Re: [R] list of lists, is this element empty
Your 'x' has length 2, so x[[3]] cannot be calculated ('subscript out of
bounds' is what I get). You can check for this with length(x)3.
In general, you want to be more precise: 'does not have a value', 'is
NULL', and 'is empty' are not synonymous. I'm not sure what 'does not have
a value' means to you. NULL is a value with a certain type, 'NULL', and
length, 0. seq_len(0) is empty, but not NULL, since it has type 'integer'.
c(1,NA) contains a 'missing value'. Can you explain what what you are
trying to check for, giving some context?
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Sat, Dec 20, 2014 at 7:58 AM, Ragia Ibrahim ragi...@hotmail.com wrote:
Hello,
Kindly I have a list of lists as follow
x
[[1]]
[1] 7
[[2]]
[1] 3 4 5
as showen x[[3]] does not have a value and it has NULL, how can I check on
this
how to test if x[[3]] is empty.
thanks in advance
Ragia
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[R] list of lists, is this element empty
Hello, Kindly I have a list of lists as follow x [[1]] [1] 7 [[2]] [1] 3 4 5 as showen x[[3]] does not have a value and it has NULL, how can I check on this how to test if x[[3]] is empty. thanks in advance Ragia [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] list of lists, is this element empty
Hi,
On Dec 20, 2014, at 10:58 AM, Ragia Ibrahim ragi...@hotmail.com wrote:
Hello,
Kindly I have a list of lists as follow
x
[[1]]
[1] 7
[[2]]
[1] 3 4 5
as showen x[[3]] does not have a value and it has NULL, how can I check on
this
how to test if x[[3]] is empty.
In general you can us is.null()
x - list(7, 3:5, NULL, A)
is.null(x[[3]])
[1] TRUE
but be aware that trying access an element by index that is greater than the
length of the list will cause you issues.
is.null(x[[10]])
Error in x[[10]] : subscript out of bounds
You can make your own function to test for the existence of an element and if
it is NULL. Note that the function isn't complete in the sense that it doesn't
test if you provide an negative index, that x is not a list, etc. You can add
all of those tests in.
is_null - function(x, index){
( index[1] length(x) ) || is.null(x[[index[1]]])
}
is_null(x, 1)
[1] FALSE
is_null(x, 3)
[1] TRUE
is_null(x, 10)
[1] TRUE
There a lot of info on index at
?`[`
Does that answer your question?
Cheers,
Ben
thanks in advance
Ragia
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Bigelow Laboratory for Ocean Sciences
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East Boothbay, Maine 04544
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Re: [R] list of lists, is this element empty
Hello, Your list seems to have only 2 elements. You can check this with length(x) Or you can try lapply(x, is.null) Hope this helps, Rui Barradas Em 20-12-2014 15:58, Ragia Ibrahim escreveu: Hello, Kindly I have a list of lists as follow x [[1]] [1] 7 [[2]] [1] 3 4 5 as showen x[[3]] does not have a value and it has NULL, how can I check on this how to test if x[[3]] is empty. thanks in advance Ragia [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] list of lists, is this element empty
This can be tricky, because depending on what the missing object is, you can
get either NULL, NA, or an error. Moreover is.na() behaves differently when
evaluated on its own, or as the condition of an if() statement. Here is a
function that may make life easier. The goal is NOT to have to pass extra
arguments.
- I use try() and return FALSE if the evaluation returns an error.
This applies to objects that are not found, incorrect syntax etc.
- List elements that don't exist are NULL and return FALSE.
- If any elements are NA, return FALSE. This handles out-of-bounds
elements AND out-of-bounds slices on vectors. But it would also
trip on valid vectors that contain an NA. I can't think of a good
way to distinguish these two cases right now. The best way for
this depends on the context.
I think I am handling the most obvious special cases - though I do expect this
can be improved.
is.valid - function(x,
na.ignore = FALSE,
null.ignore=FALSE) {
# errors are always FALSE
if (class(try(x, silent=TRUE)) == try-error) return(FALSE)
# NULL is FALSE except if ignored
if (is.null(x)) {
if (!null.ignore) return(FALSE)
return(TRUE)
}
# If all elments are NA, return FALSE except if ignored;
if (any(is.na(x))) {
if (!na.ignore) return(FALSE)
return(TRUE)
}
# Everything else is TRUE
return(TRUE)
}
# Test cases
is.valid(1) # TRUE: valid numeric constant
is.valid(FALSE) # TRUE: valid boolean constant
is.valid(nonSuch) # FALSE: object doesn't exist
x - 1:5;
is.valid(x) # TRUE: existing variable
is.valid(x[4]) # TRUE: vector element
is.valid(x[8]) # FALSE: out of bounds: NA
is.valid(x[5:6])# FALSE: partially out of bounds: (5, NA)
is.valid(x[8], na.ignore=TRUE) # TRUE
x[3] - NA
is.valid(x) # FALSE: no element can be NA
is.valid(x, na.ignore=TRUE) # TRUE
m - matrix(1:9,nrow=3, ncol=3)
is.valid(m[2,2])# TRUE
is.valid(m[2,4])# FALSE: subscript out of bounds
is.valid(m[2,2,2]) # FALSE: incorrect n of dimensions
l - list(first=7, letters, NULL)
is.valid(l[[first]]) # TRUE: existing list elements
is.valid(l[[4]])# FALSE: list element does not exist
is.valid(l[[2]][27])# FALSE: out of bounds on existing element
is.valid(l$first) # TRUE:
is.valid(l$second) # FALSE: non-existent element: NULL
is.valid(l$second, null.ignore=TRUE) # TRUE
Cheers,
B.
