Re: Bigger sites running on wicket?
Take a look at Websites based on Wickethttps://cwiki.apache.org/WICKET/websites-based-on-wicket.html( https://cwiki.apache.org/WICKET/websites-based-on-wicket.html). The project I'm working on, http://ewmix.com/, has about 100 concurrent users, but this would involves much more than just a framework. Wicket does a great job in HTML simplicity and let us create much more flexible pages, also supporting Ajax if you need. Wicket has many ready-to-use components and a consistent hierarchy tree. If the component you need is not available, it is easy to implement it. For performance, the key is to use adequate models to leverage the server cache memory. Also, you have to create a good persistence layer. Much of the latency your site could have can be reviewed by good SQL queries, correct indexes and so on. Take a look at wicket, check out our results at http://ewmix.com/. Bookmarkable links, no servlet implementation, no XML configuration and other goodies let us give wicket a try. Wicket brought some fun to web development and we are sure, after the project is launched, that it is the best choice. If you need more help, please ask us. We'll be glad to help. Rangel Preis. 2010/5/13 Zoltan Luspai zlus...@gmail.com Dear All, I'm quite fond of wicket so far, but to convince my boss further using it: I would need some samples of bigger sites or portals running on wicket. If you know such - something like 100s of concurrent users, or big number of users- please send me links and information. If possible some technical details would be nice too. Thanks, Zoltan - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
E-commerce with wicket
Hi, About two month ago we launch http://ewmix.com, a brazilian e-commerce. With the core finished we will make a new layout. Unfortunately we just sell to Brazil at this moment. All time people ask what technologic the project use so: Wicket 1.4.8 Postgres Compass (search) Spring Security with wicket auto-roles Wicket merged resources Jetty and Apache Later we plan to show more details on this project: the objectives, choices, difficulties and recommendations. We hope that those comments will help people on planning new projects using wicket, also receive ideas for the mistakes that we are doing. Thank Wicketeers again. Rangel Preis
Re: How reRender a component from parent page?
I try this again using only setOutputMarkupId without modelChanged and
onModelChange, and don't work.
I just setOutputMarkupId on my component and in the ajaxEvent i put:
target.addComponent(getPage().get(header:counter));
header is a panel and counter is a Label in this panel.
Thanks All.
2010/2/8 Rangel Preis rangel...@gmail.com:
Thanks, Don but this don't work the value don't change. And I call
setOutputMarkupId when i build it. and call it again later...
Thanks All.
2010/2/8 Don Ferguson d...@rixty.com:
I think setOutputMarkupId() should have been called earlier, in the
MyTemplate constructor when the Header was constructed. Ajax processing
needs the markup id to find the component you're changing, so setting it in
onModelChanged() is too late. Also, I don't think you need the call to
modelChanged() or to override onModelChanged. Changing the model object and
adding the component to the target should be sufficient.
-Don
On Feb 8, 2010, at 2:16 AM, Rangel Preis wrote:
My template HTML
html xmlns=http://www.w3.org/1999/xhtml;
xmlns:wicket=http://wicket.apache.org/dtds.data/wicket-xhtml1.4-strict.dtd;
head
title wicket:id=title/title
meta wicket:id=description name=description
content=/
meta wicket:id=keywords name=keywords content=/
meta wicket:id=version name=version content=/
/head
body
a href=#irconteudo style=display: none;/a
div wicket:id=header class=header/div
!-- conteudo --
div id=conteudo
table class=layout
tr
td wicket:id=col_esq
class=col_esq/
td
a name=irconteudo
style=display: none;/a
div wicket:id=feedback id=feedback/
wicket:child/
/td
td class=col_dir
/td
/tr
/table
/div
div wicket:id=footer class=footer/div
/body
/html
Header.html
wicket:panel
div class=right
div wicket:id=header_client class=client/div
/div
//Value that i want to change
div class=conter
a wicket:id=conterspan wicket:id=itens//a
/div
div class=left
a wicket:id=header_home_linkdiv class=logo//a
/div
div wicket:id=header_search class=search/div
/wicket:panel
Thanks.
