Can we please get rid of this spammer ?
On Thu, Sep 10, 2015 at 1:53 AM, Shachindra A C
wrote:
> ^^ +1
>
> On Wed, Sep 9, 2015 at 12:54 PM, Rahul Vatsa
> wrote:
>
>> Please block this guy.
>>
>> On Thu, Sep 10, 2015 at 1:08 AM, Shaik Asif
Given a array with +ve and -ve integer , find the maximum sum such that you
are not allowed to skip 2 contiguous elements ( i.e you have to select
atleast one of them to move forward).
eg :-
10 , 20 , 30, -10 , -50 , 40 , -50, -1, -3
Output : 10+20+30-10+40-1 = 89
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B+ tree is used by database... i guess same can be used here.
On 28 Dec 2014 16:13, kumar raja rajkumar.cs...@gmail.com wrote:
which is like a table in database, and produces results for user queries.
Data is: in txt file.
ID, FIRSTNAME, LASTNAME, AGE, SALARY, TITLE
1, venkatesh, kumar, 21,
It is a system design problem .
Suppose a http request is sent to server . Now Server maintains cache for
fast retrieval . if link is present int the cache then it just takes a data
from cache and return it to user but if not , then user will fetch that
http address and then store it in its
the Cache will point to the New NameServer ..
Thanks,
Somnath Singh
On Sun, Dec 14, 2014 at 2:04 PM, atul anand atul.87fri...@gmail.com
wrote:
It is a system design problem .
Suppose a http request is sent to server . Now Server maintains cache
for fast retrieval . if link is present int
People seems to confuse algogeeks with job board.
No idea, how can we get rid of these spam.
On Tue, Oct 14, 2014 at 2:25 PM, Ashish Mehta mehta.ashis...@gmail.com
wrote:
There are multiple openings in Adobe India for Developer position. Send me
your resume ASAP.
Here is the list of urgent
I am not too sure about your O (N^3) solution even. Can you link the
working code ?
On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com wrote:
This is a very good collection of DP problems.
I want the answers for problem 2(e)
and problem 14.
for problem 14 the recurrence
, and it works.
On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:
I am not too sure about your O (N^3) solution even. Can you link the
working code ?
On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
wrote:
This is a very good collection of DP problems.
I want
@Don
int coins [] = {1, 3, 5};
int cnt [] = {7, 3, 1};
int S = 9;
Your code returns 9, for the aforementioned test case. Should not it return 3 ?
Here is my take which takes O (|number of denominators| x |S| x
|maximum count for any coin|) time and
O (|number of denominators| x |S|) time. It
@Don : i am intersted in DP bottom up approach with less time complexity.
solving it recursively is a simpler approach...
On 15 May 2014 22:25, Don dondod...@gmail.com wrote:
How about this:
const int N = 6;
unsigned int coins[N] = {100,50,25,10,5,1};
unsigned int count[N] = {2, 1, 1, 5, 4,
Solving coin change problem with limited coins.
Given an array of denominations and array Count , find minimum number of
coins required to form sum S.
for eg: coins[]={1,2,3};
count[]={1,1,3};
i.e we have 1 coin of 1$ , 1 coin of 2$ , 3 coins of 3$.
input S = 6
output = 2
possible
find articulation point in graph
On 29 Apr 2014 16:56, shashi kant shashiski...@gmail.com wrote:
Problem is as follows:
1. Given a connected graph.
2. Remove a vertex out of it and if graph is divided into two components
return that vertex.
3. else find a set of vertices to be removed that
On Tue, Apr 29, 2014 at 10:33 PM, atul anand atul.87fri...@gmail.comwrote:
find articulation point in graph
It won't work.
Say there are N nodes and every node is connected to every other node.
This graph does not have any articulation point.
You need to remove more than one vertex
On Tue, Apr 29, 2014 at 4:56 PM, shashi kant shashiski...@gmail.com wrote:
Problem is as follows:
You have given a terrible description of problem.
1. Given a connected graph.
Connected, how ? Is the graph directed or undirected ?
2. Remove a vertex out of it and if graph is divided
@Don: what is the point of considering s=2 when we have already found
s=3.As question says find the maximum subsquare. Which is of size 3 and
this the expected outcome.
