onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Puneet Kinra 
Hi All

Facing some issue with context to onTimer method in processfunction

class TimerTest extends ProcessFunction,String>{

/**
*
*/
private static final long serialVersionUID = 1L;

@Override
public void processElement(Tuple2 arg0,
ProcessFunction, String>.Context ctx,
Collector arg2) throws Exception {
// TODO Auto-generated method stub
long parseLong = Long.parseLong(arg0.f1);
TimerService timerService = ctx.timerService();
ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
}

@Override
public void onTimer(long timestamp, ProcessFunction,
String>.OnTimerContext ctx,
Collector out) throws Exception {
// TODO Auto-generated method stub
super.onTimer(timestamp, ctx, out);
System.out.println("Executing timmer"+timestamp);
out.collect("Timer Testing..");
}
}

-- 
*Cheers *

*Puneet Kinra*

*Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
*

*e-mail :puneet.ki...@customercentria.com
*

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Hequn Cheng 
Hi Puneet,

The value of the registered timer should within startTime and endTime of
your job. For example, job starts at processing time t1 and stops at
processing time t2. You have to make sure t1< `parseLong + 5000` < t2.

Best, Hequn

On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
puneet.ki...@customercentria.com> wrote:

> Hi All
>
> Facing some issue with context to onTimer method in processfunction
>
> class TimerTest extends ProcessFunction,String>{
>
> /**
> *
> */
> private static final long serialVersionUID = 1L;
>
> @Override
> public void processElement(Tuple2 arg0,
> ProcessFunction, String>.Context ctx,
> Collector arg2) throws Exception {
> // TODO Auto-generated method stub
> long parseLong = Long.parseLong(arg0.f1);
> TimerService timerService = ctx.timerService();
> ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
> }
>
> @Override
> public void onTimer(long timestamp, ProcessFunction String>, String>.OnTimerContext ctx,
> Collector out) throws Exception {
> // TODO Auto-generated method stub
> super.onTimer(timestamp, ctx, out);
> System.out.println("Executing timmer"+timestamp);
> out.collect("Timer Testing..");
> }
> }
>
> --
> *Cheers *
>
> *Puneet Kinra*
>
> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
> *
>
> *e-mail :puneet.ki...@customercentria.com
> *
>
>
>

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Puneet Kinra 
Hi Hequn

Its a streaming job .

On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng  wrote:

> Hi Puneet,
>
> The value of the registered timer should within startTime and endTime of
> your job. For example, job starts at processing time t1 and stops at
> processing time t2. You have to make sure t1< `parseLong + 5000` < t2.
>
> Best, Hequn
>
> On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
> puneet.ki...@customercentria.com> wrote:
>
>> Hi All
>>
>> Facing some issue with context to onTimer method in processfunction
>>
>> class TimerTest extends ProcessFunction,String>{
>>
>> /**
>> *
>> */
>> private static final long serialVersionUID = 1L;
>>
>> @Override
>> public void processElement(Tuple2 arg0,
>> ProcessFunction, String>.Context ctx,
>> Collector arg2) throws Exception {
>> // TODO Auto-generated method stub
>> long parseLong = Long.parseLong(arg0.f1);
>> TimerService timerService = ctx.timerService();
>> ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
>> }
>>
>> @Override
>> public void onTimer(long timestamp, ProcessFunction> String>, String>.OnTimerContext ctx,
>> Collector out) throws Exception {
>> // TODO Auto-generated method stub
>> super.onTimer(timestamp, ctx, out);
>> System.out.println("Executing timmer"+timestamp);
>> out.collect("Timer Testing..");
>> }
>> }
>>
>> --
>> *Cheers *
>>
>> *Puneet Kinra*
>>
>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>> *
>>
>> *e-mail :puneet.ki...@customercentria.com
>> *
>>
>>
>>

-- 
*Cheers *

*Puneet Kinra*

*Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
*

*e-mail :puneet.ki...@customercentria.com
*

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Timo Walther 

Hi Puneet,

maybe you can show or explain us a bit more about your pipeline. From 
what I see your ProcessFunction looks correct. Are you sure the 
registering takes place?


Regards,
Timo

Am 07.01.19 um 14:15 schrieb Puneet Kinra:

Hi Hequn

Its a streaming job .

On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng > wrote:


Hi Puneet,

The value of the registered timer should within startTime and
endTime of your job. For example, job starts at processing time t1
and stops at processing time t2. You have to make sure t1<
`parseLong + 5000` < t2.

