[time-nuts] EPROMS

2011-03-24 Thread Rob Kimberley
I recently put 49 assorted EPROMs on EBay - 2732, 2764, 27128, 2564, but not
much interest (just 5 watcher after 4 days). I would rather they went to a
good home amongst the Time Nuts for the cost of postage, so have ended the
listing.

If anyone is interested please contact me off list.

Rob Kimberley





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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Bruce Griffiths
The attached circuit uses lower capacitance Schottky diodes than the 
BAT45 to reduce the capacitive feedthrough so that a much smaller value 
compensation capacitor can be used.
It also draws a relatively constant current from the supply and the 
capacitive coupling between the diodes ensures that the effect of 
transistor and diode mismatch has little effect on the switching thresholds.
Faster switching will occur if the pnp transistor (Q2, Q3) emitter 
current has a minimum value of a few mA whilst the diode current 
actually goes to zero however this requires a negative supply to ensure 
that the output signal actually switches to ground. Additional 
unswitched current sources for the pnp transistor emitters (Q2, Q3) are 
also required.


The Wenzel circuits lacking the constant current sources have a 
significant pulsed current flowing in the supply bypass system.
This can be reduced by adding an inductor in series with the emitter 
resistor, however this has the drawback that the value of the emitter 
resistor required depends on the input signal amplitude.



Bruce

Charles P. Steinmetz wrote:


One problem that is evident when a simple longtailed pair 
(differential amplifier) is used to convert a sine wave to a square 
wave is the tilt that is evident in the waveform when the output 
transistor is conducting. This is due to feedthrough from the input 
signal via the emitter base capacitance of the input transistor to 
the emitter of the output transistor.
The attached circuit schematic illustrates one classical method of 
minimising this tilt.
Compensation isn't perfect due to the voltage dependence of the 
emitter base capacitance but the tilt can be significantly reduced,


I have used the attached circuit, which is a bit simpler, to the same 
end.  For the reason you stated, the compensation is not perfect, but 
it is surprisingly good.  The compensation slows the rise and fall 
times by about 1 nS, from about 7.5 nS to about 8.5 nS.


This circuit produces 5 Vpp output -- for 3.3 Vpp output, using a 121 
ohm tail resistor should work.


Best regards,

Charles




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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Bob Camp
Hi

What is the resulting square wave going to be used for?

A simple biased ACMOS gate is adequate for a lot of applications.  A 0.1 uf cap 
to couple the signal to the input. A 120K to B+ and a 100K to ground for bias 
on the same input. Square wave comes out the other side.  One usually 
terminates the line with 50 ohms ahead of the blocking cap. If the rest of your 
hex inverter is used for other things in the circuit, it's definitely the bang 
for the buck champion. 

That said, it's not the phase noise champion, or the highest dynamic range 
circuit in the group. Which brings us back to - what are you using it for?

Bob


On Mar 24, 2011, at 5:22 AM, Bruce Griffiths wrote:

> The attached circuit uses lower capacitance Schottky diodes than the BAT45 to 
> reduce the capacitive feedthrough so that a much smaller value compensation 
> capacitor can be used.
> It also draws a relatively constant current from the supply and the 
> capacitive coupling between the diodes ensures that the effect of transistor 
> and diode mismatch has little effect on the switching thresholds.
> Faster switching will occur if the pnp transistor (Q2, Q3) emitter current 
> has a minimum value of a few mA whilst the diode current actually goes to 
> zero however this requires a negative supply to ensure that the output signal 
> actually switches to ground. Additional unswitched current sources for the 
> pnp transistor emitters (Q2, Q3) are also required.
> 
> The Wenzel circuits lacking the constant current sources have a significant 
> pulsed current flowing in the supply bypass system.
> This can be reduced by adding an inductor in series with the emitter 
> resistor, however this has the drawback that the value of the emitter 
> resistor required depends on the input signal amplitude.
> 
> 
> Bruce
> 
> Charles P. Steinmetz wrote:
>> 
>>> One problem that is evident when a simple longtailed pair (differential 
>>> amplifier) is used to convert a sine wave to a square wave is the tilt that 
>>> is evident in the waveform when the output transistor is conducting. This 
>>> is due to feedthrough from the input signal via the emitter base 
>>> capacitance of the input transistor to the emitter of the output transistor.
>>> The attached circuit schematic illustrates one classical method of 
>>> minimising this tilt.
>>> Compensation isn't perfect due to the voltage dependence of the emitter 
>>> base capacitance but the tilt can be significantly reduced,
>> 
>> I have used the attached circuit, which is a bit simpler, to the same end.  
>> For the reason you stated, the compensation is not perfect, but it is 
>> surprisingly good.  The compensation slows the rise and fall times by about 
>> 1 nS, from about 7.5 nS to about 8.5 nS.
>> 
>> This circuit produces 5 Vpp output -- for 3.3 Vpp output, using a 121 ohm 
>> tail resistor should work.
>> 
>> Best regards,
>> 
>> Charles
>> 
>> 
>> 
>> 
>> ___
>> time-nuts mailing list -- time-nuts@febo.com
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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread James Fournier
My intention is to divide the signal by 10 and feed it as  an external
frequency reference into my old HP counter. Hopefully this will increase
it's stability.

As for the circuits i have tried, there  have been so many. Most of them are
variations of each other as i experimented on a breadboard. However, a few
examples are the inverter and diff. amp. circuits from the wenzel site. The
inverter (4049) produced a small .1vpp sine wave. The amp produced another
sine wave of of basically the same magnitude as the input. I also replaced
the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
produced the same result as the inverter and the Schmidt produced no output.
I tried some small signal diodes, can't remember the #, to try and rectify
the signal and just got a high output. I tried a comparator LM339 (i think)
and i got no response from the output. I tried everything with and without
an input  capacitor (.1uf) and retried most of the experiments with a 10k
pot between 5v and ground to replace the biasing resistors to allow a finer
adjustment of the input.

I have a feeling my problem is two fold: small signal with the forward
voltage drop of many of the devices i have tried and the speed of the
signal. I'm not sure everything can handle the 10Mhz signal.

