[R] reikon: A package to interact with Thomson Reuters Eikon from R
Hi, I'm developing a package to interact from R with Eikon, the Thomson Reuters financial data platform (a la Rblpapi). You can find the package in Bitbucket at https://bitbucket.org/juancentro/reikon. The package is fully functional, but requires testing and usage in other environments than mine. It has documentation and a vignette. Please report any bugs directly in Bitbucket, and I would gladly accept help with the development. Regards Juan [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Running R in Server
Hello, I have written a R script which runs a regression of a dataset and saves the result in a csv file. Now this dataset has to be edited periodically which is done in a server. I need to run the R script in a server so that the results can also be shared in a server and used in a web application. I have coded in R and have used R in windows. I have never used Ubuntu/Linux. Is there a step by step guide on how to run a R code in server? Thanks and Regards, -- Swagato Chatterjee [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Running R in Server
Hello, I have written a R script which runs a regression of a dataset and saves the result in a csv file. Now this dataset has to be edited periodically which is done in a server. I need to run the R script in a server so that the results can also be shared in a server and used in a web application. I have coded in R and have used R in windows. I have never used Ubuntu/Linux. Is there a step by step guide on how to run a R code in server? Thanks and Regards, Swagato [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] All results not showing in console (very large dataset)
Write the results into an object and use head()? Quick example dat1 - data.frame(aa = sample(x, 500, replace = TRUE), bb = sample(x, 500, replace = TRUE), cc = sample(x, 500, replace = TRUE), dd =sample(x, 500, replace = TRUE) ) head(dat1) see ?head for more details John Kane Kingston ON Canada -Original Message- From: hazel_kn...@hotmail.co.uk Sent: Sun, 16 Aug 2015 02:10:51 -0700 (PDT) To: r-help@r-project.org Subject: [R] All results not showing in console (very large dataset) Hi, I have a very large dataset, and have run a simper test on it. However, the output is so large that I cannot see the first sets of results in the console. How can I view them? I have tried saving to text, but it only saves what's in the console. Or is there a way to report the first X number of results from each contrasting test? Or summarise each test result individually? Thanks! -- View this message in context: http://r.789695.n4.nabble.com/All-results-not-showing-in-console-very-large-dataset-tp4711150.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks orcas on your desktop! __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] All results not showing in console (very large dataset)
Hi, I have a very large dataset, and have run a simper test on it. However, the output is so large that I cannot see the first sets of results in the console. How can I view them? I have tried saving to text, but it only saves what's in the console. Or is there a way to report the first X number of results from each contrasting test? Or summarise each test result individually? Thanks! -- View this message in context: http://r.789695.n4.nabble.com/All-results-not-showing-in-console-very-large-dataset-tp4711150.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Error
Dear Sir,
I am getting this error
Error in rep(xi, length.out = nvar) :
attempt to replicate an object of type 'closure'
I have read through the websites but cant really comprehend what this means?
Need your help.