2010/2/5 Riyad Kalla rka...@gmail.com:
What do the tasty HTML bits look like? (wicket:ids and what not)
On Fri, Feb 5, 2010 at 12:50 PM, Rangel Preis rangel...@gmail.com
wrote:
How can I use Ajax to change value from a parent page in my layout. I
try to change values in header using a action from content page.
I have this:
|---|
| HEADER |
|---|
| MENU | CONTENT |
| | |
| | |
| | |
|---|---|
| FOOTER |
|---|
public class MyTemplate{
public MyTemplate() {
super();
this.add(CSSPackageResource.getHeaderContribution(...);
this.add(AbstractTemplatePage.FEEDBACK);
this.addOrReplace(new Header());
this.add(new Menu());
this.add(new Footer());
.
public class MyContetPage extends MyTemplate {
public MyContetPage(final PageParameters _parameters) {
add(new AjaxFallbackLinkVoid(rem) {
�...@override
public void onClick(final AjaxRequestTarget target) {
…...
}
});
….
}
}
How change value in the header when i click on the ajaxlink of my
content page?
In the onClick i try this; but don't work
//some function to change the model value...
this.getPage().get(header:component).modelChanged();
target.addComponent(this.getPage().get(header:component));
And in my Header.java I override onModelChanged:
protected void onModelChanged() {
super.onModelChanged();
this.addOrReplace(component).setOutputMarkupId(true));
}
Thanks all.
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Re: How reRender a component from parent page?
Yes, it's make sense.
I change to ptopertyModel and now thinks works.
Thanks Cemal.
2010/2/9 Cemal Bayramoglu jweekend_for...@cabouge.com:
Rangel,
The is a common problem people encounter while they get their head
aroung Wicket models.
In your Header class, the label's data is only ever calculated once,
on construction of the Header and is therefore is fixed.
Try something like:
final Label itens = new Label(itens, new
PropertyModel(WicketSession.get(),cart.amount));
(I have retained your spelling of itens but I assume this should be
items).
If you want to format the resulting string (as per your apparent
intention in your QuickStart), use a converter, probably best in your
case by overriding the your label's getConverter method.
The rest of your code looks OK.
Does that make sense?
Regards - Cemal
jWeekend
OO Java Technologies, Wicket
Consulting, Development, Training
http://jWeekend.com
On 9 February 2010 14:50, Rangel Preis rangel...@gmail.com wrote:
I make a quick start project (maven) to show my problem, if someone have
time...
The problem are in HomePage.java in the onClick... this don't reRender
my componente in the header.
Thanks.
2010/2/9 Rangel Preis rangel...@gmail.com:
I try this again using only setOutputMarkupId without modelChanged and
onModelChange, and don't work.
I just setOutputMarkupId on my component and in the ajaxEvent i put:
target.addComponent(getPage().get(header:counter));
header is a panel and counter is a Label in this panel.
Thanks All.
2010/2/8 Rangel Preis rangel...@gmail.com:
Thanks, Don but this don't work the value don't change. And I call
setOutputMarkupId when i build it. and call it again later...
Thanks All.
2010/2/8 Don Ferguson d...@rixty.com:
I think setOutputMarkupId() should have been called earlier, in the
MyTemplate constructor when the Header was constructed. Ajax processing
needs the markup id to find the component you're changing, so setting it
in
onModelChanged() is too late. Also, I don't think you need the call to
modelChanged() or to override onModelChanged. Changing the model object
and
adding the component to the target should be sufficient.