On Dec 20, 2014, at 11:20 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
Your list seems to have only 2 elements. You can check this with
length(x)
Or you can try
lapply(x, is.null)
Hope this helps,
Rui Barradas
Em 20-12-2014 15:58, Ragia Ibrahim escreveu:
Hello,
Kindly I have a list of lists as follow
x
[[1]]
[1] 7
[[2]]
[1] 3 4 5
as showen x[[3]] does not have a value and it has NULL, how can I check on
this
how to test if x[[3]] is empty.
thanks in advance
Ragia
[[alternative HTML version deleted]]
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Re: [R] list of lists, is this element empty
Boris et. al:
Indeed, corner cases are a bear, which is why it is incumbent on any
OP to precisely define what they mean by, say, missing,
null,empty, etc.
Here is an evil example to illustrate the sorts of nastiness that can occur:
z - list(a=NULL, b=list(), c=NA)
with(z,{
+ c(identical(a,b),
+ identical(a,c),
+ identical(b,c)
+ )
+ })
[1] FALSE FALSE FALSE
## OK, none of these three are the same in the sense of identical().
But ...
outer(z,z,identical)
Error in outer(z, z, identical) :
dims [product 9] do not match the length of object [1]
## outer gets completely flummoxed, as it should!
expand.grid(z,z)
Var1 Var2
1 NULL NULL
2 NULL NULL
3 NA NULL
4 NULL NULL
5 NULL NULL
6 NA NULL
7 NULL NA
8 NULL NA
9 NA NA
## and expand.grid gets confused, as it probably should.
:-)
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Sat, Dec 20, 2014 at 10:57 AM, Boris Steipe boris.ste...@utoronto.ca wrote:
This can be tricky, because depending on what the missing object is, you can
get either NULL, NA, or an error. Moreover is.na() behaves differently when
evaluated on its own, or as the condition of an if() statement. Here is a
function that may make life easier. The goal is NOT to have to pass extra
arguments.
- I use try() and return FALSE if the evaluation returns an error.
This applies to objects that are not found, incorrect syntax etc.
- List elements that don't exist are NULL and return FALSE.
- If any elements are NA, return FALSE. This handles out-of-bounds
elements AND out-of-bounds slices on vectors. But it would also
trip on valid vectors that contain an NA. I can't think of a good
way to distinguish these two cases right now. The best way for
this depends on the context.
I think I am handling the most obvious special cases - though I do expect
this can be improved.
is.valid - function(x,
na.ignore = FALSE,
null.ignore=FALSE) {
# errors are always FALSE
if (class(try(x, silent=TRUE)) == try-error) return(FALSE)
# NULL is FALSE except if ignored
if (is.null(x)) {
if (!null.ignore) return(FALSE)
return(TRUE)
}
# If all elments are NA, return FALSE except if ignored;
if (any(is.na(x))) {
if (!na.ignore) return(FALSE)
return(TRUE)
}
# Everything else is TRUE
return(TRUE)
}
# Test cases
is.valid(1) # TRUE: valid numeric constant
is.valid(FALSE) # TRUE: valid boolean constant
is.valid(nonSuch) # FALSE: object doesn't exist
x - 1:5;
is.valid(x) # TRUE: existing variable
is.valid(x[4]) # TRUE: vector element
is.valid(x[8]) # FALSE: out of bounds: NA
is.valid(x[5:6])# FALSE: partially out of bounds: (5, NA)
is.valid(x[8], na.ignore=TRUE) # TRUE
x[3] - NA
is.valid(x) # FALSE: no element can be NA
is.valid(x, na.ignore=TRUE) # TRUE
m - matrix(1:9,nrow=3, ncol=3)
is.valid(m[2,2])# TRUE
is.valid(m[2,4])# FALSE: subscript out of bounds
is.valid(m[2,2,2]) # FALSE: incorrect n of dimensions
l - list(first=7, letters, NULL)
is.valid(l[[first]]) # TRUE: existing list elements
is.valid(l[[4]])# FALSE: list element does not exist
is.valid(l[[2]][27])# FALSE: out of bounds on existing element
is.valid(l$first) # TRUE:
is.valid(l$second) # FALSE: non-existent element: NULL
is.valid(l$second, null.ignore=TRUE) # TRUE
Cheers,
B.
