[R] elegant way to minus on each row of a matrix
How to do this in an elegant way formatrix/data frame/zoo? mat= 1 2 3 4 5 6 7 8 9 vector= 1 2 3 result= 0 1 2 2 3 4 4 5 6 ie 1-1 2-1 3-1 4-2 5-2 6-2 7-3 8-3 9-3 Thanks in advance. _ 08 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] elegant way to minus on each row of a matrix
Brilliant! > t1=matrix(1:15,5,3) > t1 [,1] [,2] [,3] [1,]16 11 [2,]27 12 [3,]38 13 [4,]49 14 [5,]5 10 15 > t2=1:5 > t2 [1] 1 2 3 4 5 > sweep(t1, 1, t2) [,1] [,2] [,3] [1,]05 10 [2,]05 10 [3,]05 10 [4,]05 10 [5,]05 10 > Date: Sun, 2 Mar 2008 14:56:22 -0300 > From: [EMAIL PROTECTED] > To: [EMAIL PROTECTED] > Subject: Re: [R] elegant way to minus on each row of a matrix > CC: r-help@r-project.org > > Try this: > > sweep(mat, 1, vec) > > > On 02/03/2008, Bo Zhou <[EMAIL PROTECTED]> wrote: > > > > How to do this in an elegant way formatrix/data frame/zoo? > > > > mat= > > 1 2 3 > > 4 5 6 > > 7 8 9 > > > > vector= > > 1 > > 2 > > 3 > > > > > > result= > > 0 1 2 > > 2 3 4 > > 4 5 6 > > > > ie > > 1-1 2-1 3-1 > > 4-2 5-2 6-2 > > 7-3 8-3 9-3 > > > > Thanks in advance. > > > > _ > > > > > > 08 > > [[alternative HTML version deleted]] > > > > __ > > R-help@r-project.org mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > > -- > Henrique Dallazuanna > Curitiba-Paraná-Brasil > 25° 25' 40" S 49° 16' 22" O _ Need to know the score, the latest news, or you need your Hotmail®-get your "fix". [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] elegant way to minus on each row of a matrix
Hi Dimitris and everyone I tried this but now I know why it didn't work out for me initially. > t1=matrix(1:10,5,2) > t2=matrix(1,5,1) > t2 [,1] [1,]1 [2,]1 [3,]1 [4,]1 [5,]1 > t1 [,1] [,2] [1,]16 [2,]27 [3,]38 [4,]49 [5,]5 10 > t1-as.vector(t2) [,1] [,2] [1,]05 [2,]16 [3,]27 [4,]38 [5,]49 > t1-t2 Error in t1 - t2 : non-conformable arrays I'm too used to Matlab I guess. Cheers, Bo > Date: Sun, 2 Mar 2008 18:56:15 +0100 > From: [EMAIL PROTECTED] > To: [EMAIL PROTECTED] > CC: r-help@r-project.org > Subject: Re: [R] elegant way to minus on each row of a matrix > > try this: > > mat <- matrix(1:9, 3, 3, TRUE) > dat <- as.data.frame(mat) > vec <- 1:3 > > result.mat <- mat - vec > result.dat <- dat - vec > result.mat > result.dat > > > I hope it helps. > > Best, > Dimitris > > > Dimitris Rizopoulos > Biostatistical Centre > School of Public Health > Catholic University of Leuven > > Address: Kapucijnenvoer 35, Leuven, Belgium > Tel: +32/(0)16/336899 > Fax: +32/(0)16/337015 > Web: http://med.kuleuven.be/biostat/ > http://www.student.kuleuven.be/~m0390867/dimitris.htm > > > Quoting Bo Zhou <[EMAIL PROTECTED]>: > > > > > How to do this in an elegant way formatrix/data frame/zoo? > > > > mat= > > 1 2 3 > > 4 5 6 > > 7 8 9 > > > > vector= > > 1 > > 2 > > 3 > > > > > > result= > > 0 1 2 > > 2 3 4 > > 4 5 6 > > > > ie > > 1-1 2-1 3-1 > > 4-2 5-2 6-2 > > 7-3 8-3 9-3 > > > > Thanks in advance. > > > > _ > > > > > > 08 > > [[alternative HTML version deleted]] > > > > __ > > R-help@r-project.org mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > > > > > Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm > _ 08 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] elegant way to minus on each row of a matrix
Try this: sweep(mat, 1, vec) On 02/03/2008, Bo Zhou <[EMAIL PROTECTED]> wrote: > > How to do this in an elegant way formatrix/data frame/zoo? > > mat= > 1 2 3 > 4 5 6 > 7 8 9 > > vector= > 1 > 2 > 3 > > > result= > 0 1 2 > 2 3 4 > 4 5 6 > > ie > 1-1 2-1 3-1 > 4-2 5-2 6-2 > 7-3 8-3 9-3 > > Thanks in advance. > > _ > > > 08 > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] elegant way to minus on each row of a matrix
Hi Mark, (CC'ing r-help) Only need to change the parameter from 1 to 2 after that it worked great. Thanks > t1=matrix(1:15,5,3) > t1 [,1] [,2] [,3] [1,]16 11 [2,]27 12 [3,]38 13 [4,]49 14 [5,]5 10 15 > t2=1:5 > t2 [1] 1 2 3 4 5 > apply(t1,2, function(x) x - t2) [,1] [,2] [,3] [1,]05 10 [2,]05 10 [3,]05 10 [4,]05 10 [5,]05 10 > > Date: Sun, 2 Mar 2008 12:51:53 -0500 > From: [EMAIL PROTECTED] > Subject: RE: [R] elegant way to minus on each row of a matrix > To: [EMAIL PROTECTED] > > try result<-apply(mat,1, function(.row) .row - vector) but I don't have R > here so make sure it works. > > -Original Message- > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On > Behalf Of Bo Zhou > Sent: Sunday, March 02, 2008 12:43 PM > To: r-help@r-project.org > Subject: [R] elegant way to minus on each row of a matrix > > > How to do this in an elegant way formatrix/data frame/zoo? > > mat= > 1 2 3 > 4 5 6 > 7 8 9 > > vector= > 1 > 2 > 3 > > > result= > 0 1 2 > 2 3 4 > 4 5 6 > > ie > 1-1 2-1 3-1 > 4-2 5-2 6-2 > 7-3 8-3 9-3 > > Thanks in advance. > > _ > > > 08 > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > _ 08 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] elegant way to minus on each row of a matrix
try this: mat <- matrix(1:9, 3, 3, TRUE) dat <- as.data.frame(mat) vec <- 1:3 result.mat <- mat - vec result.dat <- dat - vec result.mat result.dat I hope it helps. Best, Dimitris Dimitris Rizopoulos Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/(0)16/336899 Fax: +32/(0)16/337015 Web: http://med.kuleuven.be/biostat/ http://www.student.kuleuven.be/~m0390867/dimitris.htm Quoting Bo Zhou <[EMAIL PROTECTED]>: > > How to do this in an elegant way formatrix/data frame/zoo? > > mat= > 1 2 3 > 4 5 6 > 7 8 9 > > vector= > 1 > 2 > 3 > > > result= > 0 1 2 > 2 3 4 > 4 5 6 > > ie > 1-1 2-1 3-1 > 4-2 5-2 6-2 > 7-3 8-3 9-3 > > Thanks in advance. > > _ > > > 08 > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