On Mon, Mar 31, 2014 at 11:28 PM, Don dondod...@gmail.com wrote:
00
00
010100
011100
01
00
In this
@don : According to question we want to find the maximum subsquare.
can you give me test case for which this wont work?
On Fri, Mar 28, 2014 at 9:41 PM, Don dondod...@gmail.com wrote:
No, that is not the same.
It won't find a square smaller than s.
Don
On Thursday, March 27, 2014
Hello,
i found this question online and its solution tooBut i am not able to
fully understand the solution.Need your help to proof correctness of the
algo.
Question is as follows :-
*Question:*
*Given an array A and a number S', provide an efficient algorithm (nlogn)
to find a number K
@Don : your algo time complexity is O(n^2)
It can be reduced to this :-
// Now look for largest square with top left corner at (i,j)
for(i = 0; i n; ++i)
for(j = 0; j n; ++j)
{
s = Min(countRight[i][j], countDown[i][j]);
if (countRight[i][j]
@bhargav : could you please explain your algorithmn
On 3/25/14, bhargav krishna yb ybbkris...@gmail.com wrote:
Even i completed it :). It was from one of the coding challenges...
public class Hill {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated
1) - When u login, it retrieves all the unread mails only. Which data
structure should you use ?
2)- If you get an event invitation then u have to be notified . eg if u
have two event invitations, one is in the next hour and other one 2 months
later, the one that is tomorrow will be given a
Problem is similar to coin change problem(i.e given an array of coins
denomination , Find number of ways to create N Rupees).So given input
K...fill up array from 1 to K.and use this array and a input to coin change
problem
On Sat, Mar 1, 2014 at 9:55 PM, kumar raja rajkumar.cs...@gmail.com
Let us assume you have sum S. The possible numbers it is made up are { 1,
2, .., S }.
Now, for every number belonging to the set, you have two options.
1. Subtract currently chosen number from the given set to sum.
2. Choose next number.
The state will be defined as (num, sum), where num is the
Think in binaries.
'1' = push, '0' = pop.
So a sequence of operations will consist of 0's and 1s.
Say N = length of set.
Property 1: count of 0 = count of 1 = N.
There will be N push and N pop.
Property 2: At any point count of 1s = count of 0s.
1100 is valid. [2 push, 2 pop.]
1001
@Don, amazing solution.
Let us say, I don't have the insight to see the greedy solution mentioned
by @Don there is an obvious dp solution for the general case.
typedef long long int64;
const int64 LINF = (int64) 1e16 + 5;
map int64, int64 memo;
int64
solve (int n) {
if (n 10) return n;
Given a number N, find the smallest 3 digits number such that product of
its digits is equal to N.
For Eg:-
for input 24 , output :138 (1*3*8 = 24)
for input 36 , output :149 (1*4*9 = 36)
for input 100 , output : 455 (4*5*5 = 100)
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in range (100, 1001) if int (str (i) [0]) * int (str (i)
[1]) * int (str (i) [2]) == N)
149
N = 100
min (i for i in range (100, 1001) if int (str (i) [0]) * int (str (i)
[1]) * int (str (i) [2]) == N)
455
On Wed, Feb 12, 2014 at 8:45 PM, atul anand atul.87fri...@gmail.com wrote:
Given a number N
@don : awesome +1 . I was not aware of George Marsaglia's Multiply
With Carry generator. But it is soo clll . If you have any good link
for its proof or explanation of the idea behind it then please mention it.
I never knew generating random number can be few lines of code :)
Thanks :)
@don: algo look fine..i tested it ,but it did not generate 1-10 with
probabilty of 1/10 everytime.
actually question was asked in an intrview.
question started with displaying all elements in an array randomly without
repetition i.e only once( probabilty 1/10)...which can be done with fisher
yates
Generate random number form 1 - 10 with probability of 1/10.You are not
allowed to used rand() function.
any simple way of achieving above with using any complex implementation of
random number generators algorithm .
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How about a normal binary search ?
We know that X can be [0, 2^31 - 1].
Also if X is a valid configuration, all the values above X will too.
