If a 6 o'clock the clock strikes 6times. The difference between the
first and the last strike is 30 secs. Find the time taken when it
strikes 12
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it takes 66 sec after 12correct me if i am wrong
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66 sec
On Wed, Aug 31, 2011 at 11:00 PM, htross wrote:
> If a 6 o'clock the clock strikes 6times. The difference between the
> first and the last strike is 30 secs. Find the time taken when it
> strikes 12
>
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> "Algo
ans is 20
*Stop Cramming Start Thinking*
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oh thanks :) It's given as 10 only. Printing mistake i guess.
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it's basic unitary method problem:
x men do work in 10 days
1 man will do-in 10*x days
x-10 men do it in 10*x/(x-10) = (10+10)
Solve it and x = 20
it can't be 130
On Fri, Aug 26, 2011 at 11:53 PM, gmagog...@gmail.com
wrote:
> @Rahul
>
> Assume the productivity of each man is the same
>
> l
If it is 10 days originally, answer is 20 for sure.
Sanju
:)
On Fri, Aug 26, 2011 at 11:27 AM, Sanjay Rajpal wrote:
> In this question, instead of 10, it is 100.
> Check it again.
>
>
> Sanju
> :)
>
>
>
> On Fri, Aug 26, 2011 at 11:26 AM, Sanjay Rajpal wrote:
>
>> Sry for prrevious post .
In this question, instead of 10, it is 100.
Check it again.
Sanju
:)
On Fri, Aug 26, 2011 at 11:26 AM, Sanjay Rajpal wrote:
> Sry for prrevious post .
>
> It is question of R S Aggarwal, and solved using conecpt of direct and
> indirect proportions.
>
> Originally,let there be x men.
>
> Le
Sry for prrevious post .
It is question of R S Aggarwal, and solved using conecpt of direct and
indirect proportions.
Originally,let there be x men.
Less men,more days(indirect proposition)
(x-10) : x :: 100 : 110
(x-10) * 110 = x * 100
ANS : x = 110
Sanju
:)
On Fri, Aug 26, 2011 at 11:2
@Rahul
Assume the productivity of each man is the same
let original number of man be x
The total workload= x*10*p
also workload = (x-10)(10+10)*p
solve it
so x=20
Yanan Cao
On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma wrote:
> @yanan how it is 20.
>
> Rahul Verma
>
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the answer is 130 itseems. i too got 20
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Fo
@yanan how it is 20.
Rahul Verma
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20 men ?
(x-10)20=10x
Sanju
:)
On Fri, Aug 26, 2011 at 11:17 AM, gmagog...@gmail.com
wrote:
> 20?
>
> Yanan Cao
>
>
>
> On Fri, Aug 26, 2011 at 1:12 PM, priya ramesh <
> love.for.programm...@gmail.com> wrote:
>
>> A certain number of men can finish a piece of work in 10 days. If however
>> the
i too got the same ans.
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20?
Yanan Cao
On Fri, Aug 26, 2011 at 1:12 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:
> A certain number of men can finish a piece of work in 10 days. If however
> there were 10 men less it will take 10 days more for the work to be
> finished. How
> many men were there originall
A certain number of men can finish a piece of work in 10 days. If however
there were 10 men less it will take 10 days more for the work to be
finished. How
many men were there originally?
(a) 110 men
(b) 130 men
(c) 100 men
(d) none of these
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sorry I wrote them in different order:
if (a,b) and (b,a) are considered same then answer is 12
and if they are considered different it is 24.
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The number of distinct factors a number has is given by the product of one
more than the maximum power of each of the prime factors.
the number 24*33 = 792 can be written as (2^3)*(3^2)*(11^1)
then the number of distinct factors of 792 will become (3+1)*(2+1)*(1+1) =
24
So we can form 24/2 = 12 dis
The answer can be given by writing all the prime factors as:
N = 24 * 33 = 2^3 * 3*2 * 11
=> answer will be :
(3+1)*(2+1)*(1+1) = 24
This is the answer considering (a,b) and (b,a) different
If you consider them same the answer is 24/2 = 12.
