Re: [Vo]: Why did the engineer Rossi beat all the scientists? WAS: Rossi bets the farm on Ni62?

[mixent]

In reply to  Charles Hope's message of Fri, 20 May 2011 01:01:11 -0400:
Hi,
[snip]
>Is there anyone who believes Mills' hydrino theory who also understands 
>quantum mechanics?

Yes, Mills. :)

(Actually he's not the only one, there are probably quite a few, but far less
that would go out on a limb and admit it.) 
Personally I think QM is the norm, and Mills is an allowed exception, which
means that it happens some of the time.
[snip]
Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html

Re: [Vo]: Why did the engineer Rossi beat all the scientists? WAS: Rossi bets the farm on Ni62?

[Charles Hope]

Is there anyone who believes Mills' hydrino theory who also understands quantum 
mechanics?

Sent from my iPhone. 

On May 15, 2011, at 16:08, "Mark Iverson"  wrote:

> I renamed this thread cuz I'd like to hear opinions as to WHY an engineer 
> succeeded where ALL the scientists failed in optimizing the excess heat and 
> controllability of whatever this reaction is???
>  
> In our conversation about Mills/BLP, Peter wrote:
> "His theory is OK, verified by experiment."
>  
> But an 'engineer' (i.e., someone not real knowledgeable about theoretical 
> foundations) optimized the excess heat effect and controllability of the 
> reaction in only a few years and with very little money compared to BLP (20 
> years and $60M)...
>  
> So either Mills' theory has serious errors or holes, or they have incompetent 
> scientists/engineering managers who are making  bad decisions as to what 
> tests/experiments to do, thus wasting alot of time and not achieving true 
> UNDERSTANDING of what variables affect the reaction.
>  
> If Mills' theories were accurate, then optimizing/manipulating the reaction 
> mechanisms would have happened by now... and they would have beat Rossi to 
> the market.  What's more likely is that the conclusions that come out of 
> Mills' theories have caused them to go down numerous 'dead-ends'... and 
> Mills' ego refuses to acknowledge that his theory needs some serious  
> revisions.
> -Mark
> 
> 
> From: Peter Gluck [mailto:peter.gl...@gmail.com] 
> Sent: Saturday, May 14, 2011 11:43 PM
> To: vortex-l@eskimo.com
> Subject: Re: EXTERNAL: Re: [Vo]:Rossi bets the farm on Ni62?
> 
> The reason is, in my opinion, that is very difficult to achieve
> a CONTINUOUS generation of energy- see my paper 
> http://egooutpeters.blogspot.com/2011/04/questions-preparing-swot-analysis-of-ni.html
>  what conditions are necessary for a new source of energy.
> 
> But I think this year (good for new energy, it seems) Randy will be on the 
> market with his CIHT technology.
> His theory is OK, verified by experiment. Technology is more difficult than 
> scientific experiments.
> Peter
> 
> 
> On Sun, May 15, 2011 at 9:15 AM, Mark Iverson  wrote:
> I would wager that the reason Mills hasn't got a commercial device, after 20 
> years and $60M, is because his theory is flawed...
> -Mark
> 
> 
> From: Peter Gluck [mailto:peter.gl...@gmail.com] 
> Sent: Saturday, May 14, 2011 9:46 PM
> 
> To: vortex-l@eskimo.com
> Subject: Re: EXTERNAL: Re: [Vo]:Rossi bets the farm on Ni62?
> 
> Perhaps the best person to discuss your hydrino ideas is Randy Mills himself. 
>  
> 
> 
> 
> -- 
> Dr. Peter Gluck
> Cluj, Romania
> http://egooutpeters.blogspot.com
> 

Re: [Vo]:Revised and extended Rydburg ion conjecture

[Axil Axil]

Nano-defects are very tough. This toughness and associated resistance to
melting and stress is conducive to the production of high pressure inside
defect.



The smaller the dimensions of the lattice surface defect, the greater is the
multiplier on the hardness and the resistance to stress compared to the bulk
material.  These multiplier factors can range from 3 to 10 based on the
properties of the bulk material.