On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:

> Hi
>
> What is the resulting square wave going to be used for?
>
> A simple biased ACMOS gate is adequate for a lot of applications.  A 0.1 uf
> cap to couple the signal to the input. A 120K to B+ and a 100K to ground for
> bias on the same input. Square wave comes out the other side.  One usually
> terminates the line with 50 ohms ahead of the blocking cap. If the rest of
> your hex inverter is used for other things in the circuit, it's definitely
> the bang for the buck champion.
>
> That said, it's not the phase noise champion, or the highest dynamic range
> circuit in the group. Which brings us back to - what are you using it for?
>
> Bob
>
>
> On Mar 24, 2011, at 5:22 AM, Bruce Griffiths wrote:
>
> > The attached circuit uses lower capacitance Schottky diodes than the
> BAT45 to reduce the capacitive feedthrough so that a much smaller value
> compensation capacitor can be used.
> > It also draws a relatively constant current from the supply and the
> capacitive coupling between the diodes ensures that the effect of transistor
> and diode mismatch has little effect on the switching thresholds.
> > Faster switching will occur if the pnp transistor (Q2, Q3) emitter
> current has a minimum value of a few mA whilst the diode current actually
> goes to zero however this requires a negative supply to ensure that the
> output signal actually switches to ground. Additional unswitched current
> sources for the pnp transistor emitters (Q2, Q3) are also required.
> >
> > The Wenzel circuits lacking the constant current sources have a
> significant pulsed current flowing in the supply bypass system.
> > This can be reduced by adding an inductor in series with the emitter
> resistor, however this has the drawback that the value of the emitter
> resistor required depends on the input signal amplitude.
> >
> >
> > Bruce
> >
> > Charles P. Steinmetz wrote:
> >>
> >>> One problem that is evident when a simple longtailed pair (differential
> amplifier) is used to convert a sine wave to a square wave is the tilt that
> is evident in the waveform when the output transistor is conducting. This is
> due to feedthrough from the input signal via the emitter base capacitance of
> the input transistor to the emitter of the output transistor.
> >>> The attached circuit schematic illustrates one classical method of
> minimising this tilt.
> >>> Compensation isn't perfect due to the voltage dependence of the emitter
> base capacitance but the tilt can be significantly reduced,
> >>
> >> I have used the attached circuit, which is a bit simpler, to the same
> end.  For the reason you stated, the compensation is not perfect, but it is
> surprisingly good.  The compensation slows the rise and fall times by about
> 1 nS, from about 7.5 nS to about 8.5 nS.
> >>
> >> This circuit produces 5 Vpp output -- for 3.3 Vpp output, using a 121
> ohm tail resistor should work.
> >>
> >> Best regards,
> >>
> >> Charles
> >>
> >>
> >>
> >>
> >> ___
> >> time-nuts mailing list -- time-nuts@febo.com
> >> To unsubscribe, go to
> https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
> >> and follow the instructions there.
> >
> > ___
> > time-nuts mailing list -- time-nuts@febo.com
> > To unsubscribe, go to
> https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
> > and follow the instructions there.
>
>
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>



-- 
Best Regards,

J

Re: [time-nuts] EPROMS

2011-03-24 Thread Roy Conners
Hi Rob:

I would like to give them a good home, If they are
avalible, Thank you in advance.

Roy Conners, Best 73's

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com]On
Behalf Of Rob Kimberley
Sent: Thursday, March 24, 2011 5:07 AM
To: 'Discussion of precise time and frequency measurement'
Subject: [time-nuts] EPROMS


I recently put 49 assorted EPROMs on EBay - 2732, 2764, 27128, 2564, but not
much interest (just 5 watcher after 4 days). I would rather they went to a
good home amongst the Time Nuts for the cost of postage, so have ended the
listing.

If anyone is interested please contact me off list.

Rob Kimberley





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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Bob Camp
Hi

4000 series CMOS isn't going to do very well at 10 MHz. You need to move
over to 74ACxx parts. 

The 74AC390 is a reasonable dual divide by 10. The 74AC04 is a reasonable
inverter. There are probably 100 other parts out there in the same basic
logic family that you could use. Most of them are cheap and easy to get from
a variety of places. 

Bob

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
Behalf Of James Fournier
Sent: Thursday, March 24, 2011 8:28 AM
To: Discussion of precise time and frequency measurement
Subject: Re: [time-nuts] Squaring Tbolt 10Mhz output

My intention is to divide the signal by 10 and feed it as  an external
frequency reference into my old HP counter. Hopefully this will increase
it's stability.

As for the circuits i have tried, there  have been so many. Most of them are
variations of each other as i experimented on a breadboard. However, a few
examples are the inverter and diff. amp. circuits from the wenzel site. The
inverter (4049) produced a small .1vpp sine wave. The amp produced another
sine wave of of basically the same magnitude as the input. I also replaced
the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
produced the same result as the inverter and the Schmidt produced no output.
I tried some small signal diodes, can't remember the #, to try and rectify
the signal and just got a high output. I tried a comparator LM339 (i think)
and i got no response from the output. I tried everything with and without
an input  capacitor (.1uf) and retried most of the experiments with a 10k
pot between 5v and ground to replace the biasing resistors to allow a finer
adjustment of the input.

I have a feeling my problem is two fold: small signal with the forward
voltage drop of many of the devices i have tried and the speed of the
signal. I'm not sure everything can handle the 10Mhz signal.

