Re: [Neo4j] Neo4J High Availability : embedded or server mode ?
Yes, that was my understanding too (probably because of other embedded dbs like JavaDB etc). But from the responses of Jim and others it looks like Neo4j can handle multiple connections. That's great and NOW HA in embedded makes sense :) On Fri, Mar 25, 2011 at 1:26 PM, Clement Honore honor...@gmail.com wrote: If I've well understood, you can have only one connection to the database for each VM. So, the service must be encapsulated in a singleton I guess. How many transactions each connection can handle ? 2011/3/25 Guru GV guru...@gmail.com Though I don't see a reason not to support it, but I did not understand the point of HA in a embedded mode. Would be interested in hearing couple of examples of what that would be... Embedded would mean - same VM - so replication and concurrency - do they really mean much here ? Also, that brings me to another question - is the Embedded version of Neo4j concurrent for multiple threads ? Meaning can it have multiple simultaneous connections/transactions ongoing ? Thanks Guru On Thu, Mar 24, 2011 at 4:27 PM, Jim Webber j...@neotechnology.com wrote: Hi Kiiv, Both the embedded database *and* the server database can run in HA mode. We tend to think of the server as simply a wrapper around the database that provides a RESTful API to augment the local API. So go right ahead and pick the configuration that's right for you, and you'll be able to use HA whatever configuration you decide. Jim ___ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user ___ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user ___ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user ___ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user
Re: [Neo4j] Adding multiple keys and values to index via REST API
Ville,
you can easily write a plugin to take more than one operation at a
time and insert them in a batch-kind of way,
http://docs.neo4j.org/chunked/snapshot/server-plugins.html
Otherwise, Saikat is working on a Gremlin plugin that let's you script
this kind of stuff. We hope to have something usable next week ...
Cheers,
/peter neubauer
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On Fri, Mar 25, 2011 at 5:01 PM, Ville Mattila vi...@mattila.fi wrote:
Hi there!
I was wondering if it was possible to add multiple key and value pairs
to the Neo4j via REST API? Something like posting a JSON array of node
URLs with keys and values to the index root.
POST /index/node/my_nodes
{
http://neo:7474/db/data/node/52; : {key1 : value1, key2 : value2},
http://neo:7474/db/data/node/53; : {key1 : value1, key2 : value2}
}
This would remove much overhead while using REST API and indexing.
Best regards,
Ville
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[Neo4j] simple traverse of tree
Hi, I have some graph and, part of it is a tree. I simple get root of this tree through id. How to simple tranverse only tree under this root node? From root goes three unique type relationship to three unique group type nodes. Under this three nodes are a lot of nodes. And I need to write a method which gives me all nodes under that group node. Second question is if its possible ho to get from this group noe with the highest id (last added). Matěj Plch ___ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user
Re: [Neo4j] simple traverse of tree
Sure, if the tree from your root node is just a cluster that is not connected
anywhere else (with those 3 relationship-types) it should be as simple as.
(Just written from my head, so please check the correct syntax).
Traversal.description().relationship(T1,OUTGOING).relationship(T2,OUTGOING).relationship(T3,OUTGOING).traverse(rootNode);
That returns an iterator of all paths going from your root node.
You can limit the nodes with .uniqueness() and then add the path's
(path.nodes()) to a set to collect all nodes.
For getting the one with the highest id, you can use
java.util.Collections.max(collection, new ComparatorNode(){});
How big is your tree?
Something like that should be in Graph-Algo perhaps as subgraph or tree.
HTH
Michael
Am 26.03.2011 um 19:26 schrieb Matěj Plch:
Thank you for so fast answer.
I will look at it. I have milestone tomorrow so dont have a lot of
time=) and have never worked with Groovy.
Well so there isnt any simple method how to do it in classic neo4j Java API?
Dne 26.3.2011 19:16, Saikat Kanjilal napsal(a):
You can do all of these things using gremlin and pipes. Check out github
for more details.
Sent from my iPhone
On Mar 26, 2011, at 11:13 AM, Matěj Plchplchm...@fit.cvut.cz wrote:
Hi, I have some graph and, part of it is a tree. I simple get root of
this tree through id. How to simple tranverse only tree under this root
node? From root goes three unique type relationship to three unique
group type nodes. Under this three nodes are a lot of nodes. And I need
to write a method which gives me all nodes under that group node.
Second question is if its possible ho to get from this group noe with
the highest id (last added).
Matěj Plch
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Re: [Neo4j] simple traverse of tree
Well maybe the best one to show the graph:
https://webdev.fit.cvut.cz/~plchmate/mi-w20/neoclipse.png
https://webdev.fit.cvut.cz/%7Eplchmate/mi-w20/neoclipse.png
There is a ticket node:1001 and I would like to get all nodes under for
example node Status_Events. Now there is only one node, in real there
will be more nodes. But not so much (not more than 100 Im quite sure).
Dne 26.3.2011 19:35, Michael Hunger napsal(a):
Sure, if the tree from your root node is just a cluster that is not connected
anywhere else (with those 3 relationship-types) it should be as simple as.
(Just written from my head, so please check the correct syntax).
Traversal.description().relationship(T1,OUTGOING).relationship(T2,OUTGOING).relationship(T3,OUTGOING).traverse(rootNode);
That returns an iterator of all paths going from your root node.
You can limit the nodes with .uniqueness() and then add the path's
(path.nodes()) to a set to collect all nodes.
For getting the one with the highest id, you can use
java.util.Collections.max(collection, new ComparatorNode(){});
How big is your tree?
Something like that should be in Graph-Algo perhaps as subgraph or tree.
HTH
Michael
Am 26.03.2011 um 19:26 schrieb Matěj Plch:
Thank you for so fast answer.
I will look at it. I have milestone tomorrow so dont have a lot of
time=) and have never worked with Groovy.
Well so there isnt any simple method how to do it in classic neo4j Java API?
Dne 26.3.2011 19:16, Saikat Kanjilal napsal(a):
You can do all of these things using gremlin and pipes. Check out github
for more details.
Sent from my iPhone
On Mar 26, 2011, at 11:13 AM, Matěj Plchplchm...@fit.cvut.cz wrote:
Hi, I have some graph and, part of it is a tree. I simple get root of
this tree through id. How to simple tranverse only tree under this root
node? From root goes three unique type relationship to three unique
group type nodes. Under this three nodes are a lot of nodes. And I need
to write a method which gives me all nodes under that group node.
Second question is if its possible ho to get from this group noe with
the highest id (last added).
Matěj Plch
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