Re: converting DeltaCad files

2000-04-04 Thread Alexei PACE

Hello all
I use AutoCAD and if I'm not wrong it can output files in both of
these formats.

Will let you know when i'm home in some hours.

Thanks
alexei pace



At 19:07 04/04/2000, Gordon Uber wrote:

John,

I would suggest saving the DeltaCad file in a standard CAD format (such
as DXF or an AutoCAD format) and then running it through another CAD
program which can output the HPGL2 or PLT file. HPGL (Hewlett Packard
Graphics Language) is for HP printers/plotters; I do not know what PLT
is: perhaps a Macintosh format?

Conversion programs such as HiJaak can perhaps do the conversion also,
but are a bit expensive.

It would be appreciated if you let us know what solution you find.

Best wishes,

Gordon

At 08:04 AM 4/3/00 -0700, John Carmichael wrote:
Hi Ron (or anybody else who might know):

I did some checking with a local print shop to see if they would be able
to
print large blueline copys of sundials drawn on DeltaCad. They can,
I was
told, if these files are in HPGL-2 or PLT form.

I went to save as and these files are not listed as
options. Do you know
how to convert DeltaCad files into HPGH-2 or PLT files???

Thanks,

John Carmichael
Gordon Uber [EMAIL PROTECTED] San Diego, California
USA
Webmaster: Clocks and Time:
http://www.ubr.com/clocks


*
The early bird gets the worm, but the second mouse gets the
cheese!




RE: Analemma Stuff

2000-04-04 Thread Andrew James

Thibaud Taudin-Chabot wrote

it is simple arithmetic: our watch shows mean time, so the mean of the
correction should be 0, otherwise your watch is fast or slow after a year.

I thought just the same when I first saw the question - but then I thought
again.  I believe that the above condition means that the average length of
the day (or hour, minute, second ...) shown by solar time must be the same
as by the mean sun or corresponding clock.  But you could declare solar noon
today - at the meridian or allowing for the difference in longitude - to be
at 12:02 or 11:57 or at any other time without affecting the going either of
the sun or the clock.  Therefore one can offset the EoT curve by a fixed
amount with impunity in this respect.  In fact this is exactly what we do by
adopting a time at a longitude different from our own - or still more
drastically by introducing daylight saving.

I believe that the EoT curve IS chosen so that the average IS zero, which is
the same as saying that if both its two sinusoidal components were reduced
in amplitude to zero, then it would lie along the straight line of zero
correction.  This is entirely logical as if the magnitude were zero then it
would make no sense to have a non-zero EoT.  Adding up the two sine waves,
at frequencies of 1/year and 2/year with their different zero cross points
and amplitudes, quite naturally results in the curve we know with its
particular crossing points.  These dates are therefore not arbitrary but
derive from the relationships of the phases (as they relate to our calendar)
and the amplitudes of the two contributing components of its cause, the
orbital eccentricity and the inclination.

Andrew James
01 18 W
51 04 N


Zero point on the Analemma Answer

2000-04-04 Thread BillGottesman

I think Andrew James' explanation about the sum of two symmetrical curves 
(inclination and orbital eccentricity) may be exactly how the zero point for 
the equation of time was determined.  There is a good article on this in Sky 
and Telescope, July 1972, pages 20-3 by Bernard Oliver.  He breaks down the 
analemma into these two curves, each of which is appears to be symmetrically 
referenced around the zero point (EoT=0).  He then demonstrates, as Luke 
Coletti points out, that these curves change over time, changing the overall 
shape of the analemma.  He calculates that in 1246AD the analemma was a 
symmetric figure 8, with its intersecting point (where the 8 crosses itself) 
at EoT=0.