On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:

> Hi
>
> What is the resulting square wave going to be used for?
>
> A simple biased ACMOS gate is adequate for a lot of applications.  A 0.1
uf
> cap to couple the signal to the input. A 120K to B+ and a 100K to ground
for
> bias on the same input. Square wave comes out the other side.  One usually
> terminates the line with 50 ohms ahead of the blocking cap. If the rest of
> your hex inverter is used for other things in the circuit, it's definitely
> the bang for the buck champion.
>
> That said, it's not the phase noise champion, or the highest dynamic range
> circuit in the group. Which brings us back to - what are you using it for?
>
> Bob
>
>
> On Mar 24, 2011, at 5:22 AM, Bruce Griffiths wrote:
>
> > The attached circuit uses lower capacitance Schottky diodes than the
> BAT45 to reduce the capacitive feedthrough so that a much smaller value
> compensation capacitor can be used.
> > It also draws a relatively constant current from the supply and the
> capacitive coupling between the diodes ensures that the effect of
transistor
> and diode mismatch has little effect on the switching thresholds.
> > Faster switching will occur if the pnp transistor (Q2, Q3) emitter
> current has a minimum value of a few mA whilst the diode current actually
> goes to zero however this requires a negative supply to ensure that the
> output signal actually switches to ground. Additional unswitched current
> sources for the pnp transistor emitters (Q2, Q3) are also required.
> >
> > The Wenzel circuits lacking the constant current sources have a
> significant pulsed current flowing in the supply bypass system.
> > This can be reduced by adding an inductor in series with the emitter
> resistor, however this has the drawback that the value of the emitter
> resistor required depends on the input signal amplitude.
> >
> >
> > Bruce
> >
> > Charles P. Steinmetz wrote:
> >>
> >>> One problem that is evident when a simple longtailed pair
(differential
> amplifier) is used to convert a sine wave to a square wave is the tilt
that
> is evident in the waveform when the output transistor is conducting. This
is
> due to feedthrough from the input signal via the emitter base capacitance
of
> the input transistor to the emitter of the output transistor.
> >>> The attached circuit schematic illustrates one classical method of
> minimising this tilt.
> >>> Compensation isn't perfect due to the voltage dependence of the
emitter
> base capacitance but the tilt can be significantly reduced,
> >>
> >> I have used the attached circuit, which is a bit simpler, to the same
> end.  For the reason you stated, the compensation is not perfect, but it
is
> surprisingly good.  The compensation slows the rise and fall times by
about
> 1 nS, from about 7.5 nS to about 8.5 nS.
> >>
> >> This circuit produces 5 Vpp output -- for 3.3 Vpp output, using a 121
> ohm tail resistor should work.
> >>
> >> Best regards,
> >>
> >> Charles
> >>
> >>
> >>
> >>
> >> ___
> >> time-nuts mailin

Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Greg Broburg

What is the model of the old HP counter?? Lets have a look
at the receiving end of the arrangement. In my experience
the use of an external frequency reference with HP test
boxes has been painless, not needing any extra circuitry
between the reference and the input.

Regards;

Greg



On 3/24/2011 6:27 AM, James Fournier wrote:

My intention is to divide the signal by 10 and feed it as  an external
frequency reference into my old HP counter. Hopefully this will increase
it's stability.

As for the circuits i have tried, there  have been so many. Most of them are
variations of each other as i experimented on a breadboard. However, a few
examples are the inverter and diff. amp. circuits from the wenzel site. The
inverter (4049) produced a small .1vpp sine wave. The amp produced another
sine wave of of basically the same magnitude as the input. I also replaced
the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
produced the same result as the inverter and the Schmidt produced no output.
I tried some small signal diodes, can't remember the #, to try and rectify
the signal and just got a high output. I tried a comparator LM339 (i think)
and i got no response from the output. I tried everything with and without
an input  capacitor (.1uf) and retried most of the experiments with a 10k
pot between 5v and ground to replace the biasing resistors to allow a finer
adjustment of the input.

I have a feeling my problem is two fold: small signal with the forward
voltage drop of many of the devices i have tried and the speed of the
signal. I'm not sure everything can handle the 10Mhz signal.

On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:


Hi

What is the resulting square wave going to be used for?

A simple biased ACMOS gate is adequate for a lot of applications.  A 0.1 uf
cap to couple the signal to the input. A 120K to B+ and a 100K to ground for
bias on the same input. Square wave comes out the other side.  One usually
terminates the line with 50 ohms ahead of the blocking cap. If the rest of
your hex inverter is used for other things in the circuit, it's definitely
the bang for the buck champion.

That said, it's not the phase noise champion, or the highest dynamic range
circuit in the group. Which brings us back to - what are you using it for?

Bob


On Mar 24, 2011, at 5:22 AM, Bruce Griffiths wrote:


The attached circuit uses lower capacitance Schottky diodes than the

BAT45 to reduce the capacitive feedthrough so that a much smaller value
compensation capacitor can be used.

It also draws a relatively constant current from the supply and the

capacitive coupling between the diodes ensures that the effect of transistor
and diode mismatch has little effect on the switching thresholds.

Faster switching will occur if the pnp transistor (Q2, Q3) emitter

current has a minimum value of a few mA whilst the diode current actually
goes to zero however this requires a negative supply to ensure that the
output signal actually switches to ground. Additional unswitched current
sources for the pnp transistor emitters (Q2, Q3) are also required.

The Wenzel circuits lacking the constant current sources have a

significant pulsed current flowing in the supply bypass system.

This can be reduced by adding an inductor in series with the emitter

resistor, however this has the drawback that the value of the emitter
resistor required depends on the input signal amplitude.


Bruce

Charles P. Steinmetz wrote:

One problem that is evident when a simple longtailed pair (differential

amplifier) is used to convert a sine wave to a square wave is the tilt that
is evident in the waveform when the output transistor is conducting. This is
due to feedthrough from the input signal via the emitter base capacitance of
the input transistor to the emitter of the output transistor.

The attached circuit schematic illustrates one classical method of

minimising this tilt.

Compensation isn't perfect due to the voltage dependence of the emitter

base capacitance but the tilt can be significantly reduced,

I have used the attached circuit, which is a bit simpler, to the same

end.  For the reason you stated, the compensation is not perfect, but it is
surprisingly good.  The compensation slows the rise and fall times by about
1 nS, from about 7.5 nS to about 8.5 nS.

This circuit produces 5 Vpp output -- for 3.3 Vpp output, using a 121

ohm tail resistor should work.

Best regards,

Charles




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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread paul swed
This has also been my experience. Even 5245's. Typically 1 or less volts.

