The date formats only works over a short period of time, about 2^32
seconds (4 byte word). That is about 1934 to 2035. If you are using
dates outside of that region then you need to work with dateItems and
seconds. I think dateItems gives you the largest time span. To do this
you have to convert your date to a dateItem with your own handler, not
the convert function:
put 7/18/1868 into theDate
put myDateItemHandler(theDate) into theDate
function myDateItemHandler theDate
get the itemDelimiter -- this get/set may not be needed
set the itemDelimiter to /
put item 1 of theDate into theMonth
put item 2 of theDate into theDay
put item 3 of theDate into theYear
set the itemDelimiter to it-- this get/set may not be needed
return theYearcommatheMonthcommatheDaycommacommacommacomma
end myDateItemHandler
You can convert this dateItem to seconds and do your calculations. If
you want to return a date convert your seconds to dateItems and write a
handler which creates your desired date format.
Michael
On Jan 17, 2005, at 6:58 PM, Sarah Reichelt wrote:
What do I need to do to make the following work right? To get the
centuries
right?
put 7/18/1868 into temp
put temp into fld 1
convert temp to seconds
put -- temp after fld 1
convert temp to long date
put -- temp after fld 1
Hi Nelson,
The only way I could get it to work was to use Julian dates. if you go
to my web page, you will see a DateTime library: DateTime.rev.gz,
which includes functions for translating dates to from Julian
format, originally written by Mark Weider.
Cheers,
Sarah
[EMAIL PROTECTED]
http://www.troz.net/Rev/
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