Best, Hequn

On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra
mailto:puneet.ki...@customercentria.com>> wrote:

Hi All

Facing some issue with context to onTimer method in
processfunction

class TimerTest extends
ProcessFunction,String>{

/**
*
*/
private static final long serialVersionUID = 1L;

@Override
public void processElement(Tuple2 arg0,
ProcessFunction, String>.Context ctx,
Collector arg2) throws Exception {
// TODO Auto-generated method stub
long parseLong = Long.parseLong(arg0.f1);
TimerService timerService = ctx.timerService();
ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
}

@Override
public void onTimer(long timestamp,
ProcessFunction, String>.OnTimerContext
ctx,
Collector out) throws Exception {
// TODO Auto-generated method stub
super.onTimer(timestamp, ctx, out);
System.out.println("Executing timmer"+timestamp);
out.collect("Timer Testing..");
}
}

-- 
*Cheers *

*
*
*Puneet Kinra*
*
*

*Mobile:+918800167808 | Skype :
puneet.ki...@customercentria.com
*

*e-mail :puneet.ki...@customercentria.com
*




--
*Cheers *
*
*
*Puneet Kinra*
*
*

*Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com 
*


*e-mail :puneet.ki...@customercentria.com 
*

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Puneet Kinra 
I checked the same the function is getting exited when i am calling
ctx.getTimeservice () function.

On Mon, Jan 7, 2019 at 10:27 PM Timo Walther  wrote:

> Hi Puneet,
>
> maybe you can show or explain us a bit more about your pipeline. From what
> I see your ProcessFunction looks correct. Are you sure the registering
> takes place?
>
> Regards,
> Timo
>
> Am 07.01.19 um 14:15 schrieb Puneet Kinra:
>
> Hi Hequn
>
> Its a streaming job .
>
> On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng  wrote:
>
>> Hi Puneet,
>>
>> The value of the registered timer should within startTime and endTime of
>> your job. For example, job starts at processing time t1 and stops at
>> processing time t2. You have to make sure t1< `parseLong + 5000` < t2.
>>
>> Best, Hequn
>>
>> On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
>> puneet.ki...@customercentria.com> wrote:
>>
>>> Hi All
>>>
>>> Facing some issue with context to onTimer method in processfunction
>>>
>>> class TimerTest extends ProcessFunction,String>{
>>>
>>> /**
>>> *
>>> */
>>> private static final long serialVersionUID = 1L;
>>>
>>> @Override
>>> public void processElement(Tuple2 arg0,
>>> ProcessFunction, String>.Context ctx,
>>> Collector arg2) throws Exception {
>>> // TODO Auto-generated method stub
>>> long parseLong = Long.parseLong(arg0.f1);
>>> TimerService timerService = ctx.timerService();
>>> ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
>>> }
>>>
>>> @Override
>>> public void onTimer(long timestamp, ProcessFunction>> String>, String>.OnTimerContext ctx,
>>> Collector out) throws Exception {
>>> // TODO Auto-generated method stub
>>> super.onTimer(timestamp, ctx, out);
>>> System.out.println("Executing timmer"+timestamp);
>>> out.collect("Timer Testing..");
>>> }
>>> }
>>>
>>> --
>>> *Cheers *
>>>
>>> *Puneet Kinra*
>>>
>>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>>> *
>>>
>>> *e-mail :puneet.ki...@customercentria.com
>>> *
>>>
>>>
>>>
>
> --
> *Cheers *
>
> *Puneet Kinra*
>
> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
> *
>
> *e-mail :puneet.ki...@customercentria.com
> *
>
>
>
>

-- 
*Cheers *

*Puneet Kinra*

*Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
*

*e-mail :puneet.ki...@customercentria.com
*

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Hequn Cheng 
Hi puneet,

Could you print `parseLong + 5000` and
`ctx.timerService().currentProcessingTime()` out and check the value?
I know it is a streaming program. What I mean is the timer you have
registered is not within the interval of your job, so the timer has not
been triggered. For example, parseLong + 5000 = 5000 or parseLong + 5000 =
1000(very big).