On Thu, Mar 24, 2011 at 10:31 AM, Greg Broburg  wrote:

> What is the model of the old HP counter?? Lets have a look
> at the receiving end of the arrangement. In my experience
> the use of an external frequency reference with HP test
> boxes has been painless, not needing any extra circuitry
> between the reference and the input.
>
> Regards;
>
> Greg
>
>
>
>
> On 3/24/2011 6:27 AM, James Fournier wrote:
>
>> My intention is to divide the signal by 10 and feed it as  an external
>> frequency reference into my old HP counter. Hopefully this will increase
>> it's stability.
>>
>> As for the circuits i have tried, there  have been so many. Most of them
>> are
>> variations of each other as i experimented on a breadboard. However, a few
>> examples are the inverter and diff. amp. circuits from the wenzel site.
>> The
>> inverter (4049) produced a small .1vpp sine wave. The amp produced another
>> sine wave of of basically the same magnitude as the input. I also replaced
>> the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
>> produced the same result as the inverter and the Schmidt produced no
>> output.
>> I tried some small signal diodes, can't remember the #, to try and rectify
>> the signal and just got a high output. I tried a comparator LM339 (i
>> think)
>> and i got no response from the output. I tried everything with and without
>> an input  capacitor (.1uf) and retried most of the experiments with a 10k
>> pot between 5v and ground to replace the biasing resistors to allow a
>> finer
>> adjustment of the input.
>>
>> I have a feeling my problem is two fold: small signal with the forward
>> voltage drop of many of the devices i have tried and the speed of the
>> signal. I'm not sure everything can handle the 10Mhz signal.
>>
>> On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:
>>
>>  Hi
>>>
>>> What is the resulting square wave going to be used for?
>>>
>>> A simple biased ACMOS gate is adequate for a lot of applications.  A 0.1
>>> uf
>>> cap to couple the signal to the input. A 120K to B+ and a 100K to ground
>>> for
>>> bias on the same input. Square wave comes out the other side.  One
>>> usually
>>> terminates the line with 50 ohms ahead of the blocking cap. If the rest
>>> of
>>> your hex inverter is used for other things in the circuit, it's
>>> definitely
>>> the bang for the buck champion.
>>>
>>> That said, it's not the phase noise champion, or the highest dynamic
>>> range
>>> circuit in the group. Which brings us back to - what are you using it
>>> for?
>>>
>>> Bob
>>>
>>>
>>> On Mar 24, 2011, at 5:22 AM, Bruce Griffiths wrote:
>>>
>>>  The attached circuit uses lower capacitance Schottky diodes than the

>>> BAT45 to reduce the capacitive feedthrough so that a much smaller value
>>> compensation capacitor can be used.
>>>
 It also draws a relatively constant current from the supply and the

>>> capacitive coupling between the diodes ensures that the effect of
>>> transistor
>>> and diode mismatch has little effect on the switching thresholds.
>>>
 Faster switching will occur if the pnp transistor (Q2, Q3) emitter

>>> current has a minimum value of a few mA whilst the diode current actually
>>> goes to zero however this requires a negative supply to ensure that the
>>> output signal actually switches to ground. Additional unswitched current
>>> sources for the pnp transistor emitters (Q2, Q3) are also required.
>>>
 The Wenzel circuits lacking the constant current sources have a

>>> significant pulsed current flowing in the supply bypass system.
>>>
 This can be reduced by adding an inductor in series with the emitter

>>> resistor, however this has the drawback that the value of the emitter
>>> resistor required depends on the input signal amplitude.
>>>

 Bruce

 Charles P. Steinmetz wrote:

> One problem that is evident when a simple longtailed pair (differential
>>
> amplifier) is used to convert a sine wave to a square wave is the tilt
>>> that
>>> is evident in the waveform when the output transistor is conducting. This
>>> is
>>> due to feedthrough from the input signal via the emitter base capacitance
>>> of
>>> the input transistor to the emitter of the output transistor.
>>>
 The attached circuit schematic illustrates one classical method of
>>
> minimising this tilt.
>>>
 Compensation isn't perfect due to the voltage dependence of the emitter
>>
> base capacitance but the tilt can be significantly reduced,
>>>
 I have used the attached circuit, which is a bit simpler, to the same
>
 end.  For the reason you stated, the compensation is not perfect, but it
>>> is
>>> surprisingly good.  The compensation slows the rise and fall times by
>>> about
>>> 1 nS, from about 7.5 nS to about 8.5 nS.
>>>
 This circuit produces 5 Vpp output -- for 3.3 Vpp output, using a 121
>
 oh

Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread James Fournier
The counter is an HP 5381A 80 Mhz. According to the manual it will take up
to 2Mhz as a reference input. Just for fun, i tried feeding it the 10Mhz and
it didn't like it.

On Thu, Mar 24, 2011 at 10:31 AM, Greg Broburg  wrote:

> What is the model of the old HP counter?? Lets have a look
> at the receiving end of the arrangement. In my experience
> the use of an external frequency reference with HP test
> boxes has been painless, not needing any extra circuitry
> between the reference and the input.
>
> Regards;
>
> Greg
>
>
>
>
> On 3/24/2011 6:27 AM, James Fournier wrote:
>
>> My intention is to divide the signal by 10 and feed it as  an external
>> frequency reference into my old HP counter. Hopefully this will increase
>> it's stability.
>>
>> As for the circuits i have tried, there  have been so many. Most of them
>> are
>> variations of each other as i experimented on a breadboard. However, a few
>> examples are the inverter and diff. amp. circuits from the wenzel site.
>> The
>> inverter (4049) produced a small .1vpp sine wave. The amp produced another
>> sine wave of of basically the same magnitude as the input. I also replaced
>> the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
>> produced the same result as the inverter and the Schmidt produced no
>> output.
>> I tried some small signal diodes, can't remember the #, to try and rectify
>> the signal and just got a high output. I tried a comparator LM339 (i
>> think)
>> and i got no response from the output. I tried everything with and without
>> an input  capacitor (.1uf) and retried most of the experiments with a 10k
>> pot between 5v and ground to replace the biasing resistors to allow a
>> finer
>> adjustment of the input.
>>
>> I have a feeling my problem is two fold: small signal with the forward
>> voltage drop of many of the devices i have tried and the speed of the
>> signal. I'm not sure everything can handle the 10Mhz signal.
>>
>> On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:
>>
>>  Hi
>>>
>>> What is the resulting square wave going to be used for?
>>>
>>> A simple biased ACMOS gate is adequate for a lot of applications.  A 0.1
>>> uf
>>> cap to couple the signal to the input. A 120K to B+ and a 100K to ground
>>> for
>>> bias on the same input. Square wave comes out the other side.  One
>>> usually
>>> terminates the line with 50 ohms ahead of the blocking cap. If the rest
>>> of
>>> your hex inverter is used for other things in the circuit, it's
>>> definitely
>>> the bang for the buck champion.
>>>
>>> That said, it's not the phase noise champion, or the highest dynamic
>>> range
>>> circuit in the group. Which brings us back to - what are you using it
>>> for?
>>>
>>> Bob
>>>
>>>
>>> On Mar 24, 2011, at 5:22 AM, Bruce Griffiths wrote:
>>>
>>>  The attached circuit uses lower capacitance Schottky diodes than the

