Re: [ubuntu-uk] Converting many .jpgs to mpeg4 without using wildcards
OK - apologies if I was somewhat vague in my requirements! 1) There is a directory structure with very many (several thousand) directories containing a large amount of .jpg files. 2) I have a perl script that runs periodically and using criteria stored in a mysql database identifies a subset of these files (based on a number of criteria stored within the db). 3) The files identified in 2) will be spread across a number of directories with not all files in any single directory necessarily included. 4) I wish to convert these images into a video running at (say) 10 fps using reasonably high compression which can later be viewed from Linux & Windows clients. 5) The number of images identified in each run (probably daily) will range from a few dozen to a few thousand with each image in the range 20-80k. Hope thats clearer! Dom Sean Miller wrote: > Kris Marsh wrote: > >> Dump your mysql output to a file, and then use $(cat file) in place of >> where your wildcard/files would be. >> >> > This all sounds very over the top to me... I would appreciate it if the > requirement was outlined somewhat more clearly... from what I've read, > it seems that "find" would adequately work as a command to pipe into > whatever script it is that requires the files... > > ie. > > whatever.shl < `find . -name '*wildcard*' -print` > > or... > > find . -name '*wildcard*' -print | process_archive.shl > > ...or similar... > > Sean > > -- ubuntu-uk@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk https://wiki.kubuntu.org/UKTeam/
Re: [ubuntu-uk] Converting many .jpgs to mpeg4 without using wildcards
Kris Marsh wrote: > Dump your mysql output to a file, and then use $(cat file) in place of > where your wildcard/files would be. > This all sounds very over the top to me... I would appreciate it if the requirement was outlined somewhat more clearly... from what I've read, it seems that "find" would adequately work as a command to pipe into whatever script it is that requires the files... ie. whatever.shl < `find . -name '*wildcard*' -print` or... find . -name '*wildcard*' -print | process_archive.shl ...or similar... Sean -- ubuntu-uk@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk https://wiki.kubuntu.org/UKTeam/
Re: [ubuntu-uk] Converting many .jpgs to mpeg4 without using wildcards
Dominic Forrest wrote: > > Hi, >I need to regularly convert a few hundred/thousand .jpgs to a mpeg4 > (or other) video. These files are selected as the result of a mysql > query from perl and sit within a number of directories along with many > more images which will not form part of the video - hence I cannot use > wildcards with ffmpeg (or any other tool). I can easily list all the > filenames in order to a file but am unable to find a way to use this > file (which currently has the full path to one jpg on each line) as > input to ffmpeg. > > Currently the only way I have found to do this is to copy all the > files (or create links) to a new directory which then allows me to use > wildcards - however this seems horribly inefficient! > > Any thoughts or solutions welcomed! > > > Dom > That certainly passes the list to ffmpeg as I wanted - I'm just struggling a but with ffmpeg at the moment! Thanks for the quick & helpful reply. Dom -- ubuntu-uk@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk https://wiki.kubuntu.org/UKTeam/
Re: [ubuntu-uk] Converting many .jpgs to mpeg4 without using wildcards
On 6/4/07, Dominic Forrest <[EMAIL PROTECTED]> wrote: > > Hi, > I need to regularly convert a few hundred/thousand .jpgs to a mpeg4 > (or other) video. These files are selected as the result of a mysql > query from perl and sit within a number of directories along with many > more images which will not form part of the video - hence I cannot use > wildcards with ffmpeg (or any other tool). I can easily list all the > filenames in order to a file but am unable to find a way to use this > file (which currently has the full path to one jpg on each line) as > input to ffmpeg. > > Currently the only way I have found to do this is to copy all the files > (or create links) to a new directory which then allows me to use > wildcards - however this seems horribly inefficient! > > Any thoughts or solutions welcomed! > > > Dom > > -- > ubuntu-uk@lists.ubuntu.com > https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk > https://wiki.kubuntu.org/UKTeam/ > Hi Dom. You could use $(cat file). A quick example should illustrate this for you: [EMAIL PROTECTED]:~$ echo "one" > file1 [EMAIL PROTECTED]:~$ echo "two" > file2 [EMAIL PROTECTED]:~$ echo -e "file1\nfile2" > files [EMAIL PROTECTED]:~$ cat $(cat files) one two [EMAIL PROTECTED]:~$ Dump your mysql output to a file, and then use $(cat file) in place of where your wildcard/files would be. Any good? :-) Kris -- ubuntu-uk@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk https://wiki.kubuntu.org/UKTeam/
[ubuntu-uk] Converting many .jpgs to mpeg4 without using wildcards
Hi, I need to regularly convert a few hundred/thousand .jpgs to a mpeg4 (or other) video. These files are selected as the result of a mysql query from perl and sit within a number of directories along with many more images which will not form part of the video - hence I cannot use wildcards with ffmpeg (or any other tool). I can easily list all the filenames in order to a file but am unable to find a way to use this file (which currently has the full path to one jpg on each line) as input to ffmpeg. Currently the only way I have found to do this is to copy all the files (or create links) to a new directory which then allows me to use wildcards - however this seems horribly inefficient! Any thoughts or solutions welcomed! Dom -- ubuntu-uk@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk https://wiki.kubuntu.org/UKTeam/