Monotonicity is all we need here.
So, take lo = 0 and hi = 2 ^ 31 - 1.
Now check, if your mid is a valid X.
If yes, X can lie between [0, mid]. If not, X
Imagine a binary tree lying on the floor with nodes as balls and edges
as threads, you are given a pointer to a node. When you pick the tree
from that node up what will be the structure of the tree. You have
gravity changing the structure of the tree
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Hello,
How to solve an equation with one unknown variable ?
operator allowed are : + , -
for eg . input could be :-
x + ( 5 + 4 ) = 6
(x - 7) + 7 = (x + 1) - 5
If operator also allows * (multiply) , then what change in algorithm is
required.
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We need active moderators who can ban these guys spamming the list.
This group deals with algorithm problems, we don't need salesmen and
brokers here.
On Wed, Jan 8, 2014 at 1:42 PM, RM rmath...@gmail.com wrote:
Job postings to this mailing list should be marked as spam, and the
senders
@dave : could you provide pseudo code for ur approach
On 6 Jan 2014 07:39, Dave dave_and_da...@juno.com wrote:
Use a binary search. Assume that you have arrays a[m] and b[n] sorted in
ascending order. If a[i] is the kth smallest element, then b[k-i-2] must be
smaller than a[i], and b[k-i-1]
.
i am not able to understand , how it is taking care that 3 adjacent are
colored
different.
could you please clarify my doubt.
On Thu, Dec 26, 2013 at 5:25 PM, Saurabh Paliwal
saurabh.paliwa...@gmail.com wrote:
@atul anand :- no, we need not use all the colors.
@kumar raja :- sorry dude
Yes, we know now that you are a proud owner of Apple iPod.
On Fri, Jan 2, 1970 at 9:32 AM, Chitra chitradevi.ramachand...@gmail.comwrote:
Sent from my iPod
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@kumar : i have one doubt regarding this question.Do we have to use all K
colors[K] to color all building.
for example :-
color[3]={1,2,10};
now if we have to color 6 building then i can use only 1st 2 color to color
all building and never 10 ...is this allowed ???
building[N]={1,2,1,2,1,2}
@saurabh :
answer[i][j] = min(answer[i-1][t]) + colorvalue[t] where t varies from 1 to
k except j.
how this DP is taking care of the case where no adjacent house if of same
color.
what i understand from the DP is the following :-
find minimum cost of coloring previous house with color t (
ohh shoots...my bad.got this condition wrong t varies from 1 to k
except j.
now got it :)..ignore my previous comment :) :)
On Tue, Dec 17, 2013 at 11:47 PM, atul anand atul.87fri...@gmail.comwrote:
@saurabh :
answer[i][j] = min(answer[i-1][t]) + colorvalue[t] where t varies from 1
can be done with nlogn i dont think so O(n) is possible...
On 17 Dec 2013 01:30, bujji jajala jajalabu...@gmail.com wrote:
Given an Array of integers (A1,A2,...,An) of length n, Find the maximum
possible length of increasing sub sequence formed from A1, A2,,An.
I read that it is
On Tue, Dec 17, 2013 at 1:30 AM, bujji jajala jajalabu...@gmail.com wrote:
Given an Array of integers (A1,A2,...,An) of length n, Find the maximum
possible length of increasing sub sequence formed from A1, A2,,An.
I read that it is possible to compute in linear time as mentioned in
@Don : +1 ..got it ..thanks
On Wed, Nov 13, 2013 at 10:35 PM, Dave dave_and_da...@juno.com wrote:
@Don: Excellent solution. It requires little extra data to be stored, and
it is easy to implement.
Dave
On Wednesday, November 13, 2013 9:31:47 AM UTC-6, Don wrote:
The data file contains
@don : i did not get it , what will be data in file?
On Mon, Nov 11, 2013 at 10:14 PM, Don dondod...@gmail.com wrote:
Save in preorder, tagging each node with two bits indicating if that node
has a left and right subtree.
Then rebuild like this:
Tree rebuild()
{
Tree result =
@don : it is not BST , it is binary tree ...so your approach will
not work in this case.
