Re: [sage-support] Re: Extract only some elements from a set
Thank you very much.
On 26 February 2013 18:52, Christophe BAL wrote:
> Hello,
> this is more a python question that a sympy question
>
> If L is the list [{x0:1, x1: 0, y0: 1}], then L[0] is the dictionnary
> {x0:1, x1: 0, y0: 1}. Than you can try something like L[0]["x0"] or
> L[0][x0].
>
> Hoping that this will help you.
>
> Best regards.
> Christophe.
>
>
> 2013/2/26 Santanu Sarkar
>
>> Sorry, I can not understand the approach.
>>
>> Let I=[{x0:1, x1: 0, y0: 1}]. Suppose I want to find only x0 and x1.
>> How is it possible?
>>
>>
>> On 26 February 2013 16:37, akhil wrote:
>>
>>>
>>>
>>> On Tuesday, February 26, 2013 1:40:26 PM UTC+5:30, Santanu wrote:
Dear all,
I have a set non linear equations over Boolean variables x_1,...,
x_{1}.
Sat solver gives I=[{x1: 0, x100: 1, .}]. I am interested to see
only the values
of x1,.., x100. Will you kindly help me ?
>>>
>>>
>>> Hello,
>>>
>>> Let d be the concerned dictionary, whose keys are x1 to x1, and
>>> corresponding to each key, value is in {0,1}.
>>>
>>> One can do the following:
>>>
>>> l = [ ]
>>> for i in range(1,101):
>>> l.append('x' + str(i))
>>>
>>> d1 = { }
>>>
>>> d1 = {keys:d[keys] for keys in l}
>>>
>>> The result will be the dictionary d1 containing only (key,value) pairs
>>> corresponding to keys x1,x100.
>>>
>>> Regards,
>>>
>>> AKHIL.
>>>
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>>>
>>
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>>
>
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Re: [sage-support] Re: Extract only some elements from a set
Hello,
this is more a python question that a sympy question
If L is the list [{x0:1, x1: 0, y0: 1}], then L[0] is the dictionnary
{x0:1, x1: 0, y0: 1}. Than you can try something like L[0]["x0"] or
L[0][x0].
Hoping that this will help you.
Best regards.
Christophe.
2013/2/26 Santanu Sarkar
> Sorry, I can not understand the approach.
>
> Let I=[{x0:1, x1: 0, y0: 1}]. Suppose I want to find only x0 and x1.
> How is it possible?
>
>
> On 26 February 2013 16:37, akhil wrote:
>
>>
>>
>> On Tuesday, February 26, 2013 1:40:26 PM UTC+5:30, Santanu wrote:
>>>
>>> Dear all,
>>> I have a set non linear equations over Boolean variables x_1,...,
>>> x_{1}.
>>> Sat solver gives I=[{x1: 0, x100: 1, .}]. I am interested to see
>>> only the values
>>> of x1,.., x100. Will you kindly help me ?
>>>
>>
>>
>> Hello,
>>
>> Let d be the concerned dictionary, whose keys are x1 to x1, and
>> corresponding to each key, value is in {0,1}.
>>
>> One can do the following:
>>
>> l = [ ]
>> for i in range(1,101):
>> l.append('x' + str(i))
>>
>> d1 = { }
>>
>> d1 = {keys:d[keys] for keys in l}
>>
>> The result will be the dictionary d1 containing only (key,value) pairs
>> corresponding to keys x1,x100.
>>
>> Regards,
>>
>> AKHIL.
>>
>>>
>>>
>>>
>>>
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>>
>>
>>
>
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Re: [sage-support] Re: Extract only some elements from a set
Sorry, I can not understand the approach.
Let I=[{x0:1, x1: 0, y0: 1}]. Suppose I want to find only x0 and x1.
How is it possible?
On 26 February 2013 16:37, akhil wrote:
>
>
> On Tuesday, February 26, 2013 1:40:26 PM UTC+5:30, Santanu wrote:
>>
>> Dear all,
>> I have a set non linear equations over Boolean variables x_1,...,
>> x_{1}.
>> Sat solver gives I=[{x1: 0, x100: 1, .}]. I am interested to see only
>> the values
>> of x1,.., x100. Will you kindly help me ?
>>
>
>
> Hello,
>
> Let d be the concerned dictionary, whose keys are x1 to x1, and
> corresponding to each key, value is in {0,1}.
>
> One can do the following:
>
> l = [ ]
> for i in range(1,101):
> l.append('x' + str(i))
>
> d1 = { }
>
> d1 = {keys:d[keys] for keys in l}
>
> The result will be the dictionary d1 containing only (key,value) pairs
> corresponding to keys x1,x100.
>
> Regards,
>
> AKHIL.
>
>>
>>
>>
>>
>> --
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> For more options, visit https://groups.google.com/groups/opt_out.
>
>
>
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