let's break up that line you have in the end:
int(*f)(char) = (int(*)(char))foo ;
f('a') ;
it becomes clear that f has a return type of int. So the ambiguity is
resolved...
Anil
On Tue, May 25, 2010 at 2:25 PM, Anil C R wrote:
>
> Out of curiosity why would you do something like this?
> Anil
>
Out of curiosity why would you do something like this?
Anil
On Tue, May 25, 2010 at 12:45 PM, Modeling Expert <
cs.modelingexp...@gmail.com> wrote:
> If we have templatized functions , return type becomes part of
> function signature ( which is not the case when we have normal non-
> templatized
If we have templatized functions , return type becomes part of
function signature ( which is not the case when we have normal non-
templatized functions ) , So we can have two functions like these who
differ only in return type
template int foo(T)
{ cout << " this " ; }
template bool foo(T)
{ cou