@kumar : save pre-order and in-order traversal with some delimiter in
b/w traversals.
pre-order : a b c d e
in-order : c b e a d
write in file :-
a b c d e # c b e a d
now use pre-order and in-order
we can first count number of nodes in a subtree below each node.Now
transfer message to max(count(root-left),count-root-right);
On 11/1/13, kumar raja rajkumar.cs...@gmail.com wrote:
Suppose we need to distribute a message to all the nodes in a rooted tree.
Initially, only the root
node knows
using idea mentioned in below link , we can solve this similar problem
in O(n^2*k).
http://stackoverflow.com/questions/12862077/number-of-increasing-strings-of-length-k
On 10/26/13, atul anand atul.87fri...@gmail.com wrote:
@saurabh : i did not get ur algo...can you please explain
wont be greater than O(n logn).
So it is bounded by O(nlogn) . In the worst case it might go up to
O(n^2). But i am not sure of this.
On 25 October 2013 00:17, atul anand atul.87fri...@gmail.com wrote:
OK, i got now why you were using min-heap.
now consider this example
) a[i]
delete root in min- heap
inseart a[i] in min - heap
at the end of main loop the min-heap will contain the final sequence.
On Thu, Oct 24, 2013 at 8:50 AM, atul anand
atul.87fri...@gmail.comwrote:
@Saurabh Paliwal : yes
On 10/24/13, Saurabh Paliwal saurabh.paliwa...@gmail.com
,
but min heap is used for storing the largest elements.
So it is preferable DS,
On Thu, Oct 24, 2013 at 8:35 PM, atul anand atul.87fri...@gmail.com
wrote:
@pankaj : how can you maintain increasing sub-sequence using
heapyour soln is for finding finding K largest element in the
array...so
insert because temp = 100 and 30temp
insert 8 cant insert temp = 100 and 8temp
(500temp)size of heap ==4 so delete root of min-heap(which is 2)
insert 555
now if i check the heap elements
{5, 10, 100 , 555}
On Thu, Oct 24, 2013 at 11:25 PM, atul anand
atul.87fri...@gmail.comwrote:
in your
Given an array with N elements and integer K . Find sum of longest
increasing sub-sequence of length K elements such that sub-sequence found
is maximum among all K max su-sequence.
Eg arr[]={5,2,1,10,9,30,8,55}
K = 3
output : 10,30,55sum = 10+30+55 = 95
if K=4
output : 5,10,30,55 sum =
@Saurabh Paliwal : yes
On 10/24/13, Saurabh Paliwal saurabh.paliwa...@gmail.com wrote:
Do you mean
*of all the increasing subsequences of length k in this array, find the one
with maximum sum ?*
On Wed, Oct 23, 2013 at 10:52 PM, atul anand
atul.87fri...@gmail.comwrote:
Given an array
Question seems similar to matrix chain multiplication problemhere you
need to find min cost..
Recurrence for this could be the following , please validate it.
DP(i,j) = j + (j - i) * min( DP(i , k) , DP(k, j) ) for all i k j i
j
On Sat, Oct 12, 2013 at 12:54 PM, kumar raja
Hello,
Given integer N , How to generate random number from 0 to N without
using rand() function.
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question is different...here we have to find max of k elements in the
window..not max subarry of size kfoe eg input is say ... 1 4 5 66 7 9
and k=3
then output should be
(1,4,5) = 5
(4,5,66) = 66
(5,66,7)=66
(66,7,9)=66
output - 5,66,66,66
On 19 Sep 2013 19:00, igor.b...@gmail.com
http://www.geeksforgeeks.org/check-for-identical-bsts-without-building-the-trees/
On Thu, Jun 6, 2013 at 11:27 AM, Sambhavna Singh coolsambha...@gmail.comwrote:
I came across this question on careercup: how do we go about finding
whether the BSTs formed by the given input order would be
On Wed, May 22, 2013 at 9:45 AM, emmy foramlakh...@gmail.com wrote:
problem : http://www.spoj.com/problems/FARIDA/
what is wrong with this code? The algorithm is pretty straight forward
Is it ?
1000 1 1 1000
Your code gives 1001 as output. Desired output should be 2000.