Best, Hequn


On Tue, Jan 8, 2019 at 1:38 AM Puneet Kinra <
puneet.ki...@customercentria.com> wrote:

> I checked the same the function is getting exited when i am calling
> ctx.getTimeservice () function.
>
> On Mon, Jan 7, 2019 at 10:27 PM Timo Walther  wrote:
>
>> Hi Puneet,
>>
>> maybe you can show or explain us a bit more about your pipeline. From
>> what I see your ProcessFunction looks correct. Are you sure the registering
>> takes place?
>>
>> Regards,
>> Timo
>>
>> Am 07.01.19 um 14:15 schrieb Puneet Kinra:
>>
>> Hi Hequn
>>
>> Its a streaming job .
>>
>> On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng  wrote:
>>
>>> Hi Puneet,
>>>
>>> The value of the registered timer should within startTime and endTime of
>>> your job. For example, job starts at processing time t1 and stops at
>>> processing time t2. You have to make sure t1< `parseLong + 5000` < t2.
>>>
>>> Best, Hequn
>>>
>>> On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
>>> puneet.ki...@customercentria.com> wrote:
>>>
 Hi All

 Facing some issue with context to onTimer method in processfunction

 class TimerTest extends ProcessFunction,String>{

 /**
 *
 */
 private static final long serialVersionUID = 1L;

 @Override
 public void processElement(Tuple2 arg0,
 ProcessFunction, String>.Context ctx,
 Collector arg2) throws Exception {
 // TODO Auto-generated method stub
 long parseLong = Long.parseLong(arg0.f1);
 TimerService timerService = ctx.timerService();
 ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
 }

 @Override
 public void onTimer(long timestamp, ProcessFunction>>> String>, String>.OnTimerContext ctx,
 Collector out) throws Exception {
 // TODO Auto-generated method stub
 super.onTimer(timestamp, ctx, out);
 System.out.println("Executing timmer"+timestamp);
 out.collect("Timer Testing..");
 }
 }

 --
 *Cheers *

 *Puneet Kinra*

 *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
 *

 *e-mail :puneet.ki...@customercentria.com
 *



>>
>> --
>> *Cheers *
>>
>> *Puneet Kinra*
>>
>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>> *
>>
>> *e-mail :puneet.ki...@customercentria.com
>> *
>>
>>
>>
>>
>
> --
> *Cheers *
>
> *Puneet Kinra*
>
> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
> *
>
> *e-mail :puneet.ki...@customercentria.com
> *
>
>
>

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-07 Thread Puneet Kinra 
Hi hequan

Weird behaviour when i m calling ctx.timeservice() function is getting
exited even not throwing error

On Tuesday, January 8, 2019, Hequn Cheng  wrote:

> Hi puneet,
>
> Could you print `parseLong + 5000` and 
> `ctx.timerService().currentProcessingTime()`
> out and check the value?
> I know it is a streaming program. What I mean is the timer you have
> registered is not within the interval of your job, so the timer has not
> been triggered. For example, parseLong + 5000 = 5000 or parseLong + 5000 =
> 1000(very big).
>
> Best, Hequn
>
>
> On Tue, Jan 8, 2019 at 1:38 AM Puneet Kinra  com> wrote:
>
>> I checked the same the function is getting exited when i am calling
>> ctx.getTimeservice () function.
>>
>> On Mon, Jan 7, 2019 at 10:27 PM Timo Walther  wrote:
>>
>>> Hi Puneet,
>>>
>>> maybe you can show or explain us a bit more about your pipeline. From
>>> what I see your ProcessFunction looks correct. Are you sure the registering
>>> takes place?
>>>
>>> Regards,
>>> Timo
>>>
>>> Am 07.01.19 um 14:15 schrieb Puneet Kinra:
>>>
>>> Hi Hequn
>>>
>>> Its a streaming job .
>>>
>>> On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng  wrote:
>>>
 Hi Puneet,

 The value of the registered timer should within startTime and endTime
 of your job. For example, job starts at processing time t1 and stops at
 processing time t2. You have to make sure t1< `parseLong + 5000` < t2.

 Best, Hequn

 On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
 puneet.ki...@customercentria.com> wrote:

> Hi All
>
> Facing some issue with context to onTimer method in processfunction
>
> class TimerTest extends ProcessFunction,String>{
>
> /**
> *
> */
> private static final long serialVersionUID = 1L;
>
> @Override
> public void processElement(Tuple2 arg0,
> ProcessFunction, String>.Context ctx,
> Collector arg2) throws Exception {
> // TODO Auto-generated method stub
> long parseLong = Long.parseLong(arg0.f1);
> TimerService timerService = ctx.timerService();
> ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
> }
>
> @Override
> public void onTimer(long timestamp, ProcessFunction String>, String>.OnTimerContext ctx,
> Collector out) throws Exception {
> // TODO Auto-generated method stub
> super.onTimer(timestamp, ctx, out);
> System.out.println("Executing timmer"+timestamp);
> out.collect("Timer Testing..");
> }
> }
>
> --
> *Cheers *
>
> *Puneet Kinra*
>
> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
> *
>
> *e-mail :puneet.ki...@customercentria.com
> *
>
>
>
>>>
>>> --
>>> *Cheers *
>>>
>>> *Puneet Kinra*
>>>
>>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>>> *
>>>
>>> *e-mail :puneet.ki...@customercentria.com
>>> *
>>>
>>>
>>>
>>>
>>
>> --
>> *Cheers *
>>
>> *Puneet Kinra*
>>
>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>> *
>>
>> *e-mail :puneet.ki...@customercentria.com
>> *
>>
>>
>>

