable is a factor, need to map group = 1 to # draw lines
between factor levels. geom_pointrange() can be # used to produce the 99% CIs
per factor level, geom_errorbar() # for the mean +/- SE. I ordered the geoms so
that the errorbar # is last, but if you want it (mostly) overwritten, put the #
geom_pointrange() call last.
ggplot(insectSumm, aes(x = spray, y = mean)) +
theme_bw() +
geom_line(aes(group = 1), size = 1, color = darkorange) +
geom_pointrange(aes(ymin = mean - qt(.995, 11) * se,
ymax = mean + qt(.995, 11) * se),
size = 1.5, color = firebrick) +
geom_errorbar(aes(ymin = mean - se, ymax = mean + se), width = 0.2,
size = 1)
Clearly, you can pipe all the way through the ggplot() call, but I wanted to
check the contents of the summary data frame first.
Dennis
On Mon, Jun 15, 2015 at 3:51 AM, mohan.radhakrish...@cognizant.com wrote:
Hi,
I want to plot a line graph using this data. IDX is x-axis and V1 is y-axis.
I also want standard error bars and 99% CI to be shown. My code is given
below. The section that plots the graph is the problem. I don't see all the
points in the line graph with error bars. How can I also show the 99% CI in
the graph ?
V1 IDX
1 0.987 21
2 0.585 22
3 0.770 23
4 0.711 24
library(stringr)
library(dplyr)
library(ggplot2)
data - read.table(D:\\jmh\\jmh.txt,sep=\t)
final -data %%
select(V1) %%
filter(grepl(^Iteration, V1)) %%
mutate(V1 = str_extract(V1, \\d+\\.\\d*))
final - mutate(final,IDX = 1:n())
jc - final %%
filter(IDX 21)
#Convert to numeric
jc - data.frame(sapply(jc, function(x) as.numeric(as.character(x
print(jc)
# The following section is the problem.
sem - function(x){
sd(x)/sqrt(length(x))
}
meanvalue - apply(jc,2,mean)
semvalue - apply(jc, 2, sem)
mean_sem - data.frame(mean= meanvalue, sem= semvalue,
group=names(jc))
#larger font
theme_set(theme_gray(base_size = 20))
#plot using ggplot
p - ggplot(mean_sem, aes(x=group, y=mean)) +
geom_line(stat='identity') +
geom_errorbar(aes(ymin=mean-sem, ymax=mean+sem),
width=.2)
print(p)
Thanks,
Mohan
This e-mail and any files transmitted with it are for the sole use of the
intended recipient(s) and may contain confidential and privileged
information. If you are not the intended recipient(s), please reply to the
sender and destroy all copies of the original message. Any unauthorized
review, use, disclosure, dissemination, forwarding, printing or copying of
this email, and/or any action taken in reliance on the contents of this
e-mail is strictly prohibited and may be unlawful. Where permitted by
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[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
This e-mail and any files transmitted with it are for the sole use of the
intended recipient(s) and may contain confidential and privileged information.
If you are not the intended recipient(s), please reply to the sender and
destroy all copies of the original message. Any unauthorized
Re: [R] Restricting Decimal Places in the Output
Dear Shivi On 17/06/2015 13:15, Shivi82 wrote: Hi Petr, The solution you shared worked though it does not show any decimal values. The output is Group.1 x 11/1/2015309450 2 1/10/2015 332780 Instead of mean i used sum i think that should be fine. aggr-aggregate(retail$weight,list(retail$ship.date),function(x) round(sum(x,0))) That adds all the elements of x and zero and then rounds it So if i change above code to x,1 it changes values to That will add all the elements of x and unity and then round it. Notice that your result has increased by unity each time. I think you meant to write round(sum(x), 0) or round(sum(x), 1) as the case may be Group.1 x 11/1/2015309451 2 1/10/2015 332781 Thanks, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Restricting-Decimal-Places-in-the-Output-tp4708739p4708755.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Michael http://www.dewey.myzen.co.uk/home.html __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Restricting Decimal Places in the Output
Hi Petr, The solution you shared worked though it does not show any decimal values. The output is Group.1 x 11/1/2015309450 2 1/10/2015 332780 Instead of mean i used sum i think that should be fine. aggr-aggregate(retail$weight,list(retail$ship.date),function(x) round(sum(x,0))) So if i change above code to x,1 it changes values to Group.1 x 11/1/2015309451 2 1/10/2015 332781 Thanks, Shivi -- View this message in context: http://r.789695.n4.nabble.com/Restricting-Decimal-Places-in-the-Output-tp4708739p4708755.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R-es] Regresión multinivel en R
Hola a todos Una pregunta, ¿existe algún paquete para trabajar modelos de regresión multinivel con R? Saludos ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R-es] Regresión multinivel en R
Hola. Usa lme4 o MCMCglmm, o rstan El mié., 17 de junio de 2015 14:39, José Miguel Contreras García jmcontre...@ugr.es escribió: Hola a todos Una pregunta, ¿existe algún paquete para trabajar modelos de regresión multinivel con R? Saludos ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R] Error bars and CI
I think it could be something like this. But the mean is for the entire set.