On Dec 20, 2014, at 11:20 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
Your list seems to have only 2 elements. You can check this with
length(x)
Or you can try
lapply(x, is.null)
Hope this helps,
Rui Barradas
Em 20-12-2014 15:58, Ragia Ibrahim escreveu:
Hello,
Kindly I have a list of lists as follow
x
[[1]]
[1] 7
[[2]]
[1] 3 4 5
as showen x[[3]] does not have a value and it has NULL, how can I check on
this
how to test if x[[3]] is empty.
thanks in advance
Ragia
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
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Re: [R] list of lists, is this element empty
This may be out of context, but on the face of it, this claim is wrong: On 20/12/2014, 1:57 PM, Boris Steipe wrote: Moreover is.na() behaves differently when evaluated on its own, or as the condition of an if() statement. The conditions in an if() statement are not evaluated in special conditions at all. The only way you'll get a different value is if the argument to is.na() does tricky stuff like looking at the evaluation stack. Duncan Murdoch __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] list of lists, is this element empty
Thanks. This is what I was referring to:
x - rep(NA, 3)
is.na(x)
[1] TRUE TRUE TRUE
if (is.na(x)) {print(True)}
[1] True
Warning message:
In if (is.na(x)) { :
the condition has length 1 and only the first element will be used
You are of course right - the warning is generated by if(), not by is.na() and
the reason for the warning is that is.na() returns a vector if applied to a
vector. I should have been more clear.
Cheers,
B.
On Dec 20, 2014, at 3:29 PM, Duncan Murdoch murdoch.dun...@gmail.com wrote:
This may be out of context, but on the face of it, this claim is wrong:
On 20/12/2014, 1:57 PM, Boris Steipe wrote:
Moreover is.na() behaves differently when evaluated on its own, or as
the condition of an if() statement.
The conditions in an if() statement are not evaluated in special
conditions at all. The only way you'll get a different value is if the
argument to is.na() does tricky stuff like looking at the evaluation stack.
Duncan Murdoch
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Re: [R] List of Lists by for Loop
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Munjal Patel
Sent: Monday, July 14, 2014 8:45 PM
To: r-help@r-project.org
Subject: [R] List of Lists by for Loop
Dear Experts,
I have a one more doubt about making list of lists.
Here is the simple code i have made.
I am doing the following for only one digit=20
You can try something like that (untested)
numbers-c(20, 30, 40, 50)
master-vector(length(numbers), mode=list)
k - 0
for(j in numbers)
{
k-k+1
a=vector(j,mode=list)
b=vector(j,mode=list)
for (i in 1:j){
#Do Calculation
a[[i]]=data.frame()
b[[i]]=data.frame()
}
master[[k]] - list(a, b)
}
Regards
Petr
Now i have to repeat the whole process for Digits=c(30,40,50,60)
In short I want the Master list containing following
List 1(#20)
List a
List b
List 2(#30)
List a
List b
so on
Can you please guide me in this ?
Thank you very much.
Sincerely
--
Munjal Patel
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Re: [R] List of Lists in For Loop
Munjal,
Something like this should work:
Digits = c(20, 30, 40, 50, 60)
result = vector(length(Digits), mode=list)
names(result) = Digits
for(j in seq(Digits)) {
a = vector(Digits[j], mode=list)
b = vector(Digits[j], mode=list)
for(i in 1:Digits[j]) {
#Do Calculation
a[[i]] = data.frame()
b[[i]] = data.frame()
}
result[[j]] = list(a, b)
}
Jean
On Mon, Jul 14, 2014 at 1:35 PM, Munjal Patel munjalpate...@gmail.com
wrote:
Dear Experts,
I have a one more doubt about making list of lists.
Here is the simple code i have made.
I am doing the following for only one digit=20
a=vector(20,mode=list)
b=vector(20,mode=list)
for (i in 1:20){
#Do Calculation
a[[i]]=data.frame()
b[[i]]=data.frame()
}
Now i have to repeat the whole process for Digits=c(30,40,50,60)
In short I want the Master list containing following
List 1(#20)
List a
List b
List 2(#30)
List a
List b
so on
Can you please guide me in this ?
Thank you very much.
Sincerely
--
Munjal
[[alternative HTML version deleted]]
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http://www.R-project.org/posting-guide.html
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[[alternative HTML version deleted]]
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[R] List of Lists by for Loop
Dear Experts,
I have a one more doubt about making list of lists.
Here is the simple code i have made.
I am doing the following for only one digit=20
a=vector(20,mode=list)
b=vector(20,mode=list)
for (i in 1:20){
#Do Calculation
a[[i]]=data.frame()
b[[i]]=data.frame()
}
Now i have to repeat the whole process for Digits=c(30,40,50,60)
In short I want the Master list containing following
List 1(#20)
List a
List b
List 2(#30)
List a
List b
so on
Can you please guide me in this ?
