Here is a simple Implementation for it.
http://codepad.org/6TPw3txq
On Tue, Jun 15, 2010 at 6:06 AM, Anurag Sharma wrote:
> just check the signs of the i, j components of vector from the centre of
> screen to (x,y)
>
> pseudo code:-
> getQuadrant(x,y){
>string Q[]={"1st","4th","2nd", "3rd"};
just check the signs of the i, j components of vector from the centre of
screen to (x,y)
pseudo code:-
getQuadrant(x,y){
string Q[]={"1st","4th","2nd", "3rd"};
vx=(x>=midx)?0:1
vy=(y>=midy)?0:1
return Q[(vx<<1)|vy]
}
Anurag Sharma
On Mon, Jun 14, 2010 at 5:55 PM, siddharth srivastav
Don't understand the question.
explain differently.
On 6/14/10, siddharth srivastava wrote:
> I have this code snippet:
> This code snippet defines a boundary coordinates on the screen wrt to the
> center(of the screen).
>
> if( x < x_center )
> x_border = x_center - x_shift;
> el
I have this code snippet:
This code snippet defines a boundary coordinates on the screen wrt to the
center(of the screen).
if( x < x_center )
x_border = x_center - x_shift;
else
x_border = x_center + x_shift;
if( y < y_center )
y_border = y_center - y_shift;