-- 
*Cheers *

*Puneet Kinra*

*Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
*

*e-mail :puneet.ki...@customercentria.com
*

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-08 Thread Hequn Cheng 
Hi Puneet,

Can you explain it in more detail? Do you mean the job is finished before
you call ctx.timeservice()?
Maybe you have to let your source running for a longer time.

It's better to show us the whole pipeline of your job. For example, write
a sample code(or provide a git link) that can reproduce your problem easily.

Best, Hequn


On Tue, Jan 8, 2019 at 11:44 AM Puneet Kinra <
puneet.ki...@customercentria.com> wrote:

> Hi hequan
>
> Weird behaviour when i m calling ctx.timeservice() function is getting
> exited even not throwing error
>
> On Tuesday, January 8, 2019, Hequn Cheng  wrote:
>
>> Hi puneet,
>>
>> Could you print `parseLong + 5000` and
>> `ctx.timerService().currentProcessingTime()` out and check the value?
>> I know it is a streaming program. What I mean is the timer you have
>> registered is not within the interval of your job, so the timer has not
>> been triggered. For example, parseLong + 5000 = 5000 or parseLong + 5000 =
>> 1000(very big).
>>
>> Best, Hequn
>>
>>
>> On Tue, Jan 8, 2019 at 1:38 AM Puneet Kinra <
>> puneet.ki...@customercentria.com> wrote:
>>
>>> I checked the same the function is getting exited when i am calling
>>> ctx.getTimeservice () function.
>>>
>>> On Mon, Jan 7, 2019 at 10:27 PM Timo Walther  wrote:
>>>
 Hi Puneet,

 maybe you can show or explain us a bit more about your pipeline. From
 what I see your ProcessFunction looks correct. Are you sure the registering
 takes place?

 Regards,
 Timo

 Am 07.01.19 um 14:15 schrieb Puneet Kinra:

 Hi Hequn

 Its a streaming job .

 On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng 
 wrote:

> Hi Puneet,
>
> The value of the registered timer should within startTime and endTime
> of your job. For example, job starts at processing time t1 and stops at
> processing time t2. You have to make sure t1< `parseLong + 5000` < t2.
>
> Best, Hequn
>
> On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
> puneet.ki...@customercentria.com> wrote:
>
>> Hi All
>>
>> Facing some issue with context to onTimer method in processfunction
>>
>> class TimerTest extends ProcessFunction,String>{
>>
>> /**
>> *
>> */
>> private static final long serialVersionUID = 1L;
>>
>> @Override
>> public void processElement(Tuple2 arg0,
>> ProcessFunction, String>.Context ctx,
>> Collector arg2) throws Exception {
>> // TODO Auto-generated method stub
>> long parseLong = Long.parseLong(arg0.f1);
>> TimerService timerService = ctx.timerService();
>> ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
>> }
>>
>> @Override
>> public void onTimer(long timestamp, ProcessFunction> String>, String>.OnTimerContext ctx,
>> Collector out) throws Exception {
>> // TODO Auto-generated method stub
>> super.onTimer(timestamp, ctx, out);
>> System.out.println("Executing timmer"+timestamp);
>> out.collect("Timer Testing..");
>> }
>> }
>>
>> --
>> *Cheers *
>>
>> *Puneet Kinra*
>>
>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>> *
>>
>> *e-mail :puneet.ki...@customercentria.com
>> *
>>
>>
>>

 --
 *Cheers *

 *Puneet Kinra*

 *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
 *

 *e-mail :puneet.ki...@customercentria.com
 *




>>>
>>> --
>>> *Cheers *
>>>
>>> *Puneet Kinra*
>>>
>>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>>> *
>>>
>>> *e-mail :puneet.ki...@customercentria.com
>>> *
>>>
>>>
>>>
>
> --
> *Cheers *
>
> *Puneet Kinra*
>
> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
> *
>
> *e-mail :puneet.ki...@customercentria.com
> *
>
>
>
>

Re: onTimer function is not getting executed and job is marked as finished.

2019-01-08 Thread Puneet Kinra 
Sure, I will do that.

