Which one of the following is true for a CPU having a single interrupt
request line and a single interrupt grant line?
a)Neither vectored interrupt nor multiple interrupting devices are
possible.
b)Vectored interrupts are not possible but multiple multiple
interrupting devices are possible.
complete 2 round of this single link before node p reaches
last_node . so when p reaches last_node , at that point of time q would
have reached last_node (hence completing this 2 circle).
hope this will help you in understanding the idea.
On Fri, Dec 2, 2011 at 12:14 PM, Vijay Khandar vijaykhand
What does the following program do on the singly linked list?
p=head;
q=head-next;
while(p!=null q!null)
{
if(p==q)
{
exit(0)
}
p=p-next;
q=(q-next)?(q-next-next):q-next;
}
a)traverse the entire singly linked list
b)detects the duplicate nodes
c)detects the loop in singly linked list
d)detects
But how plz explain in detail..
On Thu, Dec 1, 2011 at 8:14 PM, Karthikeyan V.B kartmu...@gmail.com wrote:
detects the loop in the linked list
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A stack is implemented with two queues then what are the minimum
enqueue and dequeue operations needed to perform for pop
operation,where '10' elements are already in the first queue?
please anyone provide soln with explation.
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, Vijay Khandar vijaykhand...@gmail.comwrote:
A stack is implemented with two queues then what are the minimum
enqueue and dequeue operations needed to perform for pop
operation,where '10' elements are already in the first queue?
please anyone provide soln with explation.
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How many bytes of data can be sent in 15 seconds over a serial link
with baud rate of 9600 inasynchronous mode with odd parity and two
stop bits in the frame?
a)10,000 bytes
b)12,000 bytes
c) 15,000 bytes
d)27,000 bytes
Plz anyone explain me.
Vijay..
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as
LOAD b
MUL a
STORE b
Where each instance of a formal parameter has been replaced by its
actual parameter.
Dave
On Nov 17, 5:32 am, Vijay Khandar vijaykhand...@gmail.com wrote:
What are x and y in the following macro definition?
macro ADD x,y
LOAD y
but why?
On Nov 18, 9:14 am, ((** VICKY **)) venkat.jun...@gmail.com wrote:
False not necessarily.
On Nov 17, 4:03 pm, Vijay Khandar vijaykhand...@gmail.com wrote:
Can anyone explain following sentence- True or False and explain
All instructions affect the flags
Vijay Khandar
Relative mode of addressing is most relevant to writing
a)coroutines
b)position-independent code
c)shareble code
d)interrupt handlers
plz anyone give me answer with explation...
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Thank u very much
On Thu, Nov 17, 2011 at 4:05 PM, Piyush piyushmadan2...@gmail.com wrote:
b) Binary search
Binary search has to be done in O(logn) but in a linked list individual
elements can't be
accessed in O(1) time. and hence its not suitable to have a linked list as
a
In the following Pascal Program segment what is the value of X after
the execution of the program segment?
X:=10; Y:=20;
If XY,then if X0 then X:=abs(X) else X:=2*X;
Plz anyone explain
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How it is Radix sort, why not Heapsort,
plz explain me in detail..
On Nov 14, 3:36 pm, Ankur Garg ankurga...@gmail.com wrote:
Radix Sort
On Mon, Nov 14, 2011 at 1:57 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
Which is the sorting algm sorts the integers [1...n^3
Which is the sorting algm sorts the integers [1...n^3] in
O(n).
a)Heapsort
b)Quicksort
c)Mergesort
d)Radix sort
please tell anyone.
Vijay.
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Plz anyone write program in C++ and C of searching,inserting and
deleting node in or from a B-tree...
Vijay..
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To
Let X and Y be jointly distributed random variables such that the
conditional distribution of Y,
given X=x, is uniform on the interval (x-1,x+1). Suppose E(X)=1 and
Var(X)=5/3.
Q.1 The mean of the random variable Y is
First question using common data:
(A) 1/2(B) 1(C)
Array of pointers is= *a=A[10];
Pointers to array means= *A[10];
is this correct?
