Thats because you have swapped pointers and printing variables.
On Mon, Oct 29, 2012 at 11:22 PM, rahul sharma rahul23111...@gmail.comwrote:
I have taken form book...i am writing exact code
#includestdio.h
#define swap(a,b,c) c t;t=a,a=b,b=t;
int main()
{
float a,x;
a=20.0;
x=30.0;
@rahul : dude it's working fine ...check your printf() statement you
are swapping the pointers and printing the original float values of a and x
it should be printf(%f%f,*p,*q);
or if you want to swap float values not the pointers then it should be
swap(a,x,float);
printf(%f%f,a,x);
On Mon,
Yeah its working...actually it was written in book...and i did nt
compilemistake of author
On Tue, Oct 30, 2012 at 12:17 PM, Vikram Pradhan vpradha...@gmail.comwrote:
@rahul : dude it's working fine ...check your printf() statement you
are swapping the pointers and printing the
@atul...mistakenly i have put w at place of t in my last post...i wana say
On Mon, Oct 29, 2012 at 10:07 AM, dCoder bansal@gmail.com wrote:
Just replace your macro with its definition and you will understand.
its not doing swapping of pointers...plz explain
@dCode i expanded..but
if you think the your expanded version is incorrect.You are wrong ,
because int * will hold pointer but you are not allocating address of
x ..instead you are allocating x value as an address of x to *t.This
wont work.
so to make it work you need to save the address of x and y in temp pointers i.e
I have taken form book...i am writing exact code
#includestdio.h
#define swap(a,b,c) c t;t=a,a=b,b=t;
int main()
{
float a,x;
a=20.0;
x=30.0;
float *p,*q;
p=a,q=x;
swap(p,q,float*);
printf(%f %f,a,x);
getchar();
}
o/p=20.000 30.000
why not swapped???
On Mon, Oct 29, 2012 at 11:01 PM, atul
well they should not , if you see it closely pointer p and q
contain contain address of a and x.
and swap() macro will swap value these pointers are holding i.e adress
of a and xbut will it reflect address of a and x ???...NO
so if you print the address p and q ...before and after the
Why the following code is not able to swap two macros???although it is
easily swapping 2 variables
#includestdio.h
#define swap(a,b,c) c t;t=a,a=b,b=t
int main
int x=10,y=20;
int *p,*q;
swap(x,y,int);
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it should swap
On 10/28/12, rahul sharma rahul23111...@gmail.com wrote:
Why the following code is not able to swap two macros???although it is
easily swapping 2 variables
#includestdio.h
#define swap(a,b,c) c t;t=a,a=b,b=t
int main
int x=10,y=20;
int *p,*q;
swap(x,y,int);
didnt get you... first it was now working , now its working...!!!
please write clearly about your doubts.
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