adding (prepending) Javascript to onchange

[Adam Koch]

I have a drop down that submits the form when the selection changes
(wantOnSelectionChangedNotifications returns true). I would like to add some
javascript to display a please wait message before the form is submitted.
How can I do that?

Thanks,
Adam

feedback message not shown from ajax button when setting new response page

[Adam Koch]

I'm having a problem with the feedback panel in conjunction with the
AjaxButton and setResponsePage(). There are two pages, a home page and a sub
page. When the user submits a form successfully on the sub page, I would
like the home page to display with an informational message.

Here is some code:
// my form
add(new AjaxButton(submitButton, this) {
protected void onSubmit(AjaxRequestTarget target, Form form) {
  // nothing, want the form submit to do the work
}
protected void onError(...) {
  // refresh the feedback panel without refreshing any page
});

protected void onSubmit() {
info(successful!);
setRedirect(false);
setResponsePage(HomePage.class);
}

What happens is the new page is displayed, but the info message isn't.

If I use a regular Button, this works, but then I don't get the Ajax
validation of the form.
And if I don't set the response page to another page, then this also works.
(Well, maybe not _that_ code, but the feedback can be refreshed with an info
message.)

Can anybody help me? I'm not sure what else I can do to debug this.

Thanks,
Adam

Re: feedback message not shown from ajax button when setting new response page

[Adam Koch]

I think I found the reason:
/**
 * If it's an ajax request we always redirect.
 *
 * @see org.apache.wicket.RequestCycle#isRedirect()
 */
public final boolean isRedirect()
{
if (getWebRequest().isAjax())
{
return true;
}
else
{
return super.isRedirect();
}
}

This is inside WebRequestCycle.  Can someone explain why if it's an ajax
request it's always a redirect?

On 10/15/07, Adam Koch [EMAIL PROTECTED] wrote:

 I'm having a problem with the feedback panel in conjunction with the
 AjaxButton and setResponsePage(). There are two pages, a home page and a sub
 page. When the user submits a form successfully on the sub page, I would
 like the home page to display with an informational message.

 Here is some code:
 // my form
 add(new AjaxButton(submitButton, this) {
 protected void onSubmit(AjaxRequestTarget target, Form form) {
   // nothing, want the form submit to do the work
 }
 protected void onError(...) {
   // refresh the feedback panel without refreshing any page
 });

 protected void onSubmit() {
 info(successful!);
 setRedirect(false);
 setResponsePage(HomePage.class);
 }

 What happens is the new page is displayed, but the info message isn't.

 If I use a regular Button, this works, but then I don't get the Ajax
 validation of the form.
 And if I don't set the response page to another page, then this also
 works. (Well, maybe not _that_ code, but the feedback can be refreshed with
 an info message.)

 Can anybody help me? I'm not sure what else I can do to debug this.

 Thanks,
 Adam




-- 
Adam A. Koch
http://www.outofthemold.com/

Re: feedback message not shown from ajax button when setting new response page

[Adam Koch]

That seems easy enough. Thanks!

Tell me if this is right. If we send an Ajax request from the browser, then
the only way to get it to refresh the page is to tell it to redirect. That's
why all Ajax calls that have render a new page have to redirect.

Thanks,
Adam

On 10/15/07, Igor Vaynberg [EMAIL PROTECTED] wrote:

 if you have feedback messages that need to last across requests/pages you
 need to use getsession().info() instead

 -igor


 On 10/15/07, Adam Koch [EMAIL PROTECTED] wrote:
 
  I'm having a problem with the feedback panel in conjunction with the
  AjaxButton and setResponsePage(). There are two pages, a home page and a
  sub
  page. When the user submits a form successfully on the sub page, I would
  like the home page to display with an informational message.
 
  Here is some code:
  // my form
  add(new AjaxButton(submitButton, this) {
  protected void onSubmit(AjaxRequestTarget target, Form form) {
// nothing, want the form submit to do the work
  }
  protected void onError(...) {
// refresh the feedback panel without refreshing any page
  });
 
  protected void onSubmit() {
  info(successful!);
  setRedirect(false);
  setResponsePage(HomePage.class);
  }
 
  What happens is the new page is displayed, but the info message isn't.
 
  If I use a regular Button, this works, but then I don't get the Ajax
  validation of the form.
  And if I don't set the response page to another page, then this also
  works.
  (Well, maybe not _that_ code, but the feedback can be refreshed with an
  info
  message.)
 
  Can anybody help me? I'm not sure what else I can do to debug this.
 
  Thanks,
  Adam
 




-- 
Adam A. Koch
http://www.outofthemold.com/