-Don
On Feb 8, 2010, at 2:16 AM, Rangel Preis wrote:
My template HTML
html xmlns=http://www.w3.org/1999/xhtml;
xmlns:wicket=http://wicket.apache.org/dtds.data/wicket-xhtml1.4-strict.dtd;
head
title wicket:id=title/title
meta wicket:id=description name=description
content=/
meta wicket:id=keywords name=keywords content=/
meta wicket:id=version name=version content=/
/head
body
a href=#irconteudo style=display: none;/a
div wicket:id=header class=header/div
!-- conteudo --
div id=conteudo
table class=layout
tr
td wicket:id=col_esq
class=col_esq/
td
a name=irconteudo
style=display: none;/a
div wicket:id=feedback id=feedback/
wicket:child/
/td
td class=col_dir
/td
/tr
/table
/div
div wicket:id=footer class=footer/div
/body
/html
Header.html
wicket:panel
div class=right
div wicket:id=header_client class=client/div
/div
//Value that i want to change
div class=conter
a wicket:id=conterspan wicket:id=itens//a
/div
div class=left
a wicket:id=header_home_linkdiv class=logo//a
/div
div wicket:id=header_search class=search/div
/wicket:panel
Thanks.
2010/2/5 Riyad Kalla rka...@gmail.com:
What do the tasty HTML bits look like? (wicket:ids and what not)
On Fri, Feb 5, 2010 at 12:50 PM, Rangel Preis rangel...@gmail.com
wrote:
How can I use Ajax to change value from a parent page in my layout. I
try to change values in header using a action from content page.
I have this:
|---|
| HEADER |
|---|
| MENU | CONTENT |
| | |
| | |
| | |
|---|---|
| FOOTER |
|---|
public class MyTemplate{
public MyTemplate() {
super();
this.add(CSSPackageResource.getHeaderContribution(...);
this.add(AbstractTemplatePage.FEEDBACK);
this.addOrReplace(new Header());
this.add(new Menu());
this.add(new Footer());
.
public class
Re: How reRender a component from parent page?
My template HTML
html xmlns=http://www.w3.org/1999/xhtml;
xmlns:wicket=http://wicket.apache.org/dtds.data/wicket-xhtml1.4-strict.dtd;
head
title wicket:id=title/title
meta wicket:id=description name=description content=/
meta wicket:id=keywords name=keywords content=/
meta wicket:id=version name=version content=/
/head
body
a href=#irconteudo style=display: none;/a
div wicket:id=header class=header/div
!-- conteudo --
div id=conteudo
table class=layout
tr
td wicket:id=col_esq
class=col_esq/
td
a name=irconteudo
style=display: none;/a
div wicket:id=feedback id=feedback/
wicket:child/
/td
td class=col_dir
/td
/tr
/table
/div
div wicket:id=footer class=footer/div
/body
/html
Header.html
wicket:panel
div class=right
div wicket:id=header_client class=client/div
/div
//Value that i want to change
div class=conter
a wicket:id=conterspan wicket:id=itens//a
/div
div class=left
a wicket:id=header_home_linkdiv class=logo//a
/div
div wicket:id=header_search class=search/div
/wicket:panel
Thanks.
2010/2/5 Riyad Kalla rka...@gmail.com:
What do the tasty HTML bits look like? (wicket:ids and what not)
On Fri, Feb 5, 2010 at 12:50 PM, Rangel Preis rangel...@gmail.com wrote:
How can I use Ajax to change value from a parent page in my layout. I
try to change values in header using a action from content page.
I have this:
|---|
| HEADER |
|---|
| MENU | CONTENT |
| | |
| | |
| | |
|---|---|
| FOOTER |
|---|
public class MyTemplate{
public MyTemplate() {
super();
this.add(CSSPackageResource.getHeaderContribution(...);
this.add(AbstractTemplatePage.FEEDBACK);
this.addOrReplace(new Header());
this.add(new Menu());
this.add(new Footer());
.
public class MyContetPage extends MyTemplate {
public MyContetPage(final PageParameters _parameters) {
add(new AjaxFallbackLinkVoid(rem) {
�...@override
public void onClick(final AjaxRequestTarget target) {
…...
}
});
….
}
}
How change value in the header when i click on the ajaxlink of my content
page?
