Re: I don't see the output under Linux

2001-08-09 Thread Stefano Bonnin

Ok, but in this case I don't see any output on the console (where I run
Tomcat)! My problem is not to redirect the stdout on a file, my proble is to
see the output.

Thanks.
- Original Message -
From: Martin van den Bemt [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, August 08, 2001 3:12 PM
Subject: RE: I don't see the output under Linux


 Just replying to the original question here :

 if you want the system.out.println logging to appear in a file instead of
 the console :
 $TOMCAT_HOME/bin/tomcat.sh start 2logfile  1errorfile
 All error and normal output to the console will be redirected this way to
 files.

 If you want logging to system.out, then the logging appears only when the
 console in which you started tomcat, not any other console which you open.

 Mvgr,
 Martin

I have introduced a System.out.println lines in my application (for
 the
testing phase), but I don't see theirs output.
I have tried to do this (every time that tomcat is started):
   
 ./tomcat start  tomcat.out
   
without success.
   





I don't see the output under Linux

2001-08-09 Thread Stefano Bonnin

Hi, I have always the same problem but I have noticed the following thing:

so far I ran tomcat with

deamon tomcat start

in this case my XSP application works but there is no output on the shell
(where I ran tomcat).

Now I decide to run tomcat with

/usr/bin/tomcat run

and the shell output is visible

BUT in this case there is another problem, if I try to access at my XSP
applycation tomcat return me the following error:

org.apache.xerces.validators.datatype.InvalidDatatypeFacetException:
[exception was kaffe.util.SupportDisabled: GNU gmp was not found by Kaffe
configure script]
 at java.lang.Throwable.fillInStackTrace(Throwable.java:native)
 at java.lang.Throwable.init(Throwable.java:38)
 at java.lang.Exception.init(Exception.java:24)
 at
org.apache.xerces.validators.datatype.XMLException.init(XMLException.java:
71)
 at
org.apache.xerces.validators.datatype.InvalidDatatypeFacetException.init(I
nvalidDatatypeFacetException.java:90)
 at
org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.createDat
atypeValidator(DatatypeValidatorFactoryImpl.java:339)
 at
org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.createDat
atypeValidator(DatatypeValidatorFactoryImpl.java:292)
 at
org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.initializ
eRegistry(DatatypeValidatorFactoryImpl.java:143)
 at
org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.init(Da
tatypeValidatorFactoryImpl.java:81)
 at
org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.clinit(
DatatypeValidatorFactoryImpl.java:76)
 at org.apache.xerces.framework.XMLParser.init(XMLParser.java:203)
 at org.apache.xerces.parsers.DOMParser.init(DOMParser.java:214)
 at org.apache.cocoon.parser.XercesParser.parse(XercesParser.java:75)
 at org.apache.cocoon.parser.AbstractParser.parse(AbstractParser.java:83)
 at org.apache.cocoon.processor.xsp.XSPProcessor.init(XSPProcessor.java:170)
 at org.apache.cocoon.framework.Manager.create(Manager.java:101)
 at org.apache.cocoon.framework.Router.init(Router.java:80)
 at org.apache.cocoon.framework.Manager.create(Manager.java:101)
 at org.apache.cocoon.Engine.init(Engine.java:171)
 at org.apache.cocoon.Engine.getInstance(Engine.java:218)
 at org.apache.cocoon.Cocoon.init(Cocoon.java:141)
 at org.apache.tomcat.core.ServletWrapper.doInit(ServletWrapper.java:line
unknown, pc 0x8936cd2)
 at org.apache.tomcat.core.Handler.init(Handler.java:line unknown, pc
0x896dd12)
 at org.apache.tomcat.core.ServletWrapper.init(ServletWrapper.java:line
unknown, pc 0x8abb1d6)
 at org.apache.tomcat.core.Handler.service(Handler.java:line unknown, pc
0x8b5c0c5)
 at org.apache.tomcat.core.ServletWrapper.service(ServletWrapper.java:line
unknown, pc 0x8b4b5dd)
 at
org.apache.tomcat.core.ContextManager.internalService(ContextManager.java:li
ne unknown, pc 0x8bfda35)
 at org.apache.tomcat.core.ContextManager.service(ContextManager.java:line
unknown, pc 0x8bfb849)
 at
org.apache.tomcat.service.http.HttpConnectionHandler.processConnection(HttpC
onnectionHandler.java:line unknown, pc 0x8bf0c2f)
 at
org.apache.tomcat.service.TcpWorkerThread.runIt(PoolTcpEndpoint.java:line
unknown, pc 0x898ae31)
 at
org.apache.tomcat.util.ThreadPool$ControlRunnable.run(ThreadPool.java:line
unknown, pc 0x8a0a439)
 at java.lang.Thread.run(Thread.java:325)
XSL Error: pattern = 'node()'
Could not find function: node
 Remaining tokens: ( '(' ')'), style tree node:
org.apache.xalan.xslt.ElemApplyTemplates@92b3e30
XSL Error: Could not parse
jar:file:/var/tomcat/lib/cocoon.jar!/org/apache/cocoon/processor/xsp/library
/java/response.xsl document!
XSL Error: SAX Exception

