@navneet: i didnt get the question that expected no. of what u r asking??
On Mon, Jun 20, 2011 at 3:56 PM, Navneet Gupta navneetn...@gmail.comwrote:
We have an unlimited number of dice at our disposal. Let's roll the
die. If the outcome is 1, 2, or 3, we stop; otherwise, if it is 4, 5,
or 6,
We have an unlimited number of dice at our disposal. Let's roll the
die. If the outcome is 1, 2, or 3, we stop; otherwise, if it is 4, 5,
or 6, a corresponding number of dice are rolled. For example, if the
first roll gives 5, then we roll 5 dice, and so on. This procedure
continues for every
after first Roll no of Expected No of Dices will be 2.5
1/2(0)+1/6(4+5+6)
so after second 2.5^2
so after N rounds 2.5^N
On Mon, Jun 20, 2011 at 3:56 PM, Navneet Gupta navneetn...@gmail.comwrote:
We have an unlimited number of dice at our disposal. Let's roll the
die. If the outcome is 1, 2, or
and Expected value should be
2.5^(N-1)*(7/2)
--
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee
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To
Can you discuss how did you arrive at this value?
Sent from my Windows Phone
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From: sunny agrawal
Sent: 20/06/2011 22:53
To: algogeeks@googlegroups.com
Subject: Re: [algogeeks] Coin Chain Reaction
and Expected value should be
2.5^(N-1)*(7/2)
--
Sunny Aggrawal
B