Nikhil Gupta
IIT Roorkee
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It would be sum of number of factors of both the numbers.
24 -1,2,3,4,6,8,12,24
33-1,3,11,33
On Tue, Aug 23, 2011 at 10:54 PM, Aman Goyal wrote:
> ans is 12, but instead of counting i am looking for some better solution.
>
>
> On Tue, Aug 23, 2011 at 10:48 PM, manish patel wrote:
>
>>
>> (24,3
ans is 12, but instead of counting i am looking for some better solution.
On Tue, Aug 23, 2011 at 10:48 PM, manish patel wrote:
>
> (24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
>
> On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal wrote:
>
>> Let a nat
(24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal wrote:
> Let a natural number N be such that N = a × b where a and b are the factors
> of N. How many such sets of (a, b) can be formed in which the selecti
is the ans 16??
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Let a natural number N be such that N = a × b where a and b are the factors
of N. How many such sets of (a, b) can be formed in which the selection of
the two numbers a and b is distinctly different if N = 24 × 33?
Please explain your solution also.
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i also have the problem , any one, in the book , the answer is not
satisfiable
Rahul
On Tue, Aug 23, 2011 at 7:52 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:
> Out of two thirds of the total number of basket -ball matches, a team has
> won 17 matches and lost 3 of them. What is the
Out of two thirds of the total number of basket -ball matches, a team has
won 17 matches and lost 3 of them. What is the maximum number of matches
that the team can lose and still win three -fourths of the total number of
matches, if it is true that no match can end in a tie? [1] 4 [2] 6 [3] 5 [4
@tushar:
thanks
On Sun, Aug 21, 2011 at 12:27 PM, Tushar Bindal wrote:
> if the cyclist would have left on time, then in those 20 minutes, he would
> have covered 4miles at a speed of 12miles/h
> so he would have been 1 mile before station whereas train would have been 5
> miles before as it is
if the cyclist would have left on time, then in those 20 minutes, he would
have covered 4miles at a speed of 12miles/h
so he would have been 1 mile before station whereas train would have been 5
miles before as it is on its normal time, so no change in its position.
then, when the cyclist covers th
@gupta:
can you explain your answer?
On Sun, Aug 21, 2011 at 1:50 AM, D!leep Gupta wrote:
> 60mph
>
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60mph
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A train and A Cyclist reaches a station every day at the same time. One
day the Cyclist starts 20 minutes late from his house.On his way to
station the train crosses him at 5 miles before station.The speed of
cyclist is12mph. Find the speed of the train.
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answer has to be sqrt(146) . 13 cant be the answer
On Wed, Aug 17, 2011 at 7:55 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:
> the answer is given as 13... even i got root(146)
>
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the answer is given as 13... even i got root(146)
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he is srqt(11^2+5^2)~12.1kms away from A.
if he would hav travelled 4 kms in east then ans would hav been 13kms
On Wed, Aug 17, 2011 at 7:43 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:
> A moves 3 kms east from his starting point . He then travels 5 kms north.
> From that point he
11.716 km
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sqrt(146)
On Wed, Aug 17, 2011 at 7:43 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:
> A moves 3 kms east from his starting point . He then travels 5 kms north.
> From that point he moves 8 kms to the east.How far is A from his starting
> point?
>
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A moves 3 kms east from his starting point . He then travels 5 kms north.
>From that point he moves 8 kms to the east.How far is A from his starting
point?
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the clock has become faster by 48 seconds in 10800 minutes
i.e., 1 sec in 225 minutes
from 8am on sunday we have to go 225*5*60 minutes behind to get time when
clock showed the correct time.
i.e., 67500 minutes or 44 days 1260 minutes
44 days 21 hours
which means clock showed correct timing at 11a
a clock gains uniformly and is 5 minute at 8.00 am on sunday.And on
next sunday it is 5 minute 48 second fast at 8.00 pm.Tell the time
when clock was showing correct time
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