66 sec
On Wed, Aug 31, 2011 at 11:00 PM, htross htb...@gmail.com wrote:
If a 6 o'clock the clock strikes 6times. The difference between the
first and the last strike is 30 secs. Find the time taken when it
strikes 12
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it takes 66 sec after 12correct me if i am wrong
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If a 6 o'clock the clock strikes 6times. The difference between the
first and the last strike is 30 secs. Find the time taken when it
strikes 12
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ans is 20
*Stop Cramming Start Thinking*
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*Dheeraj Sharma*
Comp Engg.
NIT Kurukshetra
+91 8950264227
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A certain number of men can finish a piece of work in 10 days. If however
there were 10 men less it will take 10 days more for the work to be
finished. How
many men were there originally?
(a) 110 men
(b) 130 men
(c) 100 men
(d) none of these
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20?
Yanan Cao
On Fri, Aug 26, 2011 at 1:12 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A certain number of men can finish a piece of work in 10 days. If however
there were 10 men less it will take 10 days more for the work to be
finished. How
many men were there originally?
i too got the same ans.
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20 men ?
(x-10)20=10x
Sanju
:)
On Fri, Aug 26, 2011 at 11:17 AM, gmagog...@gmail.com
gmagog...@gmail.comwrote:
20?
Yanan Cao
On Fri, Aug 26, 2011 at 1:12 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A certain number of men can finish a piece of work in 10 days. If however
@yanan how it is 20.
Rahul Verma
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the answer is 130 itseems. i too got 20
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For
@Rahul
Assume the productivity of each man is the same
let original number of man be x
The total workload= x*10*p
also workload = (x-10)(10+10)*p
solve it
so x=20
Yanan Cao
On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma rahul08k...@gmail.com wrote:
@yanan how it is 20.
Rahul Verma
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Sry for prrevious post .
It is question of R S Aggarwal, and solved using conecpt of direct and
indirect proportions.
Originally,let there be x men.
Less men,more days(indirect proposition)
(x-10) : x :: 100 : 110
(x-10) * 110 = x * 100
ANS : x = 110
Sanju
:)
On Fri, Aug 26, 2011 at
In this question, instead of 10, it is 100.
Check it again.
Sanju
:)
On Fri, Aug 26, 2011 at 11:26 AM, Sanjay Rajpal srn...@gmail.com wrote:
Sry for prrevious post .
It is question of R S Aggarwal, and solved using conecpt of direct and
indirect proportions.
Originally,let there be x
If it is 10 days originally, answer is 20 for sure.
Sanju
:)
On Fri, Aug 26, 2011 at 11:27 AM, Sanjay Rajpal srn...@gmail.com wrote:
In this question, instead of 10, it is 100.
Check it again.
Sanju
:)
On Fri, Aug 26, 2011 at 11:26 AM, Sanjay Rajpal srn...@gmail.com wrote:
Sry
it's basic unitary method problem:
x men do work in 10 days
1 man will do-in 10*x days
x-10 men do it in 10*x/(x-10) = (10+10)
Solve it and x = 20
it can't be 130
On Fri, Aug 26, 2011 at 11:53 PM, gmagog...@gmail.com
gmagog...@gmail.comwrote:
@Rahul
Assume the productivity of each man
oh thanks :) It's given as 10 only. Printing mistake i guess.
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Out of two thirds of the total number of basket -ball matches, a team has
won 17 matches and lost 3 of them. What is the maximum number of matches
that the team can lose and still win three -fourths of the total number of
matches, if it is true that no match can end in a tie? [1] 4 [2] 6 [3] 5
i also have the problem , any one, in the book , the answer is not
satisfiable
Rahul
On Tue, Aug 23, 2011 at 7:52 PM, priya ramesh
love.for.programm...@gmail.com wrote:
Out of two thirds of the total number of basket -ball matches, a team has
won 17 matches and lost 3 of them. What is the
is the ans 16??
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(24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal aman.goya...@gmail.com wrote:
Let a natural number N be such that N = a × b where a and b are the factors
of N. How many such sets of (a, b) can be formed
ans is 12, but instead of counting i am looking for some better solution.
On Tue, Aug 23, 2011 at 10:48 PM, manish patel manispatel...@gmail.comwrote:
(24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal
It would be sum of number of factors of both the numbers.
24 -1,2,3,4,6,8,12,24
33-1,3,11,33
On Tue, Aug 23, 2011 at 10:54 PM, Aman Goyal aman.goya...@gmail.com wrote:
ans is 12, but instead of counting i am looking for some better solution.
On Tue, Aug 23, 2011 at 10:48 PM, manish patel
The answer can be given by writing all the prime factors as:
N = 24 * 33 = 2^3 * 3*2 * 11
= answer will be :
(3+1)*(2+1)*(1+1) = 24
This is the answer considering (a,b) and (b,a) different
If you consider them same the answer is 24/2 = 12.
Nikhil Gupta
IIT Roorkee
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The number of distinct factors a number has is given by the product of one
more than the maximum power of each of the prime factors.
the number 24*33 = 792 can be written as (2^3)*(3^2)*(11^1)
then the number of distinct factors of 792 will become (3+1)*(2+1)*(1+1) =
24
So we can form 24/2 = 12
sorry I wrote them in different order:
if (a,b) and (b,a) are considered same then answer is 12
and if they are considered different it is 24.
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Indian Institute of Technology Roorkee,
Roorkee, Uttarakhand,
India , 247667
Phone: +91 9634990161
email: nikgp...@iitr.ernet.in
if the cyclist would have left on time, then in those 20 minutes, he would
have covered 4miles at a speed of 12miles/h
so he would have been 1 mile before station whereas train would have been 5
miles before as it is on its normal time, so no change in its position.
then, when the cyclist covers
@tushar:
thanks
On Sun, Aug 21, 2011 at 12:27 PM, Tushar Bindal tushicom...@gmail.comwrote:
if the cyclist would have left on time, then in those 20 minutes, he would
have covered 4miles at a speed of 12miles/h
so he would have been 1 mile before station whereas train would have been 5
sqrt(146)
On Wed, Aug 17, 2011 at 7:43 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A moves 3 kms east from his starting point . He then travels 5 kms north.
From that point he moves 8 kms to the east.How far is A from his starting
point?
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11.716 km
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he is srqt(11^2+5^2)~12.1kms away from A.
if he would hav travelled 4 kms in east then ans would hav been 13kms
On Wed, Aug 17, 2011 at 7:43 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A moves 3 kms east from his starting point . He then travels 5 kms north.
From that point he
the answer is given as 13... even i got root(146)
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answer has to be sqrt(146) . 13 cant be the answer
On Wed, Aug 17, 2011 at 7:55 PM, priya ramesh
love.for.programm...@gmail.com wrote:
the answer is given as 13... even i got root(146)
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a clock gains uniformly and is 5 minute at 8.00 am on sunday.And on
next sunday it is 5 minute 48 second fast at 8.00 pm.Tell the time
when clock was showing correct time
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the clock has become faster by 48 seconds in 10800 minutes
i.e., 1 sec in 225 minutes
from 8am on sunday we have to go 225*5*60 minutes behind to get time when
clock showed the correct time.
i.e., 67500 minutes or 44 days 1260 minutes
44 days 21 hours
which means clock showed correct timing at
34 matches
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