Re: [Tutor] syntax error help

[Alan Gauld via Tutor]

On 30/03/16 19:05, Awais Mamoon wrote:
> Hi my code should be working however keeps coming up with invalid syntax but
> I know there isn’t one. 

You are wrong. There is.
I suspect the error message tells you where it is.
In future please include the full error message with your code.

Look closely at this function:

> def EncryptionOrDecryption(plaintext_message, Keyword):
> 
>  NewLetter = ("")
>  Ciphertext = ("")
>  PositionKeyword = 0
>  print('Do you wish to encrypt or decrypt')
>  option = input()
> 
>  if option == "e" or "encrypt":
>   for i in plaintext_message:
>if i == "":
> Ciphertext = Ciphertext + ""
>else:
> NewLetter = (alphabet.index(i)+1) +
> alphabet.index(Keyword[PositionKeyword]
> PositionKeyword = PositionKeyword + 1
> if PositionKeyword == len(Keyword):
>  PositionKeyword = 0
> if NewLetter > 25:
> NewLetter = NewLetter - 26
>Ciphertext = Ciphertext + alphabet[NewLetter]
>  return Ciphertext
> 
>  elif option == "d" or "decrypt":
>for i in plaintext_message:
>if i == "":
> Ciphertext = Ciphertext + ""
>else:
> NewLetter = (alphabet.index(i)-1) +
> alphabet.index(Keyword[PositionKeyword])
> PositionKeyword = Keyword + 1
> if PositionKeyword == len(Keyword):
>  PositionKeyword = 0
> if NewLetter > 25:
>  NewLetter = NewLetter - 26
>Ciphertext = Ciphertext + alphabet[NewLetter]
>  return Ciphertext


-- 
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
http://www.flickr.com/photos/alangauldphotos


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Re: [Tutor] syntax error help

[David Rock]

> On Mar 30, 2016, at 13:05, Awais Mamoon  wrote:
> 
> Hi my code should be working however keeps coming up with invalid syntax but
> I know there isn’t one. Please help me its been 2 hours
> 

When you run your code, what is the actual error you get (copy and paste the 
entire thing, please)?  Where does it say the syntax error is?

— 
David Rock
da...@graniteweb.com




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[Tutor] syntax error help

[Awais Mamoon]

Hi my code should be working however keeps coming up with invalid syntax but
I know there isn’t one. Please help me its been 2 hours

Here is my code:

alphabet = 'abcdefghijklmnaopqrstuvwxyz'

 

#gets the message from the user so it can Encrypt or Decrypt

def getMessage():

 print('Enter your message:')

 return input()



#gets the key from the use so it can Encrypt or Decrypt the chosen message

def getKey():

while True:

print("please enter your keyword")

Keyword = input()

valid_Keyword = True

for letter in Keyword:

if (letter not in alphabet) and (letter != " "):

valid_Keyword = False

if valid_Keyword == False:

print("you need to enter a valid keyword")

if valid_Keyword == True:

return Keyword

 

def EncryptionOrDecryption(plaintext_message, Keyword):

 NewLetter = ("")

 Ciphertext = ("")

 PositionKeyword = 0

 print('Do you wish to encrypt or decrypt')

 option = input()

 if option == "e" or "encrypt":

  for i in plaintext_message:

   if i == "":

Ciphertext = Ciphertext + ""

   else:

NewLetter = (alphabet.index(i)+1) +
alphabet.index(Keyword[PositionKeyword]

PositionKeyword = PositionKeyword + 1

if PositionKeyword == len(Keyword):

 PositionKeyword = 0

if NewLetter > 25:

NewLetter = NewLetter - 26

   Ciphertext = Ciphertext + alphabet[NewLetter]

 return Ciphertext

 elif option == "d" or "decrypt":

   for i in plaintext_message:

   if i == "":

Ciphertext = Ciphertext + ""

   else:

NewLetter = (alphabet.index(i)-1) +
alphabet.index(Keyword[PositionKeyword])

PositionKeyword = Keyword + 1

if PositionKeyword == len(Keyword):

 PositionKeyword = 0

if NewLetter > 25:

 NewLetter = NewLetter - 26

   Ciphertext = Ciphertext + alphabet[NewLetter]

 return Ciphertext

 

 

#this makes the code abit more efficient

plaintext_message = getMessage()

Keyword = getKey()

Ciphertext = EncryptionOrDecryption(plaintext_message, Keyword)

 

#displays the Encyrpted/Decrypted message to the user 

print('Your translated text is:')

print(Ciphertext)

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Re: [Tutor] Syntax error help

[S.Irfan Rizvi]