On Mon, Aug 29, 2011 at 1:14 PM, Nitin coolguyinat...@gmail.com wrote:
Please specify the difference between Array of pointer and Pointer to
array???it's getting very messy
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ER-diagram is given and asking for min and max table. Can anyone
Explain me ..
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O\P-Bye I think so.plz explain how its hello
On Fri, Aug 26, 2011 at 12:12 PM, Suraj Fale surajfa...@gmail.com wrote:
Hey guys..
I know in this group all geeky stuffs goes on... but following lines of
code i foind it intresting and thah y wants ot sahre it with you all. Its
very
O\P= 1 2 1 3 1 2 1 is it correct?
On Fri, Aug 26, 2011 at 12:23 PM, SAMMM somnath.nit...@gmail.com wrote:
includestdio.h
void fun(int);
typedef int (*pf) (int, int);
int proc(pf, int, int);
int main()
{
int a=3;
fun(a);
return 0;
}
void fun(int n)
{
if(n 0)
{
Thank,,,Now got it.
On Tue, Aug 23, 2011 at 11:22 AM, nagarajan naga4...@gmail.com wrote:
Hi Vijay,
i = 10 10 5
= 0 5
= 1
On Tue, Aug 23, 2011 at 11:03 AM, Vijay Khandar
vijaykhand...@gmail.comwrote:
main()
{
int x=10,y=10,z=5;
int i=xyz;
pf(\n%d,i);
}
o/p is 1 .pls
) which evaluates to 1 and
that is what is assigned to i.
On Aug 23, 10:33 am, Vijay Khandar vijaykhand...@gmail.com wrote:
main()
{
int x=10,y=10,z=5;
int i=xyz;
pf(\n%d,i);
}
o/p is 1 .pls any1 explain me hw is it printing?
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main()
{
int x=10,y=10,z=5;
int i=xyz;
pf(\n%d,i);
}
o/p is 1 .pls any1 explain me hw is it printing?
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rahultiwari6...@gmail.comwrote:
@vijay
u take normalised form of 5.375 wrong .
actual normalised form of 5.375 = 0100 1010 1100
On Sun, Aug 21, 2011 at 10:12 AM, Vijay Khandar
vijaykhand...@gmail.comwrote:
but why only o/p-00 00 AC 40 and not AC 40 00 00
FUNC1(i) (i*(i-1))=so put i-1 as it is on i=so (i-1*(i-1-1)) and i=8
so(8-1*(8-1-1))=(8-1(6))=2 and mul bu 8=16
On Sun, Aug 21, 2011 at 4:03 PM, Prakash D cegprak...@gmail.com wrote:
FUNC2(8)
== 8==0? 1: 8 * FUNC1(8-1)
== 8==0? 1: 8*( 8-1* 8-1-1)
== 8 * (8-8-2)
== -16
but why 16??
Thank u very much Abhishek for this link, Now I got it ...But also u
explain me in following..
5.375 is represents 0100 1010 1100 means 4 0 A C 0
0 0 0in Hex now how it prints 00 00 AC 40 means can it accepts fm right to
left or L to R I m little
, Puneet Chawla
puneetchawla...@gmail.comwrote:
Compiler is little endian so as u have typecasted it to char pointer then
0100 1010 1100 means 4 0 A C 0 0 0 0 it will show
o/p byte by byte from LSB.
On Sun, Aug 21, 2011 at 5:47 PM, Vijay Khandar
vijaykhand
as u have typecasted it to char pointer then
0100 1010 1100 means 4 0 A C 0 0 0 0 it will show
o/p byte by byte from LSB.
On Sun, Aug 21, 2011 at 5:47 PM, Vijay Khandar
vijaykhand...@gmail.comwrote:
Thank u very much Abhishek for this link, Now I got
Congrates Harshal!!
On Sat, Aug 6, 2011 at 12:15 PM, Harshal hc4...@gmail.com wrote:
Algogeeks is really awesome and very informative. I got a job in microsoft,
and this group has played vital role in building concepts. So I just want to
thank this group and the people here..
keep it
main()
{
printf(\n %x,-14);
}
o/p-
Plz tell me anyone how this program is working? what is the meaning of
-14, 456,-665 etc.. how this statement is executed..?