Thank you very much.
Sincerely
--
Munjal Patel
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] List of Lists in For Loop
Dear Experts,
I have a one more doubt about making list of lists.
Here is the simple code i have made.
I am doing the following for only one digit=20
a=vector(20,mode=list)
b=vector(20,mode=list)
for (i in 1:20){
#Do Calculation
a[[i]]=data.frame()
b[[i]]=data.frame()
}
Now i have to repeat the whole process for Digits=c(30,40,50,60)
In short I want the Master list containing following
List 1(#20)
List a
List b
List 2(#30)
List a
List b
so on
Can you please guide me in this ?
Thank you very much.
Sincerely
--
Munjal
[[alternative HTML version deleted]]
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists
Hi,
The solution that works now is
closeAllConnections()
But even if I replace the 'list' with the 'array' I get a similar error.
Exception is Error in UseMethod(\close\): no applicable method for
'close' applied to an object of class \c('double', 'numeric')\\n
#Write each CPU's utilization data into a
#separate file
filelist.array - function(n){
cpufile - list()
cpufiledescriptors - array(n,dim=c(0,n))
length(cpufile) - n
for (i in 1:n) {
cpufile[[i]] - paste(output, i, .txt, sep = )
cpufiledescriptors[i]-file( cpufile[[i]], a )
}
listoffiles - list(cpufile=cpufile,
cpufiledescriptors=cpufiledescriptors)
return (listoffiles)
}
Thanks,
Mohan
Re: [R] List of lists
Jim Lemon
to:
mohan.radhakrishnan
31-07-2013 05:19
PM
On 07/31/2013 04:18 PM, mohan.radhakrish...@polarisft.com wrote:
Hi Jim,
close(filedescriptors$cpufiledescriptors[[1]])
close(filedescriptors$cpufiledescriptors[[2]])
close(filedescriptors$cpufiledescriptors[[3]])
I might be doing something wrong. Error is
Error in UseMethod(close) :
no applicable method for 'close' applied to an object of class c
('integer', 'numeric')
Hi Mohan,
I just ran the code within your function filelist.array and then was
able to close the connections I had created. I entered your function in R:
filelist.array- function(n){
cpufile- list()
cpufiledescriptors- list()
length(cpufile)- n
for (i in 1:n) {
cpufile[[i]]- paste(output, i, .txt, sep = )
cpufiledescriptors[[i]]-file( cpufile[[i]],
a )
}
listoffiles- list(cpufile=cpufile,
cpufiledescriptors=cpufiledescriptors)
return (listoffiles)
}
and then:
filedescriptors-filelist.array(3)
close(filedescriptors$cpufiledescriptors[[1]])
close(filedescriptors$cpufiledescriptors[[2]])
close(filedescriptors$cpufiledescriptors[[3]])
and it worked fine. Perhaps a typo in your code somewhere?
Jim
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Re: [R] List of lists
Hi Jim,
close(filedescriptors$cpufiledescriptors[[1]])
close(filedescriptors$cpufiledescriptors[[2]])
close(filedescriptors$cpufiledescriptors[[3]])
I might be doing something wrong. Error is
Error in UseMethod(close) :
no applicable method for 'close' applied to an object of class c
('integer', 'numeric')
Thanks,
Mohan
Re: [R] List of lists
Jim Lemon
to:
mohan.radhakrishnan, R-help@r-project.org
31-07-2013 03:05
AM
On 07/30/2013 10:05 PM, mohan.radhakrish...@polarisft.com wrote:
Hi,
I am creating a list of 2 lists, one containing filenames
and the other file descriptors. When I retrieve them I am unable to
close
the file descriptor.
I am getting this error when I try to call close(filedescriptors
[[2]][[1]]).
Error in UseMethod(close) :
no applicable method for 'close' applied to an object of class c
('integer', 'numeric')
print(filedescriptors[[2]][[1]]) seems to be printing individual
elements.
Thanks,
Mohan
filelist.array- function(n){
cpufile- list()
cpufiledescriptors- list()
length(cpufile)- n
for (i in 1:n) {
cpufile[[i]]- paste(output, i, .txt, sep = )
cpufiledescriptors[[i]]-file( cpufile[[i]], a )
}
listoffiles- list(cpufile=cpufile,
cpufiledescriptors=cpufiledescriptors)
return (listoffiles)
}
#Test function
test.filelist.array- function() {
filedescriptors- filelist.array(3)
print(filedescriptors[[2]][[1]])
print(filedescriptors[[2]][[2]])
print(filedescriptors[[2]][[3]])
}
Hi Mohan,
When you have opened connections as above, you need to pass the
connection, not just one element, to close:
close(listoffiles$cpufiledescriptors[[1]])
Jim
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immediately. You are also hereby notified that any use, any form of
reproduction, dissemination, copying, disclosure, modification, distribution
and/or publication of this e-mail message, contents or its attachment other
than by its intended recipient/s is strictly prohibited.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] List of lists
Hi,
I am creating a list of 2 lists, one containing filenames
and the other file descriptors. When I retrieve them I am unable to close
the file descriptor.
