@utsav u haven't initialized match anywhere so ur algo fails
On Thu, Jun 7, 2012 at 2:50 AM, utsav sharma utsav.sharm...@gmail.comwrote:
i think it can be solved using DP
word=bcdf take hash of word h[b]=1 h[c]=2 h[d]=3 h[f]=4
given 2d matrix m[][]=
{b c b e f g h
b c d f p o u
d f d
WAP to find a word in a 2D array. The word can be formed on
row/col/diagnal/reverse diagnal
Best Regards
Ashish Goel
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i did this question long time back
well simple brute force check can be doneyou can keep one flag
matrix of same size to avoid necessary recursion.
On 6/6/12, Ashish Goel ashg...@gmail.com wrote:
WAP to find a word in a 2D array. The word can be formed on
row/col/diagnal/reverse
i think it can be solved using DP
word=bcdf take hash of word h[b]=1 h[c]=2 h[d]=3 h[f]=4
given 2d matrix m[][]=
{b c b e f g h
b c d f p o u
d f d f g k p }
take another matrix match[][]
if( h[ m[i][j] ] 0 ) //if this char is in word then
{a=h[ m[i][j] ];
if (match[i-1][j] ==a-1