>>> BAT45 to reduce the capacitive feedthrough so that a much smaller value
>>> compensation capacitor can be used.
>>>
 It also draws a relatively constant current from the supply and the

>>> capacitive coupling between the diodes ensures that the effect of
>>> transistor
>>> and diode mismatch has little effect on the switching thresholds.
>>>
 Faster switching will occur if the pnp transistor (Q2, Q3) emitter

>>> current has a minimum value of a few mA whilst the diode current actually
>>> goes to zero however this requires a negative supply to ensure that the
>>> output signal actually switches to ground. Additional unswitched current
>>> sources for the pnp transistor emitters (Q2, Q3) are also required.
>>>
 The Wenzel circuits lacking the constant current sources have a

>>> significant pulsed current flowing in the supply bypass system.
>>>
 This can be reduced by adding an inductor in series with the emitter

>>> resistor, however this has the drawback that the value of the emitter
>>> resistor required depends on the input signal amplitude.
>>>

 Bruce

 Charles P. Steinmetz wrote:

> One problem that is evident when a simple longtailed pair (differential
>>
> amplifier) is used to convert a sine wave to a square wave is the tilt
>>> that
>>> is evident in the waveform when the output transistor is conducting. This
>>> is
>>> due to feedthrough from the input signal via the emitter base capacitance
>>> of
>>> the input transistor to the emitter of the output transistor.
>>>
 The attached circuit schematic illustrates one classical method of
>>
> minimising this tilt.
>>>
 Compensation isn't perfect due to the voltage dependence of the emitter
>>
> base capacitance but the tilt can be significantly reduced,
>>>
 I have used the attached circuit, which is a bit simpler, to the same
>
 end.  For the reason you stated, the compensation is not perfect, but it
>>> is
>>> surprisingly good.  The compensation slows the rise and fall times by
>>> about
>>> 1 nS, from about 7.5 nS to about 8.5

[time-nuts] chip scale Cs133 cell.

2011-03-24 Thread Luis Cupido

http://spectrum.ieee.org/semiconductors/devices/chipscale-atomic-clock

Luis Cupido
ct1dmk.


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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Bruce Griffiths

James Fournier wrote:

My intention is to divide the signal by 10 and feed it as  an external
frequency reference into my old HP counter. Hopefully this will increase
it's stability.

As for the circuits i have tried, there  have been so many. Most of them are
variations of each other as i experimented on a breadboard. However, a few
examples are the inverter and diff. amp. circuits from the wenzel site. The
inverter (4049) produced a small .1vpp sine wave. The amp produced another
sine wave of of basically the same magnitude as the input. I also replaced
the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
produced the same result as the inverter and the Schmidt produced no output.
I tried some small signal diodes, can't remember the #, to try and rectify
the signal and just got a high output. I tried a comparator LM339 (i think)
and i got no response from the output.


The LM339 is far too slow for a 10MHz input among other things its 
output stage cannot switch fast enough, faster comparators such as the 
MAX999 and ADCMP600 series work well.



  I tried everything with and without
an input  capacitor (.1uf) and retried most of the experiments with a 10k
pot between 5v and ground to replace the biasing resistors to allow a finer
adjustment of the input.

I have a feeling my problem is two fold: small signal with the forward
voltage drop of many of the devices i have tried and the speed of the
signal. I'm not sure everything can handle the 10Mhz signal.

On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:

   





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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Greg Broburg

The HP 5381A uses a Mostek MK5009 timing
generator and it operates at 1 MHz. It has a crystal
oscillator amplifier internally and this is used by
HP as the basic timebase. There is a pin made
to receive an external 1 MHz clock which is made
for TTL. The input on the 5381A is coupled directly
to the MK5009, wide open for all kinds of problems.

This should not require a lot of engineering to
interface it to the TB output. A 10 MHz input capable
of seeing the TB output followed by any of a number
of off of the shelf dividers. I would try a divide by 5
followed by a divide by 2 to drive the input of the 5009.

Bandwidth is an issue for these old PMOS parts.

Greg

On 3/24/2011 12:10 PM, Bruce Griffiths wrote:

James Fournier wrote:

My intention is to divide the signal by 10 and feed it as  an external
frequency reference into my old HP counter. Hopefully this will increase
it's stability.

As for the circuits i have tried, there  have been so many. Most of 
them are
variations of each other as i experimented on a breadboard. However, 
a few
examples are the inverter and diff. amp. circuits from the wenzel 
site. The
inverter (4049) produced a small .1vpp sine wave. The amp produced 
another
sine wave of of basically the same magnitude as the input. I also 
replaced

the inverter with a buffer (4050) and Schmidt trigger buffer. The buffer
produced the same result as the inverter and the Schmidt produced no 
output.
I tried some small signal diodes, can't remember the #, to try and 
rectify
the signal and just got a high output. I tried a comparator LM339 (i 
think)

and i got no response from the output.


The LM339 is far too slow for a 10MHz input among other things its 
output stage cannot switch fast enough, faster comparators such as the 
MAX999 and ADCMP600 series work well.



  I tried everything with and without
an input  capacitor (.1uf) and retried most of the experiments with a 
10k
pot between 5v and ground to replace the biasing resistors to allow a 
finer

adjustment of the input.

