In reply to Jones Beene's message of Sat, 4 Jul 2015 16:54:51 -0700: Hi Jones,
Actually it should be 13.598, rather than 13.6, and for a transition from 136 to 137 a catalyst with m=1 is required, which absorbs 27.2 eV first, so the actual amount remaining to be emitted as a photon would be 3658 eV. Guessing that the observed value might match a different transition, I created a little table (attached) for p = 120-136 (i.e. transitions from 120->121; 121->122; 122->123 etc.). As you can see, p=132->133 is a good match for the value you supply. (Formula is (2p-3)*13.598. This takes into account the 27.2 eV for the catalyst.) BTW a catalyst of 27.2 eV could comprise two hydrogen atoms, in a three particle collision. Perhaps not so rare as you might think, if a fast Hydrino were to impact a Hydrogen molecule, splitting the molecule into two atoms, which then catalyze the shrinkage reaction while still in the proximity of the Hydrino. >Robin, > >Yes this Rydberg calculation is close, but probably not close enough. Red >shift could change that assessment and make it exact. > >As you know, Mills addressed this issue years ago (that dark matter is >composed of hydrinos) and he concocted a formula that unfortunately provides >a value which is also close, but not even as exact as this one. I do not >have that reference handy but it is in the archives. Mills should have >waited to see the exact observed value - as now he looks a bit foolish. > >3.55 keV to 3.56 keV is the dark matter signal which is seen from satellites >in earth orbit and is verified by dozens of cosmologists and Universities >nowadays. Any theory that explains dark matter should be able to account for >this exact value. > >Since 95% of observable matter is hydrogen, it is a good bet that dark >matter is hydrogen in another form - but of course, it could be something >else entirely and there are a few candidates but none are as convincing as >dense hydrogen. > >-----Original Message----- >From: mix...@bigpond.com >In reply to Jones Beene's message: >Hi, > >For Mills, the difference between any two adjacent states is (2p-1)*13.6 eV >where p is the smaller of the two numbers. > >Thus the difference between 136 & 137 would be: > >((2*136)-1)*13.6 eV = 3686 eV. > >Regards, > >Robin van Spaandonk > >http://rvanspaa.freehostia.com/project.html Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Mathcad - table.pdf
Description: Binary data