Why? What is the difference between the deamon starting method and the
/usr/bin/tomcat starting method?

Thanks.





Re: I don't see the output under Linux

2001-08-09 Thread David Smith

I don't know about your starting methods and why they are different, but the 
last time I saw the exception you listed was when I was trying to get Tomcat 
running and didn't realize the java environment I was running was Kaffe.  
Some docs and email messages I found make it very clear Tomcat does not work 
under Kaffe.

I'd suggest using 'java -version' on the command line to determine what java 
environment you are working with.

In my case, I have to thank Mandrake for sneaking that one into my system on 
first install :-(.

On Thursday 09 August 2001 09:25 am, you wrote:
 Hi, I have always the same problem but I have noticed the following thing:

 so far I ran tomcat with

 deamon tomcat start

 in this case my XSP application works but there is no output on the shell
 (where I ran tomcat).

 Now I decide to run tomcat with

 /usr/bin/tomcat run

 and the shell output is visible

 BUT in this case there is another problem, if I try to access at my XSP
 applycation tomcat return me the following error:

 org.apache.xerces.validators.datatype.InvalidDatatypeFacetException:
 [exception was kaffe.util.SupportDisabled: GNU gmp was not found by Kaffe
 configure script]
  at java.lang.Throwable.fillInStackTrace(Throwable.java:native)
  at java.lang.Throwable.init(Throwable.java:38)
  at java.lang.Exception.init(Exception.java:24)
  at
 org.apache.xerces.validators.datatype.XMLException.init(XMLException.java
: 71)
  at
 org.apache.xerces.validators.datatype.InvalidDatatypeFacetException.init(
I nvalidDatatypeFacetException.java:90)
  at
 org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.createDa
t atypeValidator(DatatypeValidatorFactoryImpl.java:339)
  at
 org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.createDa
t atypeValidator(DatatypeValidatorFactoryImpl.java:292)
  at
 org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.initiali
z eRegistry(DatatypeValidatorFactoryImpl.java:143)
  at
 org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.init(D
a tatypeValidatorFactoryImpl.java:81)
  at
 org.apache.xerces.validators.datatype.DatatypeValidatorFactoryImpl.clinit
( DatatypeValidatorFactoryImpl.java:76)
  at org.apache.xerces.framework.XMLParser.init(XMLParser.java:203)
  at org.apache.xerces.parsers.DOMParser.init(DOMParser.java:214)
  at org.apache.cocoon.parser.XercesParser.parse(XercesParser.java:75)
  at org.apache.cocoon.parser.AbstractParser.parse(AbstractParser.java:83)
  at
 org.apache.cocoon.processor.xsp.XSPProcessor.init(XSPProcessor.java:170) at
 org.apache.cocoon.framework.Manager.create(Manager.java:101)
  at org.apache.cocoon.framework.Router.init(Router.java:80)
  at org.apache.cocoon.framework.Manager.create(Manager.java:101)
  at org.apache.cocoon.Engine.init(Engine.java:171)
  at org.apache.cocoon.Engine.getInstance(Engine.java:218)
  at org.apache.cocoon.Cocoon.init(Cocoon.java:141)
  at org.apache.tomcat.core.ServletWrapper.doInit(ServletWrapper.java:line
 unknown, pc 0x8936cd2)
  at org.apache.tomcat.core.Handler.init(Handler.java:line unknown, pc
 0x896dd12)
  at org.apache.tomcat.core.ServletWrapper.init(ServletWrapper.java:line
 unknown, pc 0x8abb1d6)
  at org.apache.tomcat.core.Handler.service(Handler.java:line unknown, pc
 0x8b5c0c5)
  at org.apache.tomcat.core.ServletWrapper.service(ServletWrapper.java:line
 unknown, pc 0x8b4b5dd)
  at
 org.apache.tomcat.core.ContextManager.internalService(ContextManager.java:l
i ne unknown, pc 0x8bfda35)
  at org.apache.tomcat.core.ContextManager.service(ContextManager.java:line
 unknown, pc 0x8bfb849)
  at
 org.apache.tomcat.service.http.HttpConnectionHandler.processConnection(Http
C onnectionHandler.java:line unknown, pc 0x8bf0c2f)
  at
 org.apache.tomcat.service.TcpWorkerThread.runIt(PoolTcpEndpoint.java:line
 unknown, pc 0x898ae31)
  at
 org.apache.tomcat.util.ThreadPool$ControlRunnable.run(ThreadPool.java:line
 unknown, pc 0x8a0a439)
  at java.lang.Thread.run(Thread.java:325)
 XSL Error: pattern = 'node()'
 Could not find function: node
  Remaining tokens: ( '(' ')'), style tree node:
 org.apache.xalan.xslt.ElemApplyTemplates@92b3e30
 XSL Error: Could not parse
 jar:file:/var/tomcat/lib/cocoon.jar!/org/apache/cocoon/processor/xsp/librar
y /java/response.xsl document!
 XSL Error: SAX Exception