Multilayer sites that penetrate down through many lattice layers are more
resilient than surface defects. There toughness is proportional to the
detailed topology and therefore not generally determined.



There is a certain minimum size which one reached reduces the hardness of
the nano-defect site. This size is on the order of less than 10 nanometers.


On Thu, May 19, 2011 at 11:01 PM,  wrote:

> In reply to  Axil Axil's message of Thu, 19 May 2011 18:13:48 -0400:
> Hi,
> [snip]
> >These atomic CN imperfections induce bond contraction and the associated
> >bond-strength gain deepens the potential well of the trapping in the
> surface
> >skin.
>
> By how much?
>
> >This CN reduction also produces an increase of charge density, energy,
> >and mass of the enclosed hydrogen contained in the relaxed surface skin
> >imperfection.
>
> How much density increase, and do you still think that would also happen
> with
> H-?
>
> Regards,
>
> Robin van Spaandonk
>
> http://rvanspaa.freehostia.com/project.html
>
>

Re: [Vo]:Revised and extended Rydburg ion conjecture

[mixent]

In reply to  Axil Axil's message of Thu, 19 May 2011 18:13:48 -0400:
Hi,
[snip]
>These atomic CN imperfections induce bond contraction and the associated
>bond-strength gain deepens the potential well of the trapping in the surface
>skin. 

By how much?

>This CN reduction also produces an increase of charge density, energy,
>and mass of the enclosed hydrogen contained in the relaxed surface skin
>imperfection. 

How much density increase, and do you still think that would also happen with
H-? 

Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html

Re: [Vo]:Revised and extended Rydberg ion conjecture

[Axil Axil]

A much denser state exists for deuterium, named D(-1). It is called
ultra-dense deuterium. This is the inverse of D(1), and the bond distance is
very small, equal to 2.3 pm (0.023 angstroms). Its density is extremely
large, >130 kg / cm3 (130,000 times as dense as water), if it can exist as a
dense phase. Due to the short bond distance, D-D fusion is expected to take
place easily in this material.


This material is probably an inverted metal with the deuterons moving in the
field from the stationary electrons. This reduces the size of the atom
because the heavy nucleus orbits the light electron. This gives a predicted
interatomic distance of 2.5 pm, close to the measured value. Experiments
show that an ultra-dense deuterium material exists.



I have not heard of inverted hydrogen H(-1), but if it existed a lot of it
could fix inside a lattice defect.



I wonder if this H(-1) nuclear configuration would reverse the catalytic
charge considerations.








On Thu, May 19, 2011 at 9:51 AM, Jones Beene  wrote:

> Holmlid's Inverted Rydberg hydrogen in not an ion, per se. But to answer
> Robin's question, the "decrease in volume" would be the end-game event
> which
> destroys the 2D form, allowing ZPE coherence.
>
> BTW - Out of respect to a famous scientist, Rydberg's name should be
> spelled
> correctly (and as a notoriously bad speller, I appreciate the extra effort
> to get names spelled correctly, especially in the Subject heading).
>
> According to my understanding of Holmlid, Miley, Lawandy, etc. "spillover
> hydrogen" can collect in two dimensions ONLY on a dielectric surface in the
> form of protons with mirror charge. The balancing negative charge is "in"
> the dielectric itself, and the protons are essentially bare on the surface
> of the dielectric held there by electrostatic forces.
>
> The thickness of a single proton is considered to make the "snowflake"
> 6-fold symmetry flat structure stable in two dimensions, but no further
> thickness is permitted.
>
> This 2D structure can probably contort into an open ended "pit" near the
> surface but because it is 2D it would seem unlikely to be transported into
> a
> subsurface cavity as the 'charge balancing' would be difficult to imagine
> and it would gain dimensionality. A "Casimir Pit" has advantages over a
> cavity since it allows unimpeded acceleration out of the open end.
>
> Jones
>
> -Original Message-
> From: Robin
>
> >> Axil: During the fusion process as the pressure within the shrinking
> lattice defect increases, the electrons circulating in the Rydberg ion are
> heated by increasing rates of subatomic collisions in an ever shrinking
> volume.
>
> > What causes the decrease in volume?
>
>
>
>

Re: [Vo]:Revised and extended Rydburg ion conjecture

[Axil Axil]

When a metal lattice is hot, three dimensional quantized vibrations travel
through its volume. These vibrations are called Phonons. The distances
between the atoms in the lattice increase and decrease in proportion to the
heat applied to the Lattice.