I have a feeling my problem is two fold: small signal with the forward
voltage drop of many of the devices i have tried and the speed of the
signal. I'm not sure everything can handle the 10Mhz signal.

On Thu, Mar 24, 2011 at 7:42 AM, Bob Camp  wrote:






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Re: [time-nuts] EPROMS

2011-03-24 Thread Rob Kimberley
Hi Roy,

Sorry, but they have gone now.

Thanks for asking.

Rob

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
Behalf Of Roy Conners
Sent: 24 March 2011 12:40 PM
To: Discussion of precise time and frequency measurement
Subject: Re: [time-nuts] EPROMS

Hi Rob:

I would like to give them a good home, If they are avalible, Thank you in
advance.

Roy Conners, Best 73's

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com]On
Behalf Of Rob Kimberley
Sent: Thursday, March 24, 2011 5:07 AM
To: 'Discussion of precise time and frequency measurement'
Subject: [time-nuts] EPROMS


I recently put 49 assorted EPROMs on EBay - 2732, 2764, 27128, 2564, but not
much interest (just 5 watcher after 4 days). I would rather they went to a
good home amongst the Time Nuts for the cost of postage, so have ended the
listing.

If anyone is interested please contact me off list.

Rob Kimberley





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Re: [time-nuts] chip scale Cs133 cell.

2011-03-24 Thread Rick Karlquist
Luis Cupido wrote:
> http://spectrum.ieee.org/semiconductors/devices/chipscale-atomic-clock
>
> Luis Cupido
> ct1dmk.
>

The IEEE did a terrible job writing this article.
I would have expected better from them.

Rick Karlquist N6RK


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Re: [time-nuts] chip scale Cs133 cell.

2011-03-24 Thread michael taylor
On Thu, Mar 24, 2011 at 3:06 PM, Rick Karlquist  wrote:
> Luis Cupido wrote:
>> http://spectrum.ieee.org/semiconductors/devices/chipscale-atomic-clock
>
> The IEEE did a terrible job writing this article.

It's for/from their IEEE Spectrum monthly glossy magazine portion
which I believe normally uses a lot of freelance journalists and press
releases for their news bites.

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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Hal Murray
> I'm not sure everything can handle the 10Mhz signal.

Bingo.

LM339 (National data sheet)
  Response time:0.5 us

CD4049B/CD405B (from TI data sheet)
  Rise time is 80 ns
  Fall time is 30 ns
Those are typicals at 5 V with a 5V input signal.


The LM399 says "low power" which usually means low speed.

I occasionally go "oops" when I sanity check the speed on a circuit I'm about 
to build using HC/LS parts.  They aren't very fast, and the old 4000 logic is 
even slower.

10 MHz is about the corner for HC.  I use the HC163 (4 bit binary counter) as 
an example.  It has a max clock frequency of 25 MHz, so you think "no 
problems" at 10 MHz.  But the setup times are 30-40 ns and the clock-out are 
40-50 ns so doing anything interesting at 10 MHz gets tight.



-- 
These are my opinions, not necessarily my employer's.  I hate spam.




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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Greg Broburg

what is the output drive circuit and what is the drive
level / source impedance from the Thunderbolt?

Greg




On 3/24/2011 2:10 PM, Hal Murray wrote:

I'm not sure everything can handle the 10Mhz signal.

Bingo.

LM339 (National data sheet)
   Response time:   0.5 us

CD4049B/CD405B (from TI data sheet)
   Rise time is 80 ns
   Fall time is 30 ns
Those are typicals at 5 V with a 5V input signal.


The LM399 says "low power" which usually means low speed.

I occasionally go "oops" when I sanity check the speed on a circuit I'm about
to build using HC/LS parts.  They aren't very fast, and the old 4000 logic is
even slower.

10 MHz is about the corner for HC.  I use the HC163 (4 bit binary counter) as
an example.  It has a max clock frequency of 25 MHz, so you think "no
problems" at 10 MHz.  But the setup times are 30-40 ns and the clock-out are
40-50 ns so doing anything interesting at 10 MHz gets tight.






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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Bob Camp
Hi

The TBolt is designed to drive 50 ohms on the 10 MHz output. Level is above
7 dbm on the ones I have looked at.

Bob

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
Behalf Of Greg Broburg
Sent: Thursday, March 24, 2011 5:20 PM
To: Discussion of precise time and frequency measurement
Subject: Re: [time-nuts] Squaring Tbolt 10Mhz output

what is the output drive circuit and what is the drive
level / source impedance from the Thunderbolt?

Greg




On 3/24/2011 2:10 PM, Hal Murray wrote:
>> I'm not sure everything can handle the 10Mhz signal.
> Bingo.
>
> LM339 (National data sheet)
>Response time: 0.5 us
>
> CD4049B/CD405B (from TI data sheet)
>Rise time is 80 ns
>Fall time is 30 ns
> Those are typicals at 5 V with a 5V input signal.
>
>
> The LM399 says "low power" which usually means low speed.
>
> I occasionally go "oops" when I sanity check the speed on a circuit I'm
about
> to build using HC/LS parts.  They aren't very fast, and the old 4000 logic
is
> even slower.
>
> 10 MHz is about the corner for HC.  I use the HC163 (4 bit binary counter)
as
> an example.  It has a max clock frequency of 25 MHz, so you think "no
> problems" at 10 MHz.  But the setup times are 30-40 ns and the clock-out
are
> 40-50 ns so doing anything interesting at 10 MHz gets tight.
>
>
>


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[time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread Brad Dye
Here is the solution that I chose:

http://g4hup.com/DFS/Iss2/SQ66M7.htm

Best regards,

Brad Dye
Editor, AAPC Wireless Messaging News
P.O. Box 266
Fairfield, IL  62837 USA
Telephone: 618-847-8118
Mobile phone: 618-599-7869
Skype: braddye
http://www.braddye.com



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[time-nuts] HG 414A Rubidium

2011-03-24 Thread Magnus Danielson

Fellow time-nuts,

Today a new box entered the lab, a Götting KG HG 414A. This is not of 
German origin, but is in fact a Soviet/Russian TSCH1-78. I've got SN 052 
made in 1992, but the manual seems to be written in 1986.