I am getting this error when I try to call close(filedescriptors
[[2]][[1]]).
Error in UseMethod(close) :
no applicable method for 'close' applied to an object of class c
('integer', 'numeric')
print(filedescriptors[[2]][[1]]) seems to be printing individual elements.
Thanks,
Mohan
filelist.array - function(n){
cpufile - list()
cpufiledescriptors - list()
length(cpufile) - n
for (i in 1:n) {
cpufile[[i]] - paste(output, i, .txt, sep = )
cpufiledescriptors[[i]]-file( cpufile[[i]], a )
}
listoffiles - list(cpufile=cpufile,
cpufiledescriptors=cpufiledescriptors)
return (listoffiles)
}
#Test function
test.filelist.array - function() {
filedescriptors - filelist.array(3)
print(filedescriptors[[2]][[1]])
print(filedescriptors[[2]][[2]])
print(filedescriptors[[2]][[3]])
}
This e-Mail may contain proprietary and confidential information and is sent
for the intended recipient(s) only. If by an addressing or transmission error
this mail has been misdirected to you, you are requested to delete this mail
immediately. You are also hereby notified that any use, any form of
reproduction, dissemination, copying, disclosure, modification, distribution
and/or publication of this e-mail message, contents or its attachment other
than by its intended recipient/s is strictly prohibited.
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__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists
On 07/30/2013 10:05 PM, mohan.radhakrish...@polarisft.com wrote:
Hi,
I am creating a list of 2 lists, one containing filenames
and the other file descriptors. When I retrieve them I am unable to close
the file descriptor.
I am getting this error when I try to call close(filedescriptors
[[2]][[1]]).
Error in UseMethod(close) :
no applicable method for 'close' applied to an object of class c
('integer', 'numeric')
print(filedescriptors[[2]][[1]]) seems to be printing individual elements.
Thanks,
Mohan
filelist.array- function(n){
cpufile- list()
cpufiledescriptors- list()
length(cpufile)- n
for (i in 1:n) {
cpufile[[i]]- paste(output, i, .txt, sep = )
cpufiledescriptors[[i]]-file( cpufile[[i]], a )
}
listoffiles- list(cpufile=cpufile,
cpufiledescriptors=cpufiledescriptors)
return (listoffiles)
}
#Test function
test.filelist.array- function() {
filedescriptors- filelist.array(3)
print(filedescriptors[[2]][[1]])
print(filedescriptors[[2]][[2]])
print(filedescriptors[[2]][[3]])
}
Hi Mohan,
When you have opened connections as above, you need to pass the
connection, not just one element, to close:
close(listoffiles$cpufiledescriptors[[1]])
Jim
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Re: [R] list of lists to matrix
Please supply some sample data. The easiest way to supply data is to use the dput() function. Example with your file named testfile: dput(testfile) Then copy the output and paste into your email. For large data sets, you can just supply a representative sample. Usually, dput(head(testfile, 100)) will be sufficient. Simpe example: aalist - list(aa = c(3.0, 2.9, 2.7), bb = c(0.86, 0.76, 0.66), cc= c(0.07, 0.04, 0.04), cc = c(a, b, c)) dput(aalist) The attached text file was useful but actual or example data is much better. John Kane Kingston ON Canada -Original Message- From: eliza_bo...@hotmail.com Sent: Mon, 7 Jan 2013 16:13:03 + To: r-help@r-project.org Subject: [R] list of lists to matrix dear R family, [a text file has been attached for better understanding] i have a list of 16 and each of of that is further subdivided into variable number of lists. So, i have a kind of list into lists phenomenon. [[1]]$'1' 1 2 3 4 5 6 7 8 9 [[1]]$'2' 1 2 3 4 5 6 7 8 9 i want to convert both these sublists into one column and then cbind it in the following way col1 col2 1 1 2 2 3 3.. 9 9 i want to the same operations on all the 16 lists. thanks in advance, elisa __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. FREE 3D EARTH SCREENSAVER - Watch the Earth right on your desktop! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] list of lists to matrix
dear R family, [a text file has been attached for better understanding] i have a list of 16 and each of of that is further subdivided into variable number of lists. So, i have a kind of list into lists phenomenon. [[1]]$'1' 1 2 3 4 5 6 7 8 9 [[1]]$'2' 1 2 3 4 5 6 7 8 9 i want to convert both these sublists into one column and then cbind it in the following way col1 col2 1 1 2 2 3 3.. 9 9 i want to the same operations on all the 16 lists. thanks in advance, elisa dear R family, i have a list of 16 and each of of that is further subdivided into variable number of lists. So, i have a kind of list of lists phenomenon. [[1]]$'1' 1 2 3 4 5 6 7 8 9 [[1]]$'2' 1 2 3 4 5 6 7 8 9 i want to convert both these sublists into one column and then cbind it in the following way col1 col2 1 1 2 2 3 3 . . 9 9 i want to the same operations on all the 16 lists. thanks in advance, elisa__ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] list of lists to matrix