Vijay
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Congrates
On Sat, Aug 20, 2011 at 10:20 AM, Ankur pratik ankurocks...@gmail.comwrote:
samsung engineering labs
On Sat, Aug 20, 2011 at 10:18 AM, sukran dhawan sukrandha...@gmail.comwrote:
where ?
On Sat, Aug 20, 2011 at 10:16 AM, ankur pratik ankurocks...@gmail.comwrote:
thanx to
-14
left shifting 4 bits
%x prints in hexa decimal format
so o/p- f f f 0
On Sat, Aug 20, 2011 at 11:39 AM, Vijay Khandar
vijaykhand...@gmail.comwrote:
main()
{
printf(\n %x,-14);
}
o/p-
Plz tell me anyone how this program is working? what
On Sat, Aug 20, 2011 at 11:55 AM, Vijay Khandar
vijaykhand...@gmail.comwrote:
Thank you very much..now i got it.
On Sat, Aug 20, 2011 at 11:51 AM, Ayswarya Srinivasan
krsayswa...@gmail.com wrote:
i guess the output is fff0
-1 = 0001
taking 1's
but why only o/p-00 00 AC 40 and not AC 40 00 00 or 00 AC 40 00 or 40 AC 00
00etc , plz explain in detail how p[0] pts to 00 and p[1] pts to 00 and p[2]
pts AC or 1010 1100 and p[3] pts to 40 or 0100 ONLY in this
way..Vijay Khandar...
On Sat, Aug 20, 2011 at 12:31 PM
Thanks to all..
On Sun, Aug 21, 2011 at 12:07 AM, Sanjay Rajpal srn...@gmail.com wrote:
it will be like .
I have mentioned that leftmost 1 bit will be carried with shift.
Sanju
:)
On Sat, Aug 20, 2011 at 11:18 AM, Abhishek
If the binary equivalent of 5.375 in normalised form is - 0100
1010 1100
what is the o/p of following code-
main()
{
float a=5.375;
char *p;
int i;
p=(char *)a;
for(i=0;i=3;i++)
printf(%02X,(unsigned char)p[i]);
}
O/P= 00 00 AC 40
Plz, Plz anyone explain me in detail,
struct list
{
int x;
struct list *next;
}*head;
The statement head.x=100
A)assigns 100 to one element of the structure list
B)creates a node of type list and assigns a value to x
C)creates a head of the list
D)error
Plz anyone provide correct option with explanation..
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Thanks
On Fri, Aug 5, 2011 at 5:25 PM, SANDEEP CHUGH sandeep.aa...@gmail.comwrote:
ERROR
On Fri, Aug 5, 2011 at 5:19 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
struct list
{
int x;
struct list *next;
}*head;
The statement head.x=100
A)assigns 100 to one element
Thanks.
On Fri, Aug 5, 2011 at 5:26 PM, ankit sambyal ankitsamb...@gmail.comwrote:
error
because head is a pointer to the structure, hence head.x gives an error
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What errors are you likely to get when you run the following program?
#includestdio.h
#includeconio.h
#includestring.h
void main()
{
clrscr();
struct emp
{
char name[20];
float sal;
};
struct emp e[10];
int i;
for(i=0;i=3;i++)
scanf(%s %f,e[i].name,e[i].sal);
getch();
}
Plz Explain
What errors are you likely to get when you run the following program?
#includestdio.h
#includeconio.h
#includestring.h
void main()
{
clrscr();
struct emp
{
char name[20];
float sal;
};
struct emp e[10];
int i;
for(i=0;i=3;i++)
scanf(%s %f,e[i].name,e[i].sal);
getch();
}
A)floating point format
But program is not working properly...
On Fri, Aug 5, 2011 at 5:44 PM, Nikhil Gupta nikhilgupta2...@gmail.comwrote:
Couldn't find any error.
On Fri, Aug 5, 2011 at 5:38 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
What errors are you likely to get when you run the following
are to make it compatible to gcc
compiler.
Check the statement in the bottom of the page.
