dialect has a has_table method:
engine.dialect.has_table(engine.connect(), mytable)
On Apr 25, 2012, at 10:33 AM, Massi wrote:
Thank you for your reply Wichert, I already used the Inspector method
get_table_names(), but using that I'd have to check if a table name is
present in a vector which can have 100.000 elements. This can be even
slower if done for lots of times. Maybe I can perform a binary search,
but I'm not sure that the resulting vector is ordered. Am I wrong?
Other Ideas?
On 25 Apr, 16:11, Wichert Akkerman wich...@wiggy.net wrote:
On 04/25/2012 03:57 PM, Massi wrote:
Hi everyone,
in my script I have to deal with a huge database with thousands of
tables. Given a table name (a python string) I would have to now if
such a table exists or not. Up to now I have written this function:
def DBGetTableByName(table_name) :
metadata = MetaData(engine)
try :
table = Table(table_name, metadata, autoload=True)
return table
except NoSuchTableError :
return None
I use its return value to check if the table exists, but the problem
is that it is too slow. Since I have to repeat this operation several
times I wonder if there is a faster (and smarter) way to perform this
control.
Any hints?
Use the inspector:
from sqlalchemy.engine.reflection import Inspector
inspector = Inspector.from_engine(engine)
print table_name in inspector.get_table_names()
You can find the documentation
here:http://docs.sqlalchemy.org/en/rel_0_7/core/schema.html?highlight=insp...
Wichert.
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