In the onClick i try this; but don't work
//some function to change the model value...
this.getPage().get(header:component).modelChanged();
target.addComponent(this.getPage().get(header:component));
And in my Header.java I override onModelChanged:
protected void onModelChanged() {
super.onModelChanged();
this.addOrReplace(component).setOutputMarkupId(true));
}
Thanks all.
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
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-
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For additional commands, e-mail: users-h...@wicket.apache.org
Re: How reRender a component from parent page?
Thanks, Don but this don't work the value don't change. And I call
setOutputMarkupId when i build it. and call it again later...
Thanks All.
2010/2/8 Don Ferguson d...@rixty.com:
I think setOutputMarkupId() should have been called earlier, in the
MyTemplate constructor when the Header was constructed. Ajax processing
needs the markup id to find the component you're changing, so setting it in
onModelChanged() is too late. Also, I don't think you need the call to
modelChanged() or to override onModelChanged. Changing the model object and
adding the component to the target should be sufficient.
-Don
On Feb 8, 2010, at 2:16 AM, Rangel Preis wrote:
My template HTML
html xmlns=http://www.w3.org/1999/xhtml;
xmlns:wicket=http://wicket.apache.org/dtds.data/wicket-xhtml1.4-strict.dtd;
head
title wicket:id=title/title
meta wicket:id=description name=description
content=/
meta wicket:id=keywords name=keywords content=/
meta wicket:id=version name=version content=/
/head
body
a href=#irconteudo style=display: none;/a
div wicket:id=header class=header/div
!-- conteudo --
div id=conteudo
table class=layout
tr
td wicket:id=col_esq
class=col_esq/
td
a name=irconteudo
style=display: none;/a
div wicket:id=feedback id=feedback/
wicket:child/
/td
td class=col_dir
/td
/tr
/table
/div
div wicket:id=footer class=footer/div
/body
/html
Header.html
wicket:panel
div class=right
div wicket:id=header_client class=client/div
/div
//Value that i want to change
div class=conter
a wicket:id=conterspan wicket:id=itens//a
/div
div class=left
a wicket:id=header_home_linkdiv class=logo//a
/div
div wicket:id=header_search class=search/div
/wicket:panel
Thanks.
2010/2/5 Riyad Kalla rka...@gmail.com:
What do the tasty HTML bits look like? (wicket:ids and what not)
On Fri, Feb 5, 2010 at 12:50 PM, Rangel Preis rangel...@gmail.com
wrote:
How can I use Ajax to change value from a parent page in my layout. I
try to change values in header using a action from content page.
I have this:
|---|
| HEADER |
|---|
| MENU | CONTENT |
| | |
| | |
| | |
|---|---|
| FOOTER |
|---|
public class MyTemplate{
public MyTemplate() {
super();
this.add(CSSPackageResource.getHeaderContribution(...);
this.add(AbstractTemplatePage.FEEDBACK);
this.addOrReplace(new Header());
this.add(new Menu());
this.add(new Footer());
.
public class MyContetPage extends MyTemplate {
public MyContetPage(final PageParameters _parameters) {
add(new AjaxFallbackLinkVoid(rem) {
�...@override
public void onClick(final AjaxRequestTarget target) {
…...
}
});
….
}
}
How change value in the header when i click on the ajaxlink of my
content page?
In the onClick i try this; but don't work
//some function to change the model value...
this.getPage().get(header:component).modelChanged();
target.addComponent(this.getPage().get(header:component));
And in my Header.java I override onModelChanged:
protected void onModelChanged() {
super.onModelChanged();
this.addOrReplace(component).setOutputMarkupId(true));
}
Thanks all.
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
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-
To unsubscribe, e
How reRender a component from parent page?
How can I use Ajax to change value from a parent page in my layout. I
try to change values in header using a action from content page.