On Fri, Aug 5, 2011 at 5:46 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
What errors are you likely to get when you run the following program?
#includestdio.h
#includeconio.h
#includestring.h
void main
emulator to be linked */
a = *b ;/* suppress the warning - variable not used */
};
On Fri, Aug 5, 2011 at 6:04 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
But program is not giving the o/p.
I have taken one printf statement same as scanf..and scanf() taking
i/p but prinf() not giving o
I dont think so dp=arr; since **dp; dp contains the addr of another ptr
variable...
On Fri, Aug 5, 2011 at 7:27 PM, Arun Vishwanathan aaron.nar...@gmail.comwrote:
I guess someone had posted a link earlier from which I have a basic doubt
when u have
int arr[3]={1,0,2};
int **dp;
int
);
}
There is always some problem in string input using %s, don't really know
why though deeply.
On 5 August 2011 17:48, Vijay Khandar vijaykhand...@gmail.com wrote:
But program is not working properly...
On Fri, Aug 5, 2011 at 5:44 PM, Nikhil Gupta
nikhilgupta2...@gmail.comwrote:
Couldn't find
)
{
float a=0,*b=a;
a=*b;
}
this code forces the emulator to be linked
On Fri, Aug 5, 2011 at 7:38 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
Yes correct, In m using very old compiler Turbo C++
On Fri, Aug 5, 2011 at 7:34 PM, Rohit Srivastava
access2ro...@gmail.comwrote:
you
element and so arr contain
address of that pointer ?
On Fri, Aug 5, 2011 at 4:06 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
I dont think so dp=arr; since **dp; dp contains the addr of another ptr
variable...
On Fri, Aug 5, 2011 at 7:27 PM, Arun Vishwanathan
aaron.nar...@gmail.com
Pointers provide a convenient way to represent multidimensional
arrays, allowing a single array multidimensional array to be replaced
by a lower-dimensional array of pointers.
this statement is true or false...
Plz Explain
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becoz , Consider two Attributes, A B
then possibility are, 1)AB is a key then directly in BCNF,
2)A is a key then automaticaly B is depend on A
3)vice versa of 2)
so
A relation with two attributes is always 2Nf,3nf and also in BCNF form.
Vijay
On Thu, Aug 4, 2011 at 2:51 PM,
#includestdio.h
#includeconio.h
void main()
{
clrscr();
float a=5.375;
char *p;
int i;
p=(char *)a;
for(i=0;i=3;i++)
printf(%02x,(unsigned char)p[i]);
getch();
}
O/P-00 00 AC 40
Plz anyone explain me output.
Vijay
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Thanks, but can u elaborate some more explanation, that how for loop is
working here
Vijay
On Thu, Aug 4, 2011 at 9:52 PM, wastrel virmanisadi...@gmail.com wrote:
floating point numbers are stored in 4 bytes with first 3 bytes storing the
mantissa part...1st bit of last byte
for(i=1,j=10;i6;++i,--j)
pf(%d %d,i,j);
and
for(i=1,j=10;i6;i++,j--)
pf(%d %d,i,j);
why this both giving same o/p, since one is pre and other is
postplz explain me
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.
As in for loop three sequential steps are .
1. Initialization
2. Checking condition
3. Increment or decrement
On Tue, Aug 2, 2011 at 2:56 PM, Vijay Khandar vijaykhand...@gmail.com
wrote:
for(i=1,j=10;i6;++i,--j)
pf(%d %d,i,j);
and
for(i=1,j=10;i6;i++,j--)
pf(%d %d,i,j);
why
Thanks Jagrati
On Tue, Aug 2, 2011 at 3:19 PM, jagrati verma
jagrativermamn...@gmail.comwrote:
coz we do in for loop 1st initialization thn condition thn increment so
in 1st for loop it will print the value thn increment the i's value so itll
behave like a i++
dats y no
#includestdio.h
#includeconio.h
#includestring.h
void main()
{
clrscr();
char str1[]=Hello;
char str2[]=Hello;
int i;
if(strcmp(str1,str2))
printf (\n Equal);
else
printf(\n Unequal);
getch();
}
Plz anyone explain me o/p with explanation.