 Why? What is the difference between the deamon starting method and the
 /usr/bin/tomcat starting method?

 Thanks.




Re: I don't see the output under Linux

2001-08-08 Thread Stefano Bonnin

I tried to correct the file, but ... nothing...

But, I noticed another thing. If I start Tomcat with

tomcat run (in /usr/bin)

the output is visible on the screen but Tomcat doesn't work properly (tomcat
start correctly but if I try to access at 8080 ... it doesn't works)

instead, if I try with:

  ./tomcat start (where tomcat in this case, is the script in
/etc/rc.d/init.d/ that run the tomcat daemon --- it run a command like:
daemon tomcat start ...)

the engine works but not the output.

Thanks, thanks for your interest!!!
- Original Message -
From: Loïc Lefèvre [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, August 07, 2001 4:32 PM
Subject: RE: I don't see the output under Linux


 Okay, this file stands in the conf directory of Tomcat on your LINUX
server?
 If the answer is true, replace
 workers.tomcat_home=c:\jakarta-tomcat

 workers.java_home=c:\jdk1.2.2

 ps=\

 with the good parameters:

 especially:  ps=/ (Path separator for Linux is equals to / not \)

 Try and tell me...

 -Message d'origine-
 De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
 Envoyé : mardi 7 août 2001 16:04
 À : [EMAIL PROTECTED]
 Objet : Re: I don't see the output under Linux


  Can you send your workers.properties file?

 Yes. This is my workers.properties:

 **
 workers.tomcat_home=c:\jakarta-tomcat

 workers.java_home=c:\jdk1.2.2

 ps=\

 worker.list=ajp12, ajp13

 worker.ajp12.port=8007
 worker.ajp12.host=localhost
 worker.ajp12.type=ajp12
 worker.ajp12.lbfactor=1

 worker.ajp13.port=8009
 worker.ajp13.host=localhost
 worker.ajp13.type=ajp13
 worker.ajp13.lbfactor=1

 worker.loadbalancer.type=lb
 worker.loadbalancer.balanced_workers=ajp12, ajp13

 worker.inprocess.type=jni

 worker.inprocess.class_path=$(workers.tomcat_home)$(ps)classes

 worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)jaxp.jar
 worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)parser.jar

 worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)jasper.jar
 worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)servlet.jar

