Re: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-19 Thread mch
I sit corrected. Actually, I'm almost laying down corrected. I've never
been so tired - even after Dayton. I had a really really busy weekend. I
thoutoughly enjoyed it, but it was still busy.

Anyway... I don't understand the intermod software's math that Ken
happened to be using. :-)

Joe M.

Ken Arck wrote:
 
 At 07:45 PM 4/18/2004 -0400, you wrote:
 
 To be honest, I didn't follow Ken's math. Must be that west coast
 version. ;- Here is how I add it up:
 
 Aside from the formatting changes due to email, that's what my
 intermod software came up with.
 
 (sure sure,  shoot the messenger!)





 
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Re: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-19 Thread Ken Arck
At 07:45 PM 4/18/2004 -0400, you wrote:

To be honest, I didn't follow Ken's math. Must be that west coast
version. ;- Here is how I add it up:


Aside from the formatting changes due to email, that's what my
intermod software came up with.

(sure sure,  shoot the messenger!)

Ken
--
President and CTO - Arcom Communications
Makers of state-of-the-art repeater controllers and accessories.
http://www.ah6le.net/arcom/index.html
Be sure to see our products at this year's Dayton Hamvention!
Repeater Builders spaces 707 through 710
AH6LE/R - IRLP Node 3000
http://www.irlp.net




 
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Re: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-19 Thread mch
Michael Singewald N1PLH wrote:
 
 First...Wow, you guys are FAST!  I cannot believe how many responses
 in 15 minutes!  Thank you all very much.
 
 The 147.225 has input 147.925 and the 146.925 has input 146.325.

Actually, your input should be 147.825 for 147.225 out.

To be honest, I didn't follow Ken's math. Must be that west coast
version. ;- Here is how I add it up:

2A-1B:
147.225 + 147.225 - 146.925 = 147.525
146.925 + 146.925 - 147.225 = 146.625

(these are both OK unless you mix the results with the outputs,
as each are 600 kHz off the TX of the other repeater)

3A-2B:
147.225 + 147.225 + 147.225 - 146.925 - 146.925 = 147.825 (sound
familiar?)
146.925 + 146.925 + 146.925 - 147.225 - 147.225 = 146.325 (again, sound
familiar?)

Each of these cases results on the two TXs mixing and ending up with
products on the inputs of the other.


 I don't understand the problem with the small difference in transmit
 frequency.  The transmit frequency is still about 1 meg away from the
 receive frequency of the other repeater.  How far apart in frequency
 would they ahve to be to co exist while running relatively low power?

It's not how far apart they are - it's the math associated between them.
The mixing products are killing you, not the signal strength. You can
have a 5 MHz TX and a 440 MHz TX mix and end up with a product (3A-2B)
on the 440 input, and those are 435 MHz apart! I don't know how the guy
in Colorado put on 440 repeaters with WWV so close out there.

Similarly, 600 kHz signals are bad for 2M repeaters, 1.6 MHz signals are
bad for 220, just about everything is bad for 6M depending on where you
live ;-, Etc.

 I don't think a different frequency will be possible since all seem
 to be taken.  Another location is always a drag as well.

It may be a drag, but may be the easiest solution.

One case in my area had two repeaters that are about 20 miles apart had
a very similar problem. I think the frequency outputs were 146.670 and
147.270 MHz. Again, 2B-1A was killing them. The solution on that case, I
think, was to change to a BPBR duplexer rather than a notch duplexer.

Joe M.





 
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RE: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-19 Thread Dave Frechette
A=frequency 1
B=frequency 2

Formula for your frequency products is 2A+b, 2A-B, 2B+A, 2B-A. Simple
math!

-Original Message-
From: mch [mailto:[EMAIL PROTECTED] 
Sent: Sunday, April 18, 2004 16:46
To: Repeater-Builder@yahoogroups.com
Subject: Re: [Repeater-Builder] Re: Is there a relationship between
147.225 and 146.925?

Michael Singewald N1PLH wrote:
 
 First...Wow, you guys are FAST!  I cannot believe how many responses
 in 15 minutes!  Thank you all very much.
 
 The 147.225 has input 147.925 and the 146.925 has input 146.325.

Actually, your input should be 147.825 for 147.225 out.