Something like do.call(cbind, lists) ? MW On Mon, Jan 7, 2013 at 4:13 PM, eliza botto eliza_bo...@hotmail.com wrote: dear R family, [a text file has been attached for better understanding] i have a list of 16 and each of of that is further subdivided into variable number of lists. So, i have a kind of list into lists phenomenon. [[1]]$'1' 1 2 3 4 5 6 7 8 9 [[1]]$'2' 1 2 3 4 5 6 7 8 9 i want to convert both these sublists into one column and then cbind it in the following way col1 col2 1 1 2 2 3 3.. 9 9 i want to the same operations on all the 16 lists. thanks in advance, elisa __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] list of lists to matrix
Thanks arun and weylandt,it perfectly worked out.. elisa From: michael.weyla...@gmail.com Date: Mon, 7 Jan 2013 16:37:53 + Subject: Re: [R] list of lists to matrix To: eliza_bo...@hotmail.com CC: r-help@r-project.org Something like do.call(cbind, lists) ? MW On Mon, Jan 7, 2013 at 4:13 PM, eliza botto eliza_bo...@hotmail.com wrote: dear R family, [a text file has been attached for better understanding] i have a list of 16 and each of of that is further subdivided into variable number of lists. So, i have a kind of list into lists phenomenon. [[1]]$'1' 1 2 3 4 5 6 7 8 9 [[1]]$'2' 1 2 3 4 5 6 7 8 9 i want to convert both these sublists into one column and then cbind it in the following way col1 col2 1 1 2 2 3 3.. 9 9 i want to the same operations on all the 16 lists. thanks in advance, elisa __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists to data frame?
I don't know if this is faster, but ...
out - do.call(rbind,
lapply(s, function(x)data.frame(x$category,x$name,as.vector(x$series
## You can then name the columns of out via names()
Note: No fancy additional packages are required.
-- Bert
On Wed, Nov 16, 2011 at 6:39 PM, Kevin Burton rkevinbur...@charter.net wrote:
Say I have the following data:
s - list()
s[[A]] - list(name=first, series=ts(rnorm(50), frequency=10,
start=c(2000,1)), category=top)
s[[B]] - list(name=second, series=ts(rnorm(60), frequency=10,
start=c(2000,2)), category=next)
If I use unlist since this is a list of lists I don't end up with a data
frame. And the number of rows in the data frame should equal the number of
time series entries. In the sample above it would be 110. I would expect
that the name and category strings would be recycled for each row. My brute
force code attempts to build the data frame by appending to the master data
frame but like I said it is *very* slow.
Kevin
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Wednesday, November 16, 2011 5:26 PM
To: rkevinbur...@charter.net
Cc: r-help@r-project.org
Subject: Re: [R] List of lists to data frame?
unlist(..., recursive = F)
Michael
On Wed, Nov 16, 2011 at 6:20 PM, rkevinbur...@charter.net wrote:
I would like to make the following faster:
df - NULL
for(i in 1:length(s))
{
df - rbind(df, cbind(names(s[i]), time(s[[i]]$series),
as.vector(s[[i]]$series), s[[i]]$category))
}
names(df) - c(name, time, value, category)
return(df)
The s object is a list of lists. It is constructed like:
s[[object]] - list(. . . . . .)
where object would be the name associated with this list
s[[i]]$series is a 'ts' object and s[[i]]$category is a name.
Constructing this list is reasonably fast but to do some more
processing on the data it would be easier if it were converted to a data
frame.
Right now the above code is unacceptably slow at converting this list
of lists to a data frame. Any suggestions on how to optimize this are
welcome.
Thank you.
Kevin
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Bert Gunter
Genentech Nonclinical Biostatistics
Internal Contact Info:
Phone: 467-7374
Website:
http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] List of lists to data frame?
I would like to make the following faster:
df - NULL
for(i in 1:length(s))
{
df - rbind(df, cbind(names(s[i]), time(s[[i]]$series),
as.vector(s[[i]]$series), s[[i]]$category))
}
names(df) - c(name, time, value, category)
return(df)
The s object is a list of lists. It is constructed like:
s[[object]] - list(. . . . . .)
where object would be the name associated with this list s[[i]]$series
is a 'ts' object and s[[i]]$category is a name.
Constructing this list is reasonably fast but to do some more processing
on the data it would be easier if it were converted to a data frame.
Right now the above code is unacceptably slow at converting this list of
lists to a data frame. Any suggestions on how to optimize this are
welcome.
Thank you.