Not groups.
I get a graph with this code but error bars are not there.
p-ggplot(jc,aes(IDX,V1,colour=V1))
p - p + stat_summary(fun.y=mean,geom=point)
p - p + stat_summary(fun.y=mean,geom=line)
p - p + stat_summary(fun.data=mean_cl_normal,conf.int = .99, geom=errorbar,
width=0.2)
Thanks,
Mohan
-Original Message-
From: Radhakrishnan, Mohan (Cognizant)
Sent: Wednesday, June 17, 2015 12:54 PM
To: 'Dennis Murphy'
Cc: r-help@r-project.org
Subject: RE: [R] Error bars and CI
Your sample code is working. But I am missing the logic when my dataset is
involved.
My full dataset is this. It is the V1 column I am interested in. I am not
'grouping' here.
V1 IDX
1 0.796 1
2 0.542 2
3 0.510 3
4 0.617 4
5 0.482 5
6 0.387 6
7 0.272 7
8 0.536 8
9 0.498 9
10 0.402 10
11 0.328 11
12 0.542 12
13 0.299 13
14 0.647 14
15 0.291 15
16 0.815 16
17 0.680 17
18 0.363 18
19 0.560 19
20 0.334 20
Thanks,
Mohan
-Original Message-
From: Dennis Murphy [mailto:djmu...@gmail.com]
Sent: Tuesday, June 16, 2015 1:18 AM
To: Radhakrishnan, Mohan (Cognizant)
Subject: Re: [R] Error bars and CI
Hi:
Firstly, your dplyr code to generate the summary data frame is unnecessary and
distracting, particularly since you didn't provide the input data set; you are
asked to provide a *minimal* reproducible example, which you could easily have
done with a built-in data set.
That said, to get what I perceive you want, I used the InsectSprays data from
the autoloaded datasets package.
# Function to compute standard error of a mean sem - function(x)
sqrt(var(x)/length(x))
## Use insectSprays data for illustration ## Compute mean and SE of count for
each level of spray
library(dplyr)
library(ggplot2)
insectSumm - InsectSprays %%
group_by(spray) %%
summarise(mean = mean(count), se = sem(count))
# Since the x-variable is a factor, need to map group = 1 to # draw lines
between factor levels. geom_pointrange() can be # used to produce the 99% CIs
per factor level, geom_errorbar() # for the mean +/- SE. I ordered the geoms so
that the errorbar # is last, but if you want it (mostly) overwritten, put the #
geom_pointrange() call last.
ggplot(insectSumm, aes(x = spray, y = mean)) +
theme_bw() +
geom_line(aes(group = 1), size = 1, color = darkorange) +
geom_pointrange(aes(ymin = mean - qt(.995, 11) * se,
ymax = mean + qt(.995, 11) * se),
size = 1.5, color = firebrick) +
geom_errorbar(aes(ymin = mean - se, ymax = mean + se), width = 0.2,
size = 1)
Clearly, you can pipe all the way through the ggplot() call, but I wanted to
check the contents of the summary data frame first.
