[R] Can a data.frame column contain lists/arrays?

2007-02-12 Thread Christian Convey
I'd like to have a data.frame structured something like the following:

d - data.frame (
   x=list( c(1,2), c(5,2), c(9,1) ),
   y=c( 1, -1, -1)
)

The reason is this: 'd' is the training data for a machine learning
algorithm.  d$x is the independent data, and d$y is the dependent
data.

In general my machine learning code will work where each element of
d$x is a vector of one or more real numbers.  So for instance, the
same code should work when d$x[1] = 42, or when d$x[1] = (42, 3, 5).
All that matters is that all element within d$x are lists/vectors of
the same length.

Does anyone know if/how I can get a data.frame set up like that?

Thanks,
Christian

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[R] Newbie: how to get unique x unique x aggregate chart?

2006-11-15 Thread Christian Convey
I'm very new to R, so please forgive me if I just missed the answer in
existing documentation...

I have a data set with at least three columns, X, Y, and Z.

I want to produce a chart where one axis shows all the unique values of X,
and the other axis shows all the unique values of Y.  Each cell within the
chart should contain the result of applying an aggregate function (such as
mean(), for example) to Z value of those rows that are associated with that
cell (via their X and Y values).

Can someone recommend a good way to do this?

Thanks very much,
Christian

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Re: [R] Newbie: how to get unique x unique x aggregate chart?

2006-11-15 Thread Christian Convey
Thanks, let me try to clarify my question with an example.

Suppose I have the following data:

Gender,   Major,  Course-Grade
F, Psy, 3.5
F, Psy, 3.1
M, Hst, 3.7
F,  Hst,  3.6
M, Hst,  2.6
M, Eng, 3.9

I want to compute a table like the following:

X-axis: Gender
Y-axis: Major
Cell(x,y) = mean course-grade

So for example, with the data above:

  F M

Psy |   3.3NA
Hst |   3.63.15
Eng |  NA3.9

If I were doing this in SQL I'd do it with a cross-tab query.  But the world
of R still has much unfamiliar terrain :)

Thanks,
Christian


On 11/15/06, Jeffrey Robert Spies [EMAIL PROTECTED] wrote:

 I'm not sure I understand the question, but you might look into the
 following functions:

 unique
 heatmap
 image

 Again, if I understand the question, you would create a length(unique
 (x)) by length(unique(y)) sized matrix, and fill it with appropriate
 values of z.  Then pass that to heatmap or image.

 Hope that helps--feel free to tell me if I've answered  the wrong
 question,

 Jeff.

 On Nov 15, 2006, at 8:30 AM, Christian Convey wrote:

  I'm very new to R, so please forgive me if I just missed the answer in
  existing documentation...
 
  I have a data set with at least three columns, X, Y, and Z.
 
  I want to produce a chart where one axis shows all the unique
  values of X,
  and the other axis shows all the unique values of Y.  Each cell
  within the
  chart should contain the result of applying an aggregate function
  (such as
  mean(), for example) to Z value of those rows that are associated
  with that
  cell (via their X and Y values).
 
  Can someone recommend a good way to do this?
 
  Thanks very much,
  Christian
 
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  guide.html
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Re: [R] Newbie: how to get unique x unique x aggregate chart?

2006-11-15 Thread Christian Convey
That did it!  Thanks Marc.

- Christian

On 11/15/06, Marc Schwartz [EMAIL PROTECTED] wrote:

 On Wed, 2006-11-15 at 15:03 -0500, Christian Convey wrote:
  Thanks, let me try to clarify my question with an example.
 
  Suppose I have the following data:
 
  Gender,   Major,  Course-Grade
  F, Psy, 3.5
  F, Psy, 3.1
  M, Hst, 3.7
  F,  Hst,  3.6
  M, Hst,  2.6
  M, Eng, 3.9
 
  I want to compute a table like the following:
 
  X-axis: Gender
  Y-axis: Major
  Cell(x,y) = mean course-grade
 
  So for example, with the data above:
 
F M
  
  Psy |   3.3NA
  Hst |   3.63.15
  Eng |  NA3.9
 
  If I were doing this in SQL I'd do it with a cross-tab query.  But the
 world
  of R still has much unfamiliar terrain :)
 
  Thanks,
  Christian


 Presuming that DF is a data frame containing your data:

  with(DF, tapply(Course.Grade, list(Major, Gender),
   mean, na.rm = TRUE))
   FM
 Eng  NA 3.90
 Hst 3.6 3.15
 Psy 3.3   NA


 See ?tapply and ?with

 HTH,

 Marc Schwartz




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