Kevin
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists to data frame?
unlist(..., recursive = F)
Michael
On Wed, Nov 16, 2011 at 6:20 PM, rkevinbur...@charter.net wrote:
I would like to make the following faster:
df - NULL
for(i in 1:length(s))
{
df - rbind(df, cbind(names(s[i]), time(s[[i]]$series),
as.vector(s[[i]]$series), s[[i]]$category))
}
names(df) - c(name, time, value, category)
return(df)
The s object is a list of lists. It is constructed like:
s[[object]] - list(. . . . . .)
where object would be the name associated with this list s[[i]]$series
is a 'ts' object and s[[i]]$category is a name.
Constructing this list is reasonably fast but to do some more processing
on the data it would be easier if it were converted to a data frame.
Right now the above code is unacceptably slow at converting this list of
lists to a data frame. Any suggestions on how to optimize this are
welcome.
Thank you.
Kevin
[[alternative HTML version deleted]]
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists to data frame?
Say I have the following data:
s - list()
s[[A]] - list(name=first, series=ts(rnorm(50), frequency=10,
start=c(2000,1)), category=top)
s[[B]] - list(name=second, series=ts(rnorm(60), frequency=10,
start=c(2000,2)), category=next)
If I use unlist since this is a list of lists I don't end up with a data
frame. And the number of rows in the data frame should equal the number of
time series entries. In the sample above it would be 110. I would expect
that the name and category strings would be recycled for each row. My brute
force code attempts to build the data frame by appending to the master data
frame but like I said it is *very* slow.
Kevin
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Wednesday, November 16, 2011 5:26 PM
To: rkevinbur...@charter.net
Cc: r-help@r-project.org
Subject: Re: [R] List of lists to data frame?
unlist(..., recursive = F)
Michael
On Wed, Nov 16, 2011 at 6:20 PM, rkevinbur...@charter.net wrote:
I would like to make the following faster:
df - NULL
for(i in 1:length(s))
{
df - rbind(df, cbind(names(s[i]), time(s[[i]]$series),
as.vector(s[[i]]$series), s[[i]]$category))
}
names(df) - c(name, time, value, category)
return(df)
The s object is a list of lists. It is constructed like:
s[[object]] - list(. . . . . .)
where object would be the name associated with this list
s[[i]]$series is a 'ts' object and s[[i]]$category is a name.
Constructing this list is reasonably fast but to do some more
processing on the data it would be easier if it were converted to a data
frame.
Right now the above code is unacceptably slow at converting this list
of lists to a data frame. Any suggestions on how to optimize this are
welcome.
Thank you.
Kevin
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists to data frame?
On Wed, Nov 16, 2011 at 9:39 PM, Kevin Burton rkevinbur...@charter.net wrote:
Say I have the following data:
s - list()
s[[A]] - list(name=first, series=ts(rnorm(50), frequency=10,
start=c(2000,1)), category=top)
s[[B]] - list(name=second, series=ts(rnorm(60), frequency=10,
start=c(2000,2)), category=next)
If I use unlist since this is a list of lists I don't end up with a data
frame. And the number of rows in the data frame should equal the number of
time series entries. In the sample above it would be 110. I would expect
that the name and category strings would be recycled for each row. My brute
force code attempts to build the data frame by appending to the master data
frame but like I said it is *very* slow.
Appending is very slow, and should be avoided. Instead, create a data frame
of the correct size before starting the loop, and add each new bit into the
appropriate place.
There may well be a more efficient solution (I don't quite understand
what your objective is), but simply getting rid of the rbind() within a
loop will help.
Kevin
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Wednesday, November 16, 2011 5:26 PM
To: rkevinbur...@charter.net
Cc: r-help@r-project.org
Subject: Re: [R] List of lists to data frame?
unlist(..., recursive = F)
Michael
On Wed, Nov 16, 2011 at 6:20 PM, rkevinbur...@charter.net wrote:
I would like to make the following faster:
df - NULL
for(i in 1:length(s))
{
df - rbind(df, cbind(names(s[i]), time(s[[i]]$series),
as.vector(s[[i]]$series), s[[i]]$category))
}
names(df) - c(name, time, value, category)
return(df)
The s object is a list of lists. It is constructed like:
s[[object]] - list(. . . . . .)
where object would be the name associated with this list
s[[i]]$series is a 'ts' object and s[[i]]$category is a name.
Constructing this list is reasonably fast but to do some more
processing on the data it would be easier if it were converted to a data
frame.
Right now the above code is unacceptably slow at converting this list
of lists to a data frame. Any suggestions on how to optimize this are
welcome.
Thank you.
Kevin
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists to data frame?