When there is a lattice defect on the surface of a lattice. The coordination
number (CN) of the atoms that form the defect decreases. This increases the
strength of the remaining bonds of the nickel atoms on the exterior walls of
the defect.



These atomic CN imperfections induce bond contraction and the associated
bond-strength gain deepens the potential well of the trapping in the surface
skin. This CN reduction also produces an increase of charge density, energy,
and mass of the enclosed hydrogen contained in the relaxed surface skin
imperfection. This increased density is far higher than it normally would be
at other sites inside the solid.



Because of this energy densification, surface stress that is in the
dimension of energy density will increase in the relaxed region.



When the phonons wave breaks upon the surface imperfection, it is amplified
by the abrupt discontinuity is the lattice and concentrated by the increased
bond-order-length-strength (BOLS) of the nickel atoms that form the walls of
the cavity.



This Phonons amplification mechanism is one big advantage provided by the
tightly coupled thermodynamic adhesion of the nano-powder to the stainless
steel walls of the reaction vessel.



This tight coupling allows the thermodynamic feed back mechanism to control
and mediate the reaction. It also amplifies and focuses the compressive
effects that phonons have on the hydrogen contained in the lattice defects.





On Wed, May 18, 2011 at 11:58 PM,  wrote:

> In reply to  Axil Axil's message of Wed, 18 May 2011 22:03:20 -0400:
> Hi,
> [snip]
> >During the fusion process as the pressure within the shrinking lattice
> >defect increases, the electrons circulating in the Rydburg ion are heated
> by
> >increasing rates of subatomic collisions in an ever shrinking volume.
>
> What causes the decrease in volume?
>
> Regards,
>
> Robin van Spaandonk
>
> http://rvanspaa.freehostia.com/project.html
>
>

Re: [Vo]:Rossi: NO MORE TESTS and other stuff

[Alan J Fletcher]

Markku Pöysti 

May 19th, 2011 at 6:52 AM 
Does the reaction stop if temperature rises to Ni melting temp? This is
rather important safety point, ie. is china syndrome possible?
Andrea Rossi 

May 19th, 2011 at 1:30 PM 
Dear Mr Markku Poysti:
If Ni melts the E-Cat stops. It works only with powders. This makes it
intrinsecally safe. And do not forget that we do not leave radioactive
material, we do not use radioactive material .
Warm regards,
A.R.

[Vo]:A couple of interesting items from Science Daily

[Ron Wormus]

Re: [Vo]:Invitation to connect on LinkedIn

[Craig Haynie]

This is a mistake. I apologize for the interruption.

Craig

[Vo]:Invitation to connect on LinkedIn

[Carlton Haynie via LinkedIn]

LinkedIn
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--

michael,

I'd like to add you to my professional network on LinkedIn.

- Carlton

Accept invitation from Carlton Haynie
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[Vo]:Parahydrogen & Nuclear Magnetic Resonance With No Magnets

[Roarty, Francis X]

A  related field? http://www.sciencedaily.com/releases/2011/05/110518131431.htm


Parahydrogen can be enhanced to 50 percent or even 100 percent using very low 
temperatures, although the right catalyst must be added or the conversion could 
take days if not weeks. Then, by chemically reacting spin-zero parahydrogen 
molecules with an initial chemical, net polarization of the product of the 
hydrogenation may end up highly polarized. This hyperpolarization can be 
extended not only to the parts of the molecule directly reacting with the 
hydrogen, but even to the far corners of large molecules

RE: [Vo]:Revised and extended Rydberg ion conjecture

[Jones Beene]

Holmlid's Inverted Rydberg hydrogen in not an ion, per se. But to answer
Robin's question, the "decrease in volume" would be the end-game event which
destroys the 2D form, allowing ZPE coherence.