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)webserver.jar

 worker.inprocess.class_path=$(workers.java_home)$(ps)lib$(ps)tools.jar

 worker.inprocess.cmd_line=-config
 worker.inprocess.cmd_line=$(workers.tomcat_home)/conf/jni_server.xml
 worker.inprocess.cmd_line=-home
 worker.inprocess.cmd_line=$(workers.tomcat_home)


worker.inprocess.jvm_lib=$(workers.java_home)$(ps)jre$(ps)bin$(ps)classic$(p
 s)jvm.dll


 #
 # Setting the place for the stdout and stderr of tomcat
 #
 worker.inprocess.stdout=$(workers.tomcat_home)$(ps)inprocess.stdout
 worker.inprocess.stderr=$(workers.tomcat_home)$(ps)inprocess.stderr



 worker.inprocess.sysprops=tomcat.home=$(workers.tomcat_home)

 

 Thanks (I wait your help).

 - Original Message -
 From: Loïc Lefèvre [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Tuesday, August 07, 2001 3:07 PM
 Subject: RE: I don't see the output under Linux


 
  -Message d'origine-
  De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
  Envoyé : mardi 7 août 2001 14:47
  À : [EMAIL PROTECTED]
  Objet : Re: I don't see the output under Linux
 
 
  Yes, if I add this attribute the tomcat.log (when I start tomcat)
become:
 
  2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /examples )
  2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /admin )
  2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /cocoon )
  2001-08-07 01:40:57 - ContextManager: Adding context Ctx(  )
  2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /test )
  2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /Cocoon )
 
  but no message other this are printed on this file.
  (All System.out.println are not printed!!)
 
  Thanks.
 
  - Original Message -
  From: Loïc Lefèvre [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Tuesday, August 07, 2001 12:23 PM
  Subject: RE: I don't see the output under Linux
 
 
   in your server.xml file, add the attibut path to:
  
   Logger name=tc_log
   path=/tmp/tomcat.log    here
   verbosityLevel = INFORMATION
   /
  
   ;)
  
   -Message d'origine-
   De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
   Envoyé : mardi 7 août 2001 09:39
   À : [EMAIL PROTECTED]
   Objet : I don't see the output under Linux
  
  
   I am a new linux user and I have just installed Tomcat under linux.
   I have developed an application and now I am testing it.
  
   Tomcat is installed on a linux server and I try to access it (at my
   application) with a windows 98 PC.
  
   I have introduced a System.out.println lines in my application (for
the
   testing phase), but I don't see theirs output.
   I have tried to do this (every time that tomcat is started):
  
./tomcat start  tomcat.out
  
   without success

RE: I don't see the output under Linux

2001-08-08 Thread Martin van den Bemt

Just replying to the original question here :

if you want the system.out.println logging to appear in a file instead of
the console :
$TOMCAT_HOME/bin/tomcat.sh start 2logfile  1errorfile
All error and normal output to the console will be redirected this way to
files.

If you want logging to system.out, then the logging appears only when the
console in which you started tomcat, not any other console which you open.

Mvgr,
Martin

   I have introduced a System.out.println lines in my application (for
the
   testing phase), but I don't see theirs output.
   I have tried to do this (every time that tomcat is started):
  
./tomcat start  tomcat.out
  
   without success.
  




I don't see the output under Linux

2001-08-07 Thread Stefano Bonnin

I am a new linux user and I have just installed Tomcat under linux.
I have developed an application and now I am testing it.

Tomcat is installed on a linux server and I try to access it (at my
application) with a windows 98 PC.

I have introduced a System.out.println lines in my application (for the
testing phase), but I don't see theirs output.
I have tried to do this (every time that tomcat is started):

 ./tomcat start  tomcat.out

without success.

How can I do a right redirect?

Thanks in advance.

Stefano




RE: I don't see the output under Linux

2001-08-07 Thread Loïc Lefèvre

in your server.xml file, add the attibut path to:

Logger name=tc_log
path=/tmp/tomcat.log    here
verbosityLevel = INFORMATION
/

;)

-Message d'origine-
De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
Envoyé : mardi 7 août 2001 09:39
À : [EMAIL PROTECTED]
Objet : I don't see the output under Linux


I am a new linux user and I have just installed Tomcat under linux.
I have developed an application and now I am testing it.

