Is there any way to dynamically allocate a 2-D array using *using single
call to malloc* in C ?
--
regards
Apoorve Mohan
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To
#includestdlib.h
int main ()
{
int *mat;
int i,j;
int ROW=4;
int COL=3;
int k=0;
mat=(int *)malloc(ROW*COL*sizeof(int));
for(i=0;iROW;i++)
for(j=0;jCOL;j++)
mat[i*COL+j]=++k;
for(i=0;iROW;i++)
for(j=0;jCOL;j++)
printf(%d,,mat[i*COL+j]);
return 0;
though thankx :)
On Thu, Jun 30, 2011 at 12:44 AM, Apoorve Mohan apoorvemo...@gmail.comwrote:
@above: man i need a 2d array not a 1d array...
On Thu, Jun 30, 2011 at 12:38 AM, hary rathor harry.rat...@gmail.comwrote:
#includestdlib.h
int main ()
{
int *mat;
int i,j;
int
int **p;
p = (int **)malloc(sizeof(int *)*row);
for(i = 0;irow;i++)
p[i] = (int *)malloc(sizeof(int)*column);
On 6/30/11, Apoorve Mohan apoorvemo...@gmail.com wrote:
though thankx :)
On Thu, Jun 30, 2011 at 12:44 AM, Apoorve Mohan
apoorvemo...@gmail.comwrote:
@above: man i need a 2d
@piyush: only one call to malloc...ur sol has 2
On Thu, Jun 30, 2011 at 12:58 AM, Piyush Sinha ecstasy.piy...@gmail.comwrote:
int **p;
p = (int **)malloc(sizeof(int *)*row);
for(i = 0;irow;i++)
p[i] = (int *)malloc(sizeof(int)*column);
On 6/30/11, Apoorve Mohan apoorvemo...@gmail.com
ohh sorrymy bad...i didnt read the whole question..i just read the
subject...:P
i think its not possible if u want other than hary's solution...
On 6/30/11, Apoorve Mohan apoorvemo...@gmail.com wrote:
@piyush: only one call to malloc...ur sol has 2
On Thu, Jun 30, 2011 at 12:58 AM, Piyush
I have solved this using one malloc find the code in http://ideone.com/BV9Kj
On Thu, Jun 30, 2011 at 1:20 AM, Piyush Sinha ecstasy.piy...@gmail.com wrote:
ohh sorrymy bad...i didnt read the whole question..i just read the
subject...:P
i think its not possible if u want other than hary's