This is my code
complete - function(directory, idvec = 1:332) {
df - data.frame(id = integer(), nobs = integer())
for (id in idvec) {
filename - paste(directory, /,
sprintf(%03d, as.integer(id)),
.csv, sep = )
filename - list.files()
data - rbind(data, read.csv(filename[id]))
}
str(data)
for (id in idvec)
{nd - data.frame(id = id,
nobs = nrow(na.omit(data)))
df - rbind(df, nd)
}
return(df)
}
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] difference between write.csv(...) and write.table(..., sep=, )
On 16-08-2015, at 16:38, Jinsong Zhao jsz...@yeah.net wrote: Hi there, I notice that write.csv is a wrap of write.table. However, I can't get the same results using both functions. Here is a reproducible example: x - matrix(1:6, nrow =2) rownames(x) - letters[1:2] colnames(x) - LETTERS[1:3] write.csv(x, ) ,A,B,C a,1,3,5 b,2,4,6 write.table(x, , sep = ,) A,B,C a,1,3,5 b,2,4,6 The difference of outputs from both functions is clear. Is it possible to get the same results of write.csv using write.table? Yes. Read the item col.names in the help for write.table and go to the section “CSV files”.. Use write.table(x, , sep = ,, col.names=NA) Learn to use R’s help. Berend Any suggestions will be really appreciated. Thanks in advance. Best, Jinsong __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] cut variable within a loop
Hi David, Thanks for your comment. I'll explain what I want to do. I explained it already earlier but the explanation might have gone lost in some of the emails. The variable irrigation ranges from 0 to 100. (maybe not in de small sample I gave, but in reality I have over 6 observations and there the variable ranges from 0 to 100). I want to make (and use) 100 different samples. The sample is based each time on the i that I put at the beginning of the loop. So: i = 1: this means there are 2 subsets. One from 0-1, another from 1-100 i = 2: this means there are 2 subsets. One from 0-2, another from 2-100 i = 3: this means there are 2 subsets. One from 0-3, another from 3-100 i = 4: this means there are 2 subsets. One from 0-4, another from 4-100 ... i = 96: this means there are 2 subsets. One from 0-96, another from 96-100 i = 97: this means there are 2 subsets. One from 0-97, another from 97-100 i = 98: this means there are 2 subsets. One from 0-98, another from 98-100 i = 99: this means there are 2 subsets. One from 0-99, another from 99-100 It might be possible that i = 1 and i = 2 give the same results in the small dataset. But in the full dataset all numbers are represented. The cut2 function is capable of cutting a sample based on a number supplied. Yet, when I tell him this number is i, then it doesn't work. If instead I write that the number is 10, then it does work and it gives me 2 subsets from 0-10 and from 10-100. Hope this is more clear! Janka 2015-08-14 20:10 GMT+02:00 David Winsemius dwinsem...@comcast.net: When using a function in R you may need to supply an argument name. Are you expecting this to be the number of groups. I cannot decipher the intent here with such sparse commentary, but this call to `cut2` does not make sense to me. Perhaps you meant the number of groups? in which case you need cut2( Alldata$irrigation, g=i ), since the arguments to cut2 are not that same as the arguments to cut. At the moment you are implicitly sending on the first pass a 1 and then on the second pass a 2 to the second argument of cut2 which is the `breaks` argument. So you wold be getting two different factors each with different cut-point levels. I looked at your data and in point of fact there would be no difference since you have 29 zero values and no values between 0 and 1. table(cut2(dat$irrigation, 1)) 0 [ 1,100] 2921 table(cut2(dat$irrigation, 2)) 0 [ 2,100] 2921 levels(Alldata$irri)-c(0,1) Alldata_Rainfed-subset(Alldata, irri == 0) Alldata_Irrigation-subset(Alldata, irri == 1) Alldata_Rainfed$w-Alldata_Rainfed$b48+Alldata_Rainfed$b50 Alldata_Irrigation$w-Alldata_Irrigation$b48+Alldata_Irrigation$b50 OLS_Rainfed - lm(LnALVperHA~ps1+ps2+ps3+ps4+ts1+ts2+ts3+ts4+ ps1sq+ps2sq+ps3sq+ps4sq+ts1sq+ts2sq+ts3sq+ts4sq+ pdnsty+portsML+cities500k+rentedland+subsidies1+ elevmean+elevrange+ t_gravel+t_gravel+t_ph_h2o+t_silt+t_sand+ AT+BE+DK+ES+FI+FR+GR+IE+IT+LU+NL+PT+SE+WDE+EDE+UK, weights=w,Alldata_Rainfed) attach(Alldata_Rainfed) CoefRainfed_ps1 - OLS_Rainfed$coeff[2] CoefRainfed_ps2 - OLS_Rainfed$coeff[3] CoefRainfed_ps3 - OLS_Rainfed$coeff[4] CoefRainfed_ps4 - OLS_Rainfed$coeff[5] CoefRainfed_ts1 - OLS_Rainfed$coeff[6] CoefRainfed_ts2 - OLS_Rainfed$coeff[7] CoefRainfed_ts3 - OLS_Rainfed$coeff[8] CoefRainfed_ts4 - OLS_Rainfed$coeff[9] CoefRainfed_ps1sq - OLS_Rainfed$coeff[10] CoefRainfed_ps2sq - OLS_Rainfed$coeff[11] CoefRainfed_ps3sq - OLS_Rainfed$coeff[12] CoefRainfed_ps4sq - OLS_Rainfed$coeff[13] CoefRainfed_ts1sq - OLS_Rainfed$coeff[14] CoefRainfed_ts2sq - OLS_Rainfed$coeff[15] CoefRainfed_ts3sq - OLS_Rainfed$coeff[16] CoefRainfed_ts4sq - OLS_Rainfed$coeff[17] attach(Alldata_Rainfed) ## MARGINAL EFFECTS SEASONAL and YEARLY and REGIONAL (EU or COUNTRY level) # Maar dit is dus de marginale impact per LnALVperHA? Alldata_Rainfed$MEts1 = CoefRainfed_ts1+2*CoefRainfed_ts1sq*Alldata_Rainfed$ts1 Alldata_Rainfed$MEts2 = CoefRainfed_ts2+2*CoefRainfed_ts2sq*Alldata_Rainfed$ts2 Alldata_Rainfed$MEts3 = CoefRainfed_ts3+2*CoefRainfed_ts3sq*Alldata_Rainfed$ts3 Alldata_Rainfed$MEts4 = CoefRainfed_ts4+2*CoefRainfed_ts4sq*Alldata_Rainfed$ts4 Alldata_Rainfed$MEt = Alldata_Rainfed$MEts1 + Alldata_Rainfed$MEts2 + Alldata_Rainfed$MEts3 + Alldata_Rainfed$MEts4 Alldata_Rainfed$MEps1 = CoefRainfed_ps1+2*CoefRainfed_ps1sq*Alldata_Rainfed$ps1 Alldata_Rainfed$MEps2 = CoefRainfed_ps2+2*CoefRainfed_ps2sq*Alldata_Rainfed$ps2 Alldata_Rainfed$MEps3 = CoefRainfed_ps3+2*CoefRainfed_ps3sq*Alldata_Rainfed$ps3 Alldata_Rainfed$MEps4 = CoefRainfed_ps4+2*CoefRainfed_ps4sq*Alldata_Rainfed$ps4 Alldata_Rainfed$MEp = Alldata_Rainfed$MEps1 + Alldata_Rainfed$MEps2 +
Re: [R] difference between write.csv(...) and write.table(..., sep=, )
On Aug 16, 2015, at 9:38 AM, Jinsong Zhao jsz...@yeah.net wrote: Hi there, I notice that write.csv is a wrap of write.table. However, I can't get the same results using both functions. Here is a reproducible example: x - matrix(1:6, nrow =2) rownames(x) - letters[1:2] colnames(x) - LETTERS[1:3] write.csv(x, ) ,A,B,C a,1,3,5 b,2,4,6 write.table(x, , sep = ,) A,B,C a,1,3,5 b,2,4,6 The difference of outputs from both functions is clear. Is it possible to get the same results of write.csv using write.table? Any suggestions will be really appreciated. Thanks in advance. Best, Jinsong write.csv(x) ,A,B,C a,1,3,5 b”,2,4,6 write.table(x, sep = ,, qmethod = double, col.names = NA) ,A,B,C a,1,3,5 b”,2,4,6 Read the section on CSV files in ?write.table Regards, Marc Schwartz __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] difference between write.csv(...) and write.table(..., sep=, )
I think that if you do ?write.csv and then page down to the section entitled CSV files the mystery will be solved for you in the first few paragraphs. On 16/08/2015 15:38, Jinsong Zhao wrote: Hi there, I notice that write.csv is a wrap of write.table. However, I can't get the same results using both functions. Here is a reproducible example: x - matrix(1:6, nrow =2) rownames(x) - letters[1:2] colnames(x) - LETTERS[1:3] write.csv(x, ) ,A,B,C a,1,3,5 b,2,4,6 write.table(x, , sep = ,) A,B,C a,1,3,5 b,2,4,6 The difference of outputs from both functions is clear. Is it possible to get the same results of write.csv using write.table? Any suggestions will be really appreciated. Thanks in advance. Best, Jinsong __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Michael http://www.dewey.myzen.co.uk/home.html __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] difference between write.csv(...) and write.table(..., sep=, )
Hi there, I notice that write.csv is a wrap of write.table. However, I can't get the same results using both functions. Here is a reproducible example: x - matrix(1:6, nrow =2) rownames(x) - letters[1:2] colnames(x) - LETTERS[1:3] write.csv(x, ) ,A,B,C a,1,3,5 b,2,4,6 write.table(x, , sep = ,) A,B,C a,1,3,5 b,2,4,6 The difference of outputs from both functions is clear. Is it possible to get the same results of write.csv using write.table? Any suggestions will be really appreciated. Thanks in advance. Best, Jinsong __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Error
What do you think data is in:
rbind(data, read.csv(filename[id]))
str(data) ## before running your function
will show you that it is probably the built in function data() which
is probably the source of your error.