Its failing i can't able to unsubcribe
please remove me from its not going to Span either









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On Mar 31, 2012 6:51 PM, "Alan Gauld"  wrote:

> On 31/03/12 03:33, S.Irfan Rizvi wrote:
>
>> Please remove me from listi can't do itthey are doing it Attention
>> __**_
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>
> Only you could have joined the list and only you can unsubscribe.
> Go to the web page and follow the instructions.
>
> If it doesn't work email me and I'll try to figure out what's
> going wrong.
>
> --
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> Tutor list moderator
> (and just home from vacation...)
>
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Re: [Tutor] Syntax error help

[Alan Gauld]

On 31/03/12 03:33, S.Irfan Rizvi wrote:

Please remove me from listi can't do itthey are doing it Attention
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Go to the web page and follow the instructions.

If it doesn't work email me and I'll try to figure out what's
going wrong.

--
Alan G
Tutor list moderator
(and just home from vacation...)

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Re: [Tutor] Syntax error help

[bob gailer]

Thank you for posting your code.

Did you forget to reply-all? I am copying this to the list this time.

You apparantly misunderstood my question about what you do to run the 
program. You said " I import then call the first function  (the 
displaymenu) or I have it called in the code it does it automatically".


I am running out of patience trying to get from you what we as a Tutor 
List need in order to help you.


Please answer the following:
What operating system are you using (Windows, Linux, Mac, ...)
WHAT DO YOU DO RUN THE PROGRAM. I gave detailed examples of potential 
answers (see below). Do you not understand what I'm looking for?


On 3/30/2012 11:22 PM, chris knarvik wrote:
Also here is my revised code with what i call a 'programmers error' 
let me know  if you  see it because i dont


Why all the imports - you are not using any math, os or sys code. Also 
You should not do 2 different imports from math. It is better to drop 
the from ...

import math
import os, sys
from math import *

def displaymenu():
print 'please make a selection';
print 'Area (1)';
choice = raw_input('enter selection number')

OK time to learn how to debug.
Since the code goes from if to print, the if condition (choice == 1) 
must be False.

What datatype does raw_input give you?
Why would that cause the condition to be False?
One way to answer that is to read the manual regarding raw_input.
Another is to use print statements with type() to tell you the types.
Therefore just before the if put
print type(choice), type(1)


if choice == 1:
   selctiona()
else:
print'choice',choice,'is wrong'
print"why god wont this thing work"


def areamenu():
print 'Square (1)'
print 'triangle (2)'
print 'rectangle (3)'
print 'trapazoid (4)'
print 'circle (5)'

def selctiona():
areamenu();
choicea = raw_input('enter selection');
if choicea == 1:
   squareacalc()

else:
print 'why god why'

def squareacalc():
sidelength = input('enter side length: ')
print "The Area Is", sidelength **2


You don't seem to call reloadarea!

def reloadarea():
   print 'would you like to calculate again'
   choicer = raw_input('yes(1) or no(2)')
   if choicer == 1:
This is called recursion. It is better in this kind of program to put 
the entire thing in a while loop(see below)*  rather than to use a 
recursive call.

   displaymenu()
   elif choicer == 2:
   print 'goodbye'

displaymenu()

i cant get past the display menu i get this result
please make a selection
Area (1)
enter selection number1
choice 1 is wrong
why god wont this thing work

>>>
let me know if you can see where i went wrong


I hope the guidance I gave above helps.

* Using a while loop instead of recursion:
while True:
  displaymenu()
  print 'would you like to calculate again'
  choicer = raw_input('yes(1) or no(2)')
  if choicer == 2: # this also will not work, for the same reason that 
choice == 1 does not work. Once you fix choice == 1 then you can also 
fix this.

break






what do you mean what do i do to run it

There are several ways to execute (run) a Python program.
You can double-click the file in an explorer.
You can at a command prompt type (e.g.) >python Area.py
or you can start an interactive session then type >>>import Area
or you can use an IDE such as IDLE.
 within IDLE you can write the program in an edit window then RUN
 or you can use the interactive window and type >>>import Area
Which of these (or what else) do you do 





--
Bob Gailer
919-636-4239
Chapel Hill NC

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Re: [Tutor] Syntax error help

[S.Irfan Rizvi]

Please remove me from listi can't do itthey are doing it Attention
On Mar 30, 2012 9:21 PM, "bob gailer"  wrote:

