Re: [R] Summarizing elements of a list
Thank you for the help, I knew it could be done with a member of the apply
family. I struggle with apply stuff though, its not always intuitive for me
with these functions.
Cheers,
JR
From: Sarah Goslee [via R] [mailto:ml-node+s789695n414453...@n4.nabble.com]
Sent: Thursday, December 01, 2011 6:44 PM
To: ROLL Josh F
Subject: Re: Summarizing elements of a list
How about:
lapply(Version1_, subset, subset=c(TRUE, FALSE))
or sapply() depending on what you want the result to look like.
Thanks for the reproducible example.
Sarah
On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 [hidden
email]/user/SendEmail.jtp?type=nodenode=4144538i=0 wrote:
Hi everyone,
I looked around the list for a while but couldn't find a solution to my
problem. I am storing some results to a simulation in a list and for each
element i have two separate vectors(is that what they are called, correct my
vocab if necessary). See below
Version1_-list()
for(i in 1:5){
Version1_[[i]]-list(First=rnorm(1),Second=rnorm(1))
}
What I want is to put all of the elements' 'First' vectors into a single
list to box plot. But whats a more elegant solution to the below?
c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
since i have 50 or more simulations this is impractical and sloppy. Do I
need to store my data differently or is their a solution on the back end?
Thanks all.
Josh
--
Sarah Goslee
http://www.functionaldiversity.org
__
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Re: [R] Summarizing elements of a list
Great, this worked the fastest of all the suggestions. Cheers,
Josh
From: Michael Weylandt [via R] [mailto:ml-node+s789695n414494...@n4.nabble.com]
Sent: Thursday, December 01, 2011 8:11 PM
To: ROLL Josh F
Subject: Re: Summarizing elements of a list
Similarly, this might work:
unlist(lapply(Version1_, `[`,First))
Michael
On Thu, Dec 1, 2011 at 9:41 PM, Sarah Goslee [hidden
email]/user/SendEmail.jtp?type=nodenode=4144941i=0 wrote:
How about:
lapply(Version1_, subset, subset=c(TRUE, FALSE))
or sapply() depending on what you want the result to look like.
Thanks for the reproducible example.
Sarah
On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 [hidden
email]/user/SendEmail.jtp?type=nodenode=4144941i=1 wrote:
Hi everyone,
I looked around the list for a while but couldn't find a solution to my
problem. I am storing some results to a simulation in a list and for each
element i have two separate vectors(is that what they are called, correct my
vocab if necessary). See below
Version1_-list()
for(i in 1:5){
Version1_[[i]]-list(First=rnorm(1),Second=rnorm(1))
}
What I want is to put all of the elements' 'First' vectors into a single
list to box plot. But whats a more elegant solution to the below?
c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
since i have 50 or more simulations this is impractical and sloppy. Do I
need to store my data differently or is their a solution on the back end?
Thanks all.
Josh
--
Sarah Goslee
http://www.functionaldiversity.org
__
[hidden email]/user/SendEmail.jtp?type=nodenode=4144941i=2 mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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Re: [R] Summarizing elements of a list
Here's a slight modification that is even faster if speed is a consideration:
sapply(Version1_, `[[`, First)
The thought process is to go through the list Version1_ and apply
the operation `[[` to each element individually. This requires a
second operator (here the element name First) which we pass through
the ... of sapply() -- I hope that helps you get a sense of the
mechanics. We use sapply() instead of lapply() because it does some
internal simplification for us to get one big vector back, effectively
cutting out the unlist of the first solution I gave you.
Michael
On Fri, Dec 2, 2011 at 2:04 PM, LCOG1 jr...@lcog.org wrote:
Great, this worked the fastest of all the suggestions. Cheers,
Josh
From: Michael Weylandt [via R]
[mailto:ml-node+s789695n414494...@n4.nabble.com]
Sent: Thursday, December 01, 2011 8:11 PM
To: ROLL Josh F
Subject: Re: Summarizing elements of a list
Similarly, this might work:
unlist(lapply(Version1_, `[`,First))
Michael
On Thu, Dec 1, 2011 at 9:41 PM, Sarah Goslee [hidden
email]/user/SendEmail.jtp?type=nodenode=4144941i=0 wrote:
How about:
lapply(Version1_, subset, subset=c(TRUE, FALSE))
or sapply() depending on what you want the result to look like.