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@karthikeyan : It is an acyclic graph not a binary tree. your solution
will work if given graph is a binary tree.
problem can be solved using dfs as suggested above
On 5/11/13, Karthikeyan V.B kartmu...@gmail.com wrote:
Since it is an acyclic graph, find the appropriate node that can be the
) or (a)-(c)
which is wrong.
On 5/12/13, Karthikeyan V.B kartmu...@gmail.com wrote:
@atul anand : acyclic graph can be converted to a tree using prim/kruskal
or by finding an appropriate node that can act like the root of a tree
On Sun, May 12, 2013 at 5:55 PM, atul anand atul.87fri...@gmail.com
{*1*,* 1*, 0, 0, 0},
{0, *1*, 0, 0, *1*},
{*1*, 0, 0, *1*, *1*},
{0, 0, 0, 0, 0},
{*1*, 0, *1*, 0, *1*}
above different set of color represent different island.Simple DFS is
//code sketch
row_len=R;
col_len=C;
r_start=0,col_start=0;
while (x R*C)
{
for i=r_start to col_len
keep extracting value from 1D and add it to mat[r_start][i]=arr[p++];
r_start++;
for i=r_start to row_len
keep extracting value from 1D and add it to mat[i][col_len]=arr[p++];
coefficient of T is 0, to
make it O(1) solution.
That does not seems to be the case here.
Say, for 4th iteration, what will be your answer ? I don't see any
closed form here.
On Wed, Apr 10, 2013 at 7:03 AM, Shashwat Anand m...@shashwat.me
mailto:m...@shashwat.me wrote:
On 4/10/13
On 4/10/13 12:13 AM, rahul sharma wrote:
If you have any other solution ..please post that...i thnik recursion
is ok with base case...we need to scan again after first iteration...??
First of all, the array size and number of iteration both won't be N or
else the answer will always be 0.
I take
are we allowed to use operation only once or multilpe times?
On Fri, Mar 22, 2013 at 6:27 AM, prankur gupta duke.lnm...@gmail.comwrote:
Hi All,
Could you help me this question.
This was asked at Yelp Interview.
Given 6 integers and 1 target value, write a function to get the target
value
@Dave solution is perfect. I prefer it over mind.
However, here is an alternate solution.
We know that this is an equation in 'x' with a degree of 1. It means it is
a straight line and root is guaranteed unless of course the equation is of
the form y = c. That is not the case here as it would
@rahul : yes
On 3/24/13, rahul sharma rahul23111...@gmail.com wrote:
So we need to implement prelocate down for deletion?
On Sunday, March 24, 2013, atul anand atul.87fri...@gmail.com wrote:
yeah implementation is wrong.
On 3/24/13, tec technic@gmail.com wrote:
The heap implementation
On 3/21/13 5:02 PM, Avinash wrote:
Given a STL map, say mapint, bool m1. Given two value a b that may
or may not exists in m1. Find the Least Common Ancestor in STL MAP.
Remember you don't have access to root, so you need to iterate using
iterator. Use the methods/function of MAP forex begin,
Ambiguity lies in the heart of this question.
If you are given a tree and you want to look for leaf nodes you can
simply do an inorder traversa,
and check for leaf nodes.
Time complexity will be O(N) and space complexity will be O(log N).
void
getLeafNodes (node *root) {
if (! root)
use hashmap
On Fri, Feb 22, 2013 at 12:58 AM, marti amritsa...@gmail.com wrote:
How do I Find the Unique Element that Appears exactly k Times in an Array?
the problem is given an integer array, only one integer appears* k* times,
all the other integers appears *m* times in the array
related to this problem, link given below :-
http://groups.google.com/group/algogeeks/browse_thread/thread/7cfb0a6f7d121d92/0adc692fad1bab40?hl=enlnk=gstq=DP+equation+for+interval+problem#0adc692fad1bab40
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Algorithm
@shady : It allows us to allocate m/m dynamically ..which in itself is
very big advantage.
m/m consumption can be ignored , if you compare with the flexibility
it provides.