> Please always reply-all so a copy goes to the list.
>
> On 3/30/2012 8:01 PM, chris knarvik wrote:
>
>> that was incomplete it was supposed to be ive fixed most of my problems
>> with your help
>>
>
> That's great. Would you post the correct program so we can all learn? And
> possibly make other helpful suggestions.
>
>  what do you mean what do i do to run it
>>
> There are several ways to execute (run) a Python program.
> You can double-click the file in an explorer.
> You can at a command prompt type (e.g.) >python Area.py
> or you can start an interactive session then type >>>import Area
> or you can use an IDE such as IDLE.
>  within IDLE you can write the program in an edit window then RUN
>  or you can use the interactive window and type >>>import Area
> Which of these (or what else) do you do
>
> --
> Bob Gailer
> 919-636-4239
> Chapel Hill NC
>
> __**_
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Re: [Tutor] Syntax error help

[bob gailer]

Please always reply-all so a copy goes to the list.

On 3/30/2012 8:01 PM, chris knarvik wrote:
that was incomplete it was supposed to be ive fixed most of my 
problems with your help


That's great. Would you post the correct program so we can all learn? 
And possibly make other helpful suggestions.



what do you mean what do i do to run it

There are several ways to execute (run) a Python program.
You can double-click the file in an explorer.
You can at a command prompt type (e.g.) >python Area.py
or you can start an interactive session then type >>>import Area
or you can use an IDE such as IDLE.
  within IDLE you can write the program in an edit window then RUN
  or you can use the interactive window and type >>>import Area
Which of these (or what else) do you do

--
Bob Gailer
919-636-4239
Chapel Hill NC

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Re: [Tutor] Syntax error help

[bob gailer]

On 3/30/2012 6:20 PM, x23ch...@gmail.com wrote:

Thanks I've fixed
Great. Please share with us your new program and tell us what you do to 
run it.


--
Bob Gailer
919-636-4239
Chapel Hill NC

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Re: [Tutor] Syntax error help

[x23ch...@gmail.com]

Thanks I've fixed

Sent from my iPod

On Mar 30, 2012, at 5:30 PM, bob gailer  wrote:

> On 3/30/2012 4:26 PM, chris knarvik wrote:
>> Alright i have been trying to right a (relatively) simple to calculate area 
>> and volume below is my current working code
> 
> Suggestion: start with a VERY SIMPLE program and get that working. Then add 
> one new feature at a time.
> 
> Is the following in Area.py? If it is then the traceback could not have come 
> from importing this code, because line 10 does not mention areamenu().
> In fact areamenu() appears ONLY in line 1, but not by itself!
> 
>> def areamenu():
>>print 'Square (1)'
>>print 'triangle (2)'
>>print 'rectangle (3)'
>>print 'trapazoid (4)'
>>print 'circle (5)'
>> 
>> def squareacalc():
>>sidelength = input('enter side length: ')
>>print ' the side length is' sidelength ** 2
>> 
>> def displaymenu():
>>print 'please make a selection';
>>print 'Area (1)';
>>choice = input(raw_input('enter selection number'):
>>if (choice == 1):
>>Areamenu():
>> 
>>else:
>>print 'choice' , choice, ' is wrong try again'
>> 
>> def selctiona():
>>Areamenu();
>>choicea = input(raw_input'enter selection');
>>if (choicea == 1):
>>squareacalc()
>> 
>> 
>> 
>> print 'good bye'
>> 
>> I keep getting this error
>> Traceback (most recent call last):
>>  File "", line 1, in 
>>import Area
>>  File "C:\Python27\Area.py", line 10
>>areamenu()
>>   ^
>> SyntaxError: invalid syntax
>> 
>> can anyone tell me what im doing wrong i cant see the problem
>> help would be appreciated
>> 
> What are you using to run the above? I'll guess the interactive window of 
> IDLE. Try reload(Area). Once a module is imported you must reload to import 
> it again. (I am assuming you made changes after the initial error.)
> 
> The above code should give you something like:
> Traceback (most recent call last):
>  File "", line 1, in 
>  File "Script3.py", line 10
>print ' the side length is' sidelength ** 2
> ^
> SyntaxError: invalid syntax
> 
> fix that (do you know what to do?) then you should get a syntax error for 
> line15. Why is there a : at the end of that line?
> then you have 1 more trailing : to deal with.
> then there is a missing )
> then there is a missing (
> 
> Once you fix all the problems then you should see
> good bye
> since that is the only executable code in Area.py other than def statements.
> 
> Suggestion: start with a VERY SIMPLE program and get that working. Then add 
> one new feature at a time.
> 
> -- 
> Bob Gailer
> 919-636-4239
> Chapel Hill NC
> 
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Re: [Tutor] Syntax error help

[Modulok]

