[symfony-users] Re: Doctrine: execute vs fetchArray
Thanks :-)
I'll keep my lovely objects !
Adrien
On 28 nov, 01:17, Alexandre SALOME alexandre.sal...@gmail.com wrote:
Yes, it's faster with a simple array hydrating... You don't instanciate your
objects, just map their configuration.
Objects are useful for executing some business logic (sometimes, very
complex). Array can be useful for templates, for example.
Depends of your case, but don't be afraid of objects ;) make some
time/memory measures in your use case, and select the best solution.
Alexandre
2009/11/28 Adrien Mogenet adrien.moge...@gmail.com
Yes I knew that, but HYDRATE_ARRAY parameters is faster and acts
differently than when we HYDRATE_OBJECT !
That was my real question... ;-)
On 27 nov, 23:40, Michael Boyd mikeboyd...@googlemail.com wrote:
The source of fetchArray() is:
public function fetchArray($params = array())
{
return $this-execute($params, Doctrine_Core::HYDRATE_ARRAY);
}
So they are exactly the same :)
On Nov 27, 8:34 pm, Adrien Mogenet adrien.moge...@gmail.com wrote:
Hi all,
I'm a Propel user, but I'm switching to Doctrine...
I don't know if I should use execute() or fetchArray() to retrieve my
data.
execute() : I get an array of Object, and I like dealing with
Objects !
fetchArray() : I read that it's better (less memory consuming ?) but I
don't really enjoy managing arrays (and arrays of arrays when I get
relationship). Moreover, when they're given to my view, it's
considered as sfOutputEscaperArrayDecorator so I have to perform -
getRawValue().
Is it really awful to call execute() method in Doctrine ?
--
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[symfony-users] yaml and mvc
I must write something about YAML in Symfony. To which group should I classify YAML: model, view or controller ? I think about view or controller or maybe both ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] Re: config/error/erro.html.php cannot be shown
Yes Lawrence, I will do your way. Thank you for your response! -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
Re: [symfony-users] yaml and mvc
YAML is a representation of a simple data structure used mostly for configuration purposes. I wouldn't class it as part of MVC at all - the same as I wouldn't XML or JSON. However, as it's a representation of data, the closest fit would be a model On 28 Nov 2009, at 09:14, mini_alexander wrote: I must write something about YAML in Symfony. To which group should I classify YAML: model, view or controller ? I think about view or controller or maybe both ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] Re: sfWidgetFormJQueryDate as default in auto generated code
On 27 Nov, 14:18, kev kbs...@gmail.com wrote: Hey Massimiliano, i'd be more than happy to try your solution, but to be honest you page is not that clear and definitely not symfony oriented. Maybe you could describe what exactly is needed, where to put it and what file to update for your solution to work in a symfony project! Thanks anyway. As stated in the top of the page, you just need the javascripts and stylesheet (you can save it from the links). I hope you're able to use symfony helpers to do it, otherwise you should read official documentation. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] generate:project directory exists?
D:\wamp\www\sf_test\lib\vendor\symfony\data\binsymfony generate:project jobeet A symfony project already exists in this directory (D:\wamp\www\sf_test \lib\ve ndor\symfony\data\bin). I am trying the jobeet tutorial.. I am using 1.4 rc2 but when i run generate project it doesn't work can anybody tell me why ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
Re: [symfony-users] yaml and mvc
In symfony, it is a tool that help us to generate our model classes, so, if it is needed , i put YAML inside the model section. In the model section you can explain in the apendix a bit about YAML and then explain the purpose of its use. Of course, don't forget that there is another ways to define you model in with Symfony. 2009/11/28 Lee Bolding l...@leesbian.net YAML is a representation of a simple data structure used mostly for configuration purposes. I wouldn't class it as part of MVC at all - the same as I wouldn't XML or JSON. However, as it's a representation of data, the closest fit would be a model On 28 Nov 2009, at 09:14, mini_alexander wrote: I must write something about YAML in Symfony. To which group should I classify YAML: model, view or controller ? I think about view or controller or maybe both ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
Re: [symfony-users] generate:project directory exists?