eg:-
int *arr=(int *)malloc(sizeof(int) * 100);
now m/m consumption here is 100*4+8;// extra 8 wont hurt if you
compare
executed your code..working fine by commenting cmnt2 and un-commenting cmnt1
--
It can be solved using DP
here is the recurrence eqn:-
coin[ i ] = 1+coin[ i - denom( j ) ] if i =1 and 1 j ArrayLen(denom)
base cases :- c[ i ]= inf if j 0
c[ i ] = 0 if j==0
On 12/23/12, Dave dave_and_da...@juno.com wrote:
@Shady. That still didn't answer my
correction above :-
It can be solved using DP
here is the recurrence eqn:-
coin[ i ] = 1+ min{ coin[ i - denom( j ) ] } if i =1 and 1 j ArrayLen(denom)
base cases :- c[ i ]= inf if i 0
c[ i ] = 0 if i==0
--
i had implemented Sieve of Eratosthenes long time back...
what i did was the following :-
say N is the range and we want to find all prime number within this range.
take size of temp array[] to half = N/2...as we only care of odd
numbers.Prime number 2 can be handled explicitly.
run outer loop
considering '+' , here will take Cn time . Here '+' is for concatenate ,
now this concatenation taking place in constant time?? , i dont think
so..internally it will be adding elements to new m/m space and for that it
need to traverse each character...so it will take cn time.
so T(n) =T(n/2) + cn
@shady : as subject says fastest sequential access , then if i am not
getting it wrong.we only care of sequential access a value not modifying
the linked list.
so i guess double linked list would be helpful
1) bcozz it can move in both the direction , so if linked list is sorted
then it would be
rushi4...@gmail.comwrote:
@atul : In the second for loop...temp will also contain one which is
being missing along with the one which is being repeated.
kindly check it once again.
On Mon, Nov 19, 2012 at 11:44 AM, atul anand atul.87fri...@gmail.comwrote:
array has all distinct
array has all distinct elements ans lie b/w 1 to n , now bcozz they are all
distinct except 1 element means it should have all element with range 1 to
n...except 1 element , which can be any element b/w 1 to n.
temp=arr[0]
*for i=1 to n
temp=temp^arr[i]; *
//now temp will contain all distinct
from each node , make 4 recursive call
1) you consider this node as part of the solution i.e left=target -
currentNode-data is passed , and consider current-left for next
recursion
2)you consider this node as part of the solution i.e left=target -
currentNode-data is passed , and consider
use enum
On Sat, Oct 27, 2012 at 3:21 AM, rahul sharma rahul23111...@gmail.comwrote:
There is question asked like
O/p of following in C(32 bit OS)
#include iostream
#includestdio.h
using namespace std;
bool IsEqual(char * a)
{
printf(abc);
return true;
}
int main()
{
@vishal : as discussed in previous post , your solution wont work for
certain test cases...and i dont think so , checking tree in inorder way is
complex .It is simple to implement , you just need to call tree recursively
in Inorder way and keep track of prev node and compare prev node with
@vaibhav : by not using extra space...i guess you mean that you were not
allowed to use one extra pointer.bcozz space complexity will remain
constant for inorder approch.
On Tue, Nov 6, 2012 at 1:07 AM, vaibhav shukla vaibhav200...@gmail.comwrote:
yes ofcourse... dats the easiest i suppose...
@Don : your algo wont work for following tree :-
30
/ \
20 31
/ \
9 41
above tree is not a BST bcozz here 41 should lie on the right side of the
30but it is not.
so we need to keep track of max and min as we move left or right part of
the tree.and each node
building tree will take O(n) time but for each node we need to find max i.e
i = max (inorder, start, end);
so complexity in worst case will we O(n^2).
