+1 @Sankalp
On Tue, Jul 5, 2011 at 5:02 PM, sankalp srivastava
wrote:
> A better place to put these types of questions would be www.stackoverflow.com
>
> On Jul 4, 10:45 pm, amit kumar wrote:
>> thanx guys...
>>
>> On Mon, Jul 4, 2011 at 5:11 PM, mahesh.jnumc...@gmail.com <
>>
>>
>>
>>
>>
>>
>>
A better place to put these types of questions would be www.stackoverflow.com
On Jul 4, 10:45 pm, amit kumar wrote:
> thanx guys...
>
> On Mon, Jul 4, 2011 at 5:11 PM, mahesh.jnumc...@gmail.com <
>
>
>
>
>
>
>
> mahesh.jnumc...@gmail.com> wrote:
> > In while loop, the value of i will be used as 0
@amit ,
Then explain me , in simpler words .. as i am not able to get it ...
On 6/17/11, Anand wrote:
> Question:
> main()
> {
> char str[] = "hai friends";
> char *p,*p1;
> p = str;
> p1=p;
> while(*p != 's')
> {
> ++*p++;
>
> }
> printf(" %s",p1);
> }
> http://codepad.org/
Question:
main()
{
char str[] = "hai friends";
char *p,*p1;
p = str;
p1=p;
while(*p != 's')
{
++*p++;
}
printf(" %s",p1);
}
http://codepad.org/24hmvzP5
Ans: ibj!gsjfoes
On Thu, Jun 16, 2011 at 9:24 AM, sunny agrawal wrote:
> @Arpit
> Thanks to Bruce Eckel :D
>
>
> On Thu,
@Arpit
Thanks to Bruce Eckel :D
On Thu, Jun 16, 2011 at 9:00 PM, Arpit Sood wrote:
> @sunny thanks, that post did clear the confusion.
>
>
> On Thu, Jun 16, 2011 at 8:17 PM, Navneet Gupta wrote:
>
>> Then i would suggest you give the original reference in such cases for
>> still better understan
@sunny thanks, that post did clear the confusion.
On Thu, Jun 16, 2011 at 8:17 PM, Navneet Gupta wrote:
> Then i would suggest you give the original reference in such cases for
> still better understanding :)
> Be it a book or a website.
>
>
> On Thu, Jun 16, 2011 at 8:13 PM, sunny agrawal wrote:
Then i would suggest you give the original reference in such cases for still
better understanding :)
Be it a book or a website.
On Thu, Jun 16, 2011 at 8:13 PM, sunny agrawal wrote:
> yes copy pasting the exact thing :)
> for better understanding :)
>
> On Thu, Jun 16, 2011 at 8:06 PM, Navneet Gu
yes copy pasting the exact thing :)
for better understanding :)
On Thu, Jun 16, 2011 at 8:06 PM, Navneet Gupta wrote:
> @Sunny, it is good that you follow Bruce Eckel, but copy pasting the exact
> thing? :)
>
>
> On Thu, Jun 16, 2011 at 7:34 PM, keyan karthi
> wrote:
>
>> "hi friends" is a strin
@Sunny, it is good that you follow Bruce Eckel, but copy pasting the exact
thing? :)
On Thu, Jun 16, 2011 at 7:34 PM, keyan karthi wrote:
> "hi friends" is a string literal.. ie the string "hi friends" is stored
> somewhere and a pointer to its base address is returned to pointer p at the
> time
"hi friends" is a string literal.. ie the string "hi friends" is stored
somewhere and a pointer to its base address is returned to pointer p at the
time of initialization... u can always make use of this pointer to traverse
/ access the "literal" but u cant "alter tat" in the code, u r trying to do
i still din't get the solution..please explain..
On 6/16/11, LALIT SHARMA wrote:
> ++*p++
> ==>
> ++(*p++) ,
> increments the value stored at p , and also increments p .
>
>
>
> On Thu, Jun 16, 2011 at 1:10 PM, sunny agrawal
> wrote:
>
>> The place where strict constness is not enforced is with c
lalit u r wrong
On Thu, Jun 16, 2011 at 1:44 PM, LALIT SHARMA wrote:
> ++*p++
> ==>
> ++(*p++) ,
> increments the value stored at p , and also increments p .
>
>
>
>
> On Thu, Jun 16, 2011 at 1:10 PM, sunny agrawal wrote:
>
>> The place where strict constness is not enforced is with character
>>
++*p++
==>
++(*p++) ,
increments the value stored at p , and also increments p .
On Thu, Jun 16, 2011 at 1:10 PM, sunny agrawal wrote:
> The place where strict constness is not enforced is with character
> array literals. You can say
> char* cp = "howdy";
> and the compiler will accept it witho
The place where strict constness is not enforced is with character
array literals. You can say
char* cp = "howdy";
and the compiler will accept it without complaint. This is
technically an error because a character array literal (“howdy” in
this case) is created by the compiler as a constant charac
//kk
//In place of
char *p="hai friends",*p1;
if i declare as
char p[]="hai friends";
char *p1;
//then ??
On Thu, Jun 16, 2011 at 8:16 AM, DIPANKAR DUTTA
wrote:
> It's ok..
>
> char *p="hai friends"...not correct
>
> bcz you did allocate memory for that string but assiging poiter to the base
It's ok..
char *p="hai friends"...not correct
bcz you did allocate memory for that string but assiging poiter to the base
address.. from where gcc will get the bse address of that string when u r
not actually allocate memory for it? thus it generate SIGSEG signal and give
invalid memory addre
Gives me a SEGFAULT on gcc.
Probably due to undefined behaviour.
--
DK
http://twitter.com/divyekapoor
http://www.divye.in
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