Manuals is some form of copy method I just can't recall right now, but 
stencil looks possible.


Mine comes with complete electrical and mechanical drawings, calibration 
manual with nice stamps . All that in russian. There is also some 
manuals translated into german which helps me a lot in the basic get 
started operation, even if my german is close to non-existent.


It is in good shape, even if a quick look at the waveforms shows that 
some improvement can be achieved. It locks and operates relatively well 
straight out of the box.


So, what does it do?

It has a Rubidium reference in it. A 5 MHz OCXO which synthesize into 90 
MHz and 5,31746 MHz which then is mixed in the cavity to 6,83468254 GHz 
with a 86,8 Hz phase-modulation for resonance sweep.


It has a lock-indicator on the front and also a trimmer for OCXO 
adjustment with indicators of direction to turn.


With that in hand, it generates 10 MHz, 5 MHz, 1 MHz and 100 kHz sine 
outputs.


It further takes a 5 MHz input and measures it's frequency over one 
second with 1E-11 resolution or over 10 or 100 s with 1E-12 resolution.
It shows 7 digit numbers. It essentially mix down to 500 Hz, 50 Hz or 5 
Hz and measures. Works nicely.


It can also measure time-differences, and thus relates to the time it 
has. It is fairly easy to set up the time of day in HH MM SS and it 
looks like you can take a PPS and time-align it to it. Then you can 
measure that time-difference. It also has a delayed output which is 
programmable in 100 ns steps.


So, this box is a bit of everything, but a rather nice one.

The DC connector is unknown to me, but the AC is a standard IEC one, so 
that took no time to hook up.


It will take some time to fully understand it, but who said it would be 
easy?


I need to brush up my russian and german... ah well.

I use a TADD-2 for wave-cleanup, but it only achieves it partly.

Cheers,
Magnus

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Re: [time-nuts] HG 414A Rubidium

2011-03-24 Thread Pete Lancashire
Pictures !!!

On Mar 24, 2011 4:31 PM, "Magnus Danielson" 
wrote:
> Fellow time-nuts,
>
> Today a new box entered the lab, a Götting KG HG 414A. This is not of
> German origin, but is in fact a Soviet/Russian TSCH1-78. I've got SN 052
> made in 1992, but the manual seems to be written in 1986.
>
> Manuals is some form of copy method I just can't recall right now, but
> stencil looks possible.
>
> Mine comes with complete electrical and mechanical drawings, calibration
> manual with nice stamps . All that in russian. There is also some
> manuals translated into german which helps me a lot in the basic get
> started operation, even if my german is close to non-existent.
>
> It is in good shape, even if a quick look at the waveforms shows that
> some improvement can be achieved. It locks and operates relatively well
> straight out of the box.
>
> So, what does it do?
>
> It has a Rubidium reference in it. A 5 MHz OCXO which synthesize into 90
> MHz and 5,31746 MHz which then is mixed in the cavity to 6,83468254 GHz
> with a 86,8 Hz phase-modulation for resonance sweep.
>
> It has a lock-indicator on the front and also a trimmer for OCXO
> adjustment with indicators of direction to turn.
>
> With that in hand, it generates 10 MHz, 5 MHz, 1 MHz and 100 kHz sine
> outputs.
>
> It further takes a 5 MHz input and measures it's frequency over one
> second with 1E-11 resolution or over 10 or 100 s with 1E-12 resolution.
> It shows 7 digit numbers. It essentially mix down to 500 Hz, 50 Hz or 5
> Hz and measures. Works nicely.
>
> It can also measure time-differences, and thus relates to the time it
> has. It is fairly easy to set up the time of day in HH MM SS and it
> looks like you can take a PPS and time-align it to it. Then you can
> measure that time-difference. It also has a delayed output which is
> programmable in 100 ns steps.
>
> So, this box is a bit of everything, but a rather nice one.
>
> The DC connector is unknown to me, but the AC is a standard IEC one, so
> that took no time to hook up.
>
> It will take some time to fully understand it, but who said it would be
> easy?
>
> I need to brush up my russian and german... ah well.
>
> I use a TADD-2 for wave-cleanup, but it only achieves it partly.
>
> Cheers,
> Magnus
>
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Re: [time-nuts] HG 414A Rubidium

2011-03-24 Thread WB6BNQ
YES ! By all means pictures please.

Pete Lancashire wrote:

> Pictures !!!
>
> On Mar 24, 2011 4:31 PM, "Magnus Danielson" 
> wrote:
> > Fellow time-nuts,
> >
> > Today a new box entered the lab, a Götting KG HG 414A. This is not of
> > German origin, but is in fact a Soviet/Russian TSCH1-78. I've got SN 052
> > made in 1992, but the manual seems to be written in 1986.
> >
> > Manuals is some form of copy method I just can't recall right now, but
> > stencil looks possible.
> >
> > Mine comes with complete electrical and mechanical drawings, calibration
> > manual with nice stamps . All that in russian. There is also some
> > manuals translated into german which helps me a lot in the basic get
> > started operation, even if my german is close to non-existent.
> >
> > It is in good shape, even if a quick look at the waveforms shows that
> > some improvement can be achieved. It locks and operates relatively well
> > straight out of the box.
> >
> > So, what does it do?
> >
> > It has a Rubidium reference in it. A 5 MHz OCXO which synthesize into 90
> > MHz and 5,31746 MHz which then is mixed in the cavity to 6,83468254 GHz
> > with a 86,8 Hz phase-modulation for resonance sweep.
> >
> > It has a lock-indicator on the front and also a trimmer for OCXO
> > adjustment with indicators of direction to turn.
> >
> > With that in hand, it generates 10 MHz, 5 MHz, 1 MHz and 100 kHz sine
> > outputs.
> >
> > It further takes a 5 MHz input and measures it's frequency over one
> > second with 1E-11 resolution or over 10 or 100 s with 1E-12 resolution.
> > It shows 7 digit numbers. It essentially mix down to 500 Hz, 50 Hz or 5
> > Hz and measures. Works nicely.
> >
> > It can also measure time-differences, and thus relates to the time it
> > has. It is fairly easy to set up the time of day in HH MM SS and it
> > looks like you can take a PPS and time-align it to it. Then you can
> > measure that time-difference. It also has a delayed output which is
> > programmable in 100 ns steps.
> >
> > So, this box is a bit of everything, but a rather nice one.
> >
> > The DC connector is unknown to me, but the AC is a standard IEC one, so
> > that took no time to hook up.
> >
> > It will take some time to fully understand it, but who said it would be
> > easy?
> >
> > I need to brush up my russian and german... ah well.
> >
> > I use a TADD-2 for wave-cleanup, but it only achieves it partly.
> >
> > Cheers,
> > Magnus
> >
> > ___
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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread James Fournier
Thanks everyone, i think the key here is to repeat with faster chips.
I appreciate  the everyone's comments.