Tomcat is installed on a linux server and I try to access it (at my
application) with a windows 98 PC.

I have introduced a System.out.println lines in my application (for the
testing phase), but I don't see theirs output.
I have tried to do this (every time that tomcat is started):

 ./tomcat start  tomcat.out

without success.

How can I do a right redirect?

Thanks in advance.

Stefano




RE: I don't see the output under Linux

2001-08-07 Thread Jacek Prucia


 in your server.xml file, add the attibut path to:
 
 Logger name=tc_log
 path=/tmp/tomcat.log    here
 verbosityLevel = INFORMATION
 /
 
 ;)

That's not going to help. Adding path attribute just makes Tomcat write
info to log file, but nothing more. Every damn System.out.println() call
writes to console from which Tomcat has been started. This problem is
probably more related to JVM rather than Tomcat.

-- 
Jacek Prucia
7bulls.com S.A.





Re: I don't see the output under Linux

2001-08-07 Thread Stefano Bonnin

 Can you send your workers.properties file?

Yes. This is my workers.properties:

**
workers.tomcat_home=c:\jakarta-tomcat

workers.java_home=c:\jdk1.2.2

ps=\

worker.list=ajp12, ajp13

worker.ajp12.port=8007
worker.ajp12.host=localhost
worker.ajp12.type=ajp12
worker.ajp12.lbfactor=1

worker.ajp13.port=8009
worker.ajp13.host=localhost
worker.ajp13.type=ajp13
worker.ajp13.lbfactor=1

worker.loadbalancer.type=lb
worker.loadbalancer.balanced_workers=ajp12, ajp13

worker.inprocess.type=jni

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)classes

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)jaxp.jar
worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)parser.jar

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)jasper.jar
worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)servlet.jar
worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)webserver.jar

worker.inprocess.class_path=$(workers.java_home)$(ps)lib$(ps)tools.jar

worker.inprocess.cmd_line=-config
worker.inprocess.cmd_line=$(workers.tomcat_home)/conf/jni_server.xml
worker.inprocess.cmd_line=-home
worker.inprocess.cmd_line=$(workers.tomcat_home)

worker.inprocess.jvm_lib=$(workers.java_home)$(ps)jre$(ps)bin$(ps)classic$(p
s)jvm.dll


#
# Setting the place for the stdout and stderr of tomcat
#
worker.inprocess.stdout=$(workers.tomcat_home)$(ps)inprocess.stdout
worker.inprocess.stderr=$(workers.tomcat_home)$(ps)inprocess.stderr



worker.inprocess.sysprops=tomcat.home=$(workers.tomcat_home)



Thanks (I wait your help).

- Original Message -
From: Loïc Lefèvre [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, August 07, 2001 3:07 PM
Subject: RE: I don't see the output under Linux



 -Message d'origine-
 De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
 Envoyé : mardi 7 août 2001 14:47
 À : [EMAIL PROTECTED]
 Objet : Re: I don't see the output under Linux


 Yes, if I add this attribute the tomcat.log (when I start tomcat) become:

 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /examples )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /admin )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /cocoon )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx(  )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /test )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /Cocoon )

 but no message other this are printed on this file.
 (All System.out.println are not printed!!)

 Thanks.

 - Original Message -
 From: Loïc Lefèvre [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Tuesday, August 07, 2001 12:23 PM
 Subject: RE: I don't see the output under Linux


  in your server.xml file, add the attibut path to:
 
  Logger name=tc_log
  path=/tmp/tomcat.log    here
  verbosityLevel = INFORMATION
  /
 
  ;)
 
  -Message d'origine-
  De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
  Envoyé : mardi 7 août 2001 09:39
  À : [EMAIL PROTECTED]
  Objet : I don't see the output under Linux
 
 
  I am a new linux user and I have just installed Tomcat under linux.
  I have developed an application and now I am testing it.
 
  Tomcat is installed on a linux server and I try to access it (at my
  application) with a windows 98 PC.
 
  I have introduced a System.out.println lines in my application (for the
  testing phase), but I don't see theirs output.
  I have tried to do this (every time that tomcat is started):
 
   ./tomcat start  tomcat.out
 
  without success.
 