Vijay
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, 2011 at 7:47 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
#includestdio.h
#includeconio.h
#includestring.h
void main()
{
clrscr();
char str1[]=Hello;
char str2[]=Hello;
int i;
if(strcmp(str1,str2))
printf (\n Equal);
else
printf(\n Unequal);
getch();
}
Plz anyone explain me o/p
main()
{
int a=6,b=10,x;
x=ab;
printf(%d,x);
}
O/P=2
Plz any one explain me ,how its come
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Thanks, but also one small doubt
If x=y=z=-4 then plz tell me o/p of
pf(++x++y||++z) and pf(x,y,z) these two statements.
On Fri, Jul 29, 2011 at 10:52 AM, jagrati verma jagrativermamn...@gmail.com
wrote:
vijay x=y=z=-1
so for ++x++y||++z
++x=0
so 1st condition will get false so
Yes , so can u explai me plz, i m little bit confusing..Vijay
On Fri, Jul 29, 2011 at 12:39 PM, Prem Krishna Chettri
hprem...@gmail.comwrote:
1
and
-3 -3 -4..
Verify the Compilation..
Regards
Prem
On Fri, Jul 29, 2011 at 12:35 PM, Vijay Khandar
vijaykhand
Thanks Prem got it now...
On Fri, Jul 29, 2011 at 12:44 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
Yes , so can u explai me plz, i m little bit confusing..Vijay
On Fri, Jul 29, 2011 at 12:39 PM, Prem Krishna Chettri hprem...@gmail.com
wrote:
1
and
-3 -3
, Jul 29, 2011 at 12:44 PM, Vijay Khandar
vijaykhand...@gmail.comwrote:
Yes , so can u explai me plz, i m little bit confusing..Vijay
On Fri, Jul 29, 2011 at 12:39 PM, Prem Krishna Chettri
hprem...@gmail.com wrote:
1
and
-3 -3 -4..
Verify the Compilation
01
Hope you get the recursion there .
On Wed, Jul 27, 2011 at 11:19 PM, Vijay Khandar
vijaykhand...@gmail.comwrote:
#includestdio.h
#includeconio.h
int f(int n)
{
if(n=1)
{
printf( %d,n);
}
else
{
f(n/2);
printf( %d,n%2);
}
}
void main()
{
clrscr();
f(173);
getch
sagarpar...@gmail.comwrote:
+1 @ankur :)
On Wed, Jul 27, 2011 at 11:23 PM, Ankur Khurana ankur.kkhur...@gmail.com
wrote:
one request : dont use trubo C
On Wed, Jul 27, 2011 at 10:23 PM, Vijay Khandar vijaykhand...@gmail.com
wrote:
I m getting o/p
1
2 1 1
1
2 2 1
but on wards when x
0
0-1-1
Thx..
On Thu, Jul 28, 2011 at 11:47 AM, sagar pareek sagarpar...@gmail.comwrote:
+1 @ankur :)
On Wed, Jul 27, 2011 at 11:23 PM, Ankur Khurana ankur.kkhur...@gmail.com
wrote:
one request : dont use trubo C
On Wed, Jul 27, 2011 at 10:23 PM, Vijay Khandar vijaykhand
#includestdio.h
#includeconio.h
void main()
{
clrscr();
int x=1,y=1,z=1;
x+=y+=z;
printf(\n %d\n ,xy?y:x);
printf(\n %d\n,xy?x++:y++);
printf(\n %d %d\n,x,y);
printf(\n %d\n,z+=xy?x++:y++);
printf(\n %d %d %d\n,x,y,z);
x=3;y=z=4;
printf(\n %d\n,z=y=x?1:0);
printf(\n %d\n,z=yy=x);
getch();
}
I m
#includestdio.h
#includeconio.h
void main()
{
clrscr();
int x,y,z;
x=y=z=1;
printf(\n %d,++x||++y++z);
printf(\n %d %d %d ,x,y,z);
x=y=z=1;
printf(\n %d,++x++y||++z);
printf(\n %d %d %d,x,y,z);
x=y=z=1;
printf(\n %d,++x++y++z);
printf(\n %d %d %d,x,y,z);
x=y=z=-1;
printf(\n %d,++x++y||++z);
I m getting o/p
1
2 1 1
1
2 2 1
but on wards when x=y=z= -1
then i m getting something different o/p.
