RE: [Vo]:Fractional Hydrogen without Mills - Mathcad - table.pdf
-Original Message- From: mix...@bigpond.com Guessing that the observed value might match a different transition, I created a little table for p = 120-136 ...As you can see, p=132-133 is a good match Interesting. Nothing obvious pops up at first glance - as to why this 132/133 level would be favored for dark matter. However, reading up on x-ray spectra in this energy range, there is almost nothing else in physics known to have much relevance. So we can relegate this datum into the archive and maybe something pops up in a few months or years ...
Re: [Vo]:Fractional Hydrogen without Mills - Mathcad - table.pdf
In reply to Jones Beene's message of Sat, 4 Jul 2015 19:47:40 -0700: Hi Jones, [snip] Ok, I found the reason. It lies in the disproportionation reactions. If you start with a mixture of p = 16 p = 4, you get:- (16^2)/2 + 4 = 132. (Formula derivation available on request). Note that water molecules are an m=3 catalyst, so interstellar water molecules reacting with Hydrogen atoms will create p = 4 hydrinos in a single reaction. This provides a relatively large population of p = 4 hydrinos. p = 16 is special because the Hydrinohydride for p = 16, has the highest binding energy for the second electron (70 eV), so obviously this hydride is going to be the most stable, which means that as hydrinos shrink, they will tend to get stuck at this level, and thus p=16 hydrinos will accumulate (as the hydride). This provides a large population of p = 16 hydrinos. When members of both populations mix, you get p=132 hydrinos. -Original Message- From: mix...@bigpond.com Guessing that the observed value might match a different transition, I created a little table for p = 120-136 ...As you can see, p=132-133 is a good match Interesting. Nothing obvious pops up at first glance - as to why this 132/133 level would be favored for dark matter. However, reading up on x-ray spectra in this energy range, there is almost nothing else in physics known to have much relevance. So we can relegate this datum into the archive and maybe something pops up in a few months or years ... Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Fractional Hydrogen without Mills - Mathcad - table.pdf
In reply to mix...@bigpond.com's message of Sun, 05 Jul 2015 13:38:34 +1000: Hi, BTW, I would guess that Hydrinos in this size category may not last long, as they would probably undergo nuclear reactions fairly readily (unless well separated from other matter), thus the spectral line seen is probably from freshly made Hydrinos. IOW this may not be a dark matter signal after all. However, on the upside, it may explain LENR quite nicely. ;) In reply to Jones Beene's message of Sat, 4 Jul 2015 19:47:40 -0700: Hi Jones, [snip] Ok, I found the reason. It lies in the disproportionation reactions. If you start with a mixture of p = 16 p = 4, you get:- (16^2)/2 + 4 = 132. (Formula derivation available on request). Note that water molecules are an m=3 catalyst, so interstellar water molecules reacting with Hydrogen atoms will create p = 4 hydrinos in a single reaction. This provides a relatively large population of p = 4 hydrinos. p = 16 is special because the Hydrinohydride for p = 16, has the highest binding energy for the second electron (70 eV), so obviously this hydride is going to be the most stable, which means that as hydrinos shrink, they will tend to get stuck at this level, and thus p=16 hydrinos will accumulate (as the hydride). This provides a large population of p = 16 hydrinos. When members of both populations mix, you get p=132 hydrinos. [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Fractional Hydrogen without Mills - Mathcad - table.pdf
In reply to Jones Beene's message of Sat, 4 Jul 2015 16:54:51 -0700: Hi Jones, Actually it should be 13.598, rather than 13.6, and for a transition from 136 to 137 a catalyst with m=1 is required, which absorbs 27.2 eV first, so the actual amount remaining to be emitted as a photon would be 3658 eV. Guessing that the observed value might match a different transition, I created a little table (attached) for p = 120-136 (i.e. transitions from 120-121; 121-122; 122-123 etc.). As you can see, p=132-133 is a good match for the value you supply. (Formula is (2p-3)*13.598. This takes into account the 27.2 eV for the catalyst.) BTW a catalyst of 27.2 eV could comprise two hydrogen atoms, in a three particle collision. Perhaps not so rare as you might think, if a fast Hydrino were to impact a Hydrogen molecule, splitting the molecule into two atoms, which then catalyze the shrinkage reaction while still in the proximity of the Hydrino. Robin, Yes this Rydberg calculation is close, but probably not close enough. Red shift could change that assessment and make it exact. As you know, Mills addressed this issue years ago (that dark matter is composed of hydrinos) and he concocted a formula that unfortunately provides a value which is also close, but not even as exact as this one. I do not have that reference handy but it is in the archives. Mills should have waited to see the exact observed value - as now he looks a bit foolish. 3.55 keV to 3.56 keV is the dark matter signal which is seen from satellites in earth orbit and is verified by dozens of cosmologists and Universities nowadays. Any theory that explains dark matter should be able to account for this exact value. Since 95% of observable matter is hydrogen, it is a good bet that dark matter is hydrogen in another form - but of course, it could be something else entirely and there are a few candidates but none are as convincing as dense hydrogen. -Original Message- From: mix...@bigpond.com In reply to Jones Beene's message: Hi, For Mills, the difference between any two adjacent states is (2p-1)*13.6 eV where p is the smaller of the two numbers. Thus the difference between 136 137 would be: ((2*136)-1)*13.6 eV = 3686 eV. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html Mathcad - table.pdf Description: Binary data