On Tue, Jan 8, 2019 at 7:25 PM Hequn Cheng  wrote:

> Hi Puneet,
>
> Can you explain it in more detail? Do you mean the job is finished before
> you call ctx.timeservice()?
> Maybe you have to let your source running for a longer time.
>
> It's better to show us the whole pipeline of your job. For example, write
> a sample code(or provide a git link) that can reproduce your problem easily.
>
> Best, Hequn
>
>
> On Tue, Jan 8, 2019 at 11:44 AM Puneet Kinra <
> puneet.ki...@customercentria.com> wrote:
>
>> Hi hequan
>>
>> Weird behaviour when i m calling ctx.timeservice() function is getting
>> exited even not throwing error
>>
>> On Tuesday, January 8, 2019, Hequn Cheng  wrote:
>>
>>> Hi puneet,
>>>
>>> Could you print `parseLong + 5000` and
>>> `ctx.timerService().currentProcessingTime()` out and check the value?
>>> I know it is a streaming program. What I mean is the timer you have
>>> registered is not within the interval of your job, so the timer has not
>>> been triggered. For example, parseLong + 5000 = 5000 or parseLong + 5000 =
>>> 1000(very big).
>>>
>>> Best, Hequn
>>>
>>>
>>> On Tue, Jan 8, 2019 at 1:38 AM Puneet Kinra <
>>> puneet.ki...@customercentria.com> wrote:
>>>
 I checked the same the function is getting exited when i am calling
 ctx.getTimeservice () function.

 On Mon, Jan 7, 2019 at 10:27 PM Timo Walther 
 wrote:

> Hi Puneet,
>
> maybe you can show or explain us a bit more about your pipeline. From
> what I see your ProcessFunction looks correct. Are you sure the 
> registering
> takes place?
>
> Regards,
> Timo
>
> Am 07.01.19 um 14:15 schrieb Puneet Kinra:
>
> Hi Hequn
>
> Its a streaming job .
>
> On Mon, Jan 7, 2019 at 5:51 PM Hequn Cheng 
> wrote:
>
>> Hi Puneet,
>>
>> The value of the registered timer should within startTime and endTime
>> of your job. For example, job starts at processing time t1 and stops at
>> processing time t2. You have to make sure t1< `parseLong + 5000` < t2.
>>
>> Best, Hequn
>>
>> On Mon, Jan 7, 2019 at 5:50 PM Puneet Kinra <
>> puneet.ki...@customercentria.com> wrote:
>>
>>> Hi All
>>>
>>> Facing some issue with context to onTimer method in processfunction
>>>
>>> class TimerTest extends
>>> ProcessFunction,String>{
>>>
>>> /**
>>> *
>>> */
>>> private static final long serialVersionUID = 1L;
>>>
>>> @Override
>>> public void processElement(Tuple2 arg0,
>>> ProcessFunction, String>.Context ctx,
>>> Collector arg2) throws Exception {
>>> // TODO Auto-generated method stub
>>> long parseLong = Long.parseLong(arg0.f1);
>>> TimerService timerService = ctx.timerService();
>>> ctx.timerService().registerProcessingTimeTimer(parseLong + 5000);
>>> }
>>>
>>> @Override
>>> public void onTimer(long timestamp, ProcessFunction>> String>, String>.OnTimerContext ctx,
>>> Collector out) throws Exception {
>>> // TODO Auto-generated method stub
>>> super.onTimer(timestamp, ctx, out);
>>> System.out.println("Executing timmer"+timestamp);
>>> out.collect("Timer Testing..");
>>> }
>>> }
>>>
>>> --
>>> *Cheers *
>>>
>>> *Puneet Kinra*
>>>
>>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>>> *
>>>
>>> *e-mail :puneet.ki...@customercentria.com
>>> *
>>>
>>>
>>>
>
> --
> *Cheers *
>
> *Puneet Kinra*
>
> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
> *
>
> *e-mail :puneet.ki...@customercentria.com
> *
>
>
>
>

 --
 *Cheers *

 *Puneet Kinra*

 *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
 *

 *e-mail :puneet.ki...@customercentria.com
 *



>>
>> --
>> *Cheers *
>>
>> *Puneet Kinra*
>>
>> *Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
>> *
>>
>> *e-mail :puneet.ki...@customercentria.com
>> *
>>
>>
>>
>>

-- 
*Cheers *

*Puneet Kinra*

*Mobile:+918800167808 | Skype : puneet.ki...@customercentria.com
*

*e-mail :puneet.ki...@customercentria.com
*