You need to run generate:project in the folder where it'll reside, not in symfony/data/bin According to your paths, go to d:\wamp\www\sf_test, and run php lib\vendor\symfony\data\bin\symfony generate:project jobeet Later on you can use `php symfony`, this is the only time you'll need to use that long path. On Sat, Nov 28, 2009 at 05:34, Mech7 chris.de@gmail.com wrote: D:\wamp\www\sf_test\lib\vendor\symfony\data\binsymfony generate:project jobeet A symfony project already exists in this directory (D:\wamp\www\sf_test \lib\ve ndor\symfony\data\bin). I am trying the jobeet tutorial.. I am using 1.4 rc2 but when i run generate project it doesn't work can anybody tell me why ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
Re: [symfony-users] generate:project directory exists?
You can also put in your environment path the path where reside the symfony bins (the directory where resides symfony and symfony.bat and other files, can't remember path). So you'll be able to run symfony generate:project $ everywhere you will want to. Note, you won't be able to run symfony generate:app $ (or module) in a not-symfony-project directory (a directory where you haven't ran symfony generate:project $ before, explicitly). Before Printing, Think about Your Environmental Responsibility! Avant d'Imprimer, Pensez à Votre Responsabilitée Environnementale! On Sat, Nov 28, 2009 at 4:44 PM, Gábor Fási maerl...@gmail.com wrote: You need to run generate:project in the folder where it'll reside, not in symfony/data/bin According to your paths, go to d:\wamp\www\sf_test, and run php lib\vendor\symfony\data\bin\symfony generate:project jobeet Later on you can use `php symfony`, this is the only time you'll need to use that long path. On Sat, Nov 28, 2009 at 05:34, Mech7 chris.de@gmail.com wrote: D:\wamp\www\sf_test\lib\vendor\symfony\data\binsymfony generate:project jobeet A symfony project already exists in this directory (D:\wamp\www\sf_test \lib\ve ndor\symfony\data\bin). I am trying the jobeet tutorial.. I am using 1.4 rc2 but when i run generate project it doesn't work can anybody tell me why ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] Re: yaml and mvc
But we can also configure Symfony using YAML and include javascript etc. - so model rather not. I think I will create special section for YAML - section with name 'Configuration'. Good idea ? On 28 Lis, 16:23, gato chlr dany...@gmail.com wrote: In symfony, it is a tool that help us to generate our model classes, so, if it is needed , i put YAML inside the model section. In the model section you can explain in the apendix a bit about YAML and then explain the purpose of its use. Of course, don't forget that there is another ways to define you model in with Symfony. 2009/11/28 Lee Bolding l...@leesbian.net YAML is a representation of a simple data structure used mostly for configuration purposes. I wouldn't class it as part of MVC at all - the same as I wouldn't XML or JSON. However, as it's a representation of data, the closest fit would be a model On 28 Nov 2009, at 09:14, mini_alexander wrote: I must write something about YAML in Symfony. To which group should I classify YAML: model, view or controller ? I think about view or controller or maybe both ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@goog legroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@goog legroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
Re: [symfony-users] Re: yaml and mvc
I would prefer saying uses of YAML in Symfony (or how symfony makes use of yaml -adding why -talking of benefits in a KISS approach ? -vs strictness of semantic and syntax of xmi/xml/emf for example)? And explains that it is a supported representation of data used for : configuring framework system-wide, project-wide, app-wide, module-wide, and so on, used for describing data-model to generate ORM classes and other forms, validators, migrations, and so on; that it is not validated against a meta-model for semantics (this have to be done by code using a yaml file), rather for syntax (yaml is a syntax to express semantic, semantic that is outside of the scope of yaml, imho), and so on. Before Printing, Think about Your Environmental Responsibility! Avant d'Imprimer, Pensez à Votre Responsabilitée Environnementale! On Sat, Nov 28, 2009 at 5:11 PM, mini_alexander aoohra...@gmail.com wrote: But we can also configure Symfony using YAML and include javascript etc. - so model rather not. I think I will create special section for YAML - section with name 'Configuration'. Good idea ? On 28 Lis, 16:23, gato chlr dany...@gmail.com wrote: In symfony, it is a tool that help us to generate our model classes, so, if it is needed , i put YAML inside the model section. In the model section you can explain in the apendix a bit about YAML and then explain the purpose of its use. Of course, don't forget that there is another ways to define you model in with Symfony. 2009/11/28 Lee Bolding l...@leesbian.net YAML is a representation of a simple data structure used mostly for configuration purposes. I wouldn't class it as part of MVC at all - the same as I wouldn't XML or JSON. However, as it's a representation of data, the closest fit would be a model On 28 Nov 2009, at 09:14, mini_alexander wrote: I must write something about YAML in Symfony. To which group should I classify YAML: model, view or controller ? I think about view or controller or maybe both ? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com symfony-users%2bunsubscr...@goog legroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com symfony-users%2bunsubscr...@goog legroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en. -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] Re: sfDoctrine2Plugin, generating models from class metadata instead of YAML mapping?
