In C, there is no difference between rules for declaring and defining
function and variable. So we can define the functions inside another
function, but their scope is limited to that function only,
In this example abf() is local function to abc(), it can't be
accessed outside environment.
On
@rahul In Standard C you cant define a function inside another function but
you can declare a function inside another function. (so the function can be
defined outside the function).
Eg:-
#includestdio.h
void abc()
{
printf(bac);
void abf();
abf();
}
void abf()
{
printf(bas);
True, we can't define a function within another function in standard C. gcc
has an extension that allows nested functions -
http://gcc.gnu.org/onlinedocs/gcc/Nested-Functions.html
On Tuesday, October 2, 2012 3:37:04 PM UTC-4, rahul sharma wrote:
Guys i have read that we cant define function
@umer : also ur code wont work if the searching element is at the middle of
the array...
On Tue, Oct 2, 2012 at 11:43 PM, atul anand atul.87fri...@gmail.com wrote:
@umer : how no. of comparison are reduced to half by moving both
sidesyou have 2 if condition inside, so you are making 2
@Dave Thanks for pointing that out.
But I still can't get what if elem is on first element or it is not present
in the array? How is your code going to handle that situation?
@Atul, Well yes, In the given question, the number of iterations were 2n.
Which I have reduced to n+n/2.
On Tue, Oct
It's compiler dependent. gcc comes from GNU project.
ANSI C doesn't allow nested function definitions.
On 3 October 2012 01:06, rahul sharma rahul23111...@gmail.com wrote:
Guys i have read that we cant define function in another function in c
Then why this followung program running fine on gcc
A solution in java without arrays...
class Combinations
{
static ArrayListString words = new ArrayListString();
static void getCombinations(ArrayListString words)
{
for(int j=0;jwords.length;word++)
{
//find the index of the word
String word = words.get(j);
//for each words, get the