Cheers,
Bert
Bert Gunter
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
-- Clifford Stoll
On Sun, Aug 16, 2015 at 2:01 AM, Nikita Dinger dingernik...@gmail.com wrote:
Dear Sir,
I am getting this error
Error in rep(xi, length.out = nvar) :
attempt to replicate an object of type 'closure'
I have read through the websites but cant really comprehend what this means?
Need your help.
This is my code
complete - function(directory, idvec = 1:332) {
df - data.frame(id = integer(), nobs = integer())
for (id in idvec) {
filename - paste(directory, /,
sprintf(%03d, as.integer(id)),
.csv, sep = )
filename - list.files()
data - rbind(data, read.csv(filename[id]))
}
str(data)
for (id in idvec)
{nd - data.frame(id = id,
nobs = nrow(na.omit(data)))
df - rbind(df, nd)
}
return(df)
}
[[alternative HTML version deleted]]
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Error while submission
I have completed part 2 of the assignment and am getting the desired output.
But on submitting the code, it shows as the answer is incorrect along with
this message:
function (..., list = character(), package = NULL, lib.loc = NULL, verbose
= getOption(verbose),
envir = .GlobalEnv)
Result: Sorry, your answer was incorrect.
The following is my code for part 2:
complete - function(directory, idvec = 1:332) {
df - data.frame(id = integer(), nobs = integer())
for (id in idvec) {
filename - paste(directory, /,
sprintf(%03d, as.integer(id)),
5.csv, sep = )
filename - list.files()
dat - rbind(dat, read.csv(filename[id]))
}
str(data)
for (id in idvec)
{nd - data.frame(id = id,
nobs = nrow(na.omit(dat)))
df - rbind(df, nd)
}
return(df)
}
I am using R 3.2.1 on a Windows 8 laptop.
How shall I solve this?
Thanks and regards
Nikita
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] cut variable within a loop
On Aug 16, 2015, at 8:57 AM, Janka VANSCHOENWINKEL wrote:
Hi David,
Thanks for your comment. I'll explain what I want to do. I explained it
already earlier but the explanation might have gone lost in some of the
emails.
I now see that you did explain that you wanted the positional matching in cut2
as a break. The code runs without error on my machine, but delivers a lot of
warnings about masking. You are repeatedly using attach on the same named
objects. Using `attach` in programming is generally not a good idea. In
interactive use it is safer to use `with`, although that is not generally
considered safe in programming, either.
You need to do a better job of nailing down the source of the difficulty what
ever it might be. While you say the cut2 function doesn't work, you don't
actually give evidence of failure.