I have this:
|---|
| HEADER |
|---|
| MENU | CONTENT |
| | |
| | |
| | |
|---|---|
| FOOTER|
|---|
public class MyTemplate{
public MyTemplate() {
super();
this.add(CSSPackageResource.getHeaderContribution(...);
this.add(AbstractTemplatePage.FEEDBACK);
this.addOrReplace(new Header());
this.add(new Menu());
this.add(new Footer());
.
public class MyContetPage extends MyTemplate {
public MyContetPage(final PageParameters _parameters) {
add(new AjaxFallbackLinkVoid(rem) {
�...@override
public void onClick(final AjaxRequestTarget target) {
…...
}
});
….
}
}
How change value in the header when i click on the ajaxlink of my content page?
In the onClick i try this; but don't work
//some function to change the model value...
this.getPage().get(header:component).modelChanged();
target.addComponent(this.getPage().get(header:component));
And in my Header.java I override onModelChanged:
protected void onModelChanged() {
super.onModelChanged();
this.addOrReplace(component).setOutputMarkupId(true));
}
Thanks all.
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Re: Proxying SSL on Apache to HTTP on Jetty + Wicket
Thanks Nino, you are correct.
In the Jetty tutorial says:
...extending the Connector class of your choice, eg the
SelectChannelConnector, and implement the customize...
public void customize(org.mortbay.io.EndPoint endpoint, Request
request) throws IOException
{
request.setScheme(https);
super.customize(endpoint, request);
}
but this don't work and i change to:
public void customize(final EndPoint endpoint, final Request
request) throws IOException {
super.customize(endpoint, request);
if (https.equals(request.getHeader(scheme))) {
request.setScheme(https);
}
}
Now this works. Thanks Nino.
2009/11/11 nino martinez wael nino.martinez.w...@gmail.com:
I think last time this came up it ended out being some issue with jetty?
2009/11/11 Rangel Preis rangel...@gmail.com
I extends HttpsRequestCycleProcessor and SwitchProtocolRequestTarget
to make my custom HttpsRequestCycleProcessor
In the method getUrl from SwitchProtocolRequestTarget i just remove the
port:
if (port != null) {
result.append(:);
result.append(port);
}
But don't work, the url are correct but the page don't load i think i
miss something in apache.
Anyone make something like this?
Thanks.
2009/11/10 Rangel Preis rangel...@gmail.com:
The unique solution that i found is extends HttpsRequestCycleProcessor
to change only the protocol.
Any other ideia? Thanks All.
2009/11/10 Rangel Preis rangel...@gmail.com:
The situation here is:
https http
- Apache --- Jetty
Using wicket in my WicketApplication I put
private static final HttpsConfig HTTPS_CONFIG = new
HttpsConfig(HTTP_PORT, HTTPS_PORT);
�...@override
protected IRequestCycleProcessor newRequestCycleProcessor() {
return new HttpsRequestCycleProcessor(HTTPS_CONFIG);
}
And in my LoginPage.java i have @RequireHttps
When i try to run the system with this config i get a error because
Wicket assumes the HTTPS control and try to change the URL (port and
replace http to https)
How i say to wicket to just change the protocol to HTTPS? And don't
change the port?
Thanks
-
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-
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Re: Proxying SSL on Apache to HTTP on Jetty + Wicket
I extends HttpsRequestCycleProcessor and SwitchProtocolRequestTarget
to make my custom HttpsRequestCycleProcessor
In the method getUrl from SwitchProtocolRequestTarget i just remove the port:
if (port != null) {
result.append(:);
result.append(port);
}
But don't work, the url are correct but the page don't load i think i
miss something in apache.
Anyone make something like this?
Thanks.
2009/11/10 Rangel Preis rangel...@gmail.com:
The unique solution that i found is extends HttpsRequestCycleProcessor
to change only the protocol.
Any other ideia? Thanks All.