On 3/30/12, chris knarvik  wrote:
> Alright i have been trying to right a (relatively) simple to calculate area
> and volume below is my current working code
> def areamenu():
> print 'Square (1)'
> print 'triangle (2)'
> print 'rectangle (3)'
> print 'trapazoid (4)'
> print 'circle (5)'
>
> def squareacalc():
> sidelength = input('enter side length: ')
> print ' the side length is' sidelength ** 2
>
> def displaymenu():
> print 'please make a selection';
> print 'Area (1)';
> choice = input(raw_input('enter selection number'):
> if (choice == 1):
> Areamenu():
>
> else:
> print 'choice' , choice, ' is wrong try again'
>
> def selctiona():
> Areamenu();
> choicea = input(raw_input'enter selection');
> if (choicea == 1):
> squareacalc()
>
>
>
>  print 'good bye'
>
> I keep getting this error
> Traceback (most recent call last):
>   File "", line 1, in 
> import Area
>   File "C:\Python27\Area.py", line 10
> areamenu()
>^
> SyntaxError: invalid syntax
>
> can anyone tell me what im doing wrong i cant see the problem
> help would be appreciated

Chris,

Your code has numerous problems. First, the only lines that should end in a
colon ':' are lines that define something, i.e. class and function signatures,
etc. Your code has them sprinkled in places where they really don't belong. For
instance:

choice = input(raw_input('enter selection number'):  #<-- No.

Additionally, python statements are almost never terminated with a semicolon
';'. Your code has those in random places as well. Python statements *can* be
semicolon terminated, but this should *only* be used if there is more than one
statement per line. (Generally a discouraged practice, unless in the case of a
list comprehensions):

choicea = input(raw_input'enter selection'); #<-- Not needed.

The other problem I see is a lot of mis-matched parentheses. For instance your
code has places where there are two opening parentheses, but only one closing
parenthesis:

choice = input(raw_input('enter selection number'):

Should be:

choice = input(raw_input('enter selection number'))

However, the above line is pretty nasty. It's making an unnecessary function
call. Above, its waiting for user input to the 'input' function, and using the
return value of the 'raw_input' function for that input, which itself is
waiting for user input. i.e. an input waiting for an input. It should instead
be something like this:

choicea = input('enter selection: ')

*If* you decide to use the 'raw_input()' function instead, remember to
type-cast the value that gets entered. By default with 'raw_input()' it is
interpreted as a string and not an integer. Thus, the comparison 'if (choicea
== 1)' wouldn't work with 'raw_input()' expected.

This is a problem as well:

print ' the side length is' sidelength ** 2

The print statement only takes a single argument, or multiple arguments *if*
they are comma separated, e.g:

print ' the side length is', sidelength ** 2

However, this whole thing would be better written using string substitution::

print ' the side length is %s' % (sidelength ** 2)

This is also incorrect:

Areamenu()

Your code defines a function named 'areamenu', not one named 'Areamenu'.
Remember, python is case sEnsItiVe. e.g: Foo() and foo() are different.

Good luck!
-Modulok-
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Re: [Tutor] Syntax error help

[bob gailer]

On 3/30/2012 4:26 PM, chris knarvik wrote:
Alright i have been trying to right a (relatively) simple to calculate 
area and volume below is my current working code


Suggestion: start with a VERY SIMPLE program and get that working. Then 
add one new feature at a time.


Is the following in Area.py? If it is then the traceback could not have 
come from importing this code, because line 10 does not mention areamenu().

In fact areamenu() appears ONLY in line 1, but not by itself!


def areamenu():
print 'Square (1)'
print 'triangle (2)'
print 'rectangle (3)'
print 'trapazoid (4)'
print 'circle (5)'

def squareacalc():
sidelength = input('enter side length: ')
print ' the side length is' sidelength ** 2

def displaymenu():
print 'please make a selection';
print 'Area (1)';
choice = input(raw_input('enter selection number'):
if (choice == 1):
Areamenu():

else:
print 'choice' , choice, ' is wrong try again'

def selctiona():
Areamenu();
choicea = input(raw_input'enter selection');
if (choicea == 1):
squareacalc()



 print 'good bye'

I keep getting this error
Traceback (most recent call last):
  File "", line 1, in 
import Area
  File "C:\Python27\Area.py", line 10
areamenu()
   ^
SyntaxError: invalid syntax

can anyone tell me what im doing wrong i cant see the problem
help would be appreciated

What are you using to run the above? I'll guess the interactive window 
of IDLE. Try reload(Area). Once a module is imported you must reload to 
import it again. (I am assuming you made changes after the initial error.)


