@Algoose Chase
point taken
Thanks
Mohit Ranjan
Samsung India Software Operations.
On Sat, May 1, 2010 at 8:43 PM, Algoose Chase harishp...@gmail.com wrote:
@mohit
The idea of DP is fine.
When you find the Max i dont think you need to include A[i+1]+B[j+1]
because it can never be greater
wat is tail recursion plz explan in detail
On 2 May 2010 08:15, Rohit Saraf rohit.kumar.sa...@gmail.com wrote:
@divya use tail recursion and rest should be fine..
--
--
Rohit Saraf
Second Year Undergraduate,
Dept. of Computer Science and
google it... u will gt it
i am on mobile... cannot explain now..
On 5/2/10, divya jain sweetdivya@gmail.com wrote:
wat is tail recursion plz explan in detail
On 2 May 2010 08:15, Rohit Saraf rohit.kumar.sa...@gmail.com wrote:
@divya use tail recursion and rest should be fine..
--
@divya You're rite. Post a solution if you have one.
--
Regards,
Vignesh
On 2 May 2010 13:14, divya jain sweetdivya@gmail.com wrote:
@Mohit
according to ur algo if a[1], b[0] has sum greater than a[0],b[1]
then i is incremented i is now 2 so for next iteration u ll compare a[2]
b[0]
I agree with abhijith. But given some very large x for which i would have to
find factorial.
I would either
(i) use gmp in cpp or BigInteger or java if its not a lab exercise or an
interview
(ii) use simple brute multiplication algorithm.
The second approach requires
(a) The no. of digits
This problem has been discussed before @
http://groups.google.co.in/group/algogeeks/browse_thread/thread/9c1e1aa8cf1ed437/d451cd9468d985f7
I believe, the problem can't be solved in O(n) but only in O(nlog n).
@Divya: Are you sure the interviewer explicitly asked for an O(n) time
algorithm?
On
Hi
will this work ?
since we need Set S with n pairs of largest values , any such pair within
the set would (always) contain A[0] or B[0] because they maximize the value
of the pair.
so
// code snippet
typedef std::vectorint,int Pairs;
Pairs.push(A[0],B[0])
int i = 1; // index for ListA
int j
@ Pradeep
*CPU stop its current processing and goes to the interrupt subroutine*
you have mentioned that the CPU stops its current processing and goes to the
interrupt subroutine..
My Question is how does the CPU stops its execution(any special hardware
involved) because it is busy in executing
This problem can be simplified to a variation of merge part of merge
sort algorithm.
- Break the set S having n^2 values into n individual arrays of length
n, say S1, S2,..Sn, where S1 = [a1+b1, a1+b2,...a1+bn].
- One can observe that each Si has entries which are themselves sorted
within Si.
-
u are given a sorted lnked list construct a balanced binary search
tree from it.
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i found this question on some site and it was mentioned there todo in o(n).
i dont have the solution
@ above
ur solution doesnt include the case of ncluding a[i] b[j] it takes only a[i]
b[0] or b[j] a[0]
On 2 May 2010 18:11, Algoose Chase harishp...@gmail.com wrote:
Hi
will this work ?
I think challenge here is not the Execution time, but the storage. 300 ! or
400! should generally go beyond the storage capabilities of long long ints
in cpp.
@ Rohit Saraf: Hence, I don't know if even tail recursion will ultimately be
able to store the output.
I think Rajesh Patidar's answer fits
OOPs.. sorry
this doesnt work !
On Sun, May 2, 2010 at 6:11 PM, Algoose Chase harishp...@gmail.com wrote:
Hi
will this work ?
since we need Set S with n pairs of largest values , any such pair within
the set would (always) contain A[0] or B[0] because they maximize the value
of the pair.
Here is a solution of O(n) , taking 4 pointers 2 for each array
#include cstdio
#includeiostream
using namespace std;
#define N 10
int main(void)
{
int arr1[N] = {8,7,4,3,2,1,1,1,1,1};
int arr2[N] = {34,23,21,19,15,13,11,8,4,2};
int *p11,*p12,*p21,*p22;
p11 = p12 = arr1;
@Prabagaran
Execution of an instruction, by the CPU, is an ATOMIC operation. Interrupts,
if any, will be processed after the execution of the current instruction.
CPU has interrupt pins attached to it. Whenever an interrupt occurs, the CPU
will be informed about the interrupt through these
we know that there are many pins available in microprocessor chips one of
them is INTR(interrupt Req)
When a CPU receives an Interrupt Request (IRQ), it first checks if it must
react to the interrupt. So-called Maskable Interrupts allow a programmer to
specify that the CPU does ignore it, while
although CPU is busy in exexcution...it check's its registers values for the
pending interrupts ..
if any interrupt is pending at the end of the current CPU cycle...it
shedules the interrupt handler to further execute the interrupt
subroutine...
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You received this message because you are
What happens when you double click a file??
(changes in Kernel DATA STRUCTURES and interrupts)
With Regards,
Prabagaran.
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