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Yes, you will have to write a quad eq. solver. It's easy to write.
On Mon, Jul 18, 2011 at 5:13 AM, Aakash Johari aakashj@gmail.comwrote:
@varun: can you write the code for one?
On Mon, Jul 18, 2011 at 5:11 AM, varun pahwa varunpahwa2...@gmail.comwrote:
The above solution will work
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How AP(ans=14) solution is satisfying the constraints?
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-unique-substring-from-a-string-google
On Tue, Jul 5, 2011 at 3:15 PM, Aakash Johari aakashj@gmail.comwrote:
Please make problem clear with example. Longest unique substring is the
string itself, or i have misunderstood the problem.
On Mon, Jul 4, 2011 at 11:53 PM, Navneet Gupta navneetn
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PM, Aakash Johari aakashj@gmail.comwrote:
It was given that one or two extra variables are allowed. So I used a
variable instead for mapping.
It is simply mapping of each character in alphabet to a bit in the
variable.
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For more
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On Sat, May 28, 2011 at 12:23 PM, Aakash Johari aakashj@gmail.comwrote:
Following code works for [A-Za-z], can be extended for whole
character-set :
#include stdio.h
int main()
{
unsigned long long int a = 0;
char str[50];
int i;
scanf (%s, str);
for ( i
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, will that not be O(n3)??
Clarify if i am wrong.
On May 30, 9:52 am, Aakash Johari aakashj@gmail.com wrote:
At the each level, traversed by BFS, you will have to check whether the
vertex in this level has the element same as it found in the previous
level.
If it is different, then count
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will be the number of
rooms required.
On Sun, May 29, 2011 at 11:29 PM, Aakash Johari aakashj@gmail.comwrote:
yes, sorry.. i misunderstood the problem.
On Sun, May 29, 2011 at 11:24 PM, anshu mishra
anshumishra6...@gmail.comwrote:
biaprtie graph is special case when we can color
No, won't work. :(
On Sun, May 29, 2011 at 11:39 PM, Aakash Johari aakashj@gmail.comwrote:
Can this solution work?
Create adjacency matrix where adj[i][j] representing person i doesnt like
person j. Now toggle the relations (means now the adj[i][j] will represent
person i and person j
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, sukhmeet singh sukhmeet2...@gmail.comwrote:
@Dave nd @Akash can u explain a bit more.. I didn't get what u say..
Inserting in a map takes O(log n) time !!
On Fri, May 20, 2011 at 8:35 PM, Aakash Johari aakashj@gmail.comwrote:
@Dave: This is what is still a doubt to me. I have searched
...!! isn't ??
On Fri, May 27, 2011 at 2:16 PM, bhavana bhavana@gmail.comwrote:
can be solved easily if the elements of the array lie in a limited
range which can b known beforehand...!!
On Fri, May 27, 2011 at 2:10 PM, Aakash Johari aakashj@gmail.com
wrote:
yes, you are right. map
the sequence
1, 4, 9, 16, 25, ..., n^2?
On Fri, May 27, 2011 at 2:44 PM, Aakash Johari aakashj@gmail.comwrote:
@sukhmeet: could you get my approach? it was same as Bhavana explained.
On Fri, May 27, 2011 at 2:12 AM, bhavana bhavana@gmail.com wrote:
hehe...d difference is regarding
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Provide some default value to the parameterized constructor.
*
A(int m = 0) {
a = m;
} *
On Fri, May 27, 2011 at 4:36 AM, D.N.Vishwakarma@IITR deok...@gmail.comwrote:
without default constructor what will be solution
On Wed, May 25, 2011 at 10:56 AM, Aakash Johari aakashj
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Sorry, it can't be because of the preferences :(...
On Tue, May 24, 2011 at 11:07 PM, Aakash Johari aakashj@gmail.comwrote:
I think, it is because of the preference of operations. I have also
implemented it and it's returning 5. Try for some modifications in the
algorithm.
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Sorry, it can't be because of the preferences :(...
On Tue, May 24, 2011 at 11:07 PM, Aakash Johari
aakashj@gmail.comwrote:
I think, it is because of the preference of operations. I have also
implemented it and it's returning 5. Try for some
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if u have many test cases, this approach is helpful.
On Tue, May 24, 2011 at 6:42 AM, Piyush Sinha ecstasy.piy...@gmail.comwrote:
its equal to calculating the Fibonacci numbers till we get a number
which is closest to and lesser than N...anything better??
On 5/24/11, Aakash Johari aakashj
/11, Aakash Johari aakashj@gmail.com wrote:
if u have many test cases, this approach is helpful.
On Tue, May 24, 2011 at 6:42 AM, Piyush Sinha
ecstasy.piy...@gmail.comwrote:
its equal to calculating the Fibonacci numbers till we get a number
which is closest to and lesser than N
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;
temp |= ((a mask) i) 1;
result = 1;
if ( temp = b ) {
result |= 1;
temp -= b;
}
}
return result;
}
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@Dave: I got you. I will have to check before pushing the element in map.
On Fri, May 20, 2011 at 7:30 AM, Dave dave_and_da...@juno.com wrote:
@Aakash: Yeah, but try the same array with sum = 6 and see what
happens.
Dave
On May 20, 9:04 am, Aakash Johari aakashj@gmail.com wrote:
int
) to map the sequence
1, 4, 9, 16, 25, ..., n^2?
Dave
On May 20, 9:39 am, Aakash Johari aakashj@gmail.com wrote:
@Dave: I got you. I will have to check before pushing the element in map.
On Fri, May 20, 2011 at 7:30 AM, Dave dave_and_da...@juno.com wrote:
@Aakash: Yeah
.
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