Thanks for the reproducible example.
Sarah
On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 [hidden
email]/user/SendEmail.jtp?type=nodenode=4144941i=1 wrote:
Hi everyone,
I looked around the list for a while but couldn't find a solution to my
problem. I am storing some results to a simulation in a list and for each
element i have two separate vectors(is that what they are called, correct my
vocab if necessary). See below
Version1_-list()
for(i in 1:5){
Version1_[[i]]-list(First=rnorm(1),Second=rnorm(1))
}
What I want is to put all of the elements' 'First' vectors into a single
list to box plot. But whats a more elegant solution to the below?
c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
since i have 50 or more simulations this is impractical and sloppy. Do I
need to store my data differently or is their a solution on the back end?
Thanks all.
Josh
--
Sarah Goslee
http://www.functionaldiversity.org
__
[hidden email]/user/SendEmail.jtp?type=nodenode=4144941i=2 mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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and provide commented, minimal, self-contained, reproducible code.
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and provide commented, minimal, self-contained, reproducible code.
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Re: [R] Summarizing elements of a list
Someone is bound to know a better way, but...
subset(unlist(Version1_), subset=names(unlist(Version1_))==First)
LCOG1 wrote
Hi everyone,
I looked around the list for a while but couldn't find a solution to my
problem. I am storing some results to a simulation in a list and for each
element i have two separate vectors(is that what they are called, correct
my vocab if necessary). See below
Version1_-list()
for(i in 1:5){
Version1_[[i]]-list(First=rnorm(1),Second=rnorm(1))
}
What I want is to put all of the elements' 'First' vectors into a single
list to box plot. But whats a more elegant solution to the below?
c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
since i have 50 or more simulations this is impractical and sloppy. Do I
need to store my data differently or is their a solution on the back end?
Thanks all.
Josh
--
View this message in context:
http://r.789695.n4.nabble.com/Summarizing-elements-of-a-list-tp4142479p4142884.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Summarizing elements of a list
How about:
lapply(Version1_, subset, subset=c(TRUE, FALSE))
or sapply() depending on what you want the result to look like.
Thanks for the reproducible example.
Sarah
On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 jr...@lcog.org wrote:
Hi everyone,
I looked around the list for a while but couldn't find a solution to my
problem. I am storing some results to a simulation in a list and for each
element i have two separate vectors(is that what they are called, correct my
vocab if necessary). See below
Version1_-list()
for(i in 1:5){
Version1_[[i]]-list(First=rnorm(1),Second=rnorm(1))
}
What I want is to put all of the elements' 'First' vectors into a single
list to box plot. But whats a more elegant solution to the below?
c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
since i have 50 or more simulations this is impractical and sloppy. Do I
need to store my data differently or is their a solution on the back end?
Thanks all.
Josh
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Summarizing elements of a list
Similarly, this might work:
unlist(lapply(Version1_, `[`,First))
Michael
On Thu, Dec 1, 2011 at 9:41 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
How about:
lapply(Version1_, subset, subset=c(TRUE, FALSE))
or sapply() depending on what you want the result to look like.
Thanks for the reproducible example.
Sarah
On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 jr...@lcog.org wrote:
Hi everyone,
I looked around the list for a while but couldn't find a solution to my
problem. I am storing some results to a simulation in a list and for each
element i have two separate vectors(is that what they are called, correct my
vocab if necessary). See below
Version1_-list()
for(i in 1:5){
Version1_[[i]]-list(First=rnorm(1),Second=rnorm(1))
}
What I want is to put all of the elements' 'First' vectors into a single
list to box plot. But whats a more elegant solution to the below?
c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
since i have 50 or more simulations this is impractical and sloppy. Do I
need to store my data differently or is their a solution on the back end?
Thanks all.
Josh
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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and provide commented, minimal, self-contained, reproducible code.