  How can I do a right redirect?
 
  Thanks in advance.
 
  Stefano
 





RE: I don't see the output under Linux

2001-08-07 Thread Loïc Lefèvre

Okay, this file stands in the conf directory of Tomcat on your LINUX server?
If the answer is true, replace
workers.tomcat_home=c:\jakarta-tomcat

workers.java_home=c:\jdk1.2.2

ps=\

with the good parameters:

especially:  ps=/ (Path separator for Linux is equals to / not \)

Try and tell me...

-Message d'origine-
De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
Envoyé : mardi 7 août 2001 16:04
À : [EMAIL PROTECTED]
Objet : Re: I don't see the output under Linux


 Can you send your workers.properties file?

Yes. This is my workers.properties:

**
workers.tomcat_home=c:\jakarta-tomcat

workers.java_home=c:\jdk1.2.2

ps=\

worker.list=ajp12, ajp13

worker.ajp12.port=8007
worker.ajp12.host=localhost
worker.ajp12.type=ajp12
worker.ajp12.lbfactor=1

worker.ajp13.port=8009
worker.ajp13.host=localhost
worker.ajp13.type=ajp13
worker.ajp13.lbfactor=1

worker.loadbalancer.type=lb
worker.loadbalancer.balanced_workers=ajp12, ajp13

worker.inprocess.type=jni

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)classes

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)jaxp.jar
worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)parser.jar

worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)jasper.jar
worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)servlet.jar
worker.inprocess.class_path=$(workers.tomcat_home)$(ps)lib$(ps)webserver.jar

worker.inprocess.class_path=$(workers.java_home)$(ps)lib$(ps)tools.jar

worker.inprocess.cmd_line=-config
worker.inprocess.cmd_line=$(workers.tomcat_home)/conf/jni_server.xml
worker.inprocess.cmd_line=-home
worker.inprocess.cmd_line=$(workers.tomcat_home)

worker.inprocess.jvm_lib=$(workers.java_home)$(ps)jre$(ps)bin$(ps)classic$(p
s)jvm.dll


#
# Setting the place for the stdout and stderr of tomcat
#
worker.inprocess.stdout=$(workers.tomcat_home)$(ps)inprocess.stdout
worker.inprocess.stderr=$(workers.tomcat_home)$(ps)inprocess.stderr



worker.inprocess.sysprops=tomcat.home=$(workers.tomcat_home)



Thanks (I wait your help).

- Original Message -
From: Loïc Lefèvre [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, August 07, 2001 3:07 PM
Subject: RE: I don't see the output under Linux



 -Message d'origine-
 De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
 Envoyé : mardi 7 août 2001 14:47
 À : [EMAIL PROTECTED]
 Objet : Re: I don't see the output under Linux


 Yes, if I add this attribute the tomcat.log (when I start tomcat) become:

 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /examples )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /admin )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /cocoon )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx(  )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /test )
 2001-08-07 01:40:57 - ContextManager: Adding context Ctx( /Cocoon )

 but no message other this are printed on this file.
 (All System.out.println are not printed!!)

 Thanks.

 - Original Message -
 From: Loïc Lefèvre [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Tuesday, August 07, 2001 12:23 PM
 Subject: RE: I don't see the output under Linux


  in your server.xml file, add the attibut path to:
 
  Logger name=tc_log
  path=/tmp/tomcat.log    here
  verbosityLevel = INFORMATION
  /
 
  ;)
 
  -Message d'origine-
  De : Stefano Bonnin [mailto:[EMAIL PROTECTED]]
  Envoyé : mardi 7 août 2001 09:39
  À : [EMAIL PROTECTED]
  Objet : I don't see the output under Linux
 
 
  I am a new linux user and I have just installed Tomcat under linux.
  I have developed an application and now I am testing it.
 
  Tomcat is installed on a linux server and I try to access it (at my
  application) with a windows 98 PC.
 
  I have introduced a System.out.println lines in my application (for the
  testing phase), but I don't see theirs output.
  I have tried to do this (every time that tomcat is started):
 
   ./tomcat start  tomcat.out
 
  without success.
 
  How can I do a right redirect?
 
  Thanks in advance.
 
  Stefano