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you found out the starting letter then check
s.substring(0,i)==s.substring(i,2i).
I hope you get the idea.
On Mon, Jun 4, 2012 at 9:14 AM, utsav sharma utsav.sharm...@gmail.comwrote:
@jeevitesh :- yes i am also thinking of suffix tree,
but i am facing problem in implementing it. did you
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will have to live with it in this case as i do not think it would be
possible in O(n) time otherwise.
On Sat, May 5, 2012 at 2:33 PM, shiv narayan narayan.shiv...@gmail.comwrote:
@jeevitesh yeah that may be right but it requires extra space as lot
of space will be wasted...
On May 5, 1:44 pm