On the face of it this looks like a job for ldply() in the plyr package which specialises in taking things apart and putting them back together. ldply() applies a function for each element of a list and then combine results into a data frame On 17 November 2011 04:53, Sarah Goslee sarah.gos...@gmail.com wrote: On Wed, Nov 16, 2011 at 9:39 PM, Kevin Burton rkevinbur...@charter.net wrote: Say I have the following data: s - list() s[[A]] - list(name=first, series=ts(rnorm(50), frequency=10, start=c(2000,1)), category=top) s[[B]] - list(name=second, series=ts(rnorm(60), frequency=10, start=c(2000,2)), category=next) If I use unlist since this is a list of lists I don't end up with a data frame. And the number of rows in the data frame should equal the number of time series entries. In the sample above it would be 110. I would expect that the name and category strings would be recycled for each row. My brute force code attempts to build the data frame by appending to the master data frame but like I said it is *very* slow. Appending is very slow, and should be avoided. Instead, create a data frame of the correct size before starting the loop, and add each new bit into the appropriate place. There may well be a more efficient solution (I don't quite understand what your objective is), but simply getting rid of the rbind() within a loop will help. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] List of lists ?
Dear list, I have to use a list of lists containing vectors. For instance : [[1]] [[1]][[1]] [1] 1 2 3 [[1]][[2]] [1] 3 2 1 I want to attribute vectors to the main list without use of an intermediate list, but it does not work : x - list() x[[1]][[1]] - c(1, 2, 3) x[[1]][[2]] - c(3, 2, 1) Thanks in advance, Carlos __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists ?
On Aug 9, 2010, at 12:57 PM, Carlos Petti wrote: Dear list, I have to use a list of lists containing vectors. For instance : [[1]] [[1]][[1]] [1] 1 2 3 [[1]][[2]] [1] 3 2 1 I want to attribute vectors to the main list without use of an intermediate list, but it does not work : More specifically it produces an error that has information in it. x[[1]][[1]] - c(1, 2, 3) Error in `*tmp*`[[1]] : subscript out of bounds x - list() x[[1]][[1]] - c(1, 2, 3) x[[1]][[2]] - c(3, 2, 1) So thinking perhaps we just needed another level of subscripting available I tried: x - list(list()) x[[1]][[1]] - c(1, 2, 3) x[[1]][[2]] - c(3, 2, 1) x [[1]] [[1]][[1]] [1] 1 2 3 [[1]][[2]] [1] 3 2 1 Success. Moral: Read the error messages for meaning or at least clues. (Further testing showed that almost anything inside the original list() call, even NULL, would have created enough structure for the interpreter to work with. David Winsemius, MD West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of lists ?
Is this what you want: x - list() x[[1]] - list(1:3) x[[2]] - list(3:1) x [[1]] [[1]][[1]] [1] 1 2 3 [[2]] [[2]][[1]] [1] 3 2 1 On Mon, Aug 9, 2010 at 12:57 PM, Carlos Petti carlos.pe...@gmail.com wrote: Dear list, I have to use a list of lists containing vectors. For instance : [[1]] [[1]][[1]] [1] 1 2 3 [[1]][[2]] [1] 3 2 1 I want to attribute vectors to the main list without use of an intermediate list, but it does not work : x - list() x[[1]][[1]] - c(1, 2, 3) x[[1]][[2]] - c(3, 2, 1) Thanks in advance, Carlos __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of Lists
See if one of %in% or match gets your further. 1:10 %in% c(1,3,5,9) [1] TRUE FALSE TRUE FALSE TRUE FALSE FALSE FALSE TRUE FALSE match(c(1,3,5,9), 1:10) [1] 1 3 5 9 match(c(1,3,5,9), 10:1) [1] 10 8 6 2 date03 as offered was not a list, but a vector. date04 - date02[which(date02$date %in% date3), ] # might work, nothing to test it on If you only want the column of matching dates and not all the rows that have matching dates then this might work: date04 - date02[which(date02$date %in% date3), date ] From you incorrect use of the term list (in the context of R, anyway), I am guessing that you don't really want lists but rather subsets of data.frames. Vector and list are not interchangeable terms in these parts. -- David Winsemius On Jan 14, 2009, at 2:53 PM, glenn wrote: Dear All; Is it possible to create a list of lists (I am sure it is) along these lines; I have a dataframe data02 that holds a lot of information, and the first column is “date” I have a list of dates in; data03-c(date1,.,daten) And would like to create a list; data04 - subset(data02, date == data03[1,]) Ie. data04 holds the data from data02 that matches a date in data03 How do I create a list data04 that instead rolls through all the elements of data03 and each element of data04 is a list Regards Glenn [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] List of Lists
On Wed, Jan 14, 2009 at 1:53 PM, glenn g1enn.robe...@btinternet.com wrote: Dear All; Is it possible to create a list of lists (I am sure it is) along these lines; I have a dataframe data02 that holds a lot of information, and the first column is ³date² I have a list of dates in; data03-c(date1,.,daten) And would like to create a list; data04 - subset(data02, date == data03[1,]) Ie. data04 holds the data from data02 that matches a date in data03 How do I create a list data04 that instead rolls through all the elements of data03 and each element of data04 is a list Have a look at ?split. Hadley -- http://had.co.nz/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