Bill Gottesman
Burlington, VT


Re: Analemma Stuff

2000-04-04 Thread Daniel Lee Wenger

Bill

I think that it was not a choice to index to those dates but instead  to
place the
analemma such that the number of days that the EoT is positive is the same as
the number of days that the EoT is negative. If the analemma is displaced this
balance cannot occur. I discuss this average on my page at

http://www.wengersundial.com/math/analemmaCalc.html

Dan Wenger


4/3/00
Does anyone know why the equation of time is indexed to zero on 9/1, 12/25,
etc.?  That is to say, when the clock was originally being indexed to the sun
(17th century?), why did they pick this set of dates as the zero point?  Why
not, for example, set the clock to where the analemma crosses itself, or to
one of the solstices, or equinoxes?  I'm sure there is a good reason, but I
haven't been able to think of it.  Maybe it has to do with indexing the clock
to sidereal time, and not to sun time.  Any takers?

Bill Gottesman
Burlington, VT


Daniel Lee Wenger
Santa Cruz, CA
[EMAIL PROTECTED]
http://wengersundial.com
http://wengersundial.com/wengerfamily



Re: Analemma Stuff

2000-04-04 Thread Fritz Stumpges

Luke, I really liked your clear explanation, but I think you meant to say
the ANALEMMA has two components, the EOT and the declination.  The EOT is
not dependent upon the obliquity; we would still have it even if the axis
were perpendicular to the ecliptic.  Luckily, both independent components
have a common, cyclical variable,  the time of the year, and therefore have
a single solution graph.  Like you said, can you imagine the changing
analemma if precession were only 100 years instead of 26,000 or so years!


Re: Analemma Stuff

2000-04-04 Thread Hank de Wit



I don't really know, but I would think that the zero level is chosen so 
that the total area of the EQT curve above the line matches that below the 
line. This would make the annual mean of the EQT would be zero minutes.


At 23:02 3/04/2000 -0400, [EMAIL PROTECTED] wrote:

4/3/00
Does anyone know why the equation of time is indexed to zero on 9/1, 12/25,
etc.?  That is to say, when the clock was originally being indexed to the sun
(17th century?), why did they pick this set of dates as the zero point?  Why
not, for example, set the clock to where the analemma crosses itself, or to
one of the solstices, or equinoxes?  I'm sure there is a good reason, but I
haven't been able to think of it.  Maybe it has to do with indexing the clock
to sidereal time, and not to sun time.  Any takers?

Bill Gottesman
Burlington, VT


Regards

Hank de Wit
Adelaide
Australia
34.9231S 138.6206E
B[EMAIL PROTECTED]/B


Re: Analemma Stuff

2000-04-04 Thread Luke Coletti

Hi Bill,

If you mean to ask why the EoT was made to be zero at a given
set of dates, I think the answer is that it wasn't. One can't
arbitrarily make the EoT zero points (four of) synchronous to a set of
dates. The EoT has two components, obliquity (the tilt of our axis
relative to the plane of our orbit) and eccentricity (the elliptical
shape of our orbit). Obliquity will always be synchronous to the four
cardinal positions of the orbit (the equinoxes and solstices),
eccentricity will always be synchronous to the passage of perihelion.
The two components however are NOT synchronous to one another, I have
explained this in some detail in earlier messages. In short, because the
two components are not synchronous to one another the EoT undergoes
variation in time. So a set of 17th century values will definitely not
be the same as those today, i.e., the shape of the analemma will be
different. 

Regards,

Luke Coletti 


[EMAIL PROTECTED] wrote:
 
 4/3/00
 Does anyone know why the equation of time is indexed to zero on 9/1, 12/25,
 etc.?  That is to say, when the clock was originally being indexed to the sun
 (17th century?), why did they pick this set of dates as the zero point?  Why
 not, for example, set the clock to where the analemma crosses itself, or to
 one of the solstices, or equinoxes?  I'm sure there is a good reason, but I
 haven't been able to think of it.  Maybe it has to do with indexing the clock
 to sidereal time, and not to sun time.  Any takers?
 
