[web2py] Re: Beginner question: foreign key constraint failed (?)
On Thursday, March 27, 2014 5:21:34 PM UTC+1, Niphlod wrote: did you try with a fresh database ? After some investigation, it seems that the problem is not related to what I wrote above (!) I tried to change the DB - to MySQL - and the error reported changed to something like 'attribute first_name not found'. From this I managed to understand what happens. In fact, the 'company' table is redefining auth_user table. However, it seems that (contrary to the documentation) the 'first_name' field is needed by the default implementation of the NavBar. And hence the error. It is weird that SQLite reports it as foreign constraint failed... Or maybe indeed there was something wrong with the SQLite database in the first place... Anyway... The conclusion is - the code I gave above actually works. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Beginner question: foreign key constraint failed (?)
Just an update. It appears to be an issue with SQLITE. The actual problem was related to the fact that I have redefined AUTH_USER table (by company table - not all of it quated in my post). I had a missing field used in the default NavBar - first_name. When I switched from SQLITE to MYSQL, the error message was more informative - somthing about missing attribute 'first_name'. This led in turn to discovering that in fact the 'first_name' is kind of required field when redefining the AUTH_USER table, even though the documentation does not say so Hope it will help others. BTW: The error message from SQLITE could be improved... -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Beginner question: foreign key constraint failed (?)
did you try with a fresh database ?
On Thursday, March 27, 2014 3:18:07 PM UTC+1, Krzysztof Socha wrote:
I created a simple table that uses another table as a list of possible
values for a field:
db.define_table('country',
Field('name','string',length=DEFAULT_STRING_LENGTH))
db.define_table('company',
Field('name', 'string',
requires=IS_NOT_EMPTY(error_message=auth.messages.is_empty)),
Field('address', 'string',
Field('country','reference country',
requires=IS_IN_DB(db,db.country.id)))
This is all very simplistic, and I just want to have the ID in the
dropdown (later to be replaced by something like 'represent=
db.country.name(db.country.id))', but it does not work as it is...
The form shows up, I need to put something in the NAME field and choose
something for the COUNTRY field - otherwise the validators complain - but
aftwerwords I systematically get:
class 'sqlite3.IntegrityError' foreign key constraint failed
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