On Wed, Jul 27, 2011 at 10:18 PM, Jnana Sagar supremeofki...@gmail.comwrote:
what do u mean by o/p..actually what r u asking for..sorry to ask
so..i couldn't get u..
On 7/27/11, Vijay
#includestdio.h
#includeconio.h
int f(int n)
{
if(n=1)
{
printf( %d,n);
}
else
{
f(n/2);
printf( %d,n%2);
}
}
void main()
{
clrscr();
f(173);
getch();
}
o/p-1 0 1 0 1 1 0 1
but i m getting 1 0 1 1 0 1 0 1
plz explain me...
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Consider the following C-function in which a[n] and b[m] are two
sorted integer arrays and c[n+m] be an other integer array.
void XYZ(int a[],int b[], int c[])
{
int i,j,k;
i=j=k=0;
while((in)(jm))
{
if (a[i]b[j])
c[k++]=a[i++];
else
c[k++]=b[j++];
}
Which of the following condition(s)
Consider the following C-function in which a[n] and b[m] are two
sorted integer arrays and c[n+m] be an other integer array.
void XYZ(int a[],int b[], int c[])
{
int i,j,k;
i=j=k=0;
while((in)(jm))
{
if (a[i]b[j])
c[k++]=a[i++];
else
c[k++]=b[j++];
}
Which of the following condition(s)
Consider these two functions and two statements S1 and S2 about them.
int work1(int *a,int i,int j)
{
int x=a[i+2];
a[j]=x+1;
return a[i+2]-3;
}
int work2(int *a,int i,int j)
{
int t1=i+2;
int t2=a[t1];
a[j]=t2+1;
return t2-3;
}
S1)The transformation from work1 to work2 is valid, i.e.,for any
Thanks Ankit..
On Tue, Jul 26, 2011 at 9:26 PM, ankit sambyal ankitsamb...@gmail.comwrote:
D) S1 and S2 both are true
S2 is true because
return a[i+2]-3; takes more time than return t2-3;
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Algorithm
ptr points to base addr of a.And on base adrr of a is 1.Assume base addr of
a is 4000 then 1-4000,2-4002,3-4004,4-4006 and 5 on 4008 so op 1if in
question asking *(ptr+2) then op is 3.
Vijay..
On Mon, Jul 25, 2011 at 8:20 PM, swetha rahul swetharahu...@gmail.comwrote:
int main()
{
O/P=9 and 49
since i++ * i++ and++ is postincrement so 3*3=9 then both i++ * i++ goes to
4and 5
now i=5.
then for ++i*++i and ++ is preincrement so first it will 6 and 7 and then
7*7=49
Vijay..
On Mon, Jul 25, 2011 at 8:22 PM, Arshad Alam alam3...@gmail.com wrote:
what would be
#includestdio.h
#includeconio.h
int f(int n,int k)
{
if (n==0)
return 0;
else
if(n%2)
return f(n/2,2*k)+k;
else return f(n/2,2*k)-k;
}
int main()
{
clrscr();
printf(\n %d,f(20,1));
getch();
}
O/p is 9.Plz explai me how it is come
Vijay.
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16-8=8
0+16 - -
*Muthuraj R.
4TH Year BE.**
Information Science Dept*
*PESIT, Bengaluru .
*
On Mon, Jul 25, 2011 at 8:48 AM, Vijay Khandar vijaykhand...@gmail.comwrote:
#includestdio.h
#includeconio.h
int f(int n,int k)
{
if (n==0)
return 0;
else
f(2,8) will be agn else and return will be f(1,16)-8
now fr f(1,16) return will be f(0,32) +16
and now at last return will be 0
so the value will be -1-2+4-8+16=9
On Mon, Jul 25, 2011 at 9:18 PM, Vijay Khandar vijaykhand...@gmail.comwrote:
#includestdio.h
#includeconio.h
int f(int n,int
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