BTW - Out of respect to a famous scientist, Rydberg's name should be spelled
correctly (and as a notoriously bad speller, I appreciate the extra effort
to get names spelled correctly, especially in the Subject heading).

According to my understanding of Holmlid, Miley, Lawandy, etc. "spillover
hydrogen" can collect in two dimensions ONLY on a dielectric surface in the
form of protons with mirror charge. The balancing negative charge is "in"
the dielectric itself, and the protons are essentially bare on the surface
of the dielectric held there by electrostatic forces. 

The thickness of a single proton is considered to make the "snowflake"
6-fold symmetry flat structure stable in two dimensions, but no further
thickness is permitted.

This 2D structure can probably contort into an open ended "pit" near the
surface but because it is 2D it would seem unlikely to be transported into a
subsurface cavity as the 'charge balancing' would be difficult to imagine
and it would gain dimensionality. A "Casimir Pit" has advantages over a
cavity since it allows unimpeded acceleration out of the open end.

Jones

-Original Message-
From: Robin

>> Axil: During the fusion process as the pressure within the shrinking
lattice defect increases, the electrons circulating in the Rydberg ion are
heated by increasing rates of subatomic collisions in an ever shrinking
volume. 

> What causes the decrease in volume?



<>

[Vo]:Temperature regulation mechanism.

[Roarty, Francis X]

On Wed, 18 May 2011 09:27:19 Axil wrote
High temperature is required to provide a vibrative movement in the walls of
the erosive cavities formed on the surface of the nickel oxide nano-powder
that are the epicenter of nuclear activity.

Reply- I would suggest vibration movement is actually change in Casimir force/ 
catalytic action - jerk like that which shears electrolytic capacitors out of 
their soldered positions in a voltage filter when tested on a vibration table.
/Reply

These holes both open wide to allow the Rydburg hydrogen condensate crystals
to enter and constricted to compress them to the state of fusion. The
temperature of the metal lattice might well provide a gate keeping function
that regulates the flow of ions into the locus of the nuclear reaction.

Reply  I would argue that the change in Casimir force/energy density is the 
cause of this Inverse Rydberg condition and that the "condensate" is a 
relativistic perspective which has an opposing perspective from within the wall 
of the corrosive cavities that you mention - that opposing perspective sees the 
walls of the cavities shrinking away into the distance making more and more 
room for additional inverse Rydberg atoms of even smaller inverse proportions 
up to 1/137 according to Bourgoin.
/Reply

A minimum temperature of the metal lattice is required to allow the smallest
sized ions to enter the reaction zone. As the temperature rises and the
mouths of the holes open wider, ever larger sized ions would be capable of
participating in the reaction.

Reply- I can't argue the ion chemistry, Mill's and others seem convinced a 3 
body reaction is necessary but personally prefer a Moller like oscillation 
between h1&H2 facilitated by change in energy density that discounts the 
disassociation - IMHO the hydride reactions are the less desirable reactions 
that slowly poison the cavities while H2<>H1 facilitated by "jerk" and PWM can 
go on forever. You also mention a minimum temperature to include the smallest 
inverse Rydberg atoms in the reaction zone - If I am correct about the 
relativistic nature of these cavities than temperature becomes a difficult 
metric because these different Rydberg "levels" are all essentially different 
inertial frames and the math would be impractical to determine the actual local 
temperature. I am not implying that the huge number of reactions are simply due 
to dilation effects but rather the abrupt increases and decreases in t' is 
discounting the disassociation levels required. /Reply


I would speculate that at low temperatures in the metal lattice only small
sized ions would enter and very light weight ash elements would be produced.
As the average temperature rises the ash content would favor the heavier
elements.

Reply- I don't have the skill set to speak to the nuclear paths but am 
convinced that a Chemical/ZPE/relativistic environment is the necessary 
precursor and that the nuclear reactions are not enabled until after some 
threshold level of energy is first derived.

Regards
Fran