Sure, thanks!
пятница, 22 марта 2019 г., 19:39:06 UTC+3 пользователь Mike Bayer написал:
>
> On Fri, Mar 22, 2019 at 10:53 AM Konstantin Naumov > wrote:
> >
> > Great, thank you!
> >
> > I thought that I can use a field of relationship() - “invited_by" in
> User model for emitting the similar query, but I'm getting an empty list.
>
> take a look at SQL being emitted with echo=True
>
>
> >
> >
> > On Mar 20, 2019, at 12:55 AM, Mike Bayer > wrote:
> >
> > On Tue, Mar 19, 2019 at 10:23 AM kosta >
> wrote:
> >
> >
> > Hello Mike,
> > Thank you for your response!
> >
> >
> > First of all, I'm apologize, I have lack knowledge in sql. I guess my
> SQL should be as:
> > Get all users invited by specific user:
> >
> > SELECT u.name AS "sender", i.name AS "invitee"
> > FROM invitation inv
> > LEFT JOIN user u ON inv.sender_id=u.id
> > LEFT JOIN user i ON inv.invitee_id=i.id
> > WHERE inv.sender_id=?;
> >
> > Get user who invited specific user:
> >
> > SELECT u.name AS "invited_by", i.name AS "invitee"
> > FROM invitation inv
> > LEFT JOIN user u ON inv.sender_id=u.id
> > LEFT JOIN user i ON inv.invitee_id=i.id
> > WHERE inv.invitee_id=?;
> >
> >
> > here's the form of the first one and the second is basically the same
> idea:
> >
> > from sqlalchemy.orm import aliased
> >
> > u = aliased(User, "u")
> > i = aliased(User, "i")
> >
> > q = session.query(
> >u.name.label("sender"),
> >i.name.label("invitee")
> > ).select_from(Invitation).\
> >outerjoin(u, Invitation.sender).\
> >outerjoin(i, Invitation.invitee).\
> >filter(Invitation.sender_id=5)
> >
> >
> >
> > понедельник, 18 марта 2019 г., 17:48:26 UTC+3 пользователь Mike Bayer
> написал:
> >
> >
> > On Sat, Mar 16, 2019 at 9:33 AM kosta wrote:
> >
> >
> > Hello everyone!
> >
> > I've designed invitation model
> > class User(Base):
> > __tablename__ = 'user'
> >
> > id = Column(Integer, primary_key=True)
> > name = Column(String(64))
> > email = Column(String(64))
> > class Invitation(Base):
> > __tablename__ = 'invitation'
> >
> > id = Column(Integer, primary_key=True)
> > sender_id = Column(Integer, ForeignKey('user.id'))
> > invitee_id = Column(Integer, ForeignKey('user.id'), unique=True)
> > sender = relationship('User', foreign_keys=[sender_id],
> backref='invite_list')
> > invitee = relationship('User', foreign_keys=[invitee_id],
> backref='invited_by', uselist=False)
> >
> > email = Column(String)
> > phone = Column(String)
> > token = Column(String)
> >
> > My logic is:
> >
> > 1. Create a new record in Invitation table: sender_id - current user,
> email or phone and unique generated token.
> > 2. Create a new record in User table keep received token, commit it.
> > 3. Find a record in Invitation table by filter token and update filed
> invitee_id == new_user.id
> >
> >
> > My problem is backref return value for invited_by - return (of course)
> Invitation record.
> > My question is whether I've possibility return for invited_by User
> record via Invitation table or not?
> >
> >
> > you can find any record via anything, what SQL would you like to emit
> please ?
> >
> >
> >
> >
> >
> > --
> > SQLAlchemy -
> > The Python SQL Toolkit and Object Relational Mapper
> >
> > http://www.sqlalchemy.org/
> >
> > To post example code, please provide an MCVE: Minimal, Complete, and
> Verifiable Example. See http://stackoverflow.com/help/mcve for a full
> description.
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> >
> >
> > --
> > SQLAlchemy -
> > The Python SQL Toolkit and Object Relational Mapper
> >
> > http://www.sqlalchemy.org/
> >
> > To post example code, please provide an MCVE: Minimal, Complete, and
> Verifiable Example. See http://stackoverflow.com/help/mcve for a full
> description.
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> >
> >
> > --
> > SQLAlchemy -
> > The Python SQL Toolkit and Object Relational Mapper
> >
> > http://www.sqlalchemy.org/
> >
> > To post example code, please provide an MCVE: Minimal, Complete, and
> Verifiable Example. See http://stackoverflow.com/help/mcve for a full
> description.
> > ---
>