It's fairly simple to show that your theory about why your code fails in some
way as being due to cut2 failing to accept an i value inside an lapply call
is just wrong:
o - lapply(1:3, function(i) { cut2( 0:10, i) } )
o
[[1]]
[1] 0 [ 1,10] [ 1,10] [ 1,10] [ 1,10] [ 1,10] [ 1,10]
[8] [ 1,10] [ 1,10] [ 1,10] [ 1,10]
Levels: 0 [ 1,10]
[[2]]
[1] [ 0, 2) [ 0, 2) [ 2,10] [ 2,10] [ 2,10] [ 2,10] [ 2,10]
[8] [ 2,10] [ 2,10] [ 2,10] [ 2,10]
Levels: [ 0, 2) [ 2,10]
[[3]]
[1] [ 0, 3) [ 0, 3) [ 0, 3) [ 3,10] [ 3,10] [ 3,10] [ 3,10]
[8] [ 3,10] [ 3,10] [ 3,10] [ 3,10]
Levels: [ 0, 3) [ 3,10]
You also have two different definitions of weight2 for your irrigation model:
Alldata_Irrigation$weight2-Alldata_Irrigation$sys02*Alldata_Irrigation$se025
Alldata_Irrigation$weight2-Alldata_Irrigation$b48+Alldata_Irrigation$b50
--
David
The variable irrigation ranges from 0 to 100. (maybe not in de small sample I
gave, but in reality I have over 6 observations and there the variable
ranges from 0 to 100). I want to make (and use) 100 different samples. The
sample is based each time on the i that I put at the beginning of the loop.
So:
i = 1: this means there are 2 subsets. One from 0-1, another from 1-100
i = 2: this means there are 2 subsets. One from 0-2, another from 2-100
i = 3: this means there are 2 subsets. One from 0-3, another from 3-100
i = 4: this means there are 2 subsets. One from 0-4, another from 4-100
...
i = 96: this means there are 2 subsets. One from 0-96, another from 96-100
i = 97: this means there are 2 subsets. One from 0-97, another from 97-100
i = 98: this means there are 2 subsets. One from 0-98, another from 98-100
i = 99: this means there are 2 subsets. One from 0-99, another from 99-100
It might be possible that i = 1 and i = 2 give the same results in the small
dataset. But in the full dataset all numbers are represented.
The cut2 function is capable of cutting a sample based on a number
supplied. Yet, when I tell him this number is i, then it doesn't work. If
instead I write that the number is 10, then it does work and it gives me 2
subsets from 0-10 and from 10-100.
Hope this is more clear!
Janka
2015-08-14 20:10 GMT+02:00 David Winsemius dwinsem...@comcast.net:
When using a function in R you may need to supply an argument name. Are you
expecting this to be the number of groups. I cannot decipher the intent here
with such sparse commentary, but this call to `cut2` does not make sense to
me. Perhaps you meant the number of groups? in which case you need
cut2( Alldata$irrigation, g=i ), since the arguments to cut2 are not that
same as the arguments to cut.
At the moment you are implicitly sending on the first pass a 1 and then on
the second pass a 2 to the second argument of cut2 which is the `breaks`
argument. So you wold be getting two different factors each with different
cut-point levels. I looked at your data and in point of fact there would be
no difference since you have 29 zero values and no values between 0 and 1.
table(cut2(dat$irrigation, 1))
0 [ 1,100]
2921
table(cut2(dat$irrigation, 2))
0 [ 2,100]
2921
levels(Alldata$irri)-c(0,1)
Alldata_Rainfed-subset(Alldata, irri == 0)
Alldata_Irrigation-subset(Alldata, irri == 1)
Alldata_Rainfed$w-Alldata_Rainfed$b48+Alldata_Rainfed$b50
Alldata_Irrigation$w-Alldata_Irrigation$b48+Alldata_Irrigation$b50
OLS_Rainfed - lm(LnALVperHA~ps1+ps2+ps3+ps4+ts1+ts2+ts3+ts4+
ps1sq+ps2sq+ps3sq+ps4sq+ts1sq+ts2sq+ts3sq+ts4sq+
pdnsty+portsML+cities500k+rentedland+subsidies1+
elevmean+elevrange+
t_gravel+t_gravel+t_ph_h2o+t_silt+t_sand+
AT+BE+DK+ES+FI+FR+GR+IE+IT+LU+NL+PT+SE+WDE+EDE+UK,
weights=w,Alldata_Rainfed)
attach(Alldata_Rainfed)
CoefRainfed_ps1 - OLS_Rainfed$coeff[2]
CoefRainfed_ps2 - OLS_Rainfed$coeff[3]
CoefRainfed_ps3 - OLS_Rainfed$coeff[4]
CoefRainfed_ps4 - OLS_Rainfed$coeff[5]
Re: [R] Error while submission
On Sun, Aug 16, 2015 at 12:39 PM, Nikita Dinger dingernik...@gmail.com wrote:
I have completed part 2 of the assignment and am getting the desired output.