 Bill Gottesman
 Burlington, VT


Re: Analemma Stuff

2000-04-04 Thread Luke Coletti

Hi Fritz,

The analemma is in essence just a graph of the EoT vs Declination, in
discussing the components of the EoT the analemma need not be mentioned,
the analemma is just another way of expressing the EoT. The dynamics of
the EoT define the shape of the analemma.

As regards to the EoT not being dependent upon obliquity, I'm not sure
what to say, other than it truly is. I can say that you are correct in
saying that some value for the EoT would still exist if our axis of
rotation was perpendicular to the plane of our orbit (zero obliquity),
assuming that there is still eccentricity to the orbit.

Also, the analemma fundamentally needs no correlation to date. The
single solution you mention has to do with orbital position not the
date. However, many (like me) include the date along the analemma and
the short term variation of the leap year cycle will effect the
placement of the date ticks. 

As regards to the variation of the EoT (changing shape of the analemma)
requiring 26,000years, this too is incorrect. I've explained this in
some length in earlier messages to the list. In short, the rate at which
the Vernal Equinox approaches perihelion is approx. 50arc-secs/yr and
the rate at which perihelion approaches the Vernal Equinox is close to 7
arc-secs/yr with a delta close to 1arc-min/yr! For example, the shape of
the analemma was symmetrical in the 16th century, is it symmetrical now?
Hmmm, what happened? Was the 16th century 26,000 year ago? 


Regards,

Luke Coletti


Fritz Stumpges wrote:
 
 Luke, I really liked your clear explanation, but I think you meant to say
 the ANALEMMA has two components, the EOT and the declination.  The EOT is
 not dependent upon the obliquity; we would still have it even if the axis
 were perpendicular to the ecliptic.  Luckily, both independent components
 have a common, cyclical variable,  the time of the year, and therefore have
 a single solution graph.  Like you said, can you imagine the changing
 analemma if precession were only 100 years instead of 26,000 or so years!


Creating .prn files for a plotter

2000-04-04 Thread Robert Terwilliger

Hi All,

Here is a way to produce .prn plotter files directly from DeltaCad, or
any CAD Program.

These directions are for Windows98, but they should adapt to other
Windows versions.

Go to Control Panel | Printers.

Select Add Printer, and follow the Wizard to install a Local
Printer.

From the list of Manufacturers: select HP (Hewlett Packard)

From the list of Printers: select 7585A (It's a plotter).

Click Next, and under Available Ports select File.

Click Next - You may need your Win98 CDROM. 

If you opted to print a test page, type afilename.prn in the dialog. 

afilename.prn should appear in the folder you selected. There isn't
much you can do with it unless you have a plotter.

---

If all has gone well the 7585A plotter should appear in your pick list
of installed printers, and any files sent to the 7585A plotter will
actually be sent to disk as a .prn file. (You must include the
extension.)

The 7585A will accept paper sizes up to 34x44 inches. I would get
together with whoever is going to plot your drawing to find out about
scale etc. They may suggest you install a different plotter to
correspond to whatever they use.

I hope this helps,

Bob


Re: Analemma Stuff

2000-04-04 Thread T. M. Taudin-Chabot

it is simple arithmetic: our watch shows mean time, so the mean of the
correction should be 0, otherwise your watch is fast or slow after a year.


At 23:02 3-4-00 EDT, you wrote:
-Original Message/Oorspronkelijk bericht--
4/3/00
Does anyone know why the equation of time is indexed to zero on 9/1, 12/25, 
etc.?  That is to say, when the clock was originally being indexed to the
sun 
(17th century?), why did they pick this set of dates as the zero point?  Why 
not, for example, set the clock to where the analemma crosses itself, or to 
one of the solstices, or equinoxes?  I'm sure there is a good reason, but I 
haven't been able to think of it.  Maybe it has to do with indexing the
clock 
to sidereal time, and not to sun time.  Any takers?

Bill Gottesman
Burlington, VT


-
Thibaud Taudin-Chabot
52°18'19.85 North  04°51'09.45 East
home email: [EMAIL PROTECTED]
(attachments max. 500kB; for larger attachments contact me first)