2009/11/10 Rangel Preis rangel...@gmail.com:
The situation here is:
https http
- Apache --- Jetty
Using wicket in my WicketApplication I put
private static final HttpsConfig HTTPS_CONFIG = new
HttpsConfig(HTTP_PORT, HTTPS_PORT);
�...@override
protected IRequestCycleProcessor newRequestCycleProcessor() {
return new HttpsRequestCycleProcessor(HTTPS_CONFIG);
}
And in my LoginPage.java i have @RequireHttps
When i try to run the system with this config i get a error because
Wicket assumes the HTTPS control and try to change the URL (port and
replace http to https)
How i say to wicket to just change the protocol to HTTPS? And don't
change the port?
Thanks
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Proxying SSL on Apache to HTTP on Jetty + Wicket
The situation here is:
https http
- Apache --- Jetty
Using wicket in my WicketApplication I put
private static final HttpsConfig HTTPS_CONFIG = new
HttpsConfig(HTTP_PORT, HTTPS_PORT);
@Override
protected IRequestCycleProcessor newRequestCycleProcessor() {
return new HttpsRequestCycleProcessor(HTTPS_CONFIG);
}
And in my LoginPage.java i have @RequireHttps
When i try to run the system with this config i get a error because
Wicket assumes the HTTPS control and try to change the URL (port and
replace http to https)
How i say to wicket to just change the protocol to HTTPS? And don't
change the port?
Thanks
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Re: Proxying SSL on Apache to HTTP on Jetty + Wicket
The unique solution that i found is extends HttpsRequestCycleProcessor
to change only the protocol.
Any other ideia? Thanks All.
2009/11/10 Rangel Preis rangel...@gmail.com:
The situation here is:
https http
- Apache --- Jetty
Using wicket in my WicketApplication I put
private static final HttpsConfig HTTPS_CONFIG = new
HttpsConfig(HTTP_PORT, HTTPS_PORT);
�...@override
protected IRequestCycleProcessor newRequestCycleProcessor() {
return new HttpsRequestCycleProcessor(HTTPS_CONFIG);
}
And in my LoginPage.java i have @RequireHttps
When i try to run the system with this config i get a error because
Wicket assumes the HTTPS control and try to change the URL (port and
replace http to https)
How i say to wicket to just change the protocol to HTTPS? And don't
change the port?
Thanks
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Problem with @RequireHttps and Tests
I put the @RequireHttps annotation in my LoginPage, and it's work fine
when i run the app.
But when i run my tests all test fail, if I remove @RequireHttps all
test pass correctly
Here's the problem, when i run this code without the annotation the
wicket tester call the button btn_login.
If i put the @RequireHttps annotation this code don't work.
protected final static void logarUsuario() {
tester.startPage(LoginPage.class);
tester.assertRenderedPage(LoginPage.class);
tester.assertNoErrorMessage();
final FormTester form = tester.newFormTester(form);
form.setValue(email, username);
form.setValue(pass, password);
form.submit(btn_login);
}
Thanks all.
-
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Re: How to add filter to palette component?
Thanks Fernando and Eyal.
But it's not work.
I try the code below, when I change the value of avaliable itens the
itens in the screen became blank , and don't show the new value.
Custem Palette
class MyPalette extends Palette {
private Component externalizedChoiceComponent;
@Override
protected Component newChoicesComponent() {
final Component result = super.newChoicesComponent();
this.externalizedChoiceComponent = result;
this.externalizedChoiceComponent.setOutputMarkupId(true);
return result;
}
public Component getExternalizedChoiceComponent() {
return this.externalizedChoiceComponent;
}
}
final IModel avaliableModel = new AbstractReadOnlyModel() {
@Override
public Object getObject() {
return this.avaliableList;
}
};
Palette creation
final MyPalette palette = new MyPalette(palette, inUseModel,
avaliableModel, renderer, 10, true);
this.form.add(new AjaxLink(btFind) {
@Override
public void onClick(final AjaxRequestTarget target) {
try {
avaliableList = getNewList();
} catch (final Exception e) {
log.error(e);
}
target.addComponent(palette.getExternalizedChoiceComponent());
}
});
Anyone have another tip?