But on submitting the code, it shows as the answer is incorrect along with
this message:
This list is not an appropriate place for you to ask for help with
your homework. Your course should have a way for you to get assistance
from instructor/TA/other students; this is not that way.
We on R-help can't do much for you, since none of us have any idea
what part 2 might be, and the list has a no-homework policy anyway.
function (..., list = character(), package = NULL, lib.loc = NULL, verbose
= getOption(verbose),
envir = .GlobalEnv)
Result: Sorry, your answer was incorrect.
The following is my code for part 2:
complete - function(directory, idvec = 1:332) {
df - data.frame(id = integer(), nobs = integer())
for (id in idvec) {
filename - paste(directory, /,
sprintf(%03d, as.integer(id)),
5.csv, sep = )
filename - list.files()
dat - rbind(dat, read.csv(filename[id]))
}
str(data)
for (id in idvec)
{nd - data.frame(id = id,
nobs = nrow(na.omit(dat)))
df - rbind(df, nd)
}
return(df)
}
I am using R 3.2.1 on a Windows 8 laptop.
How shall I solve this?
Thanks and regards
Nikita
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Error while submission
Go to where you were given this assignment and ask them for help.
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On August 16, 2015 9:39:28 AM PDT, Nikita Dinger dingernik...@gmail.com wrote:
I have completed part 2 of the assignment and am getting the desired
output.
But on submitting the code, it shows as the answer is incorrect along
with
this message:
function (..., list = character(), package = NULL, lib.loc = NULL,
verbose
= getOption(verbose),
envir = .GlobalEnv)
Result: Sorry, your answer was incorrect.
The following is my code for part 2:
complete - function(directory, idvec = 1:332) {
df - data.frame(id = integer(), nobs = integer())
for (id in idvec) {
filename - paste(directory, /,
sprintf(%03d, as.integer(id)),
5.csv, sep = )
filename - list.files()
dat - rbind(dat, read.csv(filename[id]))
}
str(data)
for (id in idvec)
{nd - data.frame(id = id,
nobs = nrow(na.omit(dat)))
df - rbind(df, nd)
}
return(df)
}
I am using R 3.2.1 on a Windows 8 laptop.
How shall I solve this?
Thanks and regards
Nikita
[[alternative HTML version deleted]]
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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Re: [R] Error - cannot open file 'specdata/001.csv': No such file or directory; Windows 8, R Version 3.2.1
Hi Nikita, To check whether the files are really there, run the following at the R prompt: getwd() list.files() *C:/Users/acer/My Documents/specdata/rprog-data-specdata/specdata* Your working path looks like you either need to set it to: C:/Users/acer/My Documents/specdata/rprog-data-specdata or change your read.csv to: df - read.csv(001.csv) cheers Peter On 15 Aug 2015, at 19:06, Nikita Dinger dingernik...@gmail.com wrote: I am having a problem in opening the excel files in specdata folder. I have completed coding the R program for the assignment but when I run the following commands in the R console, *source(pollutantmean.R)* * pollutantmean(specdata, nitrate, 23)* I get an error message stating *Error in file(file, rt) : cannot open the connection* *In addition: Warning message:* *In file(file, rt) :* * cannot open file 'specdata/023.csv': No such file or directory* I tried everything and reset my Working Directory to *C:/Users/acer/My Documents/specdata/rprog-data-specdata/specdata* After the last specdata folder are all the excel sheets numbered 001 to 332. I searched the internet and all other options available, and got a solution to open it using the following command: *df - read.csv(specdata/001.csv)* This generated the following error message *Error in file(file, rt) : cannot open the connection* *In addition: Warning message:* *In file(file, rt) :* * cannot open file 'specdata/001.csv': No such file or directory* I have tried various other commands also such as *path - c(paste(./,directory, /,formatC(id[i], width=3, flag=0),.csv,sep=))* However, all the commands show some error. What shall I do? I am using the 3.2.1 version of R on a Windows 8 laptop. Regards, Nikita Dinger [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