For anybody interested, this is possible by using the configureDoctrineConnection hook in your ProjectConfiguration class. See the following gist for an example: http://gist.github.com/244558 On Oct 18, 12:03 am, Marijn marijn.huizendv...@gmail.com wrote: Hi, Is it possible to generate the database from the phpdoc metadata mapping with sfDoctrine2Plugin instead of the default YAML mapping? Since I have already been playing a lot with doctrine 2 I don't really feel like converting all my models to YAML. Kind regards, Marijn -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] symfony upgrade from 1.2 to 1.3 fails
i wanted to upgrade a 1.2 project to 1.3 i followed the upgrade howto exactly i receive the following error message: 500 | Internal Server Error | sfParseException Configuration file /var/www/felderweb/nr1-devel/lib/vendor/ symfony-1.3.0RC2/lib/config/config/filters.yml specifies category common with missing class key. any hint from anyone? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] Re: symfony upgrade from 1.2 to 1.3 fails
RESOLVED got the svn version of 1.3 and everthing works fine ! On 28 Nov., 17:14, micon haigermo...@web.de wrote: i wanted to upgrade a 1.2 project to 1.3 i followed the upgrade howto exactly i receive the following error message: 500 | Internal Server Error | sfParseException Configuration file /var/www/felderweb/nr1-devel/lib/vendor/ symfony-1.3.0RC2/lib/config/config/filters.yml specifies category common with missing class key. any hint from anyone? -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] Re: sfValidatorDate in sf1.3/14 ?
No error i always get the today date …
Ex : type 27/11/09 - 2009-11-28 ( i try in two different module with
differents forms)
On 28 nov, 01:33, Alexandre SALOME alexandre.sal...@gmail.com wrote:
What's the outputed error ?
2009/11/27 goofy goofy.m...@gmail.com
Hi,
after migration 1.2 to 1.3, ny sfvalidatordate dont work anymore and i
cant find solution : I just want to type dd/mm/yy and get it in mysql
format :
new sfValidatorDate(array(
'date_format' = '/^(\d{2})\/(\d{2})\/(\d{2})/',
'date_output'='Y-m-d',
'with_time' = false, 'required' = true)),
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[symfony-users] issue about selecting objects in an inheritance context
Hi symfony people,
I have an issue that is quite annoying.
My environment is symfony 1.2 and propel.
I have a model where I have implemented inheritance using the single-table
strategy. So, here is an excerpt of my model:
*Ad* (id, posted_date, description)
then *RealEstateAd*(location, price, transaction_type) and *JobAd*(position,
requirements, company) which inherit both from *Ad*.
I would like to display all ads, but I would like to display a RealEstateAd
differently from a JobAd. To achieve this, I've used a partial for a
RealEstaeAd and a partial for a JobAd.
So, in the action, I did this:
*$c = new Criteria();*
*$this-allAds = AdPeer::doSelect($c);*
In the template, I did:
*?php foreach ( $allAds as $ad):?*
*?php*
*
*
*if ($add instanceof RealEstateAdd){*
*include_partial('shortViewRealEstateAd', array(add = $ad));*
*}*
*if ($add instanceof JobAd) {*
*include_partial('shortViewJobAd', array(ad = $ad));*
*}*
*?*
*hr/*
*?php endforeach; ?*
The problem is that class of an object in the $allAds array is
sfOutputEscaperObjectDecorator.
So, nothing is displayed at all.
*
*
How could I deal with this issue? is there a way to get an array with
objects which are actually of the class RealEstateAd or JobAd? How is the
hydrating process carried out here?
Many thanks for your help.
--
---
NDJIENTCHEU NGANDJUI Patrick
Software Engineer
-
To live is to choose. But to choose well, you must know who you are and
what you stand for, where you want to go and why you want to get there.
Kofi Annan
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[symfony-users] How to add additional info to cache key for some (not all) actions?