Thanks.
2009/6/23 Eyal Golan egola...@gmail.com:
Here what I did:
choiceComponent in the original Palette is private, so in my custom palette
I externalized it:
private Component externalizedChoiceComponent;
Then, I overridden the method newChoicesComponent :
�...@override
protected Component newChoicesComponent() {
final Component result = super.newChoicesComponent();
externalizedChoiceComponent = result;
externalizedChoiceComponent.setOutputMarkupId(true);
return result;
}
public Component getExternalizedChoiceComponent() {
return this.externalizedChoiceComponent;
}
My situation was that I wanted to change the choices with a DropDown
component.
We have a custom DropDown that is ajaxified:
final DropDownChoice configurationChoice = new
DropDownChoiceWithAjaxIndicator(mainConfiguration,
getConfigurationsModel(), new
ChoiceRenderer(configurationName, configurationName)) {
private static final long serialVersionUID = 1L;
�...@override
public void updateOnChange(AjaxRequestTarget target) {
target.addComponent(palette.getExternalizedChoiceComponent());
}
};
Below is the IModel for the palette that needs to be changed:
final IModel allConfigurationsModel = new AbstractReadOnlyModel() {
private static final long serialVersionUID = 1L;
�...@override
public Object getObject() {
// Do whatever you want to get the correct choices
}
};
And this is the Palette creation:
final CustomPalette palette = new CustomPalette(palette, new
PropertyModel(rolesCoverageDasboard,
comparedConfigurations), allConfigurationsModel,
choiceRenderer, 10, true);
Is this what you need?
BTW,
I think I'll have a look at the Recorder, though I'm not sure I can use it.
Maybe we should open a JIRA to have getChoicesComponent() in the Palette?
(we use 1.3.6)
Eyal Golan
egola...@gmail.com
Visit: http://jvdrums.sourceforge.net/
LinkedIn: http://www.linkedin.com/in/egolan74
P Save a tree. Please don't print this e-mail unless it's really necessary
On Mon, Jun 22, 2009 at 11:57 PM, Rangel Preis rangel...@gmail.com wrote:
Sorry Fernando but it's not helpful.
When i click in my search button (a button out of palette) i want to
change all data from the left side of palette (Available itens).
I don't want to interact with the palette buttons i want to use a
button out of the component.
Using
PropertyModel availableItens = new PropertyModel(this, listDirector);
or
Model availableItens = new ModelSerializable((Serializable)
this.listDirector);
..
form.add(new Palette(palette, selectedItens, availableItens,
renderer, 10, true));
form.add(new(AjaxLink btFilterPaletteContent = new
AjaxLink(btFilterPaletteContent){
@Override
public void onClick(AjaxRequestTarget target) {
What i can put here to change my avaliable itens (the palette left
list)?
target.addComponent(this.form);
}
};)
2009/6/22 Fernando Wermus fernando.wer...@gmail.com:
If I understood correctly you would want to do this (which It can be
found
at Palette comments at the begining)
strongAjaxifying the palette/strong: The palette itself cannot be
ajaxified because it is a
panel and therefore does not receive any javascript events. Instead ajax
behaviors can be
attached to the recorder
Re: How to add filter to palette component?
Golan... the object have the correct value in code, but in the page it's blank.
2009/6/23 Eyal Golan egola...@gmail.com:
It looks just like what I did.
Did you break-point at
public Object getObject() {
return this.avaliableList;
}
?
or at avaliableList = getNewList();
Is the list full?
Maybe you should try AjaxSubmitLink (Just a thought. I don't use it that
often)?
Eyal Golan
egola...@gmail.com
Visit: http://jvdrums.sourceforge.net/
LinkedIn: http://www.linkedin.com/in/egolan74
P Save a tree. Please don't print this e-mail unless it's really necessary
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How to add filter to palette component?