The above code should give you something like:
Traceback (most recent call last):
  File "", line 1, in 
  File "Script3.py", line 10
print ' the side length is' sidelength ** 2
 ^
SyntaxError: invalid syntax

fix that (do you know what to do?) then you should get a syntax error 
for line15. Why is there a : at the end of that line?

then you have 1 more trailing : to deal with.
then there is a missing )
then there is a missing (

Once you fix all the problems then you should see
good bye
since that is the only executable code in Area.py other than def statements.

Suggestion: start with a VERY SIMPLE program and get that working. Then 
add one new feature at a time.


--
Bob Gailer
919-636-4239
Chapel Hill NC

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Re: [Tutor] Syntax error help

[Evert Rol]

> Alright i have been trying to right a (relatively) simple to calculate area 
> and volume below is my current working code
> def areamenu():
> print 'Square (1)'
> print 'triangle (2)'
> print 'rectangle (3)'
> print 'trapazoid (4)'
> print 'circle (5)'
> 
> def squareacalc():
> sidelength = input('enter side length: ')
> print ' the side length is' sidelength ** 2
> 
> def displaymenu():
> print 'please make a selection';
> print 'Area (1)';
> choice = input(raw_input('enter selection number'):

You're missing a closing parenthesis here.

But see comments below.


> if (choice == 1):
> Areamenu():
> 
> else:
> print 'choice' , choice, ' is wrong try again'
> 
> def selctiona():
> Areamenu();
> choicea = input(raw_input'enter selection');

And here you're missing an openening parenthesis.


> if (choicea == 1):
> squareacalc()
> 
> 
> 
>  print 'good bye'
> 
> I keep getting this error
> Traceback (most recent call last):
>   File "", line 1, in 
> import Area
>   File "C:\Python27\Area.py", line 10
> areamenu()
>^
> SyntaxError: invalid syntax
> 
> can anyone tell me what im doing wrong i cant see the problem
> help would be appreciated

A syntax error is often a typing error in the code. In this case, forgotten 
parentheses, but could be forgotten colons or an unclosed string.
The parentheses problem can often be caught by using a good editor: these often 
lightlight when you close a set of parentheses, so you can spot syntax errors 
while you are typing.


There are a number of other things wrong here, though.
Style-wise: Python does not need (and prefers not to have) closing semicolons. 
In addition, there is no need to surround if statements with parentheses: "if 
choice == 1:" is perfectly fine and much more legible.
Perhaps you think (coming from another language): "but it doesn't hurt, and I 
like it this way". But then you're still programming in that other language, 
and just translating to Python; not actually coding in Python.

Also, this is odd, wrong and pretty bad:

   choice = input(raw_input('enter selection number')):

Use either raw_input() (for Python 2.x) or input() (Python 3.x).
It's wrong because you are waiting for input, then use that input as the next 
prompting string for further input. Like this
>>> choice = input(raw_input('enter selection number'))
enter selection number1
12
>>> print choice
2

(the 12 is the 1 I entered before, plus a 2 I just entered as a second entry.)
So just use one function, and the appropriate one for the Python version.
Lastly, choice will be a string, since input() and raw_input() return a string.
In the if-statement, however, you are comparing that string to an integer. 
Python does not do implicit conversion, so you'll have to convert the string to 
an integer first, or compare to a string instead.
(Something similar happens for the sidelength, btw.)
Last thing I see glancing over the code: you define areamenu(), but call 
Areamenu(). Python is case sensitive, so you'd have to call areamenu() instead.


This may be a bit more information than you asked for, but hopefully you don't 
mind.

Good luck,

  Evert




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[Tutor] Syntax error help

[chris knarvik]

Alright i have been trying to right a (relatively) simple to calculate area
and volume below is my current working code
def areamenu():
print 'Square (1)'
print 'triangle (2)'
print 'rectangle (3)'
print 'trapazoid (4)'
print 'circle (5)'

def squareacalc():
sidelength = input('enter side length: ')
print ' the side length is' sidelength ** 2

def displaymenu():
print 'please make a selection';
print 'Area (1)';
choice = input(raw_input('enter selection number'):
if (choice == 1):
Areamenu():

else:
print 'choice' , choice, ' is wrong try again'

def selctiona():
Areamenu();
choicea = input(raw_input'enter selection');
if (choicea == 1):
squareacalc()



 print 'good bye'

I keep getting this error
Traceback (most recent call last):
  File "", line 1, in 
import Area
  File "C:\Python27\Area.py", line 10
areamenu()
   ^
SyntaxError: invalid syntax

can anyone tell me what im doing wrong i cant see the problem
help would be appreciated
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