[Wien] Comparing Total Energies

2012-07-11 Thread David Tompsett
Dear Fabien,

Thanks for the response. It is probably my k-mesh that is making it
inaccurate to compare.

David.

On Tue, Jul 10, 2012 at 3:48 PM, tran at theochem.tuwien.ac.at wrote:

 Hi,

 When comparing two total energies obtained from different unit cells, one
 has to be always very careful.

 First, if you did the calculation on the
 small unit cell with a k-mesh (n1,n2,n3), then the calculation on the
 large unit cell should be done with the corresponding k-mesh
 (n1/m1,n2/m2,n3/m3), where m1, m2, and m3 indicate by how many times
 (along the lattice vectors a, b and c) is the large unit cell larger than
 the small one. You can have problems if If n1/m1, n2/m2 or n3/m3 is not
 an integer. But this not a problem if you
 are using very good k-meshes such that the energies are well converged.

 It can also happen that the orientation of the lattice vectors are
 completely different in the small and large unit cells. In this case
 some numerical noise (e.g., from the FFTs) can introduce some errors.

 But actually, what do you mean by I can't compare?

 My recommendation: use the same unit cell.

 F. Tran

 On Tue, 10 Jul 2012, David Tompsett wrote:

  Dear All,
 
  I have what is probably a very basic question about comparing total
  energies. I have been considering a system that undergoes a charge
 density
  wave transition from a high to low symmetry structure. I have been
  comparing the total energy of the high and low symmetry structures. The
  unit cell of the high symmetry structure has half as many atoms as does
 the
  low symmetry one.
 
  In my calculations it seems I can't compare 2x(total energy of high
  symmetry cell) with 1x(total energy of low symmetry cell). Instead I have
  to perform the high symmetry calculation in the same size unit cell and
  symmetry as for the low symmetry. Why is this the case? What is the
 effect
  of having different sized unit cells?
 
  Thank you,
  David Tompsett.
 
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[Wien] Comparing Total Energies

2012-07-10 Thread David Tompsett
Dear All,

I have what is probably a very basic question about comparing total
energies. I have been considering a system that undergoes a charge density
wave transition from a high to low symmetry structure. I have been
comparing the total energy of the high and low symmetry structures. The
unit cell of the high symmetry structure has half as many atoms as does the
low symmetry one.

In my calculations it seems I can't compare 2x(total energy of high
symmetry cell) with 1x(total energy of low symmetry cell). Instead I have
to perform the high symmetry calculation in the same size unit cell and
symmetry as for the low symmetry. Why is this the case? What is the effect
of having different sized unit cells?

Thank you,
David Tompsett.
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[Wien] Comparing Total Energies

2012-07-10 Thread t...@theochem.tuwien.ac.at
Hi,

When comparing two total energies obtained from different unit cells, one
has to be always very careful.

First, if you did the calculation on the
small unit cell with a k-mesh (n1,n2,n3), then the calculation on the
large unit cell should be done with the corresponding k-mesh
(n1/m1,n2/m2,n3/m3), where m1, m2, and m3 indicate by how many times
(along the lattice vectors a, b and c) is the large unit cell larger than
the small one. You can have problems if If n1/m1, n2/m2 or n3/m3 is not
an integer. But this not a problem if you
are using very good k-meshes such that the energies are well converged.

It can also happen that the orientation of the lattice vectors are
completely different in the small and large unit cells. In this case
some numerical noise (e.g., from the FFTs) can introduce some errors.

But actually, what do you mean by I can't compare?

My recommendation: use the same unit cell.  

F. Tran

On Tue, 10 Jul 2012, David Tompsett wrote:

 Dear All,
 
 I have what is probably a very basic question about comparing total
 energies. I have been considering a system that undergoes a charge density
 wave transition from a high to low symmetry structure. I have been
 comparing the total energy of the high and low symmetry structures. The
 unit cell of the high symmetry structure has half as many atoms as does the
 low symmetry one.
 
 In my calculations it seems I can't compare 2x(total energy of high
 symmetry cell) with 1x(total energy of low symmetry cell). Instead I have
 to perform the high symmetry calculation in the same size unit cell and
 symmetry as for the low symmetry. Why is this the case? What is the effect
 of having different sized unit cells?
 
 Thank you,
 David Tompsett.