To be honest, I didn't follow Ken's math. Must be that west coast
version. ;- Here is how I add it up:

2A-1B:
147.225 + 147.225 - 146.925 = 147.525
146.925 + 146.925 - 147.225 = 146.625

(these are both OK unless you mix the results with the outputs,
as each are 600 kHz off the TX of the other repeater)

3A-2B:
147.225 + 147.225 + 147.225 - 146.925 - 146.925 = 147.825 (sound
familiar?)
146.925 + 146.925 + 146.925 - 147.225 - 147.225 = 146.325 (again, sound
familiar?)

Each of these cases results on the two TXs mixing and ending up with
products on the inputs of the other.


 I don't understand the problem with the small difference in transmit
 frequency.  The transmit frequency is still about 1 meg away from the
 receive frequency of the other repeater.  How far apart in frequency
 would they ahve to be to co exist while running relatively low power?

It's not how far apart they are - it's the math associated between them.
The mixing products are killing you, not the signal strength. You can
have a 5 MHz TX and a 440 MHz TX mix and end up with a product (3A-2B)
on the 440 input, and those are 435 MHz apart! I don't know how the guy
in Colorado put on 440 repeaters with WWV so close out there.

Similarly, 600 kHz signals are bad for 2M repeaters, 1.6 MHz signals are
bad for 220, just about everything is bad for 6M depending on where you
live ;-, Etc.

 I don't think a different frequency will be possible since all seem
 to be taken.  Another location is always a drag as well.

It may be a drag, but may be the easiest solution.

One case in my area had two repeaters that are about 20 miles apart had
a very similar problem. I think the frequency outputs were 146.670 and
147.270 MHz. Again, 2B-1A was killing them. The solution on that case, I
think, was to change to a BPBR duplexer rather than a notch duplexer.

Joe M.





 
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Re: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-18 Thread Ed Yoho
Michael Singewald N1PLH wrote:
 
 First...Wow, you guys are FAST!  I cannot believe how many responses
 in 15 minutes!  Thank you all very much.
 
 The 147.225 has input 147.925 and the 146.925 has input 146.325.


(147.225 * 3) - (146.925 * 2) = 147.825
(146.925 * 3) - (147.225 * 2) = 146.325





 
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Re: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-18 Thread Kevin Custer


Michael Singewald N1PLH wrote:

I don't understand the problem with the small difference in transmit 
frequency.  The transmit frequency is still about 1 meg away from the 
receive frequency of the other repeater.  How far apart in frequency 
would they ahve to be to co exist while running relatively low power?


Look at it this way, a UHF machine utilizes a 5 meg split.  UHF 
repeaters still require a duplexer to operate without desense, or at 
least cavities if a 2 antenna system is utilized without enough vertical 
antenna separation.  Since the 2 meter band is only 4 megs wide, you 
cannot separate the two repeaters in frequency enough to make it work 
without some additional equipment.

I don't think a different frequency will be possible since all seem 
to be taken.  Another location is always a drag as well.  When you 
say equipment is available, are you referring to expensive 
multicoupler type sytems?


That is one of the best solutions.  Both repeaters could share the same 
antenna system and co-exist, but I don't think it would be possible with 
the current repeater pairs due to the nature of the frequencies.

  Even though they are on separate antennas?


How far are they apart?

I realize I could experiment with notches, but in your opinions 
(which I appreciate), that won't help enough?


I've seen people spend thousands of dollars to solve problems with 
mathematical related issues, and they not be solved.  It would be 
cheaper to move one of the repeaters to another frequency pair, and then 
solve any desense problems (due to transmitter noise) if they exist with 
notch filters, especially since neither of the two involved repeaters 
are really of commercial quality.

Kevin






 
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Re: [Repeater-Builder] Re: Is there a relationship between 147.225 and 146.925?

2004-04-18 Thread Jeff Otterson
Circulators will solve the problem if the mix is only occurring in the 
transmitters.  They will not help if the mix is happening in a receiver 
front end or anywhere else, for example the proverbial rusty tower bolt.

Circulators could add to your problem.  They are infamous for producing 
harmonics.  They should be followed with a bandpass cavity.  The bandpass 
in your duplexer may not be sufficient to keep the harmonics down.

Good luck!

Jeff


At 03:00 PM 4/18/2004, you wrote:
If circulators would solve the problem, by all means they would be
added.  I read a little about them when all the discussion here about
them was going on.  I will have to go back and reread the info.



--- In Repeater-Builder@yahoogroups.com, Ken Arck [EMAIL PROTECTED] wrote:
  At 11:46 AM 4/18/2004 -0700, you wrote:
  Not to mention there are all sorts of odd order mixes with his
freqs:
 
  ---you guys considered adding circulators to your transmitters?
That would
  solve the mixing issues..
 
  Ken






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