Hi, how can i filter the possible choices in the palette component i
read the topics below put it not helpful for me.
http://www.nabble.com/how-to-add-filter-for-Palette-choice-td23269578.html#a23269578
http://www.nabble.com/changing-choices-component-in-Palette-td23982514.html#a23982514
I have this:
final IChoiceRendererString renderer = new
ChoiceRendererString(name, name);
form.add(new Palette(paletteDiretores, selectedItens,
availableItens, renderer, 10, true));
And a button:
AjaxLink btFilterPaletteContent = new AjaxLink(btFilterPaletteContent){
@Override
public void onClick(AjaxRequestTarget target) {
availableItens = search new itens
}
};
I try this and don't work, if i inspect the objet the value is OK, but
in the screen the palette become blank.
i try to use propertymodel to avaliableitens... don't work too..
I just want to chance the content of the avaliable itens in the panel
without affect the selecteds itens.
Anyone can help me?
Thanks.
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Re: How to add filter to palette component?
Sorry Fernando but it's not helpful.
When i click in my search button (a button out of palette) i want to
change all data from the left side of palette (Available itens).
I don't want to interact with the palette buttons i want to use a
button out of the component.
Using
PropertyModel availableItens = new PropertyModel(this, listDirector);
or
Model availableItens = new ModelSerializable((Serializable)
this.listDirector);
..
form.add(new Palette(palette, selectedItens, availableItens,
renderer, 10, true));
form.add(new(AjaxLink btFilterPaletteContent = new
AjaxLink(btFilterPaletteContent){
@Override
public void onClick(AjaxRequestTarget target) {
What i can put here to change my avaliable itens (the palette left list)?
target.addComponent(this.form);
}
};)
2009/6/22 Fernando Wermus fernando.wer...@gmail.com:
If I understood correctly you would want to do this (which It can be found
at Palette comments at the begining)
strongAjaxifying the palette/strong: The palette itself cannot be
ajaxified because it is a
panel and therefore does not receive any javascript events. Instead ajax
behaviors can be
attached to the recorder component which supports the javascript
codeonchange/code event. The
recorder component can be retrieved via a call to {...@link
#getRecorderComponent()}.
Example:
pre
Form form=new Form(...);
Palette palette=new Palette(...);
palette.getRecorderComponent().add(new
AjaxFormComponentUpdatingBehavior(quot;onchangequot;) {...});
Then when someone click in any of the buttons you can take a decision over
the selected items or choiced items. You can do this without ajax replacing
the newUp, new newDown protected methods.
I hope I help you a bit.
On Mon, Jun 22, 2009 at 12:08 PM, Rangel Preis rangel...@gmail.com wrote:
Hi, how can i filter the possible choices in the palette component i
read the topics below put it not helpful for me.
http://www.nabble.com/how-to-add-filter-for-Palette-choice-td23269578.html#a23269578
http://www.nabble.com/changing-choices-component-in-Palette-td23982514.html#a23982514
I have this:
final IChoiceRendererString renderer = new
ChoiceRendererString(name, name);
form.add(new Palette(paletteDiretores, selectedItens,
availableItens, renderer, 10, true));
And a button:
AjaxLink btFilterPaletteContent = new AjaxLink(btFilterPaletteContent){
�...@override
public void onClick(AjaxRequestTarget target) {
availableItens = search new itens
}
};
I try this and don't work, if i inspect the objet the value is OK, but
in the screen the palette become blank.
i try to use propertymodel to avaliableitens... don't work too..
I just want to chance the content of the avaliable itens in the panel
without affect the selecteds itens.
Anyone can help me?
Thanks.
-
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For additional commands, e-mail: users-h...@wicket.apache.org
--
Fernando Wermus.
www.linkedin.com/in/fernandowermus
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Re: Problem refreshing a table content
Igor, Thanks for help us. Rangel Preis. 2009/6/8 Igor Vaynberg igor.vaynb...@gmail.com: listdataprovider keeps a reference to the list, so it never sees your updated reference. i would suggest you implement idataprovider yourself. -igor - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
