Re: How to make a popup page for exception handling?
Hi my wicket friends,
There is fast way to make the popup for exception handling:
try {
...
}
catch (Exception e){
target.appendJavascript(String.format(alert('%s'),
e));
}
and AjaxSubmitLink is used.
-Mo Wu
Michael O'Cleirigh wrote:
Hi Mo,
I tried them, I can generate the modal Window. but the AjaxLink is not
submit
link for a form. I need to show the error message only if there is form
processing error.
Should I use AjaxSubmitLink instead? or do you have some examples similar
to
this condition?
If the alerts you want to show are tied to the existence of form
processing errors then prehaps you should subclass FeedbackPanel to add
in a javascript popup alert in addition to/replacing the standard
behavior of displaying the form errors in an unordered list?
Or you could create a panel consisting of the modal window and the
activation link but tied to the existence of feedback messages. If
there are zero feedback messages (the form not submitted yet case) you
can have the panel invisible to start with (i.e. the link would not be
there or say something like 'No Errors'). When there are errors present
the link would be visible (or say something link 'There are X errors')
clicking the link would show the modal window with the errors.
Normally feedback messages are expected to be consumed by the feedback
panels during the rendering phase so they are cleared at the end of the
form submission request; you might have to cache it somewhere so that
the modal window will have the data available it since it populates
itself via an ajax update after the form submitting request that
generated the errors has already finished.
Regards,
Mike
cheers, :)
Mo
Newgro wrote:
Fkleinko wrote:
To show the ModalWindow you need an AjaxRequestTarget.
where do you get that from?
AjaxLink theLinkThatWillShowTheModalWindowIfItsClicked = new
AjaxLink(...)
{
public void onClick(AjaxRequestTarget target) {
myModalWindow.show(target);
}
}
Please check the examples i gave you. It's all there.
Cheers
Per
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Re: How to make a popup page for exception handling?
what is the type of the errorWindow? Is the errorWindow a new page or a part
of the existing page?
Best regards,
Mo
Newgro wrote:
I know how to show the exception in a feedback panel. But how to make the
popup dependent on the results of submission
You could add the errorWindow to your page and in your catch you can
show it. But it's only working with ajax.
add errorWindow to markup and in class.
try {
exceptionalCode();
} catch (TheExpectedException e) {
errorWindow.setModel(new Model(e));
errorWindow.show();
}
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Re: How to make a popup page for exception handling?
Its a ModalWindow. Sorry for being unclear here. Check this for usage http://www.wicket-library.com/wicket-examples/ajax/modal-window.1 http://www.wicket-library.com/wicket-examples/ajax/modal-window.1 There you can find the sources (right upper corner) on howto use it with page in it and so on. HTH Per -- View this message in context: http://www.nabble.com/How-to-make-a-popup-page-for-exception-handling--tp21588129p21601120.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: How to make a popup page for exception handling?
To show the ModalWindow you need an AjaxRequestTarget. where do you get that from? Newgro wrote: Its a ModalWindow. Sorry for being unclear here. Check this for usage http://www.wicket-library.com/wicket-examples/ajax/modal-window.1 http://www.wicket-library.com/wicket-examples/ajax/modal-window.1 There you can find the sources (right upper corner) on howto use it with page in it and so on. HTH Per -- View this message in context: http://www.nabble.com/How-to-make-a-popup-page-for-exception-handling--tp21588129p21604441.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: How to make a popup page for exception handling?
Fkleinko wrote:
To show the ModalWindow you need an AjaxRequestTarget.
where do you get that from?
AjaxLink theLinkThatWillShowTheModalWindowIfItsClicked = new AjaxLink(...) {
public void onClick(AjaxRequestTarget target) {
myModalWindow.show(target);
}
}
Please check the examples i gave you. It's all there.
Cheers
Per
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Re: How to make a popup page for exception handling?
I tried them, I can generate the modal Window. but the AjaxLink is not submit
link for a form. I need to show the error message only if there is form
processing error.
Should I use AjaxSubmitLink instead? or do you have some examples similar to
this condition?
cheers, :)
Mo
Newgro wrote:
Fkleinko wrote:
To show the ModalWindow you need an AjaxRequestTarget.
where do you get that from?
AjaxLink theLinkThatWillShowTheModalWindowIfItsClicked = new AjaxLink(...)
{
public void onClick(AjaxRequestTarget target) {
myModalWindow.show(target);
}
}
Please check the examples i gave you. It's all there.
Cheers
Per
--
View this message in context:
http://www.nabble.com/How-to-make-a-popup-page-for-exception-handling--tp21588129p21605575.html
Sent from the Wicket - User mailing list archive at Nabble.com.
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Re: How to make a popup page for exception handling?
Hi Mo,
I tried them, I can generate the modal Window. but the AjaxLink is not submit
link for a form. I need to show the error message only if there is form
processing error.
Should I use AjaxSubmitLink instead? or do you have some examples similar to
this condition?
If the alerts you want to show are tied to the existence of form
processing errors then prehaps you should subclass FeedbackPanel to add
in a javascript popup alert in addition to/replacing the standard
behavior of displaying the form errors in an unordered list?
Or you could create a panel consisting of the modal window and the
activation link but tied to the existence of feedback messages. If
there are zero feedback messages (the form not submitted yet case) you
can have the panel invisible to start with (i.e. the link would not be
there or say something like 'No Errors'). When there are errors present
the link would be visible (or say something link 'There are X errors')
clicking the link would show the modal window with the errors.
Normally feedback messages are expected to be consumed by the feedback
panels during the rendering phase so they are cleared at the end of the
form submission request; you might have to cache it somewhere so that
the modal window will have the data available it since it populates
itself via an ajax update after the form submitting request that
generated the errors has already finished.
Regards,
Mike
cheers, :)
Mo
Newgro wrote:
Fkleinko wrote:
To show the ModalWindow you need an AjaxRequestTarget.
where do you get that from?
AjaxLink theLinkThatWillShowTheModalWindowIfItsClicked = new AjaxLink(...)
{
public void onClick(AjaxRequestTarget target) {
myModalWindow.show(target);
}
}
Please check the examples i gave you. It's all there.
Cheers
Per
How to make a popup page for exception handling?
Dear experts, I have one feature to be implemented, but I dont know how to do that: I have one page, there is a form need to be submitted. after submitted, 1. If the results is correct, then the same page is returned. 2. if there are some exceptions, then a popup need to be shown up and it should also show the errorMessage. I know how to show the exception in a feedback panel. But how to make the popup dependent on the results of submission. Thanks for help! Best regards, Mo -- View this message in context: http://www.nabble.com/How-to-make-a-popup-page-for-exception-handling--tp21588129p21588129.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: How to make a popup page for exception handling?
I know how to show the exception in a feedback panel. But how to make the
popup dependent on the results of submission
You could add the errorWindow to your page and in your catch you can
show it. But it's only working with ajax.
add errorWindow to markup and in class.
try {
exceptionalCode();
} catch (TheExpectedException e) {
errorWindow.setModel(new Model(e));
errorWindow.show();
}
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
