@Saumya, This is a great approach. But it still has a small problem since
there is a non-zero probability (though small) that we need to repeat this
experiment infinitely many times to get a single random number in [1,7]. Is
this the best we can do?
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Random 5 function will ensure equal probability for all number starting from
0 to 5. Now consider an event that you will run that random 5 function
twice. This will create 25 elements in your sample space. Now make seven
groups of three elements. This means that each group will be having three