Hi! Is there any possibility in Symfony (1.2 at that point) to alter cache key generation algorithm for actions, or supply own cache_key just like it is possible with partials and components? I've read how to enable cache with PHP code for particular actions, and not with static cache.yml, using additional filter. The addCache method however needs module name, action name and parameters supplied normally in cache.yml - I'm not sure if I can add something else there. I need to make distinct cache entries for a view depending on _which_ user is logged in, and not only if an user is authenticated or not. With components and partials, I simply supply user_id as an additional parameter (or include it in sf_cache_key). I have no clue how to achieve the same thing with actions. Another case are actions which render different templates depending on the request type - whether it is typical request, or XMLHttpRequest. Am I able to make two distinct copies of such an action, or should I make two distinct actions to enable caching in that situation? Caching the view now causes trouble, because the XMLHttpRequest AJAX version returns the wrong template, which was cached before with normal request to the same action (even though the URLs are different). I'd be very grateful for any suggestions how to approach actions caching with need of additional information for cache keys. Best regards, Mateusz -- You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-us...@googlegroups.com. To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en.
[symfony-users] forms and validation
OK, newbie question here.
I used doctrine to build my forms. I then used the non-base class to
customize my forms since I don't need every single field in the form
(all I'm doing is unsetting the fields I don't want). In the
BaseContactForm class, it is setting all the fields as well as
$this-setValidators(). But it doesn't seem as if the validators are
doing anything. One field in specific is the email field.
In the setValidators function, it is set as:
'email' = new sfValidatorEmail(array('max_length' = 255,
'required' = false))
I figured that since it is calling sfValidatorEmail, it would validate
the input as being in email format, but it isn't.
Am I missing something? What do I have to do in my action to check
against the validators?
Thanks
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[symfony-users] sfWidgetFormTextareaTinyMCE class
Hello,
I'm banging my head against the wall after trying to make this work..
Here is the setting:
I have a form email like and I wanted to add TinyMCE for the main
body. I installed the sfFormExtraPlugin, and TinyMCE in my js/ folder.
Then I opened my emailForm.class.php and added:
public function configure()
{
$this-setWidgets(array( 'body' = new sfWidgetFormTextareaTinyMCE
(
array(
'width' = 550,
'height' = 350,
'config' = 'theme: simple',
),
array(
'class' = 'tiny_mce'
)
)
));
}
But then, when I render the Template containing the basic $form-render
() function it just outputs a basic textarea rows=4 cols=30
name=theemail[body] id=theemail_body/textarea
I can't make it render the TinyMCE enabled version.
TibyMCE is not the issue because if I add it manually by putting:
script type=text/javascript
tinyMCE.init({
mode: exact,
elements: theemail_body,
theme: simple
});
/script
it works..
It seems that the declaration of the new sfWidgetFormTextareaTinyMCE
() is ignored.
Any idea about how I could test the fact that the declaration is taken
into account or not and why?
Just so you know, if I mispell the new sfWidgetFormTextareaTinyMCE
() there is no error either..
Also, Eclipse seems to recognizes the class (telling me it extends the
sfWidgetFormTextarea) which would indicate that it is know by the
code..
very weirs..
Thanks
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Re: [symfony-users] forms and validation
In your action, when you bind the submitted form to your form class then the
validators kick in. So process kinda is:
- Action checks if form submitted, and it has not, so create instance of
form class with defaults and let view display form.
- User interacts with form (and your client-side javascript validation if
any) and submits succesfully.
- Action checks if form submitted, it has, so bind the post parameters to an
instance of the form class and validators will kick in to check.
- If error on bind, return to view that displays errors otherwise if no
validation errors continue processing...
For more info, look at the forms book:
http://www.symfony-project.org/forms/1_2/en/
On Sun, Nov 29, 2009 at 5:04 AM, Paul Witschger tigerseyet...@gmail.comwrote:
OK, newbie question here.
I used doctrine to build my forms. I then used the non-base class to
customize my forms since I don't need every single field in the form
(all I'm doing is unsetting the fields I don't want). In the
BaseContactForm class, it is setting all the fields as well as
$this-setValidators(). But it doesn't seem as if the validators are
doing anything. One field in specific is the email field.
In the setValidators function, it is set as:
'email' = new sfValidatorEmail(array('max_length' = 255,
'required' = false))
I figured that since it is calling sfValidatorEmail, it would validate
the input as being in email format, but it isn't.
Am I missing something? What do I have to do in my action to check
against the validators?
Thanks
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