Re: [Scilab-users] Trying to use old Scicos file with Xcos

2018-12-14 Thread JD Heinzmann
Sorry to have dropped this conversation 4 years ago.  May I bring it alive
again?

I have just installed SciLab 6.0.1 and would like to be able to use the .cos
file I have working in SciCosLab-4.4b8 with Xcos.  But there is no option
for opening it in SciLab-6.  I was able to open it in SciLab-5.4.1 (but not
run it as noted previously) and save it as a .zcos file which I am
attaching.  I am also attaching the original .cos file from 4.4b8 and the
context file which should be run first to set up the variables needed for
the simulation.

Is it possible to convert one of these files to run with Scilab 6?

FlameLicker.zcos
  
FlameLicker.cos
  
FL_Context.sce   

Thank you.

--
JD








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[Scilab-users] Output variable initialisation?

2018-12-14 Thread Federico Miyara


Dear All,

I've converted a Matlab function to Scilab. The converter inserts the
following
code:

// Output variables initialisation (not found in input variables)
z=[];

z is the output variable.

Is it necessary to initialise the output variables?

Regards,

Federico Miyara




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[Scilab-users] Possible error in manual

2018-12-14 Thread Federico Miyara


Dear All,

I've converted a Matlab function to Scilab. The converter inserts yhe
following
code:

// Output variables initialisation (not found in input variables)
z=[];

z is the output variable.

Is it necessary to initialise the output variables?

Regards,

Federico Miyara




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[Scilab-users] Possible error in manual

2018-12-14 Thread Federico Miyara


Dear All,

In the help information for the FFT function I find that, regarding the
"inverse" FFT,  fft(x,1), the formula is

n
x(k) = SUM(a(m)*exp(2*%i*%pi*(m-1)*(k-1)/n)
   m=1

But this is not the inverse FFT since it lacks the required 1/n factor;
however, fft(fft(a,-1),1) indeed returns a. So the procedure seems to be
mistakenly described in the help information.

Interestingly, the fftw3 documentation, http://www.fftw.org/fftw3.pdf,
gives, on page 42, the same formula but it indicates it is an
unnormalized transform.

Would you please clarify?

Regards,

Federico Miyara





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