Dennis
On Mon, Jun 15, 2015 at 3:51 AM, mohan.radhakrish...@cognizant.com wrote:
Hi,
I want to plot a line graph using this data. IDX is x-axis and V1 is y-axis.
I also want standard error bars and 99% CI to be shown. My code is given
below. The section that plots the graph is the problem. I don't see all the
points in the line graph with error bars. How can I also show the 99% CI in
the graph ?
V1 IDX
1 0.987 21
2 0.585 22
3 0.770 23
4 0.711 24
library(stringr)
library(dplyr)
library(ggplot2)
data - read.table(D:\\jmh\\jmh.txt,sep=\t)
final -data %%
select(V1) %%
filter(grepl(^Iteration, V1)) %%
mutate(V1 = str_extract(V1, \\d+\\.\\d*))
final - mutate(final,IDX = 1:n())
jc - final %%
filter(IDX 21)
#Convert to numeric
jc - data.frame(sapply(jc, function(x) as.numeric(as.character(x
print(jc)
# The following section is the problem.
sem - function(x){
sd(x)/sqrt(length(x))
}
meanvalue - apply(jc,2,mean)
semvalue - apply(jc, 2, sem)
mean_sem - data.frame(mean= meanvalue, sem= semvalue,
group=names(jc))
#larger font
theme_set(theme_gray(base_size = 20))
#plot using ggplot
p - ggplot(mean_sem, aes(x=group, y=mean)) +
geom_line(stat='identity') +
geom_errorbar(aes(ymin=mean-sem, ymax=mean+sem),
width=.2)
print(p)
Thanks,
Mohan
This e-mail and any files transmitted with it are for the sole use of the
intended recipient(s) and may contain confidential and privileged
information. If you are not the intended recipient(s), please reply to the
sender and destroy all copies of the original message. Any unauthorized
review, use, disclosure, dissemination, forwarding, printing or copying of
this email, and/or any action taken in reliance on the contents of this
e-mail is strictly prohibited and may be unlawful. Where permitted by
applicable law, this e-mail and other e-mail communications sent to and from
Cognizant e-mail addresses may be monitored.
[[alternative HTML version deleted]]
[R] how to call rbind using arguments from a list
Hello R users, I am trying to run the command rbind gathering the name of tables to bind from a list argument. Unfortunately I am not able to obtain it. I would appreciate any suggestions. Below is a reproducible example with the problem. Thanks Matteo ## ZA-data.frame(x = 1:2, y = 1:10,z=letters[1:5]) ZB-data.frame(x = 1, y = 5:24,z=letters[2]) a-as.list(ls(pattern= ^Z?));a # I_would_like_ZC-rbind(ZA,ZB) # this is what I would like to have # b-(paste(a, collapse = ',')) call(rbind,(b)) # I am not able to remove b-noquote(paste(a, collapse = ',')) call(rbind,(b)) # I am not able to remove [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to call rbind using arguments from a list
1. It should be: a-as.list(ls(pattern= ^Z.)) to get Z at the beginning and 1 further character. 2. Use do.call() instead of call(). The latter does not evaluate the call; the former does. 3. But most important, the args argument of do.call() must be a list of names, not character strings. This can be obtained using as.name(). This can all be effected by: a-as.list(ls(pattern= ^Z.)) do.call(rbind,lapply(a,as.name)) -- and please post in plain text, not HTML, as HTML often gets mangled when reproduced on this plain text list. Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Wed, Jun 17, 2015 at 2:58 AM, Matteo mmur...@tiscali.it wrote: Hello R users, I am trying to run the command rbind gathering the name of tables to bind from a list argument. Unfortunately I am not able to obtain it. I would appreciate any suggestions. Below is a reproducible example with the problem. Thanks Matteo ## ZA-data.frame(x = 1:2, y = 1:10,z=letters[1:5]) ZB-data.frame(x = 1, y = 5:24,z=letters[2]) a-as.list(ls(pattern= ^Z?));a # I_would_like_ZC-rbind(ZA,ZB) # this is what I would like to have # b-(paste(a, collapse = ',')) call(rbind,(b)) # I am not able to remove b-noquote(paste(a, collapse = ',')) call(rbind,(b)) # I am not able to remove [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R-es] Regresión logística