On Thu, Mar 24, 2011 at 4:26 PM, Bob Camp  wrote:

> Hi
>
> The TBolt is designed to drive 50 ohms on the 10 MHz output. Level is above
> 7 dbm on the ones I have looked at.
>
> Bob
>
> -Original Message-
> From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
> Behalf Of Greg Broburg
> Sent: Thursday, March 24, 2011 5:20 PM
> To: Discussion of precise time and frequency measurement
> Subject: Re: [time-nuts] Squaring Tbolt 10Mhz output
>
> what is the output drive circuit and what is the drive
> level / source impedance from the Thunderbolt?
>
> Greg
>
>
>
>
> On 3/24/2011 2:10 PM, Hal Murray wrote:
> >> I'm not sure everything can handle the 10Mhz signal.
> > Bingo.
> >
> > LM339 (National data sheet)
> >Response time: 0.5 us
> >
> > CD4049B/CD405B (from TI data sheet)
> >Rise time is 80 ns
> >Fall time is 30 ns
> > Those are typicals at 5 V with a 5V input signal.
> >
> >
> > The LM399 says "low power" which usually means low speed.
> >
> > I occasionally go "oops" when I sanity check the speed on a circuit I'm
> about
> > to build using HC/LS parts.  They aren't very fast, and the old 4000
> logic
> is
> > even slower.
> >
> > 10 MHz is about the corner for HC.  I use the HC163 (4 bit binary
> counter)
> as
> > an example.  It has a max clock frequency of 25 MHz, so you think "no
> > problems" at 10 MHz.  But the setup times are 30-40 ns and the clock-out
> are
> > 40-50 ns so doing anything interesting at 10 MHz gets tight.
> >
> >
> >
>
>
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-- 
Best Regards,

James Fournier
I.T. Services
6a Ave. de Lourdes
Pointe-Claire, QC
H9S-4R2

514-562-0645
ja...@jfits.ca
www.jfits.ca
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Re: [time-nuts] Squaring Tbolt 10Mhz output

2011-03-24 Thread James Fournier
Hi Brad,

Thinks for the tip. Have you used this on an actual tbolt?

On Thu, Mar 24, 2011 at 5:48 PM, Brad Dye  wrote:

> Here is the solution that I chose:
>
> http://g4hup.com/DFS/Iss2/SQ66M7.htm
>
> Best regards,
>
> Brad Dye
> Editor, AAPC Wireless Messaging News
> P.O. Box 266
> Fairfield, IL  62837 USA
> Telephone: 618-847-8118
> Mobile phone: 618-599-7869
> Skype: braddye
> http://www.braddye.com
>
>
>
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-- 
Best Regards,

James Fournier
I.T. Services
6a Ave. de Lourdes
Pointe-Claire, QC
H9S-4R2

514-562-0645
ja...@jfits.ca
www.jfits.ca
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[time-nuts] Upgrading TS2100 from TCXO to OCXO

2011-03-24 Thread Robert Watzlavick
I've been able to successfully upgrade my Datum TS2100 to an OCXO from
the stock TCXO.  I didn't see it in the archives so I thought I'd post
my findings.  I noticed that the same firmware was used regardless of
oscillator configuration so there must either be jumpers or a hidden set
of commands.  The newer versions of the ET6000 have jumpers to select
the oscillator but I couldn't find anything similar on the TS2100. 
However, in the back of the manual, 8500-0033 Rev K, Appendix I
describes how to reconfigure the unit to output GPS instead of UTC for
NTP.  I'm not interested in that but there are some hints about a hidden
menu structure (root eng ee) which allows you to change EEPROM
settings.  Here's the hidden menu items:

root eng:
start net interface
timing tools /
serial tools /
eeprom tools /
spi tools /
flash tools /
display tools /
memory tools /
intrinsic help

Going further into one of them, root eng eeprom:
ethernet address
board serial number
gain default
filter constant
low filter constant
precision
set eeprom
get eeprom
read serial eeprom
write serial eeprom
tx 16 bits to eeprom
location for image
info value
eeprom_select
intrinsic help

So that's where the default gain and filter constants are set.  You have
to jumper across J4 on the PC board to allow EEPROM writes or you get an
error.  Not sure what the "precision" setting is for (it's currently -19).

I don't have the proper OCXO (yet) but I do have an MV89A OCXO that I
was able to wire into the circuit temporarily.  There is 12V on the
board and the 0.5-4.5V EFC range works well with the MV89A.  I used a
gain of +20 and a filter setting of 0.9994965 based on Jason Rabel's
post from 9/26/2010 (note the sign change on the gain).  The EFC
algorithm had a pretty good overshoot during the first adjustment cycle
and took over an hour to completely settle in but eventually the front
panel Locked LED turned on.  I couldn't find a way to change the
starting value for EFC (d/a) value.

I *think* an Abracon AOCJY1A-10.000MHz-E-SW part will be pin compatible
on the board.  Unfortunately nobody has that one in stock and it's a 10
week lead time so I may end up installing one off-board.  The MV89A is
too tall to fit with the lid on so it's not a long term option.  I
traced out the two SMA pads on the board and they are for the EFC out
and RF in so I could always run them to the back of the unit and put the
OCXO outside the unit.

-Bob
K5RLW

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