Re: [web2py] Reading a text file after uploading in a form
where can I download the 'reports' module? I am getting error while calling
that module.
On Thu, Nov 1, 2012 at 1:12 PM, Jim S wrote:
> This is working for me. I have a similar requirement. Select a text file
> to be processed and pass it to a separate routine to process the file:
>
> form = SQLFORM.factory(
> Field('brillXf1', 'upload',
> uploadfolder=os.path.join(request.folder,'uploads'),
> label='Brill XF1 File'))
>
> if form.process().accepted:
> fileName = form.vars.brillXf1
> print fileName
> from reports import brillToDalex as btd
> btd.process('%s/%s' % (os.path.join(request.folder,'uploads'), fileName),
> 1)
> redirect(URL('nutrientConversion'))
> response.flash('File has been uploaded and email will be sent with
> results')
>
>
> The form field only returns the file name. You have to specify the path
> to it if you are going to use it later as seen in this statement:
>
> btd.process('%s/%s' % (os.path.join(request.folder,'uploads'), fileName),
> 1)
>
> -Jim
>
>
> On Thursday, November 1, 2012 3:33:50 AM UTC-5, praveen krishna wrote:
>
>> Nol there is no such requirement.Actually I am able to upload and read a
>> text file by zipping it but for my task I have upload a text file .
>>
>> On Thu, Nov 1, 2012 at 7:24 AM, Johann Spies wrote:
>>
>> On 31 October 2012 17:45, praveen krishna wrote:
>>>
Hi,
For my task I have to upload a text file in form with out zipping it
,I have prepared the form as:
form = FORM(TABLE(TR(TD('Upload File:', INPUT(_type='file',
name='myfile', id='myfile',
requires=IS_NOT_EMPTY(,TR(TD(INPUT(_type='submit',_value='Submit')
But I unable to read the file how could it be possible without using
ZipFile.
>>>
>>> You refer to 'zip' twice. Why? Is there a requirement that it should
>>> be zipped somewhere?
>>>
>>> Regards
>>> Johann
>>> --
>>> Because experiencing your loyal love is better than life itself,
>>> my lips will praise you. (Psalm 63:3)
>>>
>>> --
>>>
>>>
>>>
>>>
>>
>> --
>
>
>
>
--
Re: [web2py] Reading a text file after uploading in a form
This is working for me. I have a similar requirement. Select a text file to
be processed and pass it to a separate routine to process the file:
form = SQLFORM.factory(
Field('brillXf1', 'upload',
uploadfolder=os.path.join(request.folder,'uploads'),
label='Brill XF1 File'))
if form.process().accepted:
fileName = form.vars.brillXf1
print fileName
from reports import brillToDalex as btd
btd.process('%s/%s' % (os.path.join(request.folder,'uploads'), fileName), 1
)
redirect(URL('nutrientConversion'))
response.flash('File has been uploaded and email will be sent with results'
)
The form field only returns the file name. You have to specify the path to
it if you are going to use it later as seen in this statement:
btd.process('%s/%s' % (os.path.join(request.folder,'uploads'), fileName), 1)
-Jim
On Thursday, November 1, 2012 3:33:50 AM UTC-5, praveen krishna wrote:
>
> Nol there is no such requirement.Actually I am able to upload and read a
> text file by zipping it but for my task I have upload a text file .
>
> On Thu, Nov 1, 2012 at 7:24 AM, Johann Spies
> > wrote:
>
>> On 31 October 2012 17:45, praveen krishna
>> > wrote:
>>
>>> Hi,
>>>For my task I have to upload a text file in form with out zipping it
>>> ,I have prepared the form as:
>>> form = FORM(TABLE(TR(TD('Upload File:', INPUT(_type='file',
>>> name='myfile', id='myfile',
>>> requires=IS_NOT_EMPTY(,TR(TD(INPUT(_type='submit',_value='Submit')
>>>
>>> But I unable to read the file how could it be possible without using
>>> ZipFile.
>>>
>>
>> You refer to 'zip' twice. Why? Is there a requirement that it should
>> be zipped somewhere?
>>
>> Regards
>> Johann
>> --
>> Because experiencing your loyal love is better than life itself,
>> my lips will praise you. (Psalm 63:3)
>>
>> --
>>
>>
>>
>>
>
>
--
Re: [web2py] Reading a text file after uploading in a form
Nol there is no such requirement.Actually I am able to upload and read a
text file by zipping it but for my task I have upload a text file .
On Thu, Nov 1, 2012 at 7:24 AM, Johann Spies wrote:
> On 31 October 2012 17:45, praveen krishna wrote:
>
>> Hi,
>>For my task I have to upload a text file in form with out zipping it
>> ,I have prepared the form as:
>> form = FORM(TABLE(TR(TD('Upload File:', INPUT(_type='file',
>> name='myfile', id='myfile',
>> requires=IS_NOT_EMPTY(,TR(TD(INPUT(_type='submit',_value='Submit')
>>
>> But I unable to read the file how could it be possible without using
>> ZipFile.
>>
>
> You refer to 'zip' twice. Why? Is there a requirement that it should be
> zipped somewhere?
>
> Regards
> Johann
> --
> Because experiencing your loyal love is better than life itself,
> my lips will praise you. (Psalm 63:3)
>
> --
>
>
>
>
--
Re: [web2py] Reading a text file after uploading in a form
On 31 October 2012 17:45, praveen krishna wrote:
> Hi,
>For my task I have to upload a text file in form with out zipping it ,I
> have prepared the form as:
> form = FORM(TABLE(TR(TD('Upload File:', INPUT(_type='file', name='myfile',
> id='myfile',
> requires=IS_NOT_EMPTY(,TR(TD(INPUT(_type='submit',_value='Submit')
>
> But I unable to read the file how could it be possible without using
> ZipFile.
>
You refer to 'zip' twice. Why? Is there a requirement that it should be
zipped somewhere?
Regards
Johann
--
Because experiencing your loyal love is better than life itself,
my lips will praise you. (Psalm 63:3)
--
[web2py] Reading a text file after uploading in a form
Hi,
For my task I have to upload a text file in form with out zipping it ,I
have prepared the form as:
form = FORM(TABLE(TR(TD('Upload File:', INPUT(_type='file', name='myfile',
id='myfile',
requires=IS_NOT_EMPTY(,TR(TD(INPUT(_type='submit',_value='Submit')
But I unable to read the file how could it be possible without using
ZipFile.
--