Gracias Freddy, aumentar el número máximo de iteraciones ha funcionado... Eric, una pequeña muestra de mis datos sería esta, In.hospital_death GCS BUN 0 15 10,5 0 15 18 0 5 3 0 15 20 0 15 35 0 9 16,5 0 15 31,5 1 10 59 0 15 22 0 15 19 0 15 56 0 15 9 0 15 17 0 15 85 0 15 42 0 15 18 0 12,5 35 0 15 31 0 11 17 0 15 10 1 15 6 0 15 15,5 0 15 29,5 0 15 55 0 NA 9 0 15 23,5 1 7 22 0 8 24 Donde DatosGLM sería lo anterior definido como data.table, Este código ya funionaría: library(data.table) GLM - bigglm(In.hospital_death ~ GCS + BUN, data = DatosGLM, family = binomial(logit), maxit=1000). Ultimamente he descubierto el interfaz gráfico Rcommander es muy util para trabajar con los que no estamos muy sueltos con R, para hacer entre otras cosas, regresiones logísticas. Te permite importar datos directamente entre otros, desde excel. Yo me lo he instalado pero no me aparece esa opción, no parece que sea por el sistema operativo (windows 8), porque he probado sobre windows 7 y me ocurre lo mismo. Alguien sabe cual es el problema??? Gracias (aunque quizá esta pregunta debería haberla puesto como otra distinta en el foro, Un saludo MªLuz El 16 de junio de 2015, 21:27, eric ericconchamu...@gmail.com escribió: MaLuz, podrias adjuntar los datos o una direccion de donde descargarlos para ejecutar tu codigo y replicar el problema ? justo estoy trabajando en unas regresiones logisticas y quiza podria darte una mano. Saludos, eric. On 16/06/15 05:01, MªLuz Morales wrote: Gracias! El 15 de junio de 2015, 16:54, Freddy Omar López Quintero freddy.vat...@gmail.com escribió: Holap. ran out of iterations and failed to converge Prueba aumentando el número de iteraciones, con el argumento maxit: GLM - bigglm(In.hospital_death ~ GCS + BUN, data = DatosGLM, family = binomial(logit), maxit=1000) Salud. -- «No soy aquellas sombras tutelares que honré con versos que no olvida el tiempo.» JL Borges [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es -- Forest Engineer Master in Environmental and Natural Resource Economics Ph.D. student in Sciences of Natural Resources at La Frontera University Member in AguaDeTemu2030, citizen movement for Temuco with green city standards for living Nota: Las tildes se han omitido para asegurar compatibilidad con algunos lectores de correo. [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
[R] Merra hourly data
I am wondering if any has a script to download hourly Merra data (I am interested in wind speed and temperature) Thank you for your help AT [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R-es] Problemas al cargar Rcomander en consola de Rstudio
Holap. Loading required package: splinesLoading required package: RcmdrMiscLoading required package: carLoading required package: sandwichError : .onLoad failed in loadNamespace() for 'Rcmdr', details: call: structure(.External(.C_dotTclObjv, objv), class = tclObj) error: [tcl] invalid command name tk_messageBox. In addition: Warning message:In fun(libname, pkgname) : couldn't connect to display :0Error: package or namespace load failed for ‘Rcmdr’ Quizás peco de ingenuo pero: ¿has verificado que car y sandwich estén instalados? [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
[R] problem in function specieslevel of bipartite
Dear all, I have data for an bipartite mutualistic interaction network and I am trying to generate network metrics for this data set. All metrics could be calculated correctly. However, when trying to run specieslevel function of the package bipartite, I have the following problem: xx - specieslevel(matt) Erro em data.frame(degree = c(16, 11, 6, 5, 6, 4, 5, 4, 2, 5, 7, 4, 4, : string multibyte inválida 4 orxx - specieslevel(matt, index=species strength) Erro em data.frame(`species strength` = c(8.60588008182592, 3.82680284670328, : string multibyte inválida 4 Do you have a clue on what may be the problem? Thanks in advance!Best,Bernardo Niebuhr [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