On Tue, Nov 6, 2012 at 12:26 AM, shady sinv...@gmail.com wrote:
Sorting takes linear time, but it doesnt get repeated n times,
it is like -
a=a^b;
b=a^b;
a=a^b;
need to check if a and b are equal or not , bcozz a^a =0
On Mon, Nov 5, 2012 at 2:02 AM, manish narayan.shiv...@gmail.com wrote:
Swapping two objects (not integers/chars),without using temp...?
my solution is using xor operation..is that right and ny other solutions ?
check out my comment ...i had posted it log time back on
geekforgeeks...search for atull007 int the below link.
let me know it does not work
http://www.geeksforgeeks.org/forum/topic/adobe-interview-question-for-software-engineerdeveloper-fresher-about-bit-magic-1
On Thu, Nov 1, 2012 at 4:00 AM,
its seem to me that output buffer is not flushing ..to do so you need
to add \n while printing hello i.e
printf(Hello\n);
it was working for you when the else {} part was un-commented because you
are using \n in this statement
//printf( %d - %d \n , tmp[i], count); -- if you remove \n from
...@gmail.comwrote:
its now doing swapping of pointers...plz explain
On Sun, Oct 28, 2012 at 8:08 PM, atul anand
atul.87fri...@gmail.comwrote:
it should swap
On 10/28/12, rahul sharma rahul23111...@gmail.com wrote:
Why the following code is not able to swap two macros???although it
is
easily
()
{
float a,x;
a=20.0;
x=30.0;
float *p,*q;
p=a,q=x;
swap(p,q,float*);
printf(%f %f,a,x);
getchar();
}
o/p=20.000 30.000
why not swapped???
On Mon, Oct 29, 2012 at 11:01 PM, atul anand
atul.87fri...@gmail.comwrote:
if you think the your expanded version is incorrect.You are wrong
becoz you are sorting the aux[] , it seems to fine by replacing it with i j
On 10/28/12, rahul sharma rahul23111...@gmail.com wrote:
I wana ask that ccan i replcae while condiion with the condition as follow
while(ij)
code reference :http://www.geeksforgeeks.org/archives/23338
void
it should swap
On 10/28/12, rahul sharma rahul23111...@gmail.com wrote:
Why the following code is not able to swap two macros???although it is
easily swapping 2 variables
#includestdio.h
#define swap(a,b,c) c t;t=a,a=b,b=t
int main
int x=10,y=20;
int *p,*q;
swap(x,y,int);
didnt get you... first it was now working , now its working...!!!
please write clearly about your doubts.
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Trie or hash map can b used
On 10/24/12, rahul sharma rahul23111...@gmail.com wrote:
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use hash map...with key as original node and value as duplicate of this
node duplicate node next and random pointer is set to NULL initially.
now traverse whole linked list keep on adding node.
after this do another traversal of orig linked list taking key as orig
node ..duplicate=fetch
http://www.geeksforgeeks.org/archives/10120
On 10/21/12, rahul sharma rahul23111...@gmail.com wrote:
Guys i have read an article somewhere regarding optimization of recursive
fibonicci so that we donot need to calculate the sum that we have already
calculated...
In case if factorial,we donot
@rahul : nope it wont work ..check for this input :-
input = 1, 2,3,6,4 ,101, 6
by removing msis[i] msis[j] + arr[i] condition then you are
excluding the max sub-sequence found from j=0 to i.
On 10/21/12, rahul sharma rahul23111...@gmail.com wrote:
but if there are -ve numbers then
google searched it : geeksforgeeks + Fibonacci number ;) ;)
On 10/21/12, rahul sharma rahul23111...@gmail.com wrote:
thnx a lot atul...was looking for that only...can u plz tell me under which
section u get this post
On Sun, Oct 21, 2012 at 4:03 PM, atul anand atul.87fri...@gmail.com
][1] - M[1][1]- M[1][0]- M[0][0]- M[0][1] -- CYCLE
how you will avoid these cycles...
On Tue, Oct 16, 2012 at 8:58 AM, atul anand atul.87fri...@gmail.comwrote:
http://www.geeksforgeeks.org/archives/13376
On Tue, Oct 16, 2012 at 8:56 AM, atul anand atul.87fri...@gmail.comwrote:
can
@jaspreet : i dont find much difference between using BFS or
backtracking...which is doing similar to DFS.
On Tue, Oct 16, 2012 at 4:28 AM, Jaspreet Singh
jassajjassaj...@gmail.comwrote:
BFS
On Sun, Oct 14, 2012 at 4:21 PM, Rahul Kumar Patle
patlerahulku...@gmail.com wrote:
response
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