Re: AjaxSubmitLink accessing model object non-existent property
OK. It's clicked. I was hoping to have a simple ajaxed submit link
without having to create a fake property on the model object. No problem,
I can see what I missed.
Thanks for your help Igor.
Tim
you said it yourself:
Insure that the component identifier names match
the appropriate property names.
what that says is that the model you get is the property of the model
object that is in the cpm with the name of component id.
so since your links id is foo it will try to pull out the model
object from the cpm and call getfoo() on it, the result of which is
the model object of the link
-igor
On Tue, Apr 8, 2008 at 12:52 PM, Tim Squires [EMAIL PROTECTED] wrote:
I have read it - a few times over the last 3 years of using Wicket and
even bought the book ;)
It says
To use a CompoundPropertyModel, simply set one as the model for a
container, such as a Form or a Page. Create the contained components
with
no model of their own. Insure that the component identifier names match
the appropriate property names.
The AjaxSubmitLink is picking-up the parent forms compound property
model
but only checking to see if the mylink property exists when onSubmit
calls getModelObject().
I would like to get the Forms model via getModelObject but because it
errors when called, I have to either set a false model on the
AjaxSubmitLink or get the model object outside of the onSubmit, assign
it
to a final property and then use it in the onSubmit.
I'm happy to admit that I'm doing something wrong but I cannot see what
it
is???
Thanks again,
Tim
no, components do not randomly pick up models from their parents. i
would suggest reading the models wiki page.
-igor
On Mon, Apr 7, 2008 at 3:11 PM, Tim [EMAIL PROTECTED] wrote:
Thanks Igor but should it not pick-up the model from the Form?
There's
no
constructor that takes a model. Should the AjaxSubmitLink(id,
form)
constructor be used with the Form that it's being added to? e..g
MyForm extends Form {
public MyForm(){
add( new AjaxSubmitLink(mylink,this){
});
}}
If it's already bound to a Form, should it not pick-up the model
used
by
the form?
Am I looking at the problem/solution the wrong way???
Thanks again,
Tim
you forgot to give ajaxsubmitlink a model, so getmodelobject()
will
either return null or a compound model.confirm - neither of which
i
think you want.
-igor
On Mon, Apr 7, 2008 at 1:00 PM, Tim Squires [EMAIL PROTECTED]
wrote:
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to
access
a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget
target,
final Form form) {
if (((Will) getModelObject()).getExecutor()
!=
null)
{
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget
target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this
case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined
for
class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at
org.apache.wicket.Component.getModelObject(Component.java:1551)
at
crystalmark.willfinder.page.components.EditWillPanel$EditWillForm$5.onSubmit(EditWillPanel.java:183)
at
org.apache.wicket.ajax.markup.html.form.AjaxSubmitLink$1.onSubmit(AjaxSubmitLink.java:94)
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:128)
---
It's only when using the getModelObject method. If I get the
Will
object
Re: AjaxSubmitLink accessing model object non-existent property
you can, just give the cpm reference to link as the model.
-igor
On Wed, Apr 9, 2008 at 1:31 AM, Tim Squires [EMAIL PROTECTED] wrote:
OK. It's clicked. I was hoping to have a simple ajaxed submit link
without having to create a fake property on the model object. No problem,
I can see what I missed.
Thanks for your help Igor.
Tim
you said it yourself:
Insure that the component identifier names match
the appropriate property names.
what that says is that the model you get is the property of the model
object that is in the cpm with the name of component id.
so since your links id is foo it will try to pull out the model
object from the cpm and call getfoo() on it, the result of which is
the model object of the link
-igor
On Tue, Apr 8, 2008 at 12:52 PM, Tim Squires [EMAIL PROTECTED] wrote:
I have read it - a few times over the last 3 years of using Wicket and
even bought the book ;)
It says
To use a CompoundPropertyModel, simply set one as the model for a
container, such as a Form or a Page. Create the contained components
with
no model of their own. Insure that the component identifier names match
the appropriate property names.
The AjaxSubmitLink is picking-up the parent forms compound property
model
but only checking to see if the mylink property exists when onSubmit
calls getModelObject().
I would like to get the Forms model via getModelObject but because it
errors when called, I have to either set a false model on the
AjaxSubmitLink or get the model object outside of the onSubmit, assign
it
to a final property and then use it in the onSubmit.
I'm happy to admit that I'm doing something wrong but I cannot see what
it
is???
Thanks again,
Tim
no, components do not randomly pick up models from their parents. i
would suggest reading the models wiki page.
-igor
On Mon, Apr 7, 2008 at 3:11 PM, Tim [EMAIL PROTECTED] wrote:
Thanks Igor but should it not pick-up the model from the Form?
There's
no
constructor that takes a model. Should the AjaxSubmitLink(id,
form)
constructor be used with the Form that it's being added to? e..g
MyForm extends Form {
public MyForm(){
add( new AjaxSubmitLink(mylink,this){
});
}}
If it's already bound to a Form, should it not pick-up the model
used
by
the form?
Am I looking at the problem/solution the wrong way???
Thanks again,
Tim
you forgot to give ajaxsubmitlink a model, so getmodelobject()
will
either return null or a compound model.confirm - neither of which
i
think you want.
-igor
On Mon, Apr 7, 2008 at 1:00 PM, Tim Squires [EMAIL PROTECTED]
wrote:
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to
access
a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget
target,
final Form form) {
if (((Will) getModelObject()).getExecutor()
!=
null)
{
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget
target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this
case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined
for
class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at
org.apache.wicket.Component.getModelObject(Component.java:1551)
at
Re: AjaxSubmitLink accessing model object non-existent property
I have read it - a few times over the last 3 years of using Wicket and
even bought the book ;)
It says
To use a CompoundPropertyModel, simply set one as the model for a
container, such as a Form or a Page. Create the contained components with
no model of their own. Insure that the component identifier names match
the appropriate property names.
The AjaxSubmitLink is picking-up the parent forms compound property model
but only checking to see if the mylink property exists when onSubmit
calls getModelObject().
I would like to get the Forms model via getModelObject but because it
errors when called, I have to either set a false model on the
AjaxSubmitLink or get the model object outside of the onSubmit, assign it
to a final property and then use it in the onSubmit.
I'm happy to admit that I'm doing something wrong but I cannot see what it
is???
Thanks again,
Tim
no, components do not randomly pick up models from their parents. i
would suggest reading the models wiki page.
-igor
On Mon, Apr 7, 2008 at 3:11 PM, Tim [EMAIL PROTECTED] wrote:
Thanks Igor but should it not pick-up the model from the Form? There's
no
constructor that takes a model. Should the AjaxSubmitLink(id, form)
constructor be used with the Form that it's being added to? e..g
MyForm extends Form {
public MyForm(){
add( new AjaxSubmitLink(mylink,this){
});
}}
If it's already bound to a Form, should it not pick-up the model used
by
the form?
Am I looking at the problem/solution the wrong way???
Thanks again,
Tim
you forgot to give ajaxsubmitlink a model, so getmodelobject() will
either return null or a compound model.confirm - neither of which i
think you want.
-igor
On Mon, Apr 7, 2008 at 1:00 PM, Tim Squires [EMAIL PROTECTED] wrote:
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to access
a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget target,
final Form form) {
if (((Will) getModelObject()).getExecutor() !=
null)
{
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this
case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined for
class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at
org.apache.wicket.Component.getModelObject(Component.java:1551)
at
crystalmark.willfinder.page.components.EditWillPanel$EditWillForm$5.onSubmit(EditWillPanel.java:183)
at
org.apache.wicket.ajax.markup.html.form.AjaxSubmitLink$1.onSubmit(AjaxSubmitLink.java:94)
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:128)
---
It's only when using the getModelObject method. If I get the Will
object
from else-where it works fine.
Is this a problem with the way I'm using the model or a bug with
AjaxSubmitLink? Should I add it to jira?
Wicket 1.3.3 + JDK 1.6 + Tomcat 6
Thanks,
Tim
---
http://www.tnwdb.com - Wicket Wills!
-
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For
Re: AjaxSubmitLink accessing model object non-existent property
you said it yourself:
Insure that the component identifier names match
the appropriate property names.
what that says is that the model you get is the property of the model
object that is in the cpm with the name of component id.
so since your links id is foo it will try to pull out the model
object from the cpm and call getfoo() on it, the result of which is
the model object of the link
-igor
On Tue, Apr 8, 2008 at 12:52 PM, Tim Squires [EMAIL PROTECTED] wrote:
I have read it - a few times over the last 3 years of using Wicket and
even bought the book ;)
It says
To use a CompoundPropertyModel, simply set one as the model for a
container, such as a Form or a Page. Create the contained components with
no model of their own. Insure that the component identifier names match
the appropriate property names.
The AjaxSubmitLink is picking-up the parent forms compound property model
but only checking to see if the mylink property exists when onSubmit
calls getModelObject().
I would like to get the Forms model via getModelObject but because it
errors when called, I have to either set a false model on the
AjaxSubmitLink or get the model object outside of the onSubmit, assign it
to a final property and then use it in the onSubmit.
I'm happy to admit that I'm doing something wrong but I cannot see what it
is???
Thanks again,
Tim
no, components do not randomly pick up models from their parents. i
would suggest reading the models wiki page.
-igor
On Mon, Apr 7, 2008 at 3:11 PM, Tim [EMAIL PROTECTED] wrote:
Thanks Igor but should it not pick-up the model from the Form? There's
no
constructor that takes a model. Should the AjaxSubmitLink(id, form)
constructor be used with the Form that it's being added to? e..g
MyForm extends Form {
public MyForm(){
add( new AjaxSubmitLink(mylink,this){
});
}}
If it's already bound to a Form, should it not pick-up the model used
by
the form?
Am I looking at the problem/solution the wrong way???
Thanks again,
Tim
you forgot to give ajaxsubmitlink a model, so getmodelobject() will
either return null or a compound model.confirm - neither of which i
think you want.
-igor
On Mon, Apr 7, 2008 at 1:00 PM, Tim Squires [EMAIL PROTECTED] wrote:
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to access
a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget target,
final Form form) {
if (((Will) getModelObject()).getExecutor() !=
null)
{
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this
case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined for
class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at
org.apache.wicket.Component.getModelObject(Component.java:1551)
at
crystalmark.willfinder.page.components.EditWillPanel$EditWillForm$5.onSubmit(EditWillPanel.java:183)
at
org.apache.wicket.ajax.markup.html.form.AjaxSubmitLink$1.onSubmit(AjaxSubmitLink.java:94)
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:128)
---
It's only when using the getModelObject method. If I get the Will
object
from else-where it works fine.
Is this a problem with the way I'm using the model or a bug with
AjaxSubmitLink? Should I add it to jira?
Wicket 1.3.3 + JDK 1.6 + Tomcat 6
Thanks,
Tim
AjaxSubmitLink accessing model object non-existent property
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to access a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget target,
final Form form) {
if (((Will) getModelObject()).getExecutor() != null) {
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined for class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at org.apache.wicket.Component.getModelObject(Component.java:1551)
at
crystalmark.willfinder.page.components.EditWillPanel$EditWillForm$5.onSubmit(EditWillPanel.java:183)
at
org.apache.wicket.ajax.markup.html.form.AjaxSubmitLink$1.onSubmit(AjaxSubmitLink.java:94)
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:128)
---
It's only when using the getModelObject method. If I get the Will object
from else-where it works fine.
Is this a problem with the way I'm using the model or a bug with
AjaxSubmitLink? Should I add it to jira?
Wicket 1.3.3 + JDK 1.6 + Tomcat 6
Thanks,
Tim
---
http://www.tnwdb.com - Wicket Wills!
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: AjaxSubmitLink accessing model object non-existent property
Thanks Igor but should it not pick-up the model from the Form? There's no
constructor that takes a model. Should the AjaxSubmitLink(id, form)
constructor be used with the Form that it's being added to? e..g
MyForm extends Form {
public MyForm(){
add( new AjaxSubmitLink(mylink,this){
});
}}
If it's already bound to a Form, should it not pick-up the model used by
the form?
Am I looking at the problem/solution the wrong way???
Thanks again,
Tim
you forgot to give ajaxsubmitlink a model, so getmodelobject() will
either return null or a compound model.confirm - neither of which i
think you want.
-igor
On Mon, Apr 7, 2008 at 1:00 PM, Tim Squires [EMAIL PROTECTED] wrote:
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to access a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget target,
final Form form) {
if (((Will) getModelObject()).getExecutor() != null)
{
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined for
class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at org.apache.wicket.Component.getModelObject(Component.java:1551)
at
crystalmark.willfinder.page.components.EditWillPanel$EditWillForm$5.onSubmit(EditWillPanel.java:183)
at
org.apache.wicket.ajax.markup.html.form.AjaxSubmitLink$1.onSubmit(AjaxSubmitLink.java:94)
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:128)
---
It's only when using the getModelObject method. If I get the Will
object
from else-where it works fine.
Is this a problem with the way I'm using the model or a bug with
AjaxSubmitLink? Should I add it to jira?
Wicket 1.3.3 + JDK 1.6 + Tomcat 6
Thanks,
Tim
---
http://www.tnwdb.com - Wicket Wills!
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: AjaxSubmitLink accessing model object non-existent property
no, components do not randomly pick up models from their parents. i
would suggest reading the models wiki page.
-igor
On Mon, Apr 7, 2008 at 3:11 PM, Tim [EMAIL PROTECTED] wrote:
Thanks Igor but should it not pick-up the model from the Form? There's no
constructor that takes a model. Should the AjaxSubmitLink(id, form)
constructor be used with the Form that it's being added to? e..g
MyForm extends Form {
public MyForm(){
add( new AjaxSubmitLink(mylink,this){
});
}}
If it's already bound to a Form, should it not pick-up the model used by
the form?
Am I looking at the problem/solution the wrong way???
Thanks again,
Tim
you forgot to give ajaxsubmitlink a model, so getmodelobject() will
either return null or a compound model.confirm - neither of which i
think you want.
-igor
On Mon, Apr 7, 2008 at 1:00 PM, Tim Squires [EMAIL PROTECTED] wrote:
Hi,
When adding an AjaxSubmitLink, the onSubmit method tries to access a
property of the model object that does not exists:
---
final AjaxSubmitLink confirmLink = new
AjaxSubmitLink(confirm) {
@Override
public void onSubmit(final AjaxRequestTarget target,
final Form form) {
if (((Will) getModelObject()).getExecutor() != null)
{
willModalWindow.show(target);
} else {
warn(Please choose an executor.);
target.addComponent(feedback);
}
}
@Override
public void onError(final AjaxRequestTarget target,
final Form form) {
target.addComponent(feedback);
}
};
add(confirmLink);
---
It tries to access the confirm property of the Model, in this case a
Will object.
---
org.apache.wicket.WicketRuntimeException: No get method defined for
class:
class crystalmark.willfinder.model.Will expression: confirm
at
org.apache.wicket.util.lang.PropertyResolver.getGetAndSetter(PropertyResolver.java:433)
at
org.apache.wicket.util.lang.PropertyResolver.getObjectAndGetSetter(PropertyResolver.java:275)
at
org.apache.wicket.util.lang.PropertyResolver.getValue(PropertyResolver.java:84)
at
org.apache.wicket.model.AbstractPropertyModel.getObject(AbstractPropertyModel.java:113)
at org.apache.wicket.Component.getModelObject(Component.java:1551)
at
crystalmark.willfinder.page.components.EditWillPanel$EditWillForm$5.onSubmit(EditWillPanel.java:183)
at
org.apache.wicket.ajax.markup.html.form.AjaxSubmitLink$1.onSubmit(AjaxSubmitLink.java:94)
at
org.apache.wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(AjaxFormSubmitBehavior.java:128)
---
It's only when using the getModelObject method. If I get the Will
object
from else-where it works fine.
Is this a problem with the way I'm using the model or a bug with
AjaxSubmitLink? Should I add it to jira?
Wicket 1.3.3 + JDK 1.6 + Tomcat 6
Thanks,
Tim
---
http://www.tnwdb